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EE Electronics Circuit Design 3 Summary of Design Equations Op. Amp. Pulse Generators
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1
13 . Pulsed waveforms and Timing Circuit Design
13.1 Op. Amp. Pulse Generators13.2 555 timer IC Oscillator13.3555 Timer Variable Duty Cycle Circuits13.4 555 Timer Monostable Circuits
2EE3601-13 Electronics Circuit Design
13.1 Op. Amp. Pulse Generators
Rd
Vo
R2
R1
C
Rc
V-V+
)1(3lnCRt3lnCR/t31e5.0e5.1e)E2
E(E2E
)RRas(v2E
RRERvbut
e)EV(EvCharing
CCCC
CR/tCR/tCR/t
2121
1
CR/t1
CcCcCc
Cc
)2(3lnCRt5.0e5.1e)E2
E(E2E
)RRas(v2E
RRERvbut
e))E(V(EvingargDisch
dd
CR/tCR/t
2121
1
CR/t1
dddd
dd
EVo
E
-E
V1
-V1VC
VC t
tc tdT
)RR(R
3lnC)RR(3lnCR
Ttcycledutyf
1ttTdC
CdC
Ccdc
-147 78Study example . page -147 78Study example . page
fff ffff fffff fffffffff f fff ffff6 fff ffff fffff fffffffff f fff ffff6ff
3EE3601-13 Electronics Circuit Design
Summary of Design Equations Op. Amp. Pulse Generators
Rd
Vo
R2
R1
C
Rc
V-V+
3lnCRtCharing CC
3lnCRtingargDisch dd
Ttcycleduty
ttf
cdc
1EVo
,conditiondesignasRRIf 21
4EE3601-13 Electronics Circuit Design
Example:Example: Given the Op. Amp. Pulse Generator circuit below, (a) Given the Op. Amp. Pulse Generator circuit below, (a) calculate and sketch the output waveform (b) frequency output and calculate and sketch the output waveform (b) frequency output and (c) duty cycle of the output waveform if C = 0.1(c) duty cycle of the output waveform if C = 0.1F, R = 20kF, R = 20k, R, R11= R= R22= = RR33= 1k= 1k
R
Vo
R2
R1
C
R3
V-V+
sec1051.1)k20//k1(1.01.1)R//R(1.03lnCRte)E2E(E2
E
)k1RRas(v2E
RRERvbute)EV(EvCharing
3CCCR/t
2121
1CR/t1
Cc
Cc
S22001.11020101.03lnCRte)E2E(E2
E
)k1RRas(v2E
RRERvbute))E(V(EvingargDisch
36dd
CR/t
2121
1CR/t1
dd
dd
%6.4046.0S2305S105
TtcycledutyHz434S2305
1tt
1f cdc
E
-E
V1
-V1
t
105S 2200S2305S
5EE3601-13 Electronics Circuit Design
Example:Example: Design the Op. Amp. Pulse Generator circuit to generate a Design the Op. Amp. Pulse Generator circuit to generate a 500Hz waveform at a duty cycle of 20%. (a) Sketch the output 500Hz waveform at a duty cycle of 20%. (a) Sketch the output waveform (b) Design all charging and discharging resistors if C = waveform (b) Design all charging and discharging resistors if C = 0.10.1F and voltage divider resistors RF and voltage divider resistors R11= R= R22= 1k= 1kto provide threshold to provide threshold voltage to the generator.voltage to the generator.
ms6.14.02tTtdms4.0ms22.0t2.0%20Ttms2TT
1Hz500 ccc
E
-E
V1
-V1
t
400S 1600S2000S
k64.36-100.113100.4
CR1.1CR0.1μ0.4ms3lnCRte)E2E(E2
E
)k1RRas(v2E
RRERvthresholdbute)EV(EvCharing
CCCR/t
2121
1CR/t1
Cc
Cc
k85.464.355.1455.1464.3R
Rk64.3R//k55.14givetoRawithparallelinusedbeshouldk55.14R
Rk55.14R2.0Rk64.3k64.3
RRR
3lnCR3lnCR3lnCR
Tt
3
C33
dddC
CdC
Cc
R
Vo
R2
R1
C
R3
V-V+
6EE3601-13 Electronics Circuit Design
13.2 555 timer IC Oscillator
76
2 3
1
8
output
vcc
5k
5k
5k
R
S
2/3VCC
1/3VCC
Q
4Reset
DischargeThreshold
Trigger
Q5
Modulate
RS-Flip-flopRS-Flip-flop Reset(R) or Set(S) with Reset(R) or Set(S) with
logic high inputlogic high input
ComparatorsComparatorsMore positive applied to the More positive applied to the
positive terminal (or more negative positive terminal (or more negative applied to the negative terminal will applied to the negative terminal will
make output highmake output high
If pin 4 (Reset pin) is less than If pin 4 (Reset pin) is less than VVCCCC, PNP BJT conducts and (R) , PNP BJT conducts and (R)
becomes high to reset the Flip-becomes high to reset the Flip-flopflop
Output is zero if Reset Output is zero if Reset and high (Vand high (VCCCC) if Set) if Set
Discharge pin 7 is zero Discharge pin 7 is zero if Reset and floats if Setif Reset and floats if Set
555 Timer555 Timer
7EE3601-13 Electronics Circuit Design
76
2 3
1
8
output
vcc
5k
5k
5k
R
S
2/3VCC
1/3VCC
Q
4Reset
DischargeThreshold
Trigger
Q5
Modulate
1. If Threshold pin 6 is more 1. If Threshold pin 6 is more than 2/3 of Vthan 2/3 of VCCCC, “R” will be , “R” will be high and output Q is Set to high and output Q is Set to zerozero2. If Threshold pin 6 is 2. If Threshold pin 6 is less than 2/3 of Vless than 2/3 of VCCCC, there , there is no change at output Qis no change at output Q
3. If Trigger pin 2 is less than 3. If Trigger pin 2 is less than 1/3 of V1/3 of VCCCC, “S” will be high , “S” will be high and output Q is Set to Vand output Q is Set to VCCCC
4. If Trigger pin 2 is more 4. If Trigger pin 2 is more than 1/3 of Vthan 1/3 of VCCCC, there is , there is no change at output Qno change at output Q
5. If Modulate pin 5 is 5. If Modulate pin 5 is connected to a dc source or to connected to a dc source or to external resistor, pin 2 and pin external resistor, pin 2 and pin 6 levels will be no longer 1/3 or 6 levels will be no longer 1/3 or 2/3 of V2/3 of VCCCC but will be changed to but will be changed to any other levels.any other levels.
8EE3601-13 Electronics Circuit Design
7
6
2
3
1
8output
vccR1
C
R2ThresholdTrigger
Discharge
Astable Multivibrator (pulse generator)Astable Multivibrator (pulse generator)
VCC
0
VC t
tc tdT
(2/ 3)VCC
(1/ 3)VCC
#2. But V#2. But VCC is never charged to V is never charged to VCCCC because when V because when VCC=just above =just above (2/3)V(2/3)VCCCC pin 6 takes care and the output pin 3 will reset. pin 6 takes care and the output pin 3 will reset.#3. When pin 3 is reset(=low). Pin 7 will be zero. Then C is discharged #3. When pin 3 is reset(=low). Pin 7 will be zero. Then C is discharged to 0 through Rto 0 through R22=R=Rdd
#4. But V#4. But VCC is never discharged to 0 because when V is never discharged to 0 because when VCC= just below = just below (1/3)V(1/3)VCCCC pin 2 takes care and the output pin 3 will set. It repeats pin 2 takes care and the output pin 3 will set. It repeats step #1 again.step #1 again.
#1. Let pin 3 is set (=high). Pin 7 will float. Then C is charged to V#1. Let pin 3 is set (=high). Pin 7 will float. Then C is charged to VCCCC through Rthrough R11+R+R22=R=RCC
9EE3601-13 Electronics Circuit Design
VCC
0
VC
ttc td
T
(2/ 3)VCC
(1/ 3)VCC
2lnCRt2ln21lnCR
te3213
2eV32VV3
2
e)VV31(VV3
2e)VV(VVCharing
CCCcCR/tCR/t
CCCCCC
CR/tCCCCCCCC
CR/tfinalinitialfinalC
CcCc
CcCc
2lnCRt2ln21lnCR
te21eV3
2V31
e)0V32(0V3
1e)VV(VVDischaring
ddCcCR/tCR/t
CCCC
CR/tCCCC
CR/tfinalinitialfinalC
Ccdd
dddd
)RR(R
2lnC)RR(2lnCR
Ttcycledutyf
1ttTdC
CdC
Ccdc
Pulse frequency and duty cyclePulse frequency and duty cycle
10EE3601-13 Electronics Circuit Design
Continuous and step Pulse frequency Continuous and step Pulse frequency
7
6
2
3
1
8output
vccR1
R2
C1 C2 C3T
7
6
2
3
1
8
vccR1
R2
C1 C2 C3
T
output
Discharge RDischarge R22 is varied to get is varied to get continuous change of discharge continuous change of discharge time ttime tdd which will vary both which will vary both frequency and duty cyclefrequency and duty cycle
Decade step of capacitor CDecade step of capacitor C11 =10C =10C2 2 , C, C22=10C=10C33 is switched to get step is switched to get step change of “T” which will vary the frequency but duty cycle remains the change of “T” which will vary the frequency but duty cycle remains the samesame
RR11 is varied to change charge R is varied to change charge R11 + + RR22 to get continuous change of to get continuous change of charge time tcharge time tcc which will vary both which will vary both frequency and duty cyclefrequency and duty cycle
11EE3601-13 Electronics Circuit Design
13.3 555 Timer IC Variable Duty Cycles Circuits
7
6
2
3
1
8output
vcc
R1
C
R2
By using a diode to bypass RBy using a diode to bypass R22 while while charging the capacitor, the tcharging the capacitor, the tcc is found from is found from RR11 alone and t alone and tdd is found from R is found from R22 alone. alone.
If RIf R22 = R = R11 then duty cycle = 50% then duty cycle = 50%If RIf R22 > R > R11 then duty cycle > 50% then duty cycle > 50%If RIf R22 < R < R11 then duty cycle < 50% then duty cycle < 50%
Now tNow tcc= CR= CR11ln2 and tln2 and tdd = CR = CR22ln2ln2Duty=(CRDuty=(CR11ln2)/(CRln2)/(CR11ln2 + CRln2 + CR22ln2 ) = ln2 ) = RR11/(R/(R11+R+R22))
12EE3601-13 Electronics Circuit Design
13.4 555 timer IC Monostable Circuit
7
62
3
1
8output
vccR
CThreshold
Trigger
Discharge
Monostable Multivibrator (timer)Monostable Multivibrator (timer)VCC
0
VC
ttc
(2/ 3)VCC
tc=Pulse width
#3. Now C is charged to V#3. Now C is charged to VCCCC through R. Output pin 3 is then high through R. Output pin 3 is then high#4. But V#4. But VCC is never charged to V is never charged to VCCCC because when V because when VCC= just above = just above (2/3)V(2/3)VCCCC pin 6 takes care and the output pin 3 will reset. And it stays pin 6 takes care and the output pin 3 will reset. And it stays stable at reset all the time until another external trigger.stable at reset all the time until another external trigger.
#1. Let pin 2 is high and pin 3 is low. Pin 7 will zero. Output is also #1. Let pin 2 is high and pin 3 is low. Pin 7 will zero. Output is also zero. Then C is also discharged to 0 through pin 7zero. Then C is also discharged to 0 through pin 7#2. When pin 2 is triggered to zero for a short time, Pin 3 will be high. #2. When pin 2 is triggered to zero for a short time, Pin 3 will be high. Then pin 7 is floating.Then pin 7 is floating.
13EE3601-13 Electronics Circuit Design
Summary of Design Equations 555 Oscillator and Timer
7
6
2
3
1
8output
vccR1
C
R2Threshold
Trigger
Discharge 7
6
2
3
1
8output
vccR1
R2
C1 C2 C3T
7
6
2
3
1
8output
vcc
R1
C
R2
Ttcycleduty
ttTTf
cdc
1
xcx
dxcxxx
x
Ttcycleduty
ttTTf
1
Ttcycleduty
ttTTf
cdc
1
7
62
3
1
8output
vccR
CThreshold
Trigger
Discharge
22 21 lnCRt&lnCRt dc
22 221 lnCRt&lnCRRt dc 22 221 lnCRt&lnCRRt xdxxcx
31 lnCRtT c
Astable Multivibrator 1 Astable
Multivibrator 2
Astable Multivibrator 3 Monostable
Multivibrator
14EE3601-13 Electronics Circuit Design
Example:Example: Design the 555 Timer IC Pulse Generator circuit to generate Design the 555 Timer IC Pulse Generator circuit to generate a 500Hz waveform at a duty cycle of 80%. (a) Sketch the output a 500Hz waveform at a duty cycle of 80%. (a) Sketch the output waveform (b) Design all charging and discharging resistors if C = waveform (b) Design all charging and discharging resistors if C = 0.10.1F (c) Sketch the circuit.F (c) Sketch the circuit.
7
6
2
3
1
8output
vccR1=1.714k
C=0.1F
R2=0.571k
500Hzduty=0.8
ms4.06.12tTtms6.1ms28.0t8.0%80T
tms2TT1Hz500
cdc
c
VCC
0 ttc td
T
(2/ 3)VCC
(1/ 3)VCC
21
CC
RRk285.26-100.73106.1
CR
7.0CR0.1μms6.12lnCRtCharing
k714.1k571.0k
Rk571.0R8.0Rk285.2k285.2
RRR
2lnCR2lnCR2lnCR
Tt
285.2RCRR 21
2dd
dCC
dCCc
15EE3601-13 Electronics Circuit Design
Example:Example: Design the 555 Timer IC Pulse Generator circuit to generate Design the 555 Timer IC Pulse Generator circuit to generate a 500Hz waveform at a duty cycle of (a) 50%. (b) 20% (c) 80% Design a 500Hz waveform at a duty cycle of (a) 50%. (b) 20% (c) 80% Design all charging and discharging resistors if C = 0.1all charging and discharging resistors if C = 0.1F (c) Sketch the F (c) Sketch the circuit.circuit.
ms6.1ms28.0t)c(ms4.0ms22.0t)b(ms1ms25.0t)a(
8.0Tt)c(2.0T
t)b(5.0Tt)a(ms2TT
1Hz500
3c2c1c
ccc
k26.96-100.113101.6
13R7.0R0.1μ1.6ms
k32.26-100.113104.0
12R7.0R0.1μms4.0
k72.56-100.11310111R7.0R0.1μ1ms
13133C
12122C
11111C
2lnCRt)c(
2lnCRt)b(
2lnCRt)a(Charing
k32.2k26.916.12R1t
TR)c(k26.9k32.214.02R1t
TR)b(
k72.5k72.5112R1t
TR)a(R1tTRR
R1tT
RRR
2lnCR2lnCR2lnCR
Tt
133c
23122c
22
111c
211c
212
c211
211c
7
6
2
3
1
8output
vcc
R1
C
R2
16EE3601-13 Electronics Circuit Design
Example:Example: Design the 555 Timer IC Pulse Generator circuit to generate Design the 555 Timer IC Pulse Generator circuit to generate a 20Hz to 250Hz waveform by using a minimum discharge resistance a 20Hz to 250Hz waveform by using a minimum discharge resistance of 1kof 1k. (a) Sketch the output waveform (b) Design all charging and . (a) Sketch the output waveform (b) Design all charging and discharging resistors if Cdischarging resistors if C11 = 0.1 = 0.1F (c) Sketch the circuit (d) what is the F (c) Sketch the circuit (d) what is the maximum frequency of this generator if a decade step uses 2 more maximum frequency of this generator if a decade step uses 2 more capacitors Ccapacitors C22=0.01=0.01F, CF, C33=0.001=0.001F?F?
7
6
2
3
1
8output
vccR1
R2
C1 C2 C3T
0.1F 0.001F0.01F
kHz25Hz250100f100f.freqmax100001.0
1.0CC
2lnRRC2lnRRC
TT
ff
1331
dc3dc1
31
13
k14.55114.56k1RRk14.56k107.093.3
RttRR
R2lnCR2lnCR
tt
ms93.307.04tHz2501t
2lnCRtDisharing
minc1
mindmindminc
mincmindminc
mindminc
mindminc
mindminc
mindmind .ms07.07.0k10.1μ
max2maxd Rk5.3292
k14.55k14.575.12Rk14.55k12k14.55maxdR2
1RmindR21RmaxdR2
2lnmindR1RmindRC2lnmaxdR1RmaxdRC
minTmaxT
20250
Hz2501Hz201
17EE3601-13 Electronics Circuit Design
7
62
3
1
8output
vcc1M
C
100ms
100ms
Example:Example: Design the 555 Timer IC circuit to generate a 100ms Design the 555 Timer IC circuit to generate a 100ms pulse. (a) Design C if charging resistors is 1Mpulse. (a) Design C if charging resistors is 1M (b) Sketch the (b) Sketch the circuit.circuit.
3lnCRt3ln31lnCR
te132eVVV3
2e)V0(VV3
2e)VV(VVCharing
CcCR/tCR/tCCCCCC
CR/tCCCCCC
CR/tfinalinitialfinalC
cc
cc
VCC
0
VC
ttc
(2/ 3)VCC
tc=Pulse width
nF9110911.110
10100C1.110C3lnCR10100tCharing 96
363C