07 Electricity

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    Electricity

    Basic Concepts

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    Contents

    General Electric Current

    Voltage

    Resistance

    Ohms law

    DC/AC Frequency

    Power, Power factor

    Energy

    Power System Generation: Generators, switchyard, transformers, control andprotection

    Transmission: Components, parameters and design

    Distribution: Substations, switchgear and protection, design

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    Current

    Rate of flow of electricity or electricalcharge (electrons) through a conductor

    Measuring Unit: Amperes (mA, A, KA)

    One ampere of current represents one coulomb of electrical charge

    (6.24 x 1018charge carriers) moving past a specific point in one

    second.

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    Voltage

    Voltage, also called electromotive force, is a quantitativeexpression of the potential difference between two points.

    Voltage (or potential difference) between two points canalso be understood as the driving force which causes

    electric charge (or current) to flow between the points. The greater the voltage, the greater the flow of electrical

    current through a conducting medium for a givenresistance to the flow.

    Measuring Unit of Voltage: Volt (mV,V,kV)

    (One volt will drive one coulomb (6.24 x 1018) charge carriers, such as

    electrons, through a resistance of one Ohm in one second).

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    Resistance

    It is the property of a material which opposes the flow ofelectricity (electric charge) through them.

    Its SI unit is (Ohm).

    Resistance of a conductor depends upon the resistivityof the material, length of conductor under consideration,and its cross sectional area.

    Mathematically,

    R= x L/A ------------ (i)where, - resistivity (meter)

    L- length of conductor

    A- cross section area of conductor

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    Ohms Law

    It states that the current flowing between twopoints is directly proportional to the potential

    difference (voltage) between them and inversely

    proportional to the resistance between them. Mathematically,

    I=V/R ------------- (ii)

    Where, R- resistance, OhmV- voltage, Volt

    I- Current, Ampere

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    DC/AC

    Electric current and voltage can be eitherdirect or alternating, on the basis ofpolarity and direction of flow.

    Direct current (DC) flows in the samedirection at all points in time.

    In an alternating current (AC), the flow of

    charge carriers and the polarity reversedirection periodically.

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    Alternating Current

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    Frequency

    The number of cycles per second is also called the frequency

    The standard unit of frequency is the hertz (Hz)

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    Power Power is the rate of transfer of energy through a point.

    Apparent power (S) is the absolute value of total power, and is given by,

    S=V*I

    Its SI unit is VA (volt-ampere)

    Real power (P) is the total useful power flowing in a circuit, and is given by,

    P=V*I*Cos

    Its SI unit is Watt (W)

    Reactive power (Q) is the power which does not do useful work and ismostly lost in the form of heat, or consumed by inductive loads. It is given

    by,

    Q=V*I*Sin

    Its SI unit is VARHere, V denotes Voltage

    I denotes current and

    denotes the phase angle between voltage

    and current vectors. Cos is generally known as Power Factor.

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    Power factor

    It is the ratio of Real power to Apparentpower.

    Mathematically, it is given as the Cosine of

    phase angle between current and voltagevectors. i.e.,

    Cos

    where, is the phase angle between currentand voltage waveform.

    Power factor plays important role in the quality ofelectricity supply

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    Energy

    Energy is the total power transferred incertain amount of time.

    Generally electrical energy is measured inWatt Hour (WH).

    1 kWH is also known as 1 unit ofelectricity.

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    Power System

    It consists of three major components: Generation: Generates electricity

    Transmission: Transmits electricity throughlong distances to substations

    Distribution: Distributes electricity amongutilities/consumers

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    Power System

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    Three Phase System

    Three phase system is generally adoptedand economical method of electricity

    generation, transmission and distribution.

    In this system there are three conductorscarrying AC current, each out of phase to

    others by 120(Their instantaneousvalues reach maximum value after 1/3 and2/3 of a cycle)

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    Alternators (AC Generators)

    Generators are the machines whichconvert mechanical energy into electrical

    energy.

    Parts of generator: Rotor: Rotating part of generator

    Stator: Stationary part of generator

    Armature: Power producing part, generallypresent in stator.

    Field: Magnetic field component of generator

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    Alternator operating principle

    When field current is provided in the rotor winding,rotating magnetic field is established, and hence flux is

    linked to the stator consisting of armature winding. Due

    to the interaction of armature winding with the rotating

    field, an electromotive force (EMF) is generated causingflow of current through the armature winding of the

    generator.

    The principle is based on Farradays law of

    electromagnetism which says that an EMF is generatedin a conductor when it is placed in a varying magnetic

    flux.

    The rotor is rotated by mechanical input such as rotation

    of turbine.

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    Alternator operating principle

    The output frequency of an alternator depends on thenumber of poles and the rotational speed.

    The speed corresponding to a particular frequency iscalled the Synchronous speed for that frequency.

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    Generator parts

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    Poles in Generator

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    Generator types

    Synchronous generators They operate at synchronous speed

    Self excited- through exciter

    Voltage regulated through built in AVR Can operate at stand alone or island mode

    Induction generators They operate at higher than synchronous speed

    Require external excitation- such as from the grid

    Frequency & voltage governed by grid

    Can not run in island modewhen grid is off system

    will be down

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    Generation

    Governor: It is a device used to measure and regulate

    the speed of turbines.

    Automatic Voltage Regulator (AVR):An automatic voltage control device controls

    the field current to keep output voltage

    constant.

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    Generator sizing

    Generator rating factors.

    Max. ambient

    temperature in oC20 25 30 35 40 45 50 55

    ATemperature

    Factor1.10 1.08 1.06 1.03 1.00 0.96 0.92 0.88

    Altitude 1000 1500 2000 2500 3000 3500 4000 4500

    B Altitude Factor 1.00 0.96 0.93 0.90 0.86 0.83 0.80 0.77

    C ELC Correction Factor 0.83

    D Power Factor When load is light bulbs only 1.0

    When load includes tube light and other

    inductive loads0.8

    Power Output in kWGenerator KVA = -----------------------------

    A x B x C x D

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    Transformers They are the devices which are used in the power

    system to change the voltage level of electrical supply.

    The generation voltage is stepped up to higher level forthe purpose of transmission. Similarly the transmission

    voltage level is stepped down to lower level for

    distribution purpose. The generation voltages generally used are 400V, 6.3kV,

    6.6kV and 11kV.

    Standard transmission voltages are: 33kV, 66kV, 132kV

    and 220kV. Primary distribution voltage levels: 33kV, 11kV

    Secondary distribution voltage level: 400V

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    Powerhouse and Switchyard equipment

    Circuit Breakers: They are the devices which are used to make or break circuitsmanually, automatically and by remote control in case of any

    faulty condition and also in normal condition.

    Disconnectors

    Disconnectors are the devices which are used to isolate acertain segment of a circuit, mainly for the purpose of

    maintenance.

    Instrument transformers

    Current transformers (CT) step down the value of current to alevel at which control, protection and metering equipment can beused. (generally 5A or 1A)

    Potential transformers (PT) step down the value of voltage tolevel at which control, protection and metering equipment can be

    used. (generally 110V)

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    Powerhouse and switchyard equipment Lightening arrestors (Surge arrestors)

    They are the devices which protectthe insulation on the system from

    lightening.

    They divert the surges directly to

    ground, protecting othercomponents of the power system.

    Protective relays

    They are the devices which sense

    the faulty or abnormal conditionson a system and actuate the

    operation of circuit breakers.

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    Powerhouse and switchyard equipment

    Communication system:

    SCADA (Supervisory Control And Data Acquisition) isused for the control and supervision of the Integrated

    Power System (IPS)

    With the help of SCADA, data from all the powerstations and substations of the whole system is

    collected at the Load Dispatch System (LDC).

    Optical Fiber system or Power Line CarrierCommunication system is used as the communication

    medium.

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    Transmission System

    Transmission of power from generating stationsto distribution stations through long distances can

    incorporate huge amount of losses.

    So, power is transmitted at high voltage level inorder to minimize the loss.

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    Transmission System

    We know, P = V * I

    where, P is power,

    V is voltage and

    I is current

    So for constant power, when V increases, Idecreases.

    The loss in transmission line is given by,

    Pl = I2* R (single phase)

    Pl= 3*I2* R (three phase)

    where, Pl is power lost in line,

    and R is the line resistance.

    Hence the line loss decreases with the increase in voltage level.

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    Transmission line components Conductors

    Aluminum Core Steel Reinforced (ACSR) conductors are generally used.

    Based on their cross section diameters, code names representing differentanimals and birds are given to ACSR conductors.

    Support (Tower) Up to 33kV lines, steel tubular, wooden or RCC poles are used, where as for

    higher voltage transmission lines, rigid, self supporting lattice towers (pylons)

    are used.

    Insulators and fittings Insulators are required to support the line conductor and provide clearance from

    ground and structure.

    Toughened glass insulators are generally used in high voltage transmission lineswhere as porcelain type are mostly used up to 33kV.

    Earth wire They are strung above phase conductors, in order to provide shielding or

    protection from lightening strokes.

    They are connected to ground at each tower.

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    Transmission line design

    Standard Voltage 66, 132, 220, 400 KV (11kV and 33kV areused for transmission by small hydropower projects for short

    lines)

    Selection Criterion of Economic Voltage

    Power to be evacuated

    Length of line

    Voltage regulation

    Power loss in Transmission

    Initial and operating cost

    Present and future voltage in neighborhood

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    Voltage level selection

    The most economical voltage level selected among standardvoltage levels

    Use of empirical formula (Stills formula) for estimation ofmost economical voltage level

    V=5.5 * (0.6*L + P/100)

    Where,

    V is Voltage (kV)

    L is Length (km)

    P is Power to be transmitted (kW)

    The standard voltage level closest to the result of above

    calculation is selected.

    Note: Still's formula is one of the empirical formulas used for selection of the most economical voltage level

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    The size of conductor should be such that it can carry the rated

    current continuously without excessive rise in temperature. The line loss should be kept to a minimum (generally less than

    5%)

    The voltage regulation should be within specified limits(generally within 10%)

    The larger the conductor diameter, the lesser the resistance andthe line loss and higher is the current carrying capacity.

    So, larger conductors are used for evacuation of large amountof power.

    Conductor selection

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    Properties of some ACSR conductors

    Code

    Name Eq. Cu Area Eq. Al Resistance Inductive reactance

    Currentcarrying

    capacity

    for a

    temperatu

    re .rise of

    30 C (A)

    Current Diameter

    Sq mm Sqare inch Area at 20C Ohm/km in still air

    Square inch ohm/km Double Ckt SingleCkt (A) (cm)

    Ferret 25 0.04 41.87 0.6795 0.19988 0.4134512 170 115 0.9

    Rabbit 30 0.05 52.21 0.5449 0.19641 0.4065152 192 135 1.005

    Otter 50 0.08 82.85 0.3434 0.18931 0.3923023 250 185 1.266

    Dog 65 0.1 103.6 0.275 0.18555 0.3847883 280 205 1.414

    Wolf 95 0.15 154.3 0.1844 0.1918434 0.4047098 400 305 1.813

    Lynx 110 0.175 179 0.1589 0.17542 0.3645309 440 335 1.953

    Panther 130 0.2 207 0.1375 0.17325 0.3601944 470 370 2.1

    Lion 140 0.215 232.5 0.1223 0.17137 0.3564191 525 405 2.26

    Bear 160 0.25 258.1 0.1102 0.17053 0.3547503 570 430 2.345

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    Name Current rating in still air(Amp)

    Resistance

    (/km)Squirrel 76 1.374

    Gopher 85 1.098

    Weasel 95 0.9116

    Rabbit 135 0.5449

    Dog 205 0.2745

    Aluminum 4mm2 23 7.15

    Aluminum 6mm

    2

    30 4.76Aluminum 10mm2 40 2.86

    Aluminum 16mm2 51 1.78

    Aluminum 25mm2 70 1.14

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    Performance of a Transmission line

    Efficiency: It is the ratio of output power to input power.

    Mathematically, = (Pr/Ps) * 100%

    =(Pr/Pr+loss) * 100% and,

    Loss = 3 * I2* R (for three phase)

    Where, is efficiency

    Pr is receiving end (output) power

    Ps is sending end (input) powerR is line resistance

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    Sizing of transmission line

    (3 phase)

    Decide on transmission line voltage

    Then find resistance of ACSR based online length and size/type of cable

    Or

    Power loss is

    VICosP 3

    VCos

    PI

    3

    RIPloss

    23

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    Transmission line design exampleLet us consider, a 40MW plant has to evacuate its power through 30km

    at 132kV at a power factor of 0.8 lagging. Generally allowable line lossshould be limited to 5%

    First we try using Rabbit conductor and get the following result:

    Line loss= 5.8% > 5%

    Since the result is unsatisfactory, we choose a higher sized

    conductor.Using Wolf conductor, we get the following result:

    Line loss= 2.%

    Since the performance is good, Wolf is satisfactory. But is this tooexpensive?? Try lower size conductor.

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    Distribution System

    It is the part of the power system which isresponsible for distributing electricity among the

    utilities.

    It mainly consists of distribution substations,transformers (step down), distribution lines

    consisting of conductors, cables, poles, protection

    system etc.

    Distribution is done primarily at 33kV andsecondarily at 11kV and then at 400V (220V,

    230V or 110V)

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    Substation Part of electrical power system responsible for switching,

    voltage transformation and regulation . Components of a substation:

    Transformers

    Bus bars

    Circuit breakers Disconnectors

    Lightening arrestors

    Instrument transformers etc.

    Busbars are flat strips or hollow tubes of copper oraluminum.

    They carry large currents to multiple devices.

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    Distribution System

    3 phase 4 wire system is generally used in a distributionsystem.

    The three wires are the phase wires and the fourth one is aneutral wire.

    Among the four wires, a domestic electrical supply isprovided by tapping from one phase wire and the neutral

    wire.

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    Distribution System

    The domestic electric supply is done at 400V line- to-line (voltage between phase wires) which is equivalent to

    230V line- to- neutral (voltage between a phase wire and

    the neutral wire), according to the relation,

    Vll=3*VlnWhere, Vll is the line to line voltage and

    Vln is the line to neutral voltage

    Large (bulk) consumers like industries, hospitals etcrequire three phase supply at 11kV and even 33kV.

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    Distribution line design exampleLets consider, 100kW of power is to be delivered to a load center at a

    distance of 500m, using Dog conductor, Assume power factor = 0.8First try transmitting the power at 400V and we get the followingresult:

    Line loss= 13.3%

    Since the result is very poor, higher voltage level will be required.

    At 11kV, we get the following result:Line loss= 0.02%An excellent result is achieved. But still the cost can be reduced by using smaller

    sized conductor. So we try using smaller sized conductor

    Using Ferret conductor, we get the following result:Line loss= 0.04%

    Since the performance is good even with Ferret (smaller) conductor,we design the line using Ferret conductor at 11kV.