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12 42 21 g = PO D g = 73.5 42 × 21 = 882 12 × g = 12g 12g = 882 ÷12 ÷12

12 42 21 g = PO D g = 73.5 42 × 21 = 882 12 × g = 12g 12g = 882 ÷12

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Page 1: 12 42 21 g = PO D g = 73.5 42 × 21 = 882 12 × g = 12g 12g = 882 ÷12

1242

21g=

POD

g = 73.5

42 × 21 = 882

12 × g = 12g

12g = 882÷12 ÷12

Page 2: 12 42 21 g = PO D g = 73.5 42 × 21 = 882 12 × g = 12g 12g = 882 ÷12

1-7 Constant Rate of ChangeA rate of change is a

rate that describes how one quantity changes in relation to another.

Page 3: 12 42 21 g = PO D g = 73.5 42 × 21 = 882 12 × g = 12g 12g = 882 ÷12

In a linear relationship, the rate of change between any two quantities is the same. A linear relationship has a constant rate of change.

Page 4: 12 42 21 g = PO D g = 73.5 42 × 21 = 882 12 × g = 12g 12g = 882 ÷12

Ex: A computer programmer charges customers per line of code written. Use the data table to calculate the constant rate of change.Lines of code

50 100 150 200

Cost ($) 1,000 2,000 3,000 4,000

+50 +50 +50

+1,000 +1,000 +1,000

Change in dollarsChange in lines

= $1,00050 lines

= $201 line

The constant rate of change per line of programming code is $20

Page 5: 12 42 21 g = PO D g = 73.5 42 × 21 = 882 12 × g = 12g 12g = 882 ÷12

The graph represents the distance traveled while driving on a highway. Find the constant rate of change.

Ex:

What does point (0, 0) represent?

It means that in 0 hours the car drove 0 miles.What does point (2, 120) represent?

It means that in 2 hours the car drove 120 miles.

Page 6: 12 42 21 g = PO D g = 73.5 42 × 21 = 882 12 × g = 12g 12g = 882 ÷12

The graph represents the distance traveled while driving on a highway. Find the constant rate of change.

Ex:

To find the rate of change, pick any two points on the line, such as (0,0) and (1,60).

Change in milesChange in hours

(60 – 0) miles(1 – 0) hours

=

=60 miles1 hour

Page 7: 12 42 21 g = PO D g = 73.5 42 × 21 = 882 12 × g = 12g 12g = 882 ÷12

The graph represents the distance traveled while driving on a highway. Find the constant rate of change.

Ex:

To find the rate of change, pick any two points on the line, such as (3,180) and (1,60).

Change in milesChange in hours

(180 – 60) miles(3 – 1) hours

=

=120 miles2 hours

60 miles1 hour=

Page 8: 12 42 21 g = PO D g = 73.5 42 × 21 = 882 12 × g = 12g 12g = 882 ÷12

The graph represents the distance traveled while driving on a highway. Find the constant rate of change.

Ex:

1. Pick 2 points2. Find the difference between

the y values and the difference between the x values.

3. Write as a rate. simplify