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1 Adda247 | No. 1 APP for Banking & SSC Preparation Website:store.adda247.com | Email:[email protected]
2 Adda247 | No. 1 APP for Banking & SSC Preparation Website:store.adda247.com | Email:[email protected]
Q1. The present age of a father is 3 years more than three times the age of his son. Three years hence, father’s age will be 10 years more than twice the age of the son. Find the present age of the father. (a) 32 years (b) 33 years (c) 34 years (d) 35 years (e) 40 years Q2. In a coconut grove, (x + 2) trees yield 60 nuts per year, x trees yield 120 nuts per year and (x – 2) trees yield 180 nuts per year. If the average yield per year per tree be 100. Then the value of x is: (a) 8 (b) 4 (c) 12 (d) 10 (e) 16 Q3. A train passes two persons who are walking in the direction opposite to the direction of train at the rate of 10 m/s and 20 m/s respectively in 12 seconds and 10 seconds, respectively. Find the length of the train. (a) 500 metre (b) 900 metre (c) 400 metre (d) 600 metre (e) 650 metre Q4. The distance between two stations A and B is 138 km. A train starts from A towards B and another from B to A at the same time and they meet after 6 hours. The train travelling from A to B is slower by 7 kmph compared to other train from B to A, then find the speed of the slower train? (a) 10 kmph (b) 8 kmph (c) 12 kmph (d) 15 kmph (e) 18 kmph Q5. Ankit and Aadarsh invest Rs. 4000 and Rs. 3000 in a business
respectively. Ankit receives Rs. 20 per month out of the profit as
a remuneration for running the business and the rest of profit is
divided in proportion to the investments. If in a year Ankit
totally receives Rs. 360, what does Aadarsh receive?
(a) Rs. 90
(b) Rs. 100
(c) Rs. 120
(d) Rs. 80
(e) Rs. 110
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Q6. Nandita scored 80% marks in five subjects together Hindi, Science, Mathematics, English and
Sanskrit, where the maximum marks of each subject were 105. How many marks did Nandita
scored in Science, if she scored 89 marks in hindi 92 marks in Sanskrit, 98 marks in Mathematics
and 81 marks in English?
(a) 60
(b) 75
(c) 65
(d) 70
(e) 80
Q7. A number is divided into two parts in such a way that 80% of 1st part is 3 more than 60% of 2nd
part and 80% of 2nd part is 6 more than 90% of the 1st part. Then the number is:
(a) 125
(b) 130
(c) 135
(d) 145
(e) 155
Q8. The expenses on rice, fish and oil of a family are in the ratio 12 : 17 : 3 respectively. The price
of these articles is increased by 20%, 30% and 50% respectively. The total expenses increased by:
(a) 141
8%
(b) 71
8%
(c) 561
8%
(d) 281
8%
(e) None of these
Q9. A man purchases two articles at Rs. 1800 each. While selling in one he gains 30% and on the
other he loses 25%. What is his gain or loss percent on the whole transaction?
(a) 5% loss
(b) 2.5% loss
(c) 5% profit
(d) 2.5% profit
(e) 4% profit
Q10. A metal cube of edge 12 cm is melted and formed into three smaller cubes. If the edges of two smaller
cubes are 6 cm and 8 cm, then find the edge of the third smaller cube.
(a) 10 cm
(b) 14 cm
(c) 12 cm
(d) 16 cm
(e) 8 cm
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Directions (11-15): What will come in place of question mark (?) in the following no. series? Q11. 4, 1, 0.5, 0.5, 1, ?
(a) 4 (b) 5 (c) 6 (d) 4.5 (e) 5.5 Q12. 6, 9, 18, 45, 126, ?
(a) 396 (b) 369 (c) 362 (d) 364 (e) 352 Q13. 2, 4.5, 9.5, 19.5, 39.5, ? (a) 75.5 (b) 77.5 (c) 79.5 (d) 83.5 (e) 69.5 Q14. 677, 785, 901, 1025, ? , 1297 (a) 1162 (b) 1157 (c) 1297 (d) 1264 (e) 1257 Q15. 1, 4, 15, 64, 325, ? (a) 1856 (b) 1844 (c) 1952 (d) 1956 (e) 1786 Q16. A and B can do a job in 15 days and 10 days, respectively. They began the work together but A leaves after some days and B finished the remaining job in 5 days. After how many days did A leave? (a) 2 days (b) 3 days (c) 1 days (d) 4 days (e) 8 days
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Q17. 60 kg of an alloy X is mixed with 100 kg of alloy Y. If alloy X has lead and tin in the ratio 3 : 2
and alloy Y has tin and copper in the ratio 1 : 4, then the amount of tin in the new alloy is
(a) 36 kg
(b) 44 kg
(c) 53 kg
(d) 80 kg
(e) 85 kg
Q18. A barrel contains a mixture of wine and water in the ratio 3 : 1. How much fraction of the
mixture must be drawn off and substituted by water so that the ratio of wine and water in the
resultant mixture in the barrel becomes 1 : 1?
(a) 1
4
(b) 1
3
(c) 2
3
(d) 3
2
(e) 3
5
Q19. A and B can do piece of work in 30 days while B and C can do the same work in 24 days and
C and A in 20 days. They all work together for 10 days then B and C leave. How many days more
will A take to finish the work?
(a) 18 days
(b) 24 days
(c) 30 days
(d) 36 days
(e) 28 days
Q20. A boat while travelling upstream covers a distance of 18 km at the speed of 3 km/h, whereas
while travelling downstream it covers the same distance at a speed of 9 km/h. What is the speed of
the boat in still water?
(a) 3 km/h
(b) 5 km/h
(c) 7 km/h
(d) Cannot be determined
(e) 6 km/h
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Directions (21-25): Simplify the following questions and find the value of (?).
Q21. (252 ÷ 21 × 12) ÷ ? = 16
(a) 11
(b) 9
(c) 8
(d) 13
(e) 17
Q22. 36865 + 12473 + 21045 – 44102 =?
(a) 114485
(b) 28081
(c) 26281
(d) 114845
(e) 79821
Q23. (21.6)² ÷ (– 7.2)² × ? = 15483.36 – 15276.09
(a) 23.03
(b) 23.3
(c) 32.03
(d) 32.3
(e) 42.3
Q24. 348 ÷ 29 × 15 + 156 = (?)³ + 120
(a) 12
(b) 6
(c) 36
(d) 9
(e) 13
𝐐𝟐𝟓. (𝟐√𝟑𝟗𝟐 – 𝟐𝟏) + (√𝟖– 𝟕)𝟐
= (? )𝟐
(a) 6
(b) 4
(c) 12
(d) 2
(e) 8
Q26. 46% of 450 +? % of 19.07 = 359.56
(a) 795
(b) 805
(c) 815
(d) 800
(e) 820
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Q27. (? )𝟒 ÷ 𝟐𝟕 = 𝟐𝟒𝟑 (a) 8 (b) 12 (c) 9 (d) 11 (e) 15
Q28. 𝟐𝟐
𝟑+ 𝟑
𝟑
𝟕× 𝟒
𝟏
𝟔÷ 𝟕
𝟏
𝟕=?
(a) 17
8
(b) 42
3
(c) 41
3
(d) 82
3
(e) 31
4
Q29. 0.03 × 0.01 – 0.003 ÷ 100 + 0.03 =? (a) 0.03027 (b) 0.0327 (c) 0.3027 (d) 1.03027 (e) 0.003027 Q30. 17 × 25 – 240 +? ÷ 41 = 354 (a) 6299 (b) 6929 (c) 9629 (d) 7129 (e) 6992 Directions (31-35): The following line graph shows the production of pencils of two companies HB and Class mate during five different years. Study the graph carefully and answer the related questions.
32
48
60
40
54
36
54
30
56
72
0
10
20
30
40
50
60
70
80
2010 2011 2012 2013 2014
Pro
du
ctio
n o
f p
enci
ls (
in
tho
usa
nd
s)
HB Classmate
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Q31. What is the average no. of HB pencils produced throughout all the years?
(a) 48,900
(b) 44,800
(c) 46,800
(d) 46,200
(e) 44,650
Q32. If cost price of one class mate pencil in 2011 is Rs. 8 and class mate company made 75% profit
as a whole in the same year then find the selling price of one class mate pencil.
(a) Rs. 16
(b) Rs. 14
(c) Rs. 12
(d) Rs. 10
(e) Rs. 18
Q33. The production of HB pencils in the years 2010, 2012 and 2014 together is approximately what
percent of total classmate pencils produced in the years 2011, 2013 and 2014 together?
(a) 92%
(b) 72%
(c) 86%
(d) 80%
(e) Can’t be determined
Q34. If 10% class mate pencils out of total class mate pencils produced during all the years
together found to be defective and company made a net profit of 20% on each pencil of the
remaining non-defective pencils by selling at the rate of Rs.12 per piece then find overall
profit/loss to the classmate company. (Production cost of pencil in every year is same)
(a) Rs. 1,98,400
(b) Rs. 1,94,400
(c) Rs. 1,89,400
(d) Rs. 1,96,400
(e) Rs. 1,94,800
Q35. What is the difference between total pencils produced by
the two companies throughout all the years together?
(a) 16,000
(b) 14,000
(c) 12,500
(d) 14,400
(e) 16,600
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Solutions
S1. Ans.(b)
Sol. Let the age of father is x and age of son is y.
So, as per question
x – 3y = 3 ……….(i)
x + 3 – 2 (y + 3) = 10
or x – 2y = 13 ……….(ii)
From (i) and (ii) we get
y = 10, x = 33
S2. Ans.(b)
Sol. Given: Average yield per year per tree is 100
⇒ 100 =(𝑥 + 2)60 + 120𝑥 + (𝑥 − 2) × 180
(𝑥 + 2) + 𝑥 + 𝑥 − 2
⇒ 100 =60𝑥 + 120 + 120𝑥 + 180𝑥 − 360
3𝑥
⇒ 300𝑥 = 360𝑥 − 240
⇒ 60𝑥 = 240
⇒ 𝑥 = 4
S3. Ans.(d)
Sol. Let the speed of the train be x m/s
According to the question,
(x + 10) × 12 = (x + 20) × 10
⇒ 6𝑥 + 60 = 5𝑥 + 100
⇒ 𝑥 = 100 − 60 = 40 𝑚/𝑠
∴ Length of the train = (𝑥 + 10) × 12
= (40 + 10) × 12 = 600 metre
S4. Ans.(b)
Sol. Let the speed of slower train be x kmph
Then, speed of faster train = (x + 7) kmph
As the trains are moving in opposite directions:
Relative speed = x + (x + 7) = (2x + 7) kmph
Time taken = Distance travelled
Relative speed⇒ 6 =
138
(2𝑥+7)= 2𝑥 + 7 =
138
6
⇒ 2𝑥 + 7 = 23 ⇒ 2𝑥 = 23 − 7
∴ 𝑥 =16
2= 8 kmph
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S5. Ans.(a)
Sol. Total profit – Remuneration = Balance profit.
This balance profit is divided in proportion to their investments
= Balance profit of Ankit
Balance profit of Aadarsh
=Investment Ankit
Investment Aadarsh
⇒360 − 20 × 12
Balance profit of Aadarsh=
4000
3000=
4
3
(Since remuneration of Ankit is Rs. 20 per month)
⇒ Balance profit of Aadarsh
= 3 ×120
4= Rs. 90
Since Aadarsh does not get any remuneration, hence Aadarsh receives Rs. 90 at the end of the years.
S6. Ans.(a)
Sol. Total of maximum marks of all subjects = 105 × 5 = 525
80% of 525 = 525×80
100= 420
Obtained marks of four subjects (Hindi, Sanskrit, Mathematics and English) = 89 + 92 + 98 + 81 = 360
So, the obtained marks in Science = 420 – 360 = 60
S7. Ans.(c)
Sol. First part = Rs. x and second part = Rs. y.
∴𝑥 × 80
100=
𝑦 × 60
100+ 3
⇒4𝑥
5=
3𝑦
5+ 3
⇒ 4𝑥 − 3𝑦 = 15 ...(i)
Again, 4𝑦
5=
9𝑥
10+ 6
⇒ 8𝑦 = 9𝑥 + 60
8𝑦 − 9𝑥 = 60
By equation (i) × 8 + (ii) × 3,
32𝑥 − 24𝑦 = 120
24𝑦 − 27𝑥 = 180
5x = 300 ⇒ x = 60
From equation (i)
4 × 60 – 3y = 15
⇒ 3𝑦 = 240 − 15 = 225
⇒ 𝑦 =225
3= 75
∴ Required number = x + y = 60 + 75 = 135
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S8. Ans.(d)
Sol. Let the initial expenses on rice, fish and oil be Rs. 12x, Rs. 17x and Rs. 3x respectively.
∴ Total expenditure = Rs. (12𝑥 + 17𝑥 + 3𝑥)
= Rs. 32x
After increase,
Expenditure on rice = 120
100× 12𝑥
= Rs. 14.4x
Expenditure of fish = 130
100× 17𝑥
= Rs. 22.1x
Expenditure on oil = 150
100× 3𝑥 = 𝑅𝑠. 4.5𝑥
Total expenditure = Rs. (14.4x + 22.1x + 4.5x) = Rs. 41x
Increase = Rs. (41x – 32x) = Rs. 9x
∴ Percentage increase = 9𝑥
32𝑥× 100
=225
8= 28
1
8%
S9. Ans.(d)
Sol. CP1 = CP2 = Rs. 1800
SP1 =1800×130
100= Rs. 2340
SP2 =1800×75
100= Rs. 1350
Total CP = Rs. 3600
Total SP = Rs. 3690
Profit % = 90
3600× 100 = 2.5%
S10. Ans.(a)
Sol. Let edge of third smaller cube is a then
𝑎3 + 83 + 63 = 123
⟹ 𝑎3=1000
⟹ a = 10 cm
S11. Ans.(a)
Sol. Series is
×0.25, ×0.5, ×1, ×2, ×4
S12. Ans.(b)
Sol. Series is +31, +32, +33, +34, +35
∴ ? = 126 + 243
= 369
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S13. Ans.(c)
Sol. Series is +2.5, +5, +10, +20, +40
∴ ? = 39.5 + 40
= 79.5
S14. Ans.(b)
Sol. Series is
26² + 1 = 677
28² + 1 = 785
30² + 1 = 901
32² + 1 = 1025
34² + 1 = 1157
36² + 1 = 1297
OR
S15. Ans.(d)
Sol. Series is ×2+2, ×3+3, ×4+4, ×5+5, ×6+6
∴ ? = 325 × 6 + 6 = 1956
S16. Ans. (b)
Sol. (A+B)’s one day’s work = 1
15 +
1
10
= 1
6
Let A leaves after x days
∴ Remaining work = 1 – 𝑥
6
= (6–x
6 )
Now,
10 (6–𝑥
6) = 5
⇒ x = 3 days
S17. Ans. (b)
Sol. Amount of tin in new allay
= 2
5 × 60 +
1
5 ×100
= 44 kg
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S18. Ans.(b)
Sol.
⇒ 1
3
S19. Ans.(a)
Sol. LCM of 30, 24, 20 is 120
A + B = 30 days 4 unit/day
B + C = 24 days 5 unit/day
A + C = 20 days 6 unit/day
2(A + B + C) = 15
Or A + B + C = 15
2= 7.5 unit/day
∴ ‘A’ does = 7.5 – 5 = 2.5 unit/day
∴ Work done by A + B + C in 10 days = 10 × 7.5 = 75 units
Remaining work = 120 – 75 = 45 unit
∴ Time required by A to complete remaining work = 45
2.5= 18 days
∴ 18 days more
S20. Ans.(e)
Sol. speed of boat in still water =1
2(9 + 3) = 6 km/h
S21. Ans.(b)
Sol.
? =144
16= 9
S22. Ans.(c)
Sol. ? = 26,281
S23. Ans.(a)
Sol. 9 ×? = 207.27
⇒ ? = 23.03
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S24. Ans.(b)
Sol. (?)³ = 180 + 156 – 120 = 216
⇒ ? = 6
S25. Ans.(a)
Sol. (?)² = 2 × 7√8 – 21 + 8 + 49 – 14√8
= 57 – 21
= 36
∴ ? = ±6
S26. Ans.(d)
Sol. ?
100× 19.07 = 359.56 – 207
? =152.56 × 100
19.07
? = 800
S27. Ans.(c)
Sol. (?)⁴ = 243 × 27
(?)⁴ = (9) ⁴
⇒ ? = 9
S28. Ans.(b)
Sol.
? =8
3+
24
7×
25
6×
7
50
=8
3+ 2
= 42
3
S29. Ans.(a)
Sol. ? = 0.0003 – 0.00003 + 0.03
= 0.03027
S30. Ans.(b)
Sol. ?
41= 354 – 425 + 240
⇒ ? = 41 × 169
⇒ ? = 6929
S31. Ans.(c)
Sol. Required average = 1
5× (32 + 48 + 60 + 40 + 54) × 1000
= 46,800
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S32. Ans.(b)
Sol. S.P. of one class mate pencil
S.P. =54000×8×175
54000×100
= Rs. 14
S33. Ans.(d)
Sol. The production of HB pencils in the years 2010, 2012 and 2014 together
= (32 + 60 + 54) thousand
= 146 thousand
Production of class mate pencils in the years 2011, 2013 and 2014 together
= (54 + 56 + 72) thousand
= 182 thousand
∴ Required percentage = 146
182× 100
= 80.21%
S34. Ans.(a)
Sol. Total non-defective pencils = 90
100× 248000
= 2,23,200
∴ Production Cost of one pencil = 12 × 100
120= Rs. 10
∴ Total selling price = 2,23,200 × 12
= 26,78,400
Total production cost price = 2,48,000 × 10
= 24,80,000
∴ Overall profit/loss = 26,78,400 – 24,80,000
= Rs. 1,98,400
S35. Ans.(b)
Sol. Required difference
= (36 + 54 + 30 + 56 + 72) − (32 + 48 + 60 + 40 + 54)
= (248 − 234) thousand
= 14,000
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