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3.2 Vector Operations

3.2 Vector Operations

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3.2 Vector Operations. Review. Find the x and y component. Go 4 m to the right, 2 m up, 5 m down, 7m left, 3m to the left and 10 m up. X= 6m left y = 7m up. Pythagorean’s Theorem. c 2 = a 2 + b 2 c - PowerPoint PPT Presentation

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Page 1: 3.2 Vector Operations

3.2 Vector Operations

Page 2: 3.2 Vector Operations

ReviewFind the x and y component.

Go 4 m to the right, 2 m up, 5 m down, 7m left, 3m to the left and 10 m up.

X= 6m left y = 7m up

Page 3: 3.2 Vector Operations

Pythagorean’s Theorem

c2 = a2 + b2

c a

b

Page 4: 3.2 Vector Operations

SOH CAH TOA

• Sin = opposite hypotenuse

• Cos = adjacent hypotenuse

• Tan = oppositeadjacent

Page 5: 3.2 Vector Operations

Head to Tail Method

Page 6: 3.2 Vector Operations

Helpful Hints to Solving Vector Problems

1. Place a dot on your paper

2. Draw the first vector given in the problem in the appropriate direction.

3. Without picking your pencil point off the paper draw the next vector in the appropriate direction.

4. Continue this with as many vectors as you have.

Page 7: 3.2 Vector Operations

Helpful Hints to Solving Vector Problems

5. Draw your resultant from the dot in the beginning to the last vector arrow

6. Look at your drawing. You need to make a right triangle opposite your resultant.

7. Use pythagorean’s theorem to find the resultant side c

8. Vectors must have direction so you will use tan to find the angle from the resultant to the vector. (This angle always rotates around the original dot)

Page 8: 3.2 Vector Operations

Direction

N

W E

S

Page 9: 3.2 Vector Operations

A plane travels from Huston, Texas to Washington, DC, which is 1540 km, East and 1160km north of Houston. What is the total displacement of the plane?

C 1160 KM

1540 km

Page 10: 3.2 Vector Operations

c2 = a2 + b2

c2 = (1540 km)2 + (1160km)2

C = 1928 km = 1930 km

Tan = 1160

1540

Answer: 1930 km, north of east Practice: 90 degree Problems

Page 11: 3.2 Vector Operations
Page 12: 3.2 Vector Operations

Boat Problems

A motorboat heads due east at 16 m /s across a river that flows due south at 9.0 m /s.

A. What Is the resultant velocity of the boat.

B. If the river is 136 m wide, how long does it take the motorboat to reach the other side?

C. How far downstream is the boat when it reaches the other side of the river?

Page 13: 3.2 Vector Operations

What Is the resultant velocity of the

boat? 16 m /s

c 9 m /s

C 2 = (16)2 + (9)2 C = 18 m /s

Tan 9 / 16 = 30o

18 m /s, 30o south of east

Page 14: 3.2 Vector Operations

If the river is 136 m wide, how long does it take the motorboat to reach

the other side?

V = d t

t = d = 136 m V 16 m /s

t = 8.50 s

Page 15: 3.2 Vector Operations

How far downstream is the boat when it reaches the other side of the river?

V = d

t

d = V t

d = 9.0 m /s X 8.5 s = 77 m

Practice: Boat problems

Page 16: 3.2 Vector Operations

Components

You are given the resultant (magnitude and direction) and you find the sides or components

Use sin and cos to find the x and y component

Hypotenuse angle y

x

Page 17: 3.2 Vector Operations

Component Example

An arrow is shot from a bow at an angle of 25o above the horizontal with an initial speed of 45 m /s. Find the horizontal and vertical components of the arrow’s initial velocity.

45 m /s

25o y X

Page 18: 3.2 Vector Operations

Components

Sin 25o = y = 19 m /s 45

Cos 25o = x = 41 m /s 45

Practice problems on components

Page 19: 3.2 Vector Operations

Putting it all together

A mouse runs east for 4 m across the living room, turns 30o north of east and runs 2.8 m and finally heads due north 3 m to a hole in the wall. What is the resultant?

3 m

2.8 m 30o

4 m

Page 20: 3.2 Vector Operations

Draw and examine. Look for a right triangle. The resultant is “from where you start to where you end it does not

matter where you have been”. Find the components to make the right triangle.

3m C

q 1.4 m

4m 2.4 m

• Add up the all the x’s then all the y’s: x total = 6.4m y total = 4.4m• Use pythagorean’s theorem c 2 = a2 + b2 C = 7.8 m• tan = 4.4 / 6.4 = 35 o

7.8 m, 35 o North of East

Page 21: 3.2 Vector Operations

A camper walks 4.5 km at 45o north of east then 4.5 km due south. Find the

campers total displacement.

4.5

45o 4.5

Page 22: 3.2 Vector Operations

4.5 sin 45 = x x = 3.184.5 sin 45 = y1= 3.18

4.5 - 3.18 = 1.32c2 = 3.182 + 1.322 c = 3.4 tan = 1.32 / 3.18 = 22o

3.4 m, 22o south of east

4.5 45o 4.5

Page 23: 3.2 Vector Operations

Practice, Practice, Practice

• Practice #1

• Practice #2

• Holt Text Pg 94 1-4

• QUIZ