Upload
trevor-arnold
View
215
Download
0
Embed Size (px)
Citation preview
1
Examples of Independent Events
Some examples of independent events are:
Landing on heads after tossing a coin AND rolling a 5 on a single 6-sided die. Choosing a marble from a jar AND landing on heads after tossing a coin. Choosing a 3 from a deck of cards, replacing it, AND then choosing an ace as the second card.
Rolling a 4 on a single 6-sided die, AND then rolling a 1 on a second roll of the die.
Definition: Two events, A and B, independent if the fact that A occurs does not affect the probability of B occurring.
2
Study Not Study Total
Pass .50 .20 .70
Fail .10 .20 .30
Total .60 .40 1.0
( )What is thevalueof Pass Study
( Study)Solve for Pass
( )What is thevalueof Pass Study
Joint Probability Table
3
Study Not Study Total
Pass .50 .20 .70
Fail .10 .20 .30
Total .60 .40 1.0
( ) (.70) (.60) (.50) 0.80Pass Study P P P ( ) ( ) ( ) ( )Pass Study P Pass P Study P Pass Study
( ) (.50)( Study) 0.834
( ) (.60)
P Pass Study PP Pass
P Study P
( ) ( ) ( ) (.60)(.70) (.42)Does Pass Study P Study P Pass Are these events independent?
( ) ( ) ( Study) (.60)(.834) (.50)Pass Study P Study P Pass
4
Health Insurance
Age Yes No
18 to 34 750 170
35 and over 950 130
Let A = 18 to 34 age groupB = 35 and over age
groupY = Insurance coverageN = No insurance
coverage
What is the value of P(A) P(B) P(Y) P(N)?
Construct a Joint Probability Table
(N A), (N B), ( N)Solve for P P P A
5
Health Insurance
Age Yes No
18 to 34 750 170
35 and over 950 130
Total sample size = 2000Dividing each entry by 2000 provides
the following joint probability table.
Health InsuranceAge Yes No Total18 to 34 .375 .085 .4635 and over .475 .065 .54
.850 .150 1.00
Let A = 18 to 34 age groupB = 35 and over age
groupY = Insurance coverageN = No insurance
coverage
(N A) .085(N A) .1848
(A) .46
PP
P
(N B) .065(N B) .1204
(B) .54
PP
P
(A N) .085(A N) .5677
(N) .150
PP
P
P(A) = .46 P(B) = .54 P(Y) = .85 P(N) = .15