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2 pt 3 pt 4 pt 5pt 1 pt 2 pt 3 pt 4 pt 5 pt 1 pt 2pt 3 pt 4pt 5 pt 1pt 2pt 3 pt 4 pt 5 pt 1 pt 2 pt 3 pt 4pt 5 pt 1pt Area of Quadrilaterals and Triangles Circles Area of Composite Figures Volume

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Angles and Angle Relationships. Area of Quadrilaterals and Triangles. Circles. Area of Composite Figures. Volume. 1pt. 1 pt. 1 pt. 1pt. 1 pt. 2 pt. 2 pt. 2pt. 2pt. 2 pt. 3 pt. 3 pt. 3 pt. 3 pt. 3 pt. 4 pt. 4 pt. 4pt. 4 pt. 4pt. 5pt. 5 pt. 5 pt. 5 pt. 5 pt. - PowerPoint PPT Presentation

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Area ofQuadrilateralsand Triangles

Circles

Area of Composite

FiguresVolume

Page 2: 2 pt

Find the measure of the missing angle

x° 65°

Page 3: 2 pt

x + 65 = 90 - 65 -65

x = 35°

Page 4: 2 pt

Find the measure of the missing angle

136° y°

Page 5: 2 pt

y + 136 = 180

-136 -136 y = 44°

Page 6: 2 pt

Find the measure of the missing angle

120° x°

60° 120°

Page 7: 2 pt

x + 120 + 60 + 120 = 360x + 300 = 360 - 300 -300x = 60°

Page 8: 2 pt

Find the measure of the missing angle

125° 63°

62°x°

Page 9: 2 pt

x + 125 + 63 + 62 = 360x + 250 = 360 - 250 - 250x = 110°

Page 10: 2 pt

Find the measures of the missing angles

100° 5x°

3x° 60°

Page 11: 2 pt

3x + 100 + 5x + 60 = 3608x + 160 = 360 - 160 -1608x = 200 8 8 x = 25So 3x = 3(25) = 75°and 5x = 5(25) = 125°

Page 12: 2 pt

Find the area 12 ft

5 ft

Page 13: 2 pt

A = lwA = 12 • 5A = 60 ft2

Page 14: 2 pt

Find the area 20 yd

12 yd 10 yd

Page 15: 2 pt

A = bhA = 20 • 10A = 200 yd2

Page 16: 2 pt

Find the area

12 m

15 m

Page 17: 2 pt
Page 18: 2 pt

Solve for the missing value

9 ft

x

Area = 45 ft2

Page 19: 2 pt

A = bh45 = 9h 9 9 h = 5 ft

Page 20: 2 pt

Solve for the missing value

Area = 100 m2

12 m

b

Page 21: 2 pt
Page 22: 2 pt

Find the Circumference

7 ft

Page 23: 2 pt

C = 2πrC = 2•3.14•7C = 6.28•7C = 43.96 ft

Page 24: 2 pt

Find the Area

12 m

Page 25: 2 pt

Cut the 12 in half (diameter - radius)A = πr2

A = 3.14•62

A = 3.14•36A = 113.04 m2

Page 26: 2 pt

Find the Circumference

11 yd

Page 27: 2 pt

Cut the 11 in half (diameter – radius)C = 2πrC = 2•3.14•5.5C = 6.28•5.5C = 34.54 yd

Page 28: 2 pt

Find the Area of the Sector

14

in

Page 29: 2 pt
Page 30: 2 pt

Find the area of the shaded region if the radius is 9 ft.

Page 31: 2 pt
Page 32: 2 pt

Find the area of the figure below

8 yd 12 yd

4 yd

24 yd

Page 33: 2 pt

A = lw A = lwA = 8 • 4 A = 12 • 16 A = 32 yd2 A = 192 yd2

Total Area = 32 + 192Total Area = 224 yd2

Page 34: 2 pt

Find the area of the figure below 10 ft

7 ft

6 ft

15 ft

Page 35: 2 pt

A = lwA = 7 • 10A = 70 ft2

Total Area = 70 + 75Total Area = 145 ft2

Page 36: 2 pt

Find the area of the figure below

9 ft

12 ft

20 ft

Page 37: 2 pt

A = lwA = 12 • 20A = 240 ft2

Total Area = 90 + 240Total Area = 330 ft2

Page 38: 2 pt

Find the area of the figure below

7 m 8 m

14 m 12

m 4 m

25 m

Page 39: 2 pt

A = lw A = lw A = lwA = 14•7 A = 8•12 A = 10•4A = 98 m2 A = 96 m2 A = 40 m2

Total Area = 98 + 96 + 40Total Area = 234 m2

Page 40: 2 pt

Find the area of the figure below 40 yd

10 yd

50 yd

Page 41: 2 pt

A = lwA = 10 • 40A = 400 yd2

Total Area = 400 + 50 + 39.25Total Area = 489.25 yd2

Page 42: 2 pt

Find the volume of the figure below

6 in 4 in

12 in

Page 43: 2 pt

V = lwhV = 12 • 6 • 4V = 72 • 4V = 288 in3

Page 44: 2 pt

Find the volume of the figure below

24 ft

8 ft

Page 45: 2 pt

V = πr2hV = 3.14 • 82 • 24V = 3.14 • 64 • 24V = 200.96 • 24V = 4823.04 ft3

Page 46: 2 pt

Find the volume of the figure below

Page 47: 2 pt
Page 48: 2 pt

Find the missing measurement

24 m

h 6 m

Volume = 720 m3

Page 49: 2 pt

V = lwh720 = 24 • 6 • h720 = 144 h144 144h = 5 m

Page 50: 2 pt

How much would the liquid in a pipe weigh if water weighed about 62 pounds per cubic foot?

20

ft 40 ft

Page 51: 2 pt

V = πr2hV = 3.14•102•40(radius is half diameter)V = 3.14•100•40V = 314•40V = 12560 ft3Now for the weightTotal Weight = 12560 • 62Total Weight = 778720 lb