Upload
tad-harper
View
17
Download
0
Embed Size (px)
DESCRIPTION
Angles and Angle Relationships. Area of Quadrilaterals and Triangles. Circles. Area of Composite Figures. Volume. 1pt. 1 pt. 1 pt. 1pt. 1 pt. 2 pt. 2 pt. 2pt. 2pt. 2 pt. 3 pt. 3 pt. 3 pt. 3 pt. 3 pt. 4 pt. 4 pt. 4pt. 4 pt. 4pt. 5pt. 5 pt. 5 pt. 5 pt. 5 pt. - PowerPoint PPT Presentation
Citation preview
2 pt
3 pt
4 pt
5pt
1 pt
2 pt
3 pt
4 pt
5 pt
1 pt
2pt
3 pt
4pt
5 pt
1pt
2pt
3 pt
4 pt
5 pt
1 pt
2 pt
3 pt
4pt
5 pt
1pt
Area ofQuadrilateralsand Triangles
Circles
Area of Composite
FiguresVolume
Find the measure of the missing angle
x° 65°
x + 65 = 90 - 65 -65
x = 35°
Find the measure of the missing angle
136° y°
y + 136 = 180
-136 -136 y = 44°
Find the measure of the missing angle
120° x°
60° 120°
x + 120 + 60 + 120 = 360x + 300 = 360 - 300 -300x = 60°
Find the measure of the missing angle
125° 63°
62°x°
x + 125 + 63 + 62 = 360x + 250 = 360 - 250 - 250x = 110°
Find the measures of the missing angles
100° 5x°
3x° 60°
3x + 100 + 5x + 60 = 3608x + 160 = 360 - 160 -1608x = 200 8 8 x = 25So 3x = 3(25) = 75°and 5x = 5(25) = 125°
Find the area 12 ft
5 ft
A = lwA = 12 • 5A = 60 ft2
Find the area 20 yd
12 yd 10 yd
A = bhA = 20 • 10A = 200 yd2
Find the area
12 m
15 m
Solve for the missing value
9 ft
x
Area = 45 ft2
A = bh45 = 9h 9 9 h = 5 ft
Solve for the missing value
Area = 100 m2
12 m
b
Find the Circumference
7 ft
C = 2πrC = 2•3.14•7C = 6.28•7C = 43.96 ft
Find the Area
12 m
Cut the 12 in half (diameter - radius)A = πr2
A = 3.14•62
A = 3.14•36A = 113.04 m2
Find the Circumference
11 yd
Cut the 11 in half (diameter – radius)C = 2πrC = 2•3.14•5.5C = 6.28•5.5C = 34.54 yd
Find the Area of the Sector
14
in
Find the area of the shaded region if the radius is 9 ft.
Find the area of the figure below
8 yd 12 yd
4 yd
24 yd
A = lw A = lwA = 8 • 4 A = 12 • 16 A = 32 yd2 A = 192 yd2
Total Area = 32 + 192Total Area = 224 yd2
Find the area of the figure below 10 ft
7 ft
6 ft
15 ft
A = lwA = 7 • 10A = 70 ft2
Total Area = 70 + 75Total Area = 145 ft2
Find the area of the figure below
9 ft
12 ft
20 ft
A = lwA = 12 • 20A = 240 ft2
Total Area = 90 + 240Total Area = 330 ft2
Find the area of the figure below
7 m 8 m
14 m 12
m 4 m
25 m
A = lw A = lw A = lwA = 14•7 A = 8•12 A = 10•4A = 98 m2 A = 96 m2 A = 40 m2
Total Area = 98 + 96 + 40Total Area = 234 m2
Find the area of the figure below 40 yd
10 yd
50 yd
A = lwA = 10 • 40A = 400 yd2
Total Area = 400 + 50 + 39.25Total Area = 489.25 yd2
Find the volume of the figure below
6 in 4 in
12 in
V = lwhV = 12 • 6 • 4V = 72 • 4V = 288 in3
Find the volume of the figure below
24 ft
8 ft
V = πr2hV = 3.14 • 82 • 24V = 3.14 • 64 • 24V = 200.96 • 24V = 4823.04 ft3
Find the volume of the figure below
Find the missing measurement
24 m
h 6 m
Volume = 720 m3
V = lwh720 = 24 • 6 • h720 = 144 h144 144h = 5 m
How much would the liquid in a pipe weigh if water weighed about 62 pounds per cubic foot?
20
ft 40 ft
V = πr2hV = 3.14•102•40(radius is half diameter)V = 3.14•100•40V = 314•40V = 12560 ft3Now for the weightTotal Weight = 12560 • 62Total Weight = 778720 lb