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Example 4 Sketch the graph of the function k(x) = (x2-4)4/5.
Solution Observe that k is an even function, and its graph is symmetric with respect to the y-axis.
I. Intercepts
The x-intercepts occur when 0 = x2-4 , i.e. when x=-2 and when x=2.
The y-intercept occurs at
II. Asymptotes The graph of k has no asymptotes.
III. First Derivative
By the chain rule,
555154 82256256400k( )() //
.)()()(
)()() ////
5151512512
2x2x5x8
4x5x8
x24x54
(xk
Since k/(x)>0 for –2<x<0 and x>2, the function k is increasing there. Since k/(x)<0 for x<-2 and 0<x<2, the function k is decreasing there. We depict this information on a real number line.
2
decr -2 i n cr 0 decr 2 i n cr
si gn k ’(x )x
- - - - D N E + + + + 0 - - - - - - - D N E + + + + +
loca lm i n
l oca lm i n
l oca lm ax
Note that k has three critical points: x=0 where the derivative is zero and x=-2, x=2 where the derivative does not exist. By the First Derivative Test x=-2 is a local minimum, x=0 is a local maximum and x=2 is a local minimum.
IV. Vertical Tangents and Cusps
Observe that at x=-2 the left derivative of k is - and the right derivative is +, and k has a vertical cusp there. Similarly, at x=2 the left derivative of k is -and the right derivative is +, and k also has a vertical cusp there.
V. Concavity and Inflection Points
By the quotient rule:
5/65/65/65/6
2
5/65/6
2
5/62
22
5/42
5/42
5/22
5/425/12
)2()2(25
)203)(203(8
)2()2(25
)203(8
)2()2(25
16024
)4(25
16)4(40
)4(5
)4(5
)4(5
)2()4(51
8)4)(8()(
xx
xx
xx
x
xx
x
x
xx
x
x
x
xxxxxk
5151 2x2x5x8
(xk // )()()
3
VI. Sketch the graph
We summarize our conclusions and sketch the graph of k.
Since the concavity of k changes from up to down at there is an inflection point there. Since the concavity of k changes from down to up at there is an inflection point there.
The denominator of k//(x) is always positive, so k//(x) has the same sign as
its numerator. Hence k//(x) is positive for
and is concave up there. k//(x) is negative for and is concave down there. We sketch this information on a number line.
5/65/6 )2()2(25
)203)(203(8)(
xx
xxxk
320 and 320 xx
320320 x
,320x
,320x
320 3
20
4
k is an even function x-intercepts: x=-2 and x=2 y-intercept:
increasing: –2<x<0 or x>2 decreasing: x<-2 or 0<x<2
local min: x=-2 and x=2 local max: x=0 vertical cusps: x=-2 and x=2
concave up: concave down:
inflection points:
5 82y
k(x) =(x2-4)4/5
320320 x320 and 320 xx
320 and 320 xx
3
20
3
20
5 82