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1 Chapter 10 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display. Chemical Bonding II: Molecular Geometry and Hybridization of Atomic Orbitals

1 Chapter 10 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display. Chemical Bonding II: Molecular Geometry and Hybridization

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Page 1: 1 Chapter 10 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display. Chemical Bonding II: Molecular Geometry and Hybridization

1

Chapter 10

Copyright © The McGraw-Hill Companies, Inc.  Permission required for reproduction or display.

Chemical Bonding II:Molecular Geometry and

Hybridization of Atomic Orbitals

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AB2 2 0 linear linear

Class

# of atomsbonded to

central atom

# lonepairs on

central atomArrangement of electron pairs

MolecularGeometry

VSEPR

AB3 3 0trigonal planar

trigonal planar

AB4 4 0 tetrahedral tetrahedral

AB5 5 0trigonal

bipyramidaltrigonal

bipyramidal

AB6 6 0 octahedraloctahedral

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Cl ClBe

2 atoms bonded to central atom

0 lone pairs on central atom

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Page 6: 1 Chapter 10 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display. Chemical Bonding II: Molecular Geometry and Hybridization

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Page 10: 1 Chapter 10 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display. Chemical Bonding II: Molecular Geometry and Hybridization

10bonding-pair vs. bonding

pair repulsionlone-pair vs. lone pair

repulsionlone-pair vs. bonding

pair repulsion> >

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Predicting Molecular Geometry1. Draw Lewis structure for molecule.

2. Count number of lone pairs on the central atom and number of atoms bonded to the central atom.

3. Use VSEPR to predict the geometry of the molecule.

What are the molecular geometries of SO2 and SF4?

SO O

AB2E

bent

S

F

F

F F

AB4E

distortedtetrahedron

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Dipole Moments and Polar Molecules

H F

electron richregion

electron poorregion

= Q x rQ is the charge

r is the distance between charges

1 D = 3.36 x 10-30 C m

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Bond moments and resultant dipole moments in NH3 and NF3.

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Which of the following molecules have a dipole moment? H2O, CO2, SO2, and CF4

O HH

dipole momentpolar molecule

SO

O

CO O

no dipole momentnonpolar molecule

dipole momentpolar molecule

C

F

FFF

no dipole momentnonpolar molecule

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Does BF3 have a dipole moment?

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Does CH2Cl2 have a dipole moment?

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Valence Bond Theory and NH3

N – 1s22s22p3

3 H – 1s1

If the bonds form from overlap of 3 2p orbitals on nitrogen with the 1s orbital on each hydrogen atom, what would the molecular geometry of NH3 be?

If use the3 2p orbitalspredict 90o

Actual H-N-Hbond angle is

107.3o

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Hybridization – mixing of two or more atomic orbitals to form a new set of hybrid orbitals.

1. Mix at least 2 nonequivalent atomic orbitals (e.g. s and p). Hybrid orbitals have very different shape from original atomic orbitals.

2. Number of hybrid orbitals is equal to number of pure atomic orbitals used in the hybridization process.

3. Covalent bonds are formed by:

a. Overlap of hybrid orbitals with atomic orbitals

b. Overlap of hybrid orbitals with other hybrid orbitals

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Formation of sp3 Hybrid Orbitals

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Formation of Covalent Bonds in CH4

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Predict correctbond angle

sp3-Hybridized N Atom in NH3

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Formation of sp Hybrid Orbitals

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Formation of sp2 Hybrid Orbitals

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# of Lone Pairs+

# of Bonded Atoms Hybridization Examples

2

3

4

5

6

sp

sp2

sp3

sp3d

sp3d2

BeCl2

BF3

CH4, NH3, H2O

PCl5

SF6

How do I predict the hybridization of the central atom?

1. Draw the Lewis structure of the molecule.

2. Count the number of lone pairs AND the number of atoms bonded to the central atom

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sp2 Hybridization of Carbon

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Unhybridized 2pz orbital (gray), which is perpendicular to the plane of the hybrid (green) orbitals.

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Sigma bond () – electron density between the 2 atoms

Pi bond () – electron density above and below plane of nuclei of the bonding atoms

Bonding in Ethylene, C2H4

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Another View of Bonding in Ethylene, C2H4

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sp Hybridization of Carbon

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Bonding in Acetylene, C2H2

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Another View of the Bonding in Ethylene, C2H4

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Describe the bonding in CH2O.

CH

OH

C – 3 bonded atoms, 0 lone pairsC – sp2

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Sigma () and Pi Bonds ()

Single bond 1 sigma bond

Double bond 1 sigma bond and 1 pi bond

Triple bond 1 sigma bond and 2 pi bonds

How many and bonds are in the acetic acid (vinegar) molecule CH3COOH?

C

H

H

CH

O

O H bonds = 6 + 1 = 7

bonds = 1