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7/28/2019 28. the Integral as Net Change
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7/28/2019 28. the Integral as Net Change
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-100
-50
0
50
100
2 4 6 8 10
ft
min
minutes
A honey bee makes several trips from the hive to a flowergarden. The velocity graph is shown below.
What is the total distance traveled by the bee?
200ft
200ft
200ft
100ft
200 200 200 100 700 700 feet
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-100
-50
0
50
100
2 4 6 8 10
ft
min
minutes
What is the displacementdisplacement of the bee?
200ft
-200ft
200ft
-100ft
200 200 200 100 100 100 feet towards the hive
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To find the displacementdisplacement (position shift) from the velocityfunction, we just integrate the function. The negative
areas below the x-axis are subtracted from the totaldisplacement.
Displacement
b
a
V t d t
Distance Traveledb
aV t dt
To find distance traveleddistance traveled we have to use absolute value.
Find the roots of the velocity equation and integrate in
pieces, just like when we found the area between a curveand the x-axis. (Take the absolute value of each integral.)
Or you can use your calculator to integrate the absolutevalue of the velocity function.
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-2
-1
0
1
2
1 2 3 4 5
velocity graph
-2
-1
0
1
2
1 2 3 4 5
position graph
1
2
1
2
1
2
Displacement:
1 11 2 1
2 2
Distance Traveled:
1 11 2 42 2
Many exams have at leastone problem requiringstudents to interpretvelocity and positiongraphs.
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In the linear motion equation:
dS
V tdt
V(t) is a function of time.
For a very small change in time, V(t) can beconsidered a constant.
dS V t dt
S V t t We add up all the small changes in Sto getthe total distance.
1 2 3S V t V t V t
1 2 3S V V V t
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S V t t We add up all the small changes in Sto getthe total distance.
1 2 3S V t V t V t
1 2 3S V V V t
1
k
nn
S V t
1
n
n
S V t
S V t dt
As the number of subintervals becomesinfinitely large (and the width becomesinfinitely small), we have integration.
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This same technique is used in many different real-life
problems.
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Example: National Potato Consumption
The rate of potato consumptionfor a particular country was:
2.2 1.1tC t
where tis the number of years
since 1970 and Cis in millionsof bushels per year.
For a small , the rate of consumption is constant.t
The amount consumed during that short time is . C t t
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Example 5: National Potato Consumption
2.2 1.1t
C t The amount consumed during that short time is . C t t
We add up all these smallamounts to get the totalconsumption:
total consumption C t dt
4
2 2.2 1.1
tdt
4
2
1
2.2 1.1ln1.1
t
t
From the beginning of 1972 tothe end of 1973:
7.066
million
bushels
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Work:
work force distance
Calculating the work is easywhen the force and distance are
constant.
When the amount of force
varies, we get to use calculus!
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Hookes law for springs: F kx
x = distance that
the spring isextended beyondits natural length
k= spring
constant
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Hookes law for springs: F kx
Example:
It takes 10 Newtons to stretch a
spring 2 meters beyond its naturallength.
F=10 N
x=2 M
10 2k
5 k 5F x
How much work is done stretchingthe spring to 4 meters beyond itsnatural length?
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F(x)
x=4 M
How much work is done stretchingthe spring to 4 meters beyond its
natural length?
For a very small change inx, the
force is constant.
dw F x dx
5dw x dx
5dw x dx
4
05W x dx
4
2
0
5
2W x
40W newton-meters
40W joules
5F x x