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https://ivyleaguecenter.wordpress.com/ Tel: 301-922-9508 Email: [email protected] Page 1 2018 AMC 12A Problem 1 Problem 2 Problem 3 Problem 4

201 8 AMC 12A - WordPress.com · 201 8 AMC 12A Problem 1 Problem 2 ... at a right angle, ... midpoint of AB, and let E be the midpoint of AC. The angle bisector of

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Page 1: 201 8 AMC 12A - WordPress.com · 201 8 AMC 12A Problem 1 Problem 2 ... at a right angle, ... midpoint of AB, and let E be the midpoint of AC. The angle bisector of

https://ivyleaguecenter.wordpress.com/

Tel: 301-922-9508

Email: [email protected] Page 1

2018 AMC 12A

Problem 1

Problem 2

Problem 3

Problem 4

Page 2: 201 8 AMC 12A - WordPress.com · 201 8 AMC 12A Problem 1 Problem 2 ... at a right angle, ... midpoint of AB, and let E be the midpoint of AC. The angle bisector of

https://ivyleaguecenter.wordpress.com/

Tel: 301-922-9508

Email: [email protected] Page 2

Problem 5

Problem 6

Problem 7

Problem 8

Page 3: 201 8 AMC 12A - WordPress.com · 201 8 AMC 12A Problem 1 Problem 2 ... at a right angle, ... midpoint of AB, and let E be the midpoint of AC. The angle bisector of

https://ivyleaguecenter.wordpress.com/

Tel: 301-922-9508

Email: [email protected] Page 3

Problem 9

Problem 10

Problem 11

Page 4: 201 8 AMC 12A - WordPress.com · 201 8 AMC 12A Problem 1 Problem 2 ... at a right angle, ... midpoint of AB, and let E be the midpoint of AC. The angle bisector of

https://ivyleaguecenter.wordpress.com/

Tel: 301-922-9508

Email: [email protected] Page 4

Problem 12

Problem 13

Problem 14

Problem 15

Page 5: 201 8 AMC 12A - WordPress.com · 201 8 AMC 12A Problem 1 Problem 2 ... at a right angle, ... midpoint of AB, and let E be the midpoint of AC. The angle bisector of

https://ivyleaguecenter.wordpress.com/

Tel: 301-922-9508

Email: [email protected] Page 5

Problem 16

Problem 17

Problem 18

Page 6: 201 8 AMC 12A - WordPress.com · 201 8 AMC 12A Problem 1 Problem 2 ... at a right angle, ... midpoint of AB, and let E be the midpoint of AC. The angle bisector of

https://ivyleaguecenter.wordpress.com/

Tel: 301-922-9508

Email: [email protected] Page 6

Problem 19

Problem 20

Problem 21

Problem 22

Page 7: 201 8 AMC 12A - WordPress.com · 201 8 AMC 12A Problem 1 Problem 2 ... at a right angle, ... midpoint of AB, and let E be the midpoint of AC. The angle bisector of

https://ivyleaguecenter.wordpress.com/

Tel: 301-922-9508

Email: [email protected] Page 7

Problem 23

Problem 24

Problem 25