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Darcy’s law Groundwater Hydraulics Daene C. McKinney

03 darcys law

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Page 1: 03 darcys law

Darcy’s lawGroundwater Hydraulics

Daene C. McKinney

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Outline• Properties – Aquifer Storage• Darcy’s Law• Hydraulic Conductivity• Heterogeneity and Anisotropy• Refraction of Streamlines• Generalized Darcy’s Law

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Aquifer Storage

• Storativity (S) - ability of an aquifer to store water

• Change in volume of stored water due to change in piezometric head.

• Volume of water released (taken up) from aquifer per unit decline (rise) in piezometric head.

Unit area

Unit decline in head

Released water

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Aquifer Storage

• Fluid Compressibility (b)• Aquifer Compressibility (a)• Confined Aquifer

– Water produced by 2 mechanisms

1. Aquifer compaction due to increasing effective stress

2. Water expansion due to decreasing pressure

• Unconfined aquifer– Water produced by draining

pores

gV

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Unconfined Aquifer Storage

• Storativity of an unconfined aquifer (Sy, specific yield) depends on pore space drainage.

• Some water will remain in the pores - specific retention, Sr

• Sy = f – Sr

Unit area

Unit decline in head

Released water

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Porosity, Specific Yield, & Specific Retentionyr SS

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Confined Aquifer Storage

• Storativity of a confined aquifer (Ss) depends on both the compressibility of the water (b) and the compressibility of the porous medium itself (a).

Unit area

Unit decline in head

Released water

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Example

• Storage in a sandstone aqufier• f = 0.1, a = 4x10-7 ft2/lb, b = 2.8x10-8 ft2/lb, g = 62.4 lb/ft3

• = ga 2.5x10-5 ft-1 and = gbf 1.4x10-7 ft-1

• Solid Fluid• 2 orders of magnitude more storage in solid• b = 100 ft, A = 10 mi2 = 279,000,000 ft2

S = Ss*b = 2.51x10-3

• If head in the aquifer is lowered 3 ft, what volume is released?DV = SADh = 2.1x10-6 ft3

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Darcy

http://biosystems.okstate.edu/Darcy/English/index.htm

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Darcy’s Experiments

• Discharge is Proportional to – Area– Head differenceInversely proportional to – Length

• Coefficient of proportionality is K = hydraulic conductivity

L

hhAQ 21

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Darcy’s Data

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Hydraulic Conductivity• Has dimensions of velocity [L/T]• A combined property of the medium and the fluid• Ease with which fluid moves through the medium

k = cd2 intrinsic permeability ρ = densityµ = dynamic viscosityg = specific weight

Porous medium property

Fluid properties

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Hydraulic Conductivity

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Groundwater Velocity

• q - Specific dischargeDischarge from a unit cross-section area of aquifer formation normal to the direction of flow.

• v - Average velocityAverage velocity of fluid flowing per unit cross-sectional area where flow is ONLY in pores. A

Qq

A

Qqv

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dh = (h2 - h1) = (10 m – 12 m) = -2 m

J = dh/dx = (-2 m)/100 m = -0.02 m/m

q = -KJ = -(1x10-5 m/s) x (-0.02 m/m) = 2x10-7 m/s

Q = qA = (2x10-7 m/s) x 50 m2 = 1x10-5 m3/s

v = q/f = 2x10-7 m/s / 0.3 = 6.6x10-7 m/s

/”

h1 = 12m h2 = 12m

L = 100m

10m

5 m

FlowPorous medium

Example

K = 1x10-5 m/sf = 0.3

Find q, Q, and v

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Hydraulic Gradient

Gradient vector points in the direction of greatest rate of increase of h

Specific discharge vector points in the opposite direction of h

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Well Pumping in an Aquifer

Aquifer (plan view)

y

h1 < h2 < h3

x

h1

h2 h3

Well, Q

q

Dh

Circular hydraulic head contours

K, conductivity, Is constant

Hydraulic gradient

Specific discharge

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Validity of Darcy’s Law

• We ignored kinetic energy (low velocity)• We assumed laminar flow• We can calculate a Reynolds Number for the flow

q = Specific discharged10 = effective grain size diameter

• Darcy’s Law is valid for NR < 1 (maybe up to 10)

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Specific Discharge vs Head Gradient

q

Re = 10

Re = 1

Experiment shows this

a

tan-1(a)= (1/K)

Darcy Law predicts this

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Estimating ConductivityKozeny – Carman Equation

• Kozeny used bundle of capillary tubes model to derive an expression for permeability in terms of a constant (c) and the grain size (d)

• So how do we get the parameters we need for this equation?

22

32

)1(180dcdk

Kozeny – Carman eq.

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Measuring ConductivityPermeameter Lab Measurements

• Darcy’s Law is useless unless we can measure the parameters

• Set up a flow pattern such that– We can derive a solution – We can produce the flow pattern experimentally

• Hydraulic Conductivity is measured in the lab with a permeameter– Steady or unsteady 1-D flow– Small cylindrical sample of medium

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Measuring ConductivityConstant Head Permeameter

• Flow is steady• Sample: Right circular cylinder

– Length, L– Area, A

• Constant head difference (h) is applied across the sample producing a flow rate Q

• Darcy’s Law

Continuous Flow

OutflowQ

Overflow

A

Sample

head difference

flow

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Measuring ConductivityFalling Head Permeameter

• Flow rate in the tube must equal that in the column

OutflowQ

Sample

flow

Initial head

Final head

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Heterogeneity and Anisotropy • Homogeneous

– Properties same at every point

• Heterogeneous– Properties different at every

point • Isotropic

– Properties same in every direction

• Anisotropic– Properties different in different

directions• Often results from stratification

during sedimentation

verticalhorizontal KK

www.usgs.gov

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Example

• a = ???, b = 4.673x10-10 m2/N, g = 9798 N/m3, • S = 6.8x10-4, b = 50 m, f = 0.25, • Saquifer = gabb = ???

• Swater = gbfb

• % storage attributable to water expansion • • %storage attributable to aquifer expansion •

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Layered Porous Media(Flow Parallel to Layers)

3K

2K

1K

W

b

1b

2b

3b

1Q

2Q

3Q

Dh

h2

h1

Piezometric surface

Q

datum

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Layered Porous Media(Flow Perpendicular to Layers)

Q

3K2K1K

bQ

L

L3L2L1

Dh1

Piezometric surface

Dh2

Dh3

Dh

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Example

• Find average K

Flow Q

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Example

• Find average K

Flow Q

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Anisotrpoic Porous Media• General relationship between specific

discharge and hydraulic gradient

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Principal Directions

• Often we can align the coordinate axes in the principal directions of layering

• Horizontal conductivity often order of magnitude larger than vertical conductivity

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Groundwater Flow Direction

• Water level measurements from three wells can be used to determine groundwater flow direction

GroundwaterContours

GroundwaterFlow, Q

x

y

z

Head Gradient, J

hk

hjhi

hi > hj > hk

h1(x1,y1)h3(x3,y3)

h2(x2,y2)

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Groundwater Flow Direction

Magnitude of head gradient =

Angle of head gradient =

Head gradient =

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Groundwater Flow Direction

Set of linear equations can be solved for a, b and c given (xi, hi, i=1, 2, 3)

3 points can be used to define a plane

Equation of a plane in 2DGroundwaterFlow, Q

x

y

z

Head Gradient, J

h1(x1,y1)h3(x3,y3)

h2(x2,y2)

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Groundwater Flow Direction

Negative of head gradient in x direction

Negative of head gradient in y direction

Magnitude of head gradient

Direction of flow

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x

Well 2(200 m, 340 m)55.11 m

Well 1(0 m,0 m)57.79 m

Well 3(190 m, -150 m)52.80 m

ExampleFind:

Magnitude of head gradient

Direction of flow

y

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Contour Map of Groundwater Levels

• Contours of groundwater level (equipotential lines) and Flowlines (perpendicular to equipotiential lines) indicate areas of recharge and discharge

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Refraction of Streamlines• Vertical component of

velocity must be the same on both sides of interface

• Head continuity along interface

• So

2K

1KUpper Formation

12 KK

y

x

1

2

2q

1q

Lower Formation

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Summary• Properties – Aquifer Storage• Darcy’s Law

– Darcy’s Experiment– Specific Discharge– Average Velocity– Validity of Darcy’s Law

• Hydraulic Conductivity– Permeability– Kozeny-Carman Equation– Constant Head Permeameter– Falling Head Permeameter

• Heterogeneity and Anisotropy– Layered Porous Media

• Refraction of Streamlines• Generalized Darcy’s Law

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Darcy’s LawExamples

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Example

• a = ???, b = 4.673x10-10 m2/N, g = 9798 N/m3, • S = 6.8x10-4, b = 50 m, f = 0.25, • Saquifer = gabb = ???

• Swater = gbfb = (9798 N/m3)(4.673x10-10 m2/N)(0.25)(50 m)

• = 5.72x10-5

• percent of storage coefficient attributable to water expansion • = Swater /S = 5.72x10-5 /6.8x10-4 *100 = 8.4%• percent of storage coefficient attributable to aquifer

expansion • = Saquifer /S = 1 – (Swater /S ) = 91.6%

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Example

Flow Q

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ExampleFlow Q

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xq = -5.3 deg

Well 2(200, 340)55.11 m

Well 1(0,0)57.79 m

Well 3(190, -150)52.80 m

Example