2Crystal Physics 2013

Embed Size (px)

Citation preview

  • 8/12/2019 2Crystal Physics 2013

    1/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    1

    DEPARTMENT OF SCIENCE & HUMANITIES

    INTRODUCTION TO CRYSTALLOGRAPHY

    A crystal is a solid composed of atoms or other microscopic particles arranged in an orderlyperiodic array.

    The three general types of solids: amorphous, polycrystalline and single crystal aredistinguished by the same periodicity over entire regions within the materials. Order in

    amorphous solids is limited to a few molecular distances. In polycrystalline materials, thesolid is made-up of grains which have same periodicity over smaller regions separated byboundaries from regions of other periodicity or same periodicity with different orientation.

    Single crystals have long-range order. Many important properties of materials are found to

    depend on the structure of crystals and on the electron states within the crystals. At thebeginning of the study of crystals it was their external form which was related to the

    physical properties. In this way only a limited success was achieved. Towards the middle oflast century a deeper understanding developed regarding the correlation of the structure ofcrystals and{mechanical, thermal, electrical and magnetic} properties of solids. This isprimarily due to the advances in the band theory of electron states and in the theory of

    bonding in solids. This knowledge has led to the development of newer and better materials

    for electrical, electronic and structural engineering. The study of crystal physics aims tointerpret the macroscopic properties in terms of properties of the microscopic particles of

    which the solid is composed. The study of the geometric form and other physical propertiesof crystalline solids by using x-rays, electron beams and neutron beams constitute thescience of Crystallography or Crystal Physics.

    Single Pyri te Crystal and Amorphous soli ds:

  • 8/12/2019 2Crystal Physics 2013

    2/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    2

    DEPARTMENT OF SCIENCE & HUMANITIES

    Di stincti on between Crystal li ne soli ds and Amorphous soli ds

    A crystalis a three-dimensional periodic arrangements of atoms in space.

    Crystal structure- The arrangement of atoms, ions, or molecules in a crystal. Crystals are

    solids having, in all three dimensions of space, a regular repeating internal unit of structure.

    Space Lattice- A regular periodic 3 dimensional arrangement of points in space.

    Unit cell- The smallest group of atoms or molecules whose repetition at regular intervals inthree dimensions produces the lattices of a crystal

    Primitive cellUnit cell of the crystal which has one lattice point per cell. Eg: Cubic cell -Each atom is shared by 8 cells. So per cell there are (1/8 x 8) = 1 lattice point/cell= 1

    atom/cell in a SC.

    S. No. Crystalline solids Amorphous solids1 The internal arrangement of

    particles is regular so they possess definite

    and regular geometry

    The internal arrangement of particles is irregular. Thus

    they do not have any definite geometry

    2. They have sharp melting points They do not have sharp melting points

    3. There is regularity in the external form

    when crystals are formed

    There is no regularity in the external form when

    amorphous solids are formed

    4. Crystalline solids give a regular cut

    when cut with a sharp edged knife

    Amorphous solids give irregular

    cut.

    5. They have characteristic heat of fusion They do not have characteristic heat of fusion

    6. Crystalline solids are rigid and their shape

    is not distorted by mild distorting forces

    Amorphous solids are not rigid. They are distorted by

    bending or compressive forces

    7 Crystalline solids are regarded as true

    solids

    Amorphous solids are regarded as super cooled liquids or

    pseudo solids

    8 Crystalline solids are anisotropic Amorphous solids are isotropic

  • 8/12/2019 2Crystal Physics 2013

    3/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    3

    DEPARTMENT OF SCIENCE & HUMANITIES

    Basis Group of atoms or molecules identical in composition.

    Apart from the fundamental translation symmetry, a lattice may also exhibit othersymmetries:Rotations by 2/n where n=1,2,3,4,6. Reflection in a plane through a lattice point.

    Inversion, i.e. a rotation of + a reflection in a plane orthogonal to the rotation axis. Lattice

    Point groups collection of symmetry operations which when applied about a lattice point,leaves the lattice invariant. No. of different (independent) possible lattice types can be

  • 8/12/2019 2Crystal Physics 2013

    4/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    4

    DEPARTMENT OF SCIENCE & HUMANITIES

    grouped, based on symmetry operations, or their combinations into Bravais lattices. There

    are 5 types in two dimensions and 14 ones in three dimensions.

    Lattice parameters of an unit cell

    The parameters that define a unitcell are:a, b, c unit cell dimensions along x, y, z respectively , , angles between b,c ();a,c (); a,b ()

    Crystal systems and Bravais lattices

    The number of different Bravais lattices is determined by symmetry considerations

    Two dimensional space five Bravais latticesThree dimensional space 14 Bravais lattices grouped into seven crystal systems

    The classification of crystal lattice is based1) On equality (or inequality) of the lengths a,b,c of the edges of the conventional

    cell,2) On the angles , , between each pair of them

    3) and on possible occurrence of additional lattice points at the centre of opposite faces

    or at the center of the cell.

  • 8/12/2019 2Crystal Physics 2013

    5/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    5

    DEPARTMENT OF SCIENCE & HUMANITIES

    S. No. Crystal System Lattice Parameters Bravais Lattice Example

    1 Cubic a=b=c

    ===901. Simple2. Body centred3. Face Centred

    PoloniumNa, Cu2O, Ag, Au,Cu

    2 Tetragonal a=bc===90

    1. Simple2. Body centred

    TiO2, SnO2,KH2PO4

    3 Orthorhombic abc== 90

    1. Simple2. Body centred3. Face centred4. Base centred

    C15H20O2, Sulphur,KNO3

    4 Monoclinic abc===90

    1. Simple2. Base centred

    Gypsum, Na2SO4,FeSO4

    5 Triclinic abc

    90

    1. Simple K2Cr2O7, CuSO4

    6 Trigonal a=b=c

    ==901. Simple Calcite, Sb, Bi

    7 Hexagonal a=bc== 90=120

    1. Simple Quartz, Zn, Cd

  • 8/12/2019 2Crystal Physics 2013

    6/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    6

    DEPARTMENT OF SCIENCE & HUMANITIES

    Crystal Planes

    Within a crystal lattice it is possible to identify sets of equally spaced parallel planes. Theseare called lattice planes. In the figure density of lattice points on each plane of a set is thesame and all lattice points are contained on each set of planes.

    The set of planes in 2D lattice

    Miller Indices

    Miller Indices are a symbolic vector representation for the orientation of an atomic planein a crystal lattice. It is defined as the reciprocals of the fractional intercepts which the plane

    makes with the crystallographic axes. Miller indices are represented by a set of 3 integernumbers h,k and l given in brackets (hkl).

    [ hkl ] represents direction perpendicular to the crystal plane

    represented by (hkl).{ hkl } represents set of planes parallel to ( h k l ).

    Procedure for finding Miller indices

    Consider a crystal plane. Let us find its Miller indices as follows.

    Step 1: Find intercepts of the plane along the coordinate axes X,Y, Z.

    (The intercepts are measured as multiples of the fundamental vectors.)

    Step 2: Take the reciprocal of these intercepts.Step 3: Reduce the reciprocals into whole numbers by multiplying each ofthem with their least common multiple. Let us represent these numbers as h, k and l.

    Step 4: Write these integers within paratheses to get Miller indices.

  • 8/12/2019 2Crystal Physics 2013

    7/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    7

    DEPARTMENT OF SCIENCE & HUMANITIES

    Example:

    Step 1: Intercepts a, b, c are 1 1

    Step 2: Reciprocals 1/1 1/1 1/

    Step 3: Reduction 1 1 0

    Step 4: (1 1 0)

    Derivation of interplanar spacing of cubic crystal

    The interplanar spacing or distance dhkl between adjacent planes of Miller indices (hkl) isdefined as the spacing between the first such plane and a parallel plane passing through the

    origin.ais the lattice constant. Let h, k, and l are the Miller indices for a plane ABC. An

    equation is to be derived for interplanar distanced of plane ABC from a plane parallel to it

    and passing through o (origin) in terms ofh,k,land a. OD is the normal from O on plane

    ABC. OD d = interplanar distance. The intercepts of the plane ABC on the three axis i.c.,X,

    Y and Z axis are OA, OB and OC respectively.

    Now, OA=a/h, OB=a/k,OC=a/l (i)

    Also, cos =OD/OA= d/(a/h) =dh/a (ii)

    cos = OD/OA= d/(a/k)= dk/a (iii)

    cos =OD/OC = d/(a/l) = dl/a (iv)

    Since, cos2+ cos2 + cos2 = 1. therefore

    (dh/a)2+(dk/a)2+ (dl/a)2= 1 d2h2/a2 + d2k2/a2 + d2l2/a2= 1

  • 8/12/2019 2Crystal Physics 2013

    8/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    8

    DEPARTMENT OF SCIENCE & HUMANITIES

    d2(h2+ k2 + l2) =a2

    d2=a2 /(h2+ k2 + l2)

    d= a2 /(h2+ k2 + l2)

    This is the relation between interplanar spacing d, cube edge a and Miller indices (h k l )

    Characteristics of an unit cell

    Number of atoms per unit cell It is the number of atoms possessed by an unit cell.Nearest neighbour distance (2r)Distance between the centres

    of nearest neighbouring atoms.

    Atomic radius (r)Half the distance between the nearestneighbouring atoms.Coordination number (N)Number of equidistant nearest

    neighbours

    Atomic Packing Factor or Packing densityratio of the volumeOccupied by the atoms in an unit cell (v) to the total volume of

    the unit cell (V).

    Packing factor= v/ V

    Crystal Structures

    Simple Cubic (SC) Structur e

    One atom at each of the eight Corners of the unit cell

    Co-ordination number= 6

    4-same layer1-top layer

    1-bottom layer

  • 8/12/2019 2Crystal Physics 2013

    9/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    9

    DEPARTMENT OF SCIENCE & HUMANITIES

    Nearest neighbour distance, 2r=a

    Atomic radius, r= a/2

    No. of atoms/cell=(1/8) x 8 = 1 (Primitive cell)

    Packing factor= No. Of atoms/cell x volume of one atom

    __________________________________

    Total volume of the unit cell

    =

    = = 0.52 = 52%Example: Polonium

    Body-centered Cubic (BCC) structure

    Co-ordination number8 (Look at the atom at body centre)

    No. of atoms/cell= [(1/8) x 8] + 1 = 2= corner atoms + body centered atom

    Diagonal length= 4r3a = 4 r

    Atomic radius r= (3 a/4)

  • 8/12/2019 2Crystal Physics 2013

    10/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    10

    DEPARTMENT OF SCIENCE & HUMANITIES

    Lattice constant a = 4r/3

    Packing factor= No. Of atoms/cell x volume of one atom

    __________________________________

    Total volume of the unit cell

    =

    =

    = 0.68 = 68%

    Example: Tungsten, Chromium, Molybdenum

    Face centred cubic (FCC) structure

    Co-ordination number4+4+4=12

    No. of atoms/cell= [(1/8) x 8] + [(1/2)x6] = 4

    = corner atoms + Face centered atoms

    Face diagonal AC=2 a=4r

  • 8/12/2019 2Crystal Physics 2013

    11/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    11

    DEPARTMENT OF SCIENCE & HUMANITIES

    Atomic radius r=(2/4)a= a/(22)

    Lattice constant, a= 22r

    Packing factor= No. Of atoms/cell x volume of one atom__________________________________

    Total volume of the unit cell

    =

    =

    = 0.74 = 74%

    Example: Copper, Aluminium, Nickel, Gold

    Hexagonal close packed structur e (hcp)

    Co-ordination number3+6+3=12

    No. of atoms/cell= [(1/6) x 6] + [(1/6)x6] + [(1/2)x2] + 3 = 6= corner atoms + central atoms (upper & lower) + body centred atoms

  • 8/12/2019 2Crystal Physics 2013

    12/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    12

    DEPARTMENT OF SCIENCE & HUMANITIES

    Atomic radius 2r = a

    r = a/2

    Relation between c and a

    Refer the above fig.

    AA = AB COS 30 = a

    AX = AA

    AC2 = AX2 + CX2

    CX2 = AC2 - AX2

    CX2= a2 -

    From fig. CX =2, {|2}2 =

  • 8/12/2019 2Crystal Physics 2013

    13/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    13

    DEPARTMENT OF SCIENCE & HUMANITIES

    {|}2 =

    Therefore, {|}2 = 1.633

    Calculation of packing factor

    Area of the base = 6 x area of the triangle ABO

    Area of the base = 6 x1xABx OO = 3 x a x

    x a

    Area of the base =

    Volume of the unit cell V = Area of the base x height

    =

    x c

    Packing factor = No. Of atoms / unit cell x volume of one atom

    __________________________________

    Total volume of the unit cell

    P.F. = 3

    =

    = 0.74 = 74%

  • 8/12/2019 2Crystal Physics 2013

    14/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    14

    DEPARTMENT OF SCIENCE & HUMANITIES

    Diamond Structure

    It is formed by carbon atoms. Each carbon atom is surrounded by four other carbon atomssituated at the corners of regular tetrahedral by the covalent linkages. The diamond cubic

    structure is a combination of two interpenetrating FCC sub lattices displaced along the body

    diagonal of the cubic cell by 1/4th length of that diagonal. Thus the origins of two FCC sublattices lie at (0, 0, 0) and (1/4, 1/4,1/4).

    The points at 0 and 1/2 are on the FCC lattice, those at 1/4 and 3/4 are on a similar FCC

    lattice displaced along the body diagonal by one-fourth of its length. In the diamond cubic

    unit cell, there are eight corner atoms, six face centred atoms and four more atoms. No. of

    atoms contributed by the corner atoms to an unit cell is 1/88 =1. No. of atoms

    contributed by the face centred atoms to the unit cell is 1/2 6 = 3. There are four moreatoms inside the structure. No.of atoms present in a diamond cubic unit cell is 1 + 3 + 4 =

    8. Since each carbon atom is surrounded by four more carbon atoms, the co-ordination

    number is 4.

    ATOMIC RADIUS(R)

    From the figure,in the triangle WXY,

    XY2= XW2+ WY2

    = +

    XY2=

    In triangle XYZ,

    XZ2= XY2+ YZ2

  • 8/12/2019 2Crystal Physics 2013

    15/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    15

    DEPARTMENT OF SCIENCE & HUMANITIES

    Since XZ = 2r,

    (2)2 =

    +

    r =

    Packing factor = No. Of atoms / unit cell x volume of one atom

    __________________________________Total volume of the unit cell

    =8 x 4 x 33 x 3

    51a =16 = 0.34 = 34 %

    Graphite Structure

    Graphite is also a crystalline form of carbon. In graphite each carbon atom is covalently

    bonded to three carbon atoms to give trigonal geometry. Bond angle in graphite is 120oC.Each carbon atom in graphite is sp2 hybridized. Three out of four valence electrons of each

    carbon atom are used in bond formation with three other carbon atoms while the fourthelectron is free to move in the structure of graphite. Basic trigonal units unite together to

    give basic hexagonal ring. In graphite these rings form flat layers. These layers arearranged in parallel, one above the other. These layers are held together by weak

    vanderwaals forces only.These layers can slide one over another.Thus it is very soft. Fourth

    electron of each carbon atom which spreads uniformly over all carbon atoms. Due to thisreason graphite conducts electricity parallel to the of its plane.

  • 8/12/2019 2Crystal Physics 2013

    16/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    16

    DEPARTMENT OF SCIENCE & HUMANITIES

    METHODS OF CRYSTAL GROWTH

    Growth of crystal ranges from a small inexpensive technique to a complex sophisticated

    expensive process and crystallization time ranges from minutes, hours, days and to months.

    Single crystals may be produced by the transport of crystal constituents in the solid, liquidor vapour phase. On the basis of this, crystal growth may be classified into three categoriesas follows,

    Solid Growth - Solid-to-Solid phase transformation

    Liquid Growth - Liquid to Solid phase transformation

    Vapour Growth - Vapour to Solid phase transformation

    Based on the phase transformation process, crystal growth techniques are classified as solid

    growth, vapour growth, melt growth and solution growth. Several techniques have been

    developed for each method of growth to achieve better control over the growth and suit to

    the requirements of newer materials.

    GROWTH FROM SOLUTION

    Materials, which have high solubility and have variation in solubility with temperature can begrown easily by solution method. There are two methods in solution growth depending on

    the solvents and the solubility of the solute. They are

    1. High temperature solution growth

    2. Low temperature solution growth

    In high-temperature solutions, the constituents of the material to be crystallized are

    dissolved in a suitable solvent and crystallization occurs as the solution becomes critically

    supersaturated. The supersaturated may bepromoted by evaporation of the solvent, bycooling the solution or by a transport process in which the solute is made to flow from ahotter to a cooler region. The high temperature crystal growth can be divided into two

    major categories:

    1. Growth from single component system.2. Growth from multi component system.

    This method is widely used for the growth of oxide crystals. The procedure is to heat the

    container having flux and the solute to a temperature so that all the solute materials

  • 8/12/2019 2Crystal Physics 2013

    17/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    17

    DEPARTMENT OF SCIENCE & HUMANITIES

    dissolve. This temperature is maintained for a soak period of several hours and then the

    temperature is lowered very slowly.

    Basic apparatus for solution growth

    Hydrothermal growth

    Hydrothermal implies conditions of high pressure as well as high temperature. Substances

    like calcite, quartz is considered to be insoluble in water but at high temperature and

    pressure, these substances are soluble. This method of crystal growth at high temperatureand pressure is known as hydrothermal method. Temperatures are typically in the range of

    400 C to 600 C and the pressure involved is large (hundreds or thousands of

    atmospheres).Growth is usually carried out in steel autoclaves with gold or silver linings. Depending on the

    pressure the autoclaves are grouped into low, medium and high-pressure autoclaves. The

    concentration gradient required to produce growth is provided by a temperature difference

    between the nutrient and growth areas. The requirement of high pressure presents practical

    difficulties and there are only a few crystals of good quality and large dimensions are grown

    by this technique. Quartz is the outstanding example of industrial hydrothermal

    crystallization. One serious disadvantage of this technique is the frequent incorporation of

    OH

    -

    ions into the crystal, which makes them unsuitable for many applications.

    GEL GROWTH

    It is an alternative technique to solution growth with controlled diffusion and the growth

    process is free from convection. Gel is a two-component system of a semisolid rich in liquid

    and inert in nature. The material, which decomposes before melting, can be grown in this

  • 8/12/2019 2Crystal Physics 2013

    18/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    18

    DEPARTMENT OF SCIENCE & HUMANITIES

    medium by counter diffusing two suitable reactants. Crystals with dimensions of several mm

    can be grown in a period of 3 to 4 weeks. The crystals grown by this technique have highdegree of perfection and fewer defects since the growth takes place at room temperature.

    GROWTH FROM MELT

    All materials can be grown in single crystal form from the melt provided they melt

    congruently without decomposition at the melting point and do not undergo any phase

    transformation between the melting point and room temperature. Depending on the thermal

    characteristics, the following techniques are employed.

    1. Bridgman technique

    2. Czhochralski technique

    Bridgman technique

    Bridgman method is based on crystal growth from a melt but a temperature gradient

    furnace is gradually lowered and crystallization begins at the cooler end, fixed crystal and

    changing temperature gradient.

    Bridgman method involve controlled solidification of a stoichiometric melt of the material

    to be crystallized in a temperature gradient.

    Enables oriented solidification

    Melt passes through a temperature gradient.

    Crystallization occurs at a cooler end.

  • 8/12/2019 2Crystal Physics 2013

    19/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    19

    DEPARTMENT OF SCIENCE & HUMANITIES

    This method benefit from seed crystals, predetermined orientation and controlled

    atmospheres.

    Advantages:

    1. Relatively lower cost

    2. Melt composition can be controlled during the growth.

    Dis-advantages:

    1. Growth rate is very low.

    2. This technique cannot be used for materials which decompose before melting.

    CZOCHRALSKI METHOD

    This technique originates from pioneering work by Czochralski in 1917 who pulled single

    crystals of metals. Since crystal pulling was first developed as a technique for growing single

    crystals, it has been used to grow germanium and silicon and extended to grow a wide

    range of compound semiconductors, oxides, metals, and halides. It is the dominant

    technique for the commercial production of most of these materials.

    Single crystal growth from the melt precursors

    Crystal seed of material to be grown placed in contact with the surface of the melt.

    Temperature of melt held just above melting point, highest viscosity, lowest vapour

    pressure favors the crystal growth.

    Seed gradually pulled out of the melt.

    Melt solidifies on surface of the seed

  • 8/12/2019 2Crystal Physics 2013

    20/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    20

    DEPARTMENT OF SCIENCE & HUMANITIES

    Melt and seed usually rotated counter clockwise with respect to each other to maintain

    constant temperature and to facilitate uniformity of the melt during crystal growth,produces higher quality crystals and less defects.

    Inert atomosphere often under pressure around growing & melt during crystal & melt to

    prevent any materials loss and undesirable reactions like oxidation nitration etc.

    The Czochralski crystal pulling technique is invaluable for growing many large single

    crystals as a rod to be cut into wafers and polished for various applications like Si, Ge,

    lithium niobate.

    Advantages:

    1. Relatively lower cost

    2. Ability to produce larger wafer sizes as in float zone process.

    Dis-advantages:

    1. Melt is accumulated with dopants during the process.

    2. Impurities or metals can dissolve from the crucible and built into the crystal.

    Crystal growth from vapour phase

    In this technique the material to be grown is supplied in the form of vapour. The powders

    of the desired crystalline material are atomized by exposing it to an electric arc or hot

  • 8/12/2019 2Crystal Physics 2013

    21/21

    KGiSL INSTITUTE OF TECHNOLOGY

    ENGINEERING PHYSICS I

    UNI T I - CRYSTAL PHYSICS

    21

    flame. A seed crystal is brought somewhere near the melting point so that the arriving

    atoms or molecules will have sufficiently high mobility on the growing surface.

    At very low temperature many crystals in a very high state of purity has been grown from

    the vapour phase.