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Lecture 12

Pointers and Strings

Section 5.4, 5.7-5.10, 5.12.1

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5.4Calling Functions by Reference 3 ways to pass arguments to function

Pass-by-value Pass-by-reference with reference arguments Pass-by-reference with pointer arguments

return can return one value from function Arguments passed to function using

reference arguments Modify original values of arguments More than one value “returned”

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5.4Calling Functions by Reference Pass-by-reference with pointer arguments

Simulate pass-by-reference Use pointers and indirection operator

Pass address of argument using & operator Arrays not passed with & because array name

already pointer * operator used as alias/nickname for variable

inside of function

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fig05_06.cpp(1 of 2)

1 // Fig. 5.6: fig05_06.cpp

2 // Cube a variable using pass-by-value.

3 #include <iostream>

4 5 using std::cout;

6 using std::endl;

7 8 int cubeByValue( int ); // prototype

9 10 int main()

11 {12 int number = 5;

13 14 cout << "The original value of number is " << number;

15 16 // pass number by value to cubeByValue

17 number = cubeByValue( number );

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Pass number by value; result returned by cubeByValue

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fig05_06.cpp(2 of 2)

fig05_06.cppoutput (1 of 1)

19 cout << "\nThe new value of number is " << number << endl;

20 21 return 0; // indicates successful termination

22 23 } // end main

24 25 // calculate and return cube of integer argument

26 int cubeByValue( int n )

27 { 28 return n * n * n; // cube local variable n and return result

29 30 } // end function cubeByValue

The original value of number is 5

The new value of number is 125

cubeByValue receives parameter passed-by-value

Cubes and returns local variable n

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fig05_07.cpp(1 of 2)

1 // Fig. 5.7: fig05_07.cpp

2 // Cube a variable using pass-by-reference

3 // with a pointer argument.

4 #include <iostream>

5 6 using std::cout;

7 using std::endl;

8 9 void cubeByReference( int * ); // prototype

10 11 int main()

12 {13 int number = 5;

14 15 cout << "The original value of number is " << number;

16 17 // pass address of number to cubeByReference

18 cubeByReference( &number );

Apply address operator & to pass address of number to cubeByReference

Prototype indicates parameter is pointer to int

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fig05_07.cpp(2 of 2)

fig05_07.cppoutput (1 of 1)

19 20 cout << "\nThe new value of number is " << number << endl;

21 22 return 0; // indicates successful termination

23 24 } // end main

25 26 // calculate cube of *nPtr; modifies variable number in main

27 void cubeByReference( int *nPtr )

28 { 29 *nPtr = *nPtr * *nPtr * *nPtr; // cube *nPtr

30 31 } // end function cubeByReference

The original value of number is 5

The new value of number is 125

cubeByReference receives address of int variable,i.e., pointer to an int

Modify and access int variable using indirection operator *

cubeByReference modified variable number

int value = *nPtr;*nPtr = value * value * value;

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5.7Pointer Expressions and Pointer Arithmetic

Pointer arithmetic Increment/decrement pointer (++ or --) Add/subtract an integer to/from a pointer( + or += , - or -=) Pointers may be subtracted from each other Pointer arithmetic meaningless unless performed on pointer to

array 5 element int array on a machine using 4 byte ints

vPtr points to first element v[ 0 ], which is at location 3000vPtr = 3000

vPtr += 2; sets vPtr to 3008vPtr points to v[ 2 ]

pointer variable vPtr

v[0] v[1] v[2] v[4]v[3]

3000 3004 3008 3012 3016location

 

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5.7Pointer Expressions and Pointer Arithmetic Subtracting pointers

Returns number of elements between two addressesvPtr2 = v[ 2 ];vPtr = v[ 0 ];vPtr2 - vPtr == 2

Pointer assignment Pointer can be assigned to another pointer if both of same type If not same type, cast operator must be used Exception: pointer to void (type void *)

Generic pointer, represents any type No casting needed to convert pointer to void pointer void pointers cannot be dereferenced

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5.7Pointer Expressions and Pointer Arithmetic Pointer comparison

Use equality and relational operators Comparisons meaningless unless pointers point

to members of same array Compare addresses stored in pointers Example: could show that one pointer points to

higher numbered element of array than other pointer

Common use to determine whether pointer is 0 (does not point to anything) (ptr != NULL)

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5.8Relationship Between Pointers and Arrays Arrays and pointers closely related

Array name like constant pointer Pointers can do array subscripting operations

Accessing array elements with pointers Element b[ n ] can be accessed by *( bPtr + n )

Called pointer/offset notation Addresses

&b[ 3 ] same as bPtr + 3 Array name can be treated as pointer

b[ 3 ] same as *( b + 3 ) Pointers can be subscripted (pointer/subscript notation)

bPtr[ 3 ] same as b[ 3 ]

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fig05_20.cpp(1 of 3)

1 // Fig. 5.20: fig05_20.cpp

2 // Using subscripting and pointer notations with arrays.

3 4 #include <iostream>

5 6 using std::cout;

7 using std::endl;

8 9 int main()

10 {11 int b[] = { 10, 20, 30, 40 };

12 int *bPtr = b; // set bPtr to point to array b

13 14 // output array b using array subscript notation

15 cout << "Array b printed with:\n"

16 << "Array subscript notation\n";

17 18 for ( int i = 0; i < 4; i++ )

19 cout << "b[" << i << "] = " << b[ i ] << '\n';

Using array subscript notation.

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fig05_20.cpp(2 of 3)

21 // output array b using the array name and

22 // pointer/offset notation

23 cout << "\nPointer/offset notation where "

24 << "the pointer is the array name\n";

25 26 for ( int offset1 = 0; offset1 < 4; offset1++ )

27 cout << "*(b + " << offset1 << ") = "

28 << *( b + offset1 ) << '\n';

29 30 // output array b using bPtr and array subscript notation

31 cout << "\nPointer subscript notation\n";

32 33 for ( int j = 0; j < 4; j++ )

34 cout << "bPtr[" << j << "] = " << bPtr[ j ] << '\n';

35 36 cout << "\nPointer/offset notation\n";

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Using array name and pointer/offset notation.

Using pointer subscript notation.

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fig05_20.cpp(3 of 3)

38 // output array b using bPtr and pointer/offset notation

39 for ( int offset2 = 0; offset2 < 4; offset2++ )

40 cout << "*(bPtr + " << offset2 << ") = "

41 << *( bPtr + offset2 ) << '\n';

42 43 return 0; // indicates successful termination

44 45 } // end main

Using bPtr and pointer/offset notation.

Array b printed with:

 

Array subscript notation

b[0] = 10

b[1] = 20

b[2] = 30

b[3] = 40

 

fig05_20.cppoutput (1 of 2)

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 Pointer/offset notation where the pointer is the array name

*(b + 0) = 10

*(b + 1) = 20

*(b + 2) = 30

*(b + 3) = 40

Pointer subscript notation

bPtr[0] = 10

bPtr[1] = 20

bPtr[2] = 30

bPtr[3] = 40

 

Pointer/offset notation

*(bPtr + 0) = 10

*(bPtr + 1) = 20

*(bPtr + 2) = 30

*(bPtr + 3) = 40

fig05_20.cppoutput (2 of 2)

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fig05_21.cpp(1 of 3)

1 // Fig. 5.21: fig05_21.cpp

2 // Copying a string using array notation

3 // and pointer notation.

4 #include <iostream>

5 6 using std::cout;

7 using std::endl;

8 9 void copy1( char *, const char * ); // prototype

10 void copy2( char *, const char * ); // prototype

11 12 int main()

13 {14 char string1[ 10 ];

15 char *string2 = "Hello";

16 char string3[ 10 ];

17 char string4[] = "Good Bye";

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fig05_21.cpp(2 of 3)

19 copy1( string1, string2 );

20 cout << "string1 = " << string1 << endl;

21 22 copy2( string3, string4 );

23 cout << "string3 = " << string3 << endl;

24 25 return 0; // indicates successful termination

26 27 } // end main

28 29 // copy s2 to s1 using array notation

30 void copy1( char *s1, const char *s2 )

31 {32 for ( int i = 0; ( s1[ i ] = s2[ i ] ) != '\0'; i++ )

33 ; // do nothing in body

34 35 } // end function copy1

Use array subscript notation to copy string in s2 to character array s1.

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fig05_21.cpp(3 of 3)

fig05_21.cppoutput (1 of 1)

37 // copy s2 to s1 using pointer notation

38 void copy2( char *s1, const char *s2 )

39 {40 for ( ; ( *s1 = *s2 ) != '\0'; s1++, s2++ )

41 ; // do nothing in body

42 43 } // end function copy2

string1 = Hello

string3 = Good Bye

Use pointer notation to copy string in s2 to character array in s1.

Increment both pointers to point to next elements in corresponding arrays.

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5.9Arrays of Pointers

Arrays can contain pointers Commonly used to store array of strings

char *suit[ 4 ] = {"Hearts", "Diamonds", "Clubs", "Spades" };

Each element of suit points to char * (a string) Array does not store strings, only pointers to strings

suit array has fixed size, but strings can be of any size

suit[3]

suit[2]

suit[1]

suit[0] ’H’ ’e’ ’a’ ’r’ ’t’ ’s’ ’\0’

’D’ ’i’ ’a’ ’m’ ’o’ ’n’ ’d’ ’s’ ’\0’

’C’ ’l’ ’u’ ’b’ ’s’ ’\0’

’S’ ’p’ ’a’ ’d’ ’e’ ’s’ ’\0’

 

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5.10 Case Study: Card Shuffling and Dealing Simulation Card shuffling program

Use an array of pointers to strings, to store suit names Use a double scripted array (suit by value)

Place 1-52 into the array to specify the order in which the cards are dealt

deck[2][12] represents the King of Clubs

HeartsDiamondsClubsSpades

0

1

2

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Ace Two ThreeFour Five Six SevenEightNine Ten Jack QueenKing0 1 2 3 4 5 6 7 8 9 10 11 12

Clubs King

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5.10 Case Study: Card Shuffling and Dealing Simulation Pseudocode for shuffling and dealing

simulation

For each of the 52 cards

Place card number in randomly selected unoccupied slot of deck

For each of the 52 cards

Find card number in deck array and print face and suit of card

Choose slot of deck randomly

While chosen slot of deck has been previously chosen

Choose slot of deck randomlyPlace card number in chosen slot of deck

For each slot of the deck array

If slot contains card number Print the face and suit of the card

Second refinement

Third refinement

First refinement

Initialize the suit arrayInitialize the face arrayInitialize the deck array

Shuffle the deck

Deal 52 cards

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fig05_24.cpp(1 of 4)

1 // Fig. 5.24: fig05_24.cpp

2 // Card shuffling dealing program.

3 #include <iostream>

4 5 using std::cout;

6 using std::left;

7 using std::right;

8 9 #include <iomanip>

10 11 using std::setw;

12 13 #include <cstdlib> // prototypes for rand and srand

14 #include <ctime> // prototype for time

15 16 // prototypes

17 void shuffle( int [][ 13 ] );

18 void deal( const int [][ 13 ], const char *[], const char *[] );

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fig05_24.cpp(2 of 4)

20 int main() {21 // initialize suit array

22 const char *suit[ 4 ] =

23 { "Hearts", "Diamonds", "Clubs", "Spades" };

24 25 // initialize face array

26 const char *face[ 13 ] = { "Ace", "Deuce", "Three", "Four", "Five",

27 "Six", "Seven", "Eight", "Nine", "Ten", "Jack", "Queen", "King" };

28 29 // initialize deck array

30 int deck[ 4 ][ 13 ] = { 0 };

31 32 srand( time( 0 ) ); // seed random number generator

33 34 shuffle( deck );

35 deal( deck, face, suit ); 36 return 0; // indicates successful termination

37 } // end main

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face array contains pointers to char arrays.

suit array contains pointers to char arrays.

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fig05_24.cpp(3 of 4)

39 // shuffle cards in deck

40 void shuffle( int wDeck[][ 13 ] ) {41 int row;

42 int column;

43 44 // for each of the 52 cards, choose slot of deck randomly

45 for ( int card = 1; card <= 52; card++ ) { 46 // choose new random location until unoccupied slot found

47 do {

48 row = rand() % 4;

49 column = rand() % 13;

50 } while ( wDeck[ row ][ column ] != 0 ); // end do/while

51 // place card number in chosen slot of deck

52 wDeck[ row ][ column ] = card;

53 54 } // end for

55 56 } // end function shuffle

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Current position is at randomly selected row and column.

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fig05_24.cpp(4 of 4)

58 // deal cards in deck

59 void deal( const int wDeck[][ 13 ], const char *wFace[],

60 const char *wSuit[] ) {61 // for each of the 52 cards

62 for ( int card = 1; card <= 52; card++ ) 63 // loop through rows of wDeck

64 for ( int row = 0; row <= 3; row++ )

65 66 // loop through columns of wDeck for current row

67 for ( int column = 0; column <= 12; column++ )

68 69 // if slot contains current card, display card

70 if ( wDeck[ row ][ column ] == card ) {

71 cout << setw( 5 ) << right << wFace[ column ]

72 << " of " << setw( 8 ) << left

73 << wSuit[ row ]

74 << ( card % 2 == 0 ? '\n' : '\t' );

75 } // end if

76 } // end function deal

Cause face to be output right justified in field of 5 characters.

Cause suit to be output left justified in field of 8 characters.

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Nine of Spades Seven of Clubs

Five of Spades Eight of Clubs

Queen of Diamonds Three of Hearts

Jack of Spades Five of Diamonds

Jack of Diamonds Three of Diamonds

Three of Clubs Six of Clubs

Ten of Clubs Nine of Diamonds

Ace of Hearts Queen of Hearts

Seven of Spades Deuce of Spades

Six of Hearts Deuce of Clubs

Ace of Clubs Deuce of Diamonds

Nine of Hearts Seven of Diamonds

Six of Spades Eight of Diamonds

Ten of Spades King of Hearts

Four of Clubs Ace of Spades

Ten of Hearts Four of Spades

Eight of Hearts Eight of Spades

Jack of Hearts Ten of Diamonds

Four of Diamonds King of Diamonds

Seven of Hearts King of Spades

Queen of Spades Four of Hearts

Nine of Clubs Six of Diamonds

Deuce of Hearts Jack of Clubs

King of Clubs Three of Spades

Queen of Clubs Five of Clubs

Five of Hearts Ace of Diamonds

fig05_24.cppoutput (1 of 1)

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5.12.1 Fundamentals of Characters and Strings Character constant

Integer value represented as character in single quotes 'z' is integer value of z

122 in ASCII String

Series of characters treated as single unit Can include letters, digits, special characters +, -, * ... String literal (string constants)

Enclosed in double quotes, for example:"I like C++"

Array of characters, ends with null character '\0' String is constant pointer

Pointer to string’s first character Like arrays

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5.12.1 Fundamentals of Characters and Strings

String assignment Character array

char color[] = "blue"; Creates 5 element char array color

last element is '\0' Variable of type char *

char *colorPtr = "blue"; Creates pointer colorPtr to letter b in string “blue”

“blue” somewhere in memory

Alternative for character array char color[] = { ‘b’, ‘l’, ‘u’, ‘e’, ‘\0’ };

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5.12.1 Fundamentals of Characters and Strings Reading strings

Assign input to character array word[ 20 ]cin >> word

Reads characters until whitespace or EOF String could exceed array size

cin >> setw( 20 ) >> word; Reads 19 characters (space reserved for '\0')

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5.12.1 Fundamentals of Characters and Strings cin.getline

Read line of text cin.getline( array, size, delimiter ); Copies input into specified array until either

One less than size is reached delimiter character is input

Examplechar sentence[ 80 ];cin.getline( sentence, 80, '\n' );orstring sent;getline(cin, sent, ‘\n’);