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Page 1: < > Source :- 1 · 2018. 9. 1. · 30469 AL/2011/02-S..1 Chemistry Two hours * ea 08 * * I EàO 50 (l), (1), (3), (4),.(5) (X) CE5ê)850. 8.314 J K-l 6.022 x 1023 mol-I . @

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The Mole Concept Avagadro’s Number = 6.022 x 10 23

The Mole Concept Avagadro’s Number = 6.022 x 10 23

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< > Source :- 1 · 71341 AL/2013/02/S-11A / All Rights Sri New S llabus w 11 Chemis 11 15 Oog R = 8.314 J mol—I NA = 6.022 x mol-I A 0030ee - B C - (SQ 9 - 14)

< > Source :- 1 · 71341 AL/2013/02/S-11A / All Rights Sri New S llabus w 11 Chemis 11 15 Oog R = 8.314 J mol—I NA = 6.022 x mol-I A 0030ee - B C - (SQ 9 - 14)

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E-Cigarette Airflow Rate Modulates Toxicant Profiles …ciencias.bogota.unal.edu.co/.../cursos/quimica_basica/...problem_.pdf · eq = −G rxn / RT, where R = 8.314 × 10−3 kJ/mol

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Chemistry Reference Tables...Avogadro’s number 6.022 10× 23 particles/mole Gas constant (R) 0.0821 L atm mole K 62.4 L mmHg mole K 8.314 L kPa mole K Standard pressure 1.00 atm

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JEE-MAIN-2020 SEPTEMBER ATTEMPT CHEMISTRY - Narayana … · 2020. 9. 5. · k Ae RT 2 1 1 2 K Ea 1 1 ln K R T T ln 5 Ea 1 1 8.314 300 315 Ea 15 1.6094 8.314 300 315 Ea= 84.30 kJ 20

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