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University of Santo Tomas PHYS 104 Faculty of Engineering Physics 2 Lecture Institute of Information and Computing Sciences Rating: NAME: ____________________________ SECTION: ____________ DATE: _____________ PROBLEM SET THERMAL EXPANSION PRACTICE SET 1. TEMPERATURE SCALE. The temperature difference between the inside and the outside of a home on a cold winter day is 37F O . Express this difference on a) Celsius scale and b) Kelvin scale 2. THERMAL EXPANSION CONSIDERING 1 MATERIAL. A spherical steel ball bearing has a diameter of 2.440 cm at 20 O C. a) What is its diameter when its temperature is raised to 100.0 O C. b) What is the temperature required to increase its volume by 5.000%? [α (steel) = 1.2×10 5 C 0-1 ] 3. THERMAL EXPANSION CONSIDERING 2 MATERIALS. An iron ball has a diameter of 7.0 cm and is 0.01 mm too large to pass through a hole in a brass ring when both are at a temperature of 30.0 O C. To what temperature should the brass ring be heated so that the ball just passes through the hole? What if both are heated? [α (iron) = 3.6×10 5 C 0-1 , α (brass) = 5.7×10 5 C 0-1 ] EXERCISES/ASSIGNMENT 1. Show that the temperature 40.0 O C is unique and it has the same numerical value on the Celsius and Fahrenheit Scales. 2. A metal plate is 15.0 cm 2 . What is the temperature needed to decrease this area by 2%? 3. A medical device used for handling tissue samples has two metal screws, one 30.0 cm long and made from brass and the other 40.0 cm, made from aluminum. A gap of 1.00 mm exists between the ends of the screws at 22.0 O C. At what temperature will the two screws touch? [α (aluminum) = 3.6×10 5 C 0-1 , α (brass) = 5.7×10 5 C 0-1 ] SHOW YOUR SOLUTION ON THE UPPER PART OF THE BACK FACE OF THIS SHEET. 4. A circular steel ring at 40 O C has a hole with an area of 5.680 cm 2 . A copper rod having a cross sectional area of 5.690 cm 2 was slipped on this hole before it was heated. What was the temperature that enabled the two to be slipped together? [α (copper) = 1.7×10 5 C 0-1 , α (steel) = 1.2×10 5 C 0-1 ] SHOW YOUR SOLUTION ON THE LOWER PART OF THE BACK FACE OF THIS SHEET. References: Serway, R.A. and Chris Vuille. (2013). College Physics. 9th Edition. Canada: Cengage Learning Asia. pp. 403-404 Bauer, Wolfgang and Garr D. Westfall. (2014). University Physics with Modern Physics. 2nd Ed. New York: MacGraw Hill

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Page 1: 1 Thermal Expansion

University of Santo Tomas PHYS 104 Faculty of Engineering Physics 2 Lecture Institute of Information and Computing Sciences Rating:

NAME: ____________________________ SECTION: ____________ DATE: _____________

PROBLEM SET – THERMAL EXPANSION

PRACTICE SET

1. TEMPERATURE SCALE.

The temperature difference between the inside and the outside of a home on a cold winter day is 37FO. Express this

difference on a) Celsius scale and b) Kelvin scale

2. THERMAL EXPANSION CONSIDERING 1 MATERIAL.

A spherical steel ball bearing has a diameter of 2.440 cm at 20OC. a) What is its diameter when its temperature is

raised to 100.0OC. b) What is the temperature required to increase its volume by 5.000%? [α (steel) = 1.2×10−5 C0-1]

3. THERMAL EXPANSION CONSIDERING 2 MATERIALS.

An iron ball has a diameter of 7.0 cm and is 0.01 mm too large to pass through a hole in a brass ring when both are

at a temperature of 30.0 OC. To what temperature should the brass ring be heated so that the ball just passes

through the hole? What if both are heated? [α (iron) = 3.6×10−5 C0-1, α (brass) = 5.7×10−5 C0-1]

EXERCISES/ASSIGNMENT

1. Show that the temperature – 40.0OC is unique and it

has the same numerical value on the Celsius and

Fahrenheit Scales.

2. A metal plate is 15.0 cm2. What is the temperature

needed to decrease this area by 2%?

3. A medical device used for handling tissue samples

has two metal screws, one 30.0 cm long and made from

brass and the other 40.0 cm, made from aluminum. A

gap of 1.00 mm exists between the ends of the screws

at 22.0OC. At what temperature will the two screws

touch?

[α (aluminum) = 3.6×10−5 C0-1, α (brass) = 5.7×10−5 C0-1]

SHOW YOUR SOLUTION ON THE UPPER PART OF THE

BACK FACE OF THIS SHEET.

4. A circular steel ring at 40OC has a hole with an area of

5.680 cm2. A copper rod having a cross sectional area of

5.690 cm2 was slipped on this hole before it was heated.

What was the temperature that enabled the two to be

slipped together?

[α (copper) = 1.7×10−5C0-1, α (steel) = 1.2×10−5C0-1]

SHOW YOUR SOLUTION ON THE LOWER PART OF THE

BACK FACE OF THIS SHEET.

References:

Serway, R.A. and Chris Vuille. (2013). College Physics. 9th Edition. Canada: Cengage Learning Asia. pp. 403-404

Bauer, Wolfgang and Garr D. Westfall. (2014). University Physics with Modern Physics. 2nd Ed. New York: MacGraw Hill