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ReviewReview
We demonstrate (show) that an argument is valid
by derivingderiving (deducing) its conclusion
from its premises
using a few fundamental modes of reasoning.
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Initial Modes of ReasoningInitial Modes of ReasoningModus (Tollendo) Tollens(denying by denying)
––––––
Modus (Ponendo) Ponens(affirming by affirming)
––––––
Modus Tollendo Ponens (1)(affirming by denying)
––––––
Modus Tollendo Ponens (2)(affirming by denying)
––––––
aka disjunctive syllogism
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Example 1 (review)Example 1 (review)
5,9, Q4,8, P3,7, T1,2, RDD: QPrP QPrP TPrR TPrR SPrS
S ; RS ; RT ; PT ; PQ / Q
MP
MTP2
MTP1
MT
1.write all premises
3.apply rules to available lines
4.box and cancel(high-five!)
2.write ‘show’ conclusion
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Rule SheetRule Sheet
available on courseweb page(textbook)
provided on exams
keep this in front of you when doing homework
don’t make
upyourownrules
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Rules discussed TodayRules discussed Today
&I &O & & –––––– –––––– –––––– –––––– & & I O –––––– –––––– –––––– –––––– I see CD O ––––––– ––––––– DN DN ––––– –––––
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Rules of Inference – Basic IdeaRules of Inference – Basic Idea
Every connective has
(1) a take-out rule
also called an:
elimination-rule
OUTOUT-rule-rule
(2) a put-in rule
also called an:
introduction-rule
ININ-rule-rule
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Ampersand-Out (&O)Ampersand-Out (&O)
if you have a conjunctionconjunction && then you are entitled to infer –––––– its first conjunctfirst conjunct
if you have a conjunctionconjunction && then you are entitled to infer –––––– its second conjunctsecond conjunct
‘have’ means ‘have as a whole line’
rules apply only to whole linesnot pieces of lines
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Ampersand-IN (&Ampersand-IN (&II))
if you have a formulaformula and you have a formulaformula then you are entitled to infer ––––––their (first) conjunctionconjunction &&
if you have a formulaformula and you have a formulaformula then you are entitled to infer ––––––their (second) conjunctionconjunction &&
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Wedge-Out (Wedge-Out (O)O)
if you have a disjunctiondisjunction and you have the negationnegation of its 11stst disjunct disjunct then you are entitled to infer ––––––its second disjunctsecond disjunct
if you have a disjunctiondisjunction and you have the negationnegation of its 22ndnd disjunct disjunct then you are entitled to infer ––––––its first disjunctfirst disjunct
what we earlier called ‘modus tollendo ponens’
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Wedge-IN (Wedge-IN (II))
if you have a formulaformula then you are entitled to infer ––––––its disjunctiondisjunction with anyany formula to its right
if you have a formulaformula then you are entitled to infer ––––––its disjunctiondisjunction with anyany formula to its left
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Arrow-Out (Arrow-Out (O)O)
if you have a conditionalconditional and you have its antecedentantecedent then you are entitled to infer ––––––its consequentconsequent
if you have a conditionalconditional and you have the negationnegation of its consequentconsequent then you are entitled to infer ––––––the negationnegation of its antecedentantecedent
What we earlier called ‘modus ponens’ and ‘modus tollens’
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Arrow-IntroductionArrow-Introduction
THERE IS NO SUCH THING ASTHERE IS NO SUCH THING ASARROW-IN ARROW-IN ((I)I)
what we have instead is
CONDITIONAL DERIVATION CONDITIONAL DERIVATION (CD)(CD)
which we examine later
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Double-Negation (DN) Double-Negation (DN)
if you have a formula then you are entitled to infer –––––
its double-negative
if you have a double-negative then you are entitled to infer –––––
the formula
rules apply only to whole linesnot pieces of lines
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: °
°
°
Direct DerivationDirect Derivation
In Direct Derivation (DD),one directly arrives at
DD
The Original and Fundamental -Rule
the very formula one is trying to show.
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Example 2Example 2
5,9, Q4,8, P3,7, T1,2, RDD: QPrP QPrP TPrR TPrR SPrS
S ; R S ; R T ; P T ; P Q / Q
O
O
O
O
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Arrow-Out StrategyArrow-Out Strategy
If you have a line of the form , then try to apply arrow-outarrow-out (OO),
which requires a second formula as input,
in particular, either or .
deduce
find
have
or
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Example 3Example 3
5,9, Q4,8, P3,7, T1,2, RDD: QPrP QPrP TPrR TPrR SPrS
S ; R S ; R T ; P T ; P Q / Q
O
OOO
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Wedge-Out StrategyWedge-Out Strategy
If you have a line of the form , then try to apply wedge-outwedge-out (OO),
which requires a second formula as input,
in particular, either or .
deduce
find
have
or
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Example 4Example 4
5,7, R
3,6, Q R
1,5, P Q
1,2, RDD: QPr(P Q) (Q R)
Pr[(P Q) R] RPr(P Q) R
(P Q) R ; [(P Q) R] R ; (P Q) (Q R) / Q
O
O
OO
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Example 5Example 5
2,7, T
6, R S1,5, S
3, P QDD: TPrP
Pr(R S) TPr(P Q) S
(P Q) S ; (R S) T) ; P / T
O
IOI
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Wedge-In StrategyWedge-In Strategy
If you need
then look for either disjunct:
find OR
find then
apply vvII to get
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Example 6Example 6
1,7, Q
3,6, R2,9, Q S
8,10, S
8,11, Q & S
P 4,&O
TDDQ & S
PrT & P
PrR TPrR (Q S)
PrP Q
P Q ; R (Q S) ; R T ; T & P / Q & S
O
O
OO
&I
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Ampersand-Out StrategyAmpersand-Out Strategy
If you have a line of the form
&&, then apply ampersand-outampersand-out (&O),
which can be applied immediatelyto produce
andand
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Ampersand-In StrategyAmpersand-In Strategy
If you are trying to find or show
&&then look for both conjuncts:
find AND
find then
apply &&II to get &&