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2. Wave Diffraction and Reciprocal Lattice. Diffraction of Waves by Crystals Scattered Wave Amplitude Brillouin Zones Fourier Analysis of the Basis Quasicrystals. Diffraction Of Waves By Crystals. Bragg’s Law. Reflectance of each plane is about 10 3 to 10 5. Monochromator. - PowerPoint PPT Presentation
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2. Wave Diffraction and Reciprocal Lattice
• Diffraction of Waves by Crystals
• Scattered Wave Amplitude
• Brillouin Zones
• Fourier Analysis of the Basis
• Quasicrystals
Diffraction Of Waves By Crystals
Bragg’s Law
2 sind n
Reflectance of each plane is about 103 to 105 .
Monochromator
X-ray Diffractometer on Powdered Si
1.16A neutron beam on CaF2
Relative intensities are due to basis.
Scattered Wave Amplitude
Fourier Analysis n n r T r integersi i ii
l l T a
→ in n e GG
r
G
rwhere 2 integer TG T
1 i
cellC
n dV n eV
G rG r
i ii
mG b mi integers
bi is called the primitive vectors of the reciprocal lattice, and G a reciprocal lattice vector.
2i j i j b aDefine then
*n real n n G Gr
1 2 3
2 j ki
a
a ab
a
a i,j,k cyclic
1 2 3jj k
k
j ki
a a
a a a
1
1 if , , is permutation of 1, 2,3
0i j k
even
i j k odd
not
,i
VdV e V k
rk0 →
Diffraction Conditions
Difference in phases between waves scattered at r and O
rk k k r
k k k
Scattering amplitude
iF dV n e k k rr idV n e k rr
Scattering vector
in dV e G kG
G
r
,n V G G kG
some reciprocal lattice vector if
0
V n
otherwise
G k G
Diffraction condition: k k k G
k k 22 0G k G 22 G k G(G G)
From Problem 1: 2d hkl n
G
where 1 2 3h k l G b b b
22 2 sinG
k G
4 2sin G n
d
Diffraction condition can be written as
2 sind n Bragg’s law
k k G
Laue EquationsDiffraction condition: j j
j
n G bk
→ j i jij
n a ba k 2 in
k lies in the intersection of 3 cones about the crystal axes.
Ewald construction
• White dots are reciprocal lattice points.• Incident k drawn with end at lattice point.• Scattered k obtained by drawing a circle.
Brillouin Zones
Brillouin Zone Wigner-Seitz cell of reciprocal lattice.
Diffraction condition22 G k G →
2
2 2
G
Gk
→ k is on boundary of BZ.
k k G
Square lattice
Reciprocal Lattice to SC Lattice
Primitive lattice vectors: 1 ˆaa x 2 ˆaa y 3 ˆaa z
Primitive cell volume:
1
2ˆ
a
b x 2
2ˆ
a
b y 3
2ˆ
a
b zPrimitive reciprocal lattice vectors:
3V a
Reciprocal lattice is also SC.
Reciprocal Lattice to BCC Lattice
Primitive lattice vectors: 1 ˆ ˆ ˆ2
a a x y z
Primitive cell volume:
1
2ˆ ˆ
a
b y zPrimitive reciprocal lattice vectors:
31 1 1
1 1 18
1 1 1
aV
Reciprocal lattice is FCC.
2 ˆ ˆ ˆ2
a a x y z 3 ˆ ˆ ˆ
2
a a x y z
31
2a
2
2ˆ ˆ
a
b x z 3
2ˆ ˆ
a
b x y
Reciprocal lattice vector: j jj
nG b 2 3 1 3 1 2
2, ,n n n n n n
a
bcc
1st BZ
rhombic dodecahedron
Cartesian coord
Reciprocal Lattice to FCC Lattice
Primitive lattice vectors: 1 ˆ ˆ2
a a y z
Primitive cell volume:
1
2ˆ ˆ ˆ
a
b x y z
Primitive reciprocal lattice vectors:
30 1 1
1 0 18
1 1 0
aV
Reciprocal lattice is BCC.
2 ˆ ˆ2
a a x z 3 ˆ ˆ
2
a a x y
31
4a
2
2ˆ ˆ ˆ
a
b x y z 3
2ˆ ˆ ˆ
a
b x y z
Reciprocal lattice vector: j jj
nG b 1 2 3 1 2 3 1 2 3
2, ,n n n n n n n n n
a
fcc
1st BZ
Cartesian coord
Fourier Analysis of the Basis
Scattering amplitude F N SG G
Structure factor i
cellS dV n e G r
G r
For a basis with s atoms 1
s
j jj
n n
r r r
ij jcel
jl
S dV n e G rG r r ji i
jcellj
e dV n e G r G ρρj ρ r r
j
j
i
jS e f G r
G G ij jcell
f dV n e G ρG ρ atomic form factor
cellV n G
Structure Factor of BCC Lattice
With respect to the SC lattice, the BCC has a basis of 2 atoms at
1 0,0,0r and 2 1,1,12
ar
→ 1 2 3
1 2 3, , 1i n n n
S S n n n f e G
1 2 3
2, ,n n n
a
G
1 2 3
0
2
oddfor n n n
f even
E.g., metallic Na: no (100), (300), (111), or (221) lines (cancelled by extra plane at half separation)
Structure Factor of FCC Lattice
With respect to the SC lattice, the FCC has a basis of 4 atoms at
1 0,0,0r 2 0,1,12
ar
→ 1 3 1 22 3
1 2 3, , 1i n n i n ni n nS S n n n f e e e G
1 2 3
2, ,n n n
a
G
4
0jf n all odd or all even
forotherwise
3 1,0,12
ar 4 1,1,0
2
ar
f K f Cl
Atomic Form Factor
For a spherical distribution of electron density
i
cellf dV n e G ρρ
12 cos
0 1
2 cos i G rr dr d n r e
2
0
2i G r i G re e
r dr n ri G r
2
0
sin4
Grr dr n r
G r
For n Z r r f Z
For forward scattering, G 0 , so that f Z.
For X-ray diffraction, f Z. ( X-ray not sensitive to change in n(r) caused by bonding)