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Resistance to penetration
or localized plastic deformation
Hardness
Commonly measured by:
Rockwell or Brinell test
Hardness
IndenterRockwell test
Rockwell test
Hardness
Indenters: conical diamond or hardened steel balls
(1/16, 1/8, 1/4 or inch dia)
Depth
Brale
Depth
Ball
F F
Hardness number: from the difference in depth
of penetration resulting from the application of
an initial minor load (10 kg) followed by a larger
major load (60, 100 or 150 kg)
Hardness
Rockwell test
Depth
Brale
Depth
Ball
F F
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Indenter: hardened steel or tungsten carbide ball
10 mm dia
Load: 500 to 3000 kg in increments of 500 kg
Hardness
Diameter
F
Brinell test
Hardness is related to load and diameter of indentation
The Brinell hardness number is designated as HB
Hardness
Diameter
F
Brinell test
Differences between Rockwell and Brinell tests
Hardness
Indenters: a conical diamond in Rockwell
for hard materials
Hardness related to
depth of penetration In Rockwell
width of indentation in Brinell
Brinell test uses much higher loads than Rockwell
Hardness
Knoop and Vickers microhardness tests
Lower loads and smaller indenter size
Indenter (both tests):a very small pyramidal diamond
Load: between 1 and 1000 gmuch lower than Rockwell and Brinell tests
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Hardness
They measure the hardness of small specimens
Knoop is used for brittle materials like ceramics
Knoop and Vickers hardness numbers: HK and HV
Knoop and Vickers microhardness tests
Tensile Strength versus Hardness
Both indicate resistance to plastic deformation
Relation between Tensile Strength (TS) and
Brinell Hardness (HB) for steels: TS (psi) = 500 HB
0
50
100
150
200
250
300
0 100 200 300 400 500 600
Brinell Hardness
350650Fractures before yieldingE
2107200.14850700D
3105000.15550415C
1501050.40120100B
2102650.23340310A
Elastic
Modulus
1000 MPa
Fracture
Strength
MPa
Strain at
Fracture
Tensile
Strength
MPa
Yield
Strength
MPa
Alloy
Which of these materials:
(a) is the hardest?
(b) will experience the greatest % reduction in area?
(c) is the strongest?
(d) is the stiffest?
(e) has the highest modulus of resilience?
Explain why.
(a) Which of these materials is the hardest? Why?
-- Alloy D is the hardest
because it has the highest yield strength
350650Fractures before yieldingE
2107200.14850700D
3105000.15550415C
1501050.40120100B
2102650.23340310A
Elastic
Modulus
1000 MPa
Fracture
Strength
MPa
Strain at
Fracture
Tensile
Strength
MPa
Yield
Strength
MPa
Alloy
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(b) Which of these materials will experience the greatest
% reduction in area? Why?
- Alloy B. It has the highest strain at fracture, and,
therefore is most ductile.
350650Fractures before yieldingE
2107200.14850700D
3105000.15550415C
1501050.40120100B
2102650.23340310A
Elastic
Modulus1000 MPa
Fracture
StrengthMPa
Strain at
Fracture
Tensile
StrengthMPa
Yield
StrengthMPa
Alloy
(c) Which of these materials is the strongest? Why?
- Alloy D is the strongest as it has the highest yield strength.
350650Fractures before yieldingE
2107200.14850700D
3105000.15550415C
1501050.40120100B
2102650.23340310A
Elastic
Modulus1000 MPa
Fracture
StrengthMPa
Strain at
Fracture
Tensile
StrengthMPa
Yield
StrengthMPa
Alloy
(d) Which of these materials is the stiffest? Why?
- Alloy E is the stiffest as it has the highest elastic modulus.
350650Fractures before yieldingE
2107200.14850700D
3105000.15550415C
1501050.40120100B
2102650.23340310A
Elastic
Modulus
1000 MPa
Fracture
Strength
MPa
Strain at
Fracture
Tensile
Strength
MPa
Yield
Strength
MPa
Alloy
(e) Which of these materials has the highest modulus ofresilience? Why?
- Modulus of resilience = 0.5y2/E
Alloy D has the highest value.
350650Fractures before yieldingE
2107200.14850700D
3105000.15550415C
1501050.40120100B
2102650.23340310A
Elastic
Modulus
1000 MPa
Fracture
Strength
MPa
Strain at
Fracture
Tensile
Strength
MPa
Yield
Strength
MPa
Alloy
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Stress calculations are approximate
Safety Factor
Design allowances must be made to protect against
unanticipated failure
Need to establish a safe stress or a working stress
Working stress = Yield strength/Factor of safety
w = y/N
Safety Factor
Factor of safety: 1.2 to 4.0 (normal range)
Based on consequences of failure, economics,
previous experience and the accuracy of theproperty data
Impact Test
What if a material is subjected to a sudden,
intense blow?
It would behave in a much more brittle mannerthan observed in the tensile test
This behavior is tested by impact test (Charpy test)
Impact Test
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Impact Test Impact Test
hf
ho
Impact Test
Impact enegry needed for fracture
is measured from h (i.e. ho-hf)