10
Lewis Dot Structure How to create a… #1 Count the total number of valence electrons in the molecule C: 4 electrons x 1 atom = 4 valence electrons H: 1 electron x 4 atoms = 4 valence electrons Total = 8 valence electrons …for CH 4

#1 Count the total number of valence electrons in the molecule C: 4 electrons x 1 atom = 4 valence electrons H: 1 electron x 4 atoms = 4 valence electrons

Embed Size (px)

Citation preview

Page 1: #1 Count the total number of valence electrons in the molecule C: 4 electrons x 1 atom = 4 valence electrons H: 1 electron x 4 atoms = 4 valence electrons

Lewis Dot StructureHow to create a…

#1 Count the total number of valence electrons in the molecule

C: 4 electrons x 1 atom = 4 valence electronsH: 1 electron x 4 atoms = 4 valence electrons

Total = 8 valence electrons

…for CH4

Page 2: #1 Count the total number of valence electrons in the molecule C: 4 electrons x 1 atom = 4 valence electrons H: 1 electron x 4 atoms = 4 valence electrons

Lewis Dot StructureHow to create a…

#2 Find the number of “octet” electrons for the molecule.

C: 8 octet electrons x 1 atom = 8 octet electronsH: 2 octet electrons x 4 atoms = 8 octet electrons

Total = 16 octet electrons

Rules: Hydrogen always has 2 octet electronsBeryllium always has 4 octet electronsBoron wants 6 for neutral molecules (8 if it’s an anion)

…for CH4

Page 3: #1 Count the total number of valence electrons in the molecule C: 4 electrons x 1 atom = 4 valence electrons H: 1 electron x 4 atoms = 4 valence electrons

Lewis Dot StructureHow to create a…

#3 Subtract the number of valence electrons from the

number of octet electrons to find the number of bonding

electrons.

16 – 8 = 8 bonding electrons

…for CH4

Page 4: #1 Count the total number of valence electrons in the molecule C: 4 electrons x 1 atom = 4 valence electrons H: 1 electron x 4 atoms = 4 valence electrons

Lewis Dot StructureHow to create a…

#4 Divide the number of bonding electrons by 2 to find the number of bonds in the

molecule.

8 / 2 = 4 bonds in CH4

Why 2? Because there are two electrons in every covalent bond!

…for CH4

Page 5: #1 Count the total number of valence electrons in the molecule C: 4 electrons x 1 atom = 4 valence electrons H: 1 electron x 4 atoms = 4 valence electrons

Lewis Dot StructureHow to create a…

#5 Draw an arrangement of atoms that has the number of bonds you found in step 4. Of course, there are more rules…

Hydrogen and Halogens = bond once!Oxygen’s family and Beryllium bond twice in neutral

moleculesNitrogen’s family and Boron bond 3 times in neutral

moleculesCarbon’s family = bonds 4 times!

…for CH4

Page 6: #1 Count the total number of valence electrons in the molecule C: 4 electrons x 1 atom = 4 valence electrons H: 1 electron x 4 atoms = 4 valence electrons

Lewis Dot StructureHow to create a…

More hints…

If you bond everything together and you have bonds left over, look for

double/triple bonds.

The atom nearest to the left side of the periodic table is probably in the

middle of the molecule.

…for CH4

Page 7: #1 Count the total number of valence electrons in the molecule C: 4 electrons x 1 atom = 4 valence electrons H: 1 electron x 4 atoms = 4 valence electrons

Draw the Lewis structures for the following compounds:

H2O

 CCl4

 NH3

  CO2

 PCL3

Page 8: #1 Count the total number of valence electrons in the molecule C: 4 electrons x 1 atom = 4 valence electrons H: 1 electron x 4 atoms = 4 valence electrons

Draw the Lewis structures for the following compounds:

N2

CH4

C2H6

CH3OH

BH3

Page 9: #1 Count the total number of valence electrons in the molecule C: 4 electrons x 1 atom = 4 valence electrons H: 1 electron x 4 atoms = 4 valence electrons

Draw the Lewis structures for the following compounds:

PBr3

 N2H2

   C2H2

SiH4

 C2H4

Page 10: #1 Count the total number of valence electrons in the molecule C: 4 electrons x 1 atom = 4 valence electrons H: 1 electron x 4 atoms = 4 valence electrons

Draw the Lewis structures for the following compounds:

 HF 

  HCl

CCl2F2