( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

Embed Size (px)

Citation preview

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    1/188

    P a r t I

    A P P L I C A T I O N S O F L I N E A R

    A L G E B R A

    I N T R O D U C T I O N

    T h i s c o u r s e \ A p p l i c a t i o n s o f L i n e a r A l g e b r a " i s b a s e d o n t h e l e c t u r e s

    g i v e n b y t h e a u t h o r t o p o s t g r a d u a t e s t u d e n t s a t T a l l i n n T e c h n i c a l U n i v e r -

    s i t y . O u r a i m w a s t o a c q u a i n t t h e s t u d e n t s w i t h t h e l i n e a r a l g e b r a p a c k a g e s

    L I N P A C K , E I S P A C K a n d L A P A C K , a n d w i t h t h e t h e o r e t i c a l f u n d a m e n t a l s

    o f t h e p a r t s o f t h e p a c k a g e s M A T L A B , M A P L E , M A T H C A D a n d M A T H -

    E M A T I C A r e l a t e d t o l i n e a r a l g e b r a . W e h a v e t r i e d t o e x p l a i n t h e l i n e a r

    a l g e b r a m e t h o d s w h i c h f o r m t h e b a s i s f o r t h e c o m p u t i n g m e t h o d s u s e d i n

    t h e p a c k a g e s . W e w o u l d l i k e t o s t r e s s t h a t t h e a i m o f t h e c o u r s e i s n o t t o

    w o r k o u t c o n c r e t e c o m p u t i n g a l g o r i t h m s b u t t o l e a r n a b o u t t h e b a s i c i d e a s

    r e l a t e d t o t h e s e a l g o r i t h m s . I t w i l l b e a s s u m e d t h a t t h e r e a d e r i s a c q u a i n t e d

    w i t h t h e b a s i c i d e a s o f a l g e b r a .

    T h e a u t h o r w o u l d l i k e t o t h a n k A s s o c . P r o f . E l l e n R e d i ( T a l l i n n P e d -

    a g o g i c a l U n i v e r s i t y ) w h o s e h e l p i n t h e i m p r o v e m e n t o f t h e p r e s e n t e d m a t h -

    e r i a l b o t h i n i t s c o n t e n t s a n d i t s f o r m h a s b e e n e n o r m o u s . M a n y o f t h e

    e x a m p l e s a n d p r o b l e m s w e r e p r e p a r e d b y s t u d e n t s K r i s t i i n a K r u s p a n , K a d r i

    M i k k , R e e n a P r i n t s ( T a l l i n n P e d a g o g i c a l U n i v e r s i t y ) , A n d r e i F i l o n o v , D m i t r i

    T s e l u i k o ( T a r t u U n i v e r s i t y ) J u h a n - P e e p E r n i t s a n d H e i k i H i i s j a r v ( T a l l i n n

    T e c h n i c a l U n i v e r s i t y ) w i t h i n t h e f r a m e w o r k o f t h e T E M P U S - p r o j e c t d u r i n g

    t h e i r s t a y a t T a m p e r e U n i v e r s i t y o f T e c h n o l o g y i n J u n e , 1 9 9 7 .

    T h e n u m b e r s o f t h e i r e x a m p l e s a n d p r o b l e m s a r e m a r k e d b y a n a s t e r i s k

    \ * " .

    T h e m a t h e r i a l i s b a s e d o n t h e m o n o g r a p h s o f G . H . G o l u b a n d C . F . V a n

    L o a n ( 1 9 9 6 ) , a n d G . S t r a n g ( 1 9 8 8 ) .

    I h o p e t h a t t h e c o u r s e w i l l h e l p t h e r e a d e r i n t e r e s t e d i n a p p l i c a t i o n s o f

    l i n e a r a l g e b r a m o r e t o u s e t h e l i n e a r a l g e b r a p a c k a g e s m o r e e e c t i v e l y .

    A u t h o r .

    1

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    2/188

    1 F U N D A M E N T A T I O N S O F L I N E A R A L -

    G E B R A

    1 . 1 V e c t o r s

    1 . 1 . 1 V e c t o r S p a c e s

    O n e o f t h e f u n d a m e n t a l c o n c e p t s o f l i n e a r a l g e b r a i s t h a t o f v e c t o r s p a c e .

    A t t h e s a m e t i m e i t i s o n e o f t h e m o r e o f t e n u s e d c o n c e p t s o f a l g e b r a i c

    s t r u c t u r e i n m o d e r n m a t h e m a t i c s . F o r e x a m p l e , m a n y f u n c t i o n s e t s s t u d i e d

    i n m a t h e m a t i c a l a n a l y s i s a r e w i t h r e s p e c t t o t h e i r a l g e b r a i c p r o p e r t i e s v e c t o r

    s p a c e s . I n a n a l y s i s t h e n o t i o n \ l i n e a r s p a c e " i s u s e d i n s t e a d o f t h e n o t i o n

    \ v e c t o r s p a c e " .

    D e n i t i o n 1 . 1 . 1 : A s e t X i s c a l l e d a v e c t o r s p a c e o v e r t h e n u m b e r e l d K

    i f t o e v e r y p a i r ( x y ) o f e l e m e n t s o f X t h e r e c o r r e s p o n d s a s u m x + y 2 X ,

    a n d t o e v e r y p a i r ( x ) w h e r e 2 K a n d x 2 X , t h e r e c o r r e s p o n d s a n

    e l e m e n t x 2 X , w i t h t h e p r o p e r t i e s 1 - 8 :

    1 . x + y = y + x ( c o m m u t a b i l i t y o f a d d i t i o n )

    2 . x + ( y + z ) = ( x + y ) + z ( a s s o c i a t i v i t y o f a d d i t i o n )

    3 . 9 0 2 X : 0 + x = x ( e x i s t e n c e o f n u l l e l e m e n t )

    4 .

    8x

    2X

    ) 9 ;x

    2X : x + (

    ;x ) = 0 ( e x i s t e n c e o f t h e i n v e r s e

    e l e m e n t )

    5 . 1

    x = x ( u n i t a r i s m )

    6 . ( x ) = ( ) x ( a s s o c i a t i v i t y w i t h r e s p e c t t o n u m b e r m u l t i p l i c a t i o n )

    7 . ( x + y ) = x + y ( d i s t r i b u t i v i t y w i t h r e s p e c t t o v e c t o r a d d i t i o n )

    8 . ( + ) x = x + x ( d i s t r i b u t i v i t y w i t h r e s p e c t t o n u m b e r a d d i t i o n ) .

    T h e p r o p e r t i e s 1 - 8 a r e c a l l e d t h e v e c t o r s p a c e a x i o m s . A x i o m s 1 - 4 s h o w

    t h a t X i s a c o m m u t a t i v e g r o u p o r a n A b e l i a n g r o u p w i t h r e s p e c t t o v e c t o r

    a d d i t i o n . T h e s e c o n d c o r r e s p o n d e n c e i s c a l l e d m u l t i p l i c a t i o n o f t h e v e c t o r b y

    a n u m b e r , a n d i t s a t i s e s a x i o m s 5 - 8 . E l e m e n t s o f a v e c t o r s p a c e a r e c a l l e d

    v e c t o r s . I f K = R , t h e n o n e s p e a k s o f a r e a l v e c t o r s p a c e , a n d i f K = C ,

    t h e n o f a c o m p l e x v e c t o r s p a c e . I n s t e a d o f t h e n o t i o n \ v e c t o r s p a c e " w e s h a l l

    u s e t h e a b b r e v i a t i v e \ s p a c e " .

    2

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    3/188

    E x a m p l e 1 . 1 . 1 . L e t u s c o n s i d e r t h e s e t o f a l l n 1 ; m a t r i c e s w i t h r e a l

    e l e m e n t s :

    X = f x : x =

    2

    6

    6

    4

    1

    .

    .

    .

    n

    3

    7

    7

    5

    i

    2 R g :

    T h e s u m o f t w o m a t r i c e s w e d e n e i n t h e u s u a l w a y b y t h e a d d i t i o n o f t h e

    c o r r e s p o n d i n g e l e m e n t s . B y m u l t i p l y i n g t h e m a t r i x b y a r e a l n u m b e r w e

    m u l t i p l y a l l e l e m e n t s o f t h e m a t r i x b y t h i s n u m b e r . T h e s i m p l e c h e c k w i l l

    s h o w t h a t c o n d i t i o n s 1 - 8 a r e s a t i s e d . F o r e x a m p l e , l e t u s c h e c k c o n d i t i o n s

    3 a n d 4 . W e c o n s t r u c t

    0 =

    2

    6

    6

    4

    0

    .

    .

    .

    0

    3

    7

    7

    5

    ;x =

    2

    6

    6

    4

    ;

    1

    .

    .

    .

    ;

    n

    3

    7

    7

    5

    :

    A s

    0 + x =

    2

    6

    6

    4

    0

    .

    .

    .

    0

    3

    7

    7

    5

    +

    2

    6

    6

    4

    1

    .

    .

    .

    n

    3

    7

    7

    5

    =

    2

    6

    6

    4

    0 +

    1

    .

    .

    .

    0 +

    n

    3

    7

    7

    5

    =

    2

    6

    6

    4

    1

    .

    .

    .

    n

    3

    7

    7

    5

    = x

    t h e e l e m e n t 0 s a t i s e s c o n d i t i o n 3 f o r a r b i t r a r y x 2 X , a n d t h u s i t i s t h e

    n u l l e l e m e n t o f t h e s p a c e X . F o r t h e e l e m e n t ; x

    x + ( ; x ) =

    2

    6

    6

    4

    1

    .

    .

    .

    n

    3

    7

    7

    5

    +

    2

    6

    6

    4

    ;

    1

    .

    .

    .

    ;

    n

    3

    7

    7

    5

    =

    2

    6

    6

    4

    1

    ;

    1

    .

    .

    .

    n

    ;

    n

    3

    7

    7

    5

    =

    2

    6

    6

    4

    0

    .

    .

    .

    0

    3

    7

    7

    5

    = 0

    i . e . , c o n d i t i o n 4 i s s a t i s e d . M a k e s u r e o f t h e v a l i t i d y o f t h e r e m a i n i n g

    c o n d i t i o n s 1 - 2 a n d 5 - 8 .

    T h e v e c t o r s p a c e i n e x a m p l e 1 . 1 . 1 i s c a l l e d a n n - d i m e n s i o n a l r e a l a r i t h -

    m e t i c a l s p a c e o r i n s h o r t R

    n

    . D e c l a r i n g t h e v e c t o r x o f t h e s p a c e R

    n

    w e o f t e n

    u s e t h e t r a n s p o s e d m a t r i x

    x =

    h

    1

    : : :

    n

    i

    T

    :

    I n t h i s p r e s e n t a t i o n w e o f t e n u s e p u n c t u a t i o n m a r k s ( c o m m a , s e m i c o l o n ) t o

    s e p a r a t e t h e c o m p o n e n t s o f t h e v e c t o r , f o r e x a m p l e

    x =

    h

    1

    : : :

    n

    i

    T

    :

    3

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    4/188

    E x a m p l e 1 . 1 . 1 .

    L e t U b e a s e t t h a t c o n s i s t s o f a l l p a i r s o f r e a l n u m b e r s

    a = (

    1

    2

    ) b = (

    1

    2

    ) : : : W e d e n e a d d i t i o n a n d m u l t i p l i c a t i o n b y a

    s c a l a r i n U a s f o l l o w s :

    a + b = ( (

    3

    1

    +

    3

    1

    )

    1 = 3

    (

    3

    2

    +

    3

    2

    )

    1 = 3

    )

    a = (

    1

    2

    ) :

    I s t h e s e t U a v e c t o r s p a c e ?

    P r o p o s i t i o n 1 . 1 . 1 . L e t X b e a v e c t o r s p a c e . F o r a r b i t r a r y v e c t o r s

    x y 2 X a n d n u m b e r 2 K t h e f o l l o w i n g a s s e r t i o n s a n d e q u a l i t i e s a r e v a l i d :

    t h e n u l l v e c t o r 0 o f t h e v e c t o r s p a c e X i s u n i q u e

    t h e i n v e r s e v e c t o r ; x o f e a c h x 2 X i s u n i q u e

    t h e u n i q u e n e s s o f t h e i n v e r s e v e c t o r a l l o w s t o d e n e t h e o p e r a t i o n o f

    s u b t r a c t i o n b y

    x ; y

    d e f

    = x + ( ; y )

    x = y , x ; y = 0

    0 x = 0 8 x 2 X

    0 = 0 8 2 K

    ( ; 1 ) x = ; x

    x = 0 , ( = 0 _ x = 0 ) :

    B e c o m e c o n v i n c e d o f t h e t r u e n e s s o f t h e s e a s s e r t i o n s ! 2

    E x a m p l e 1 . 1 . 2 . L e t u s c o n s i d e r t h e s e t o f a l l ( m n ) ; m a t r i c e s w i t h

    c o m p l e x e l e m e n t s . T h e s u m o f t h e s e m a t r i c e s w i l l b e d e n e d b y t h e a d d i t i o n

    o f t h e c o r r e s p o n d i n g e l e m e n t s o f t h e m a t r i c e s . B y m u l t i p l y i n g t h e m a t r i x b y

    a c o m p l e x n u m b e r o n e w i l l m u l t i p l y b y t h i s n u m b e r a l l t h e e l e m e n t s o f t h e

    m a t r i x . W e l e a v e t h e c h e c k t h a t a l l c o n d i t i o n s 1 - 8 a r e s a t i s e d t o t h e r e a d e r .

    T h i s v e c t o r s p a c e o v e r t h e c o m p l e x n u m b e r e l d C w i l l b e d e n o t e d C

    m n

    : I f

    w e c o n n e o u r s e l v e s t o r e a l m a t r i c e s , t h e n w e s h a l l g e t a v e c t o r s p a c e R

    m n

    o v e r t h e n u m b e r e l d R : T h e s p a c e C

    m 1

    w i l l b e i d e n t i e d w i t h t h e s p a c e

    C

    m

    a n d t h e s p a c e R

    m 1

    w i t h t h e s p a c e R

    m

    :

    4

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    5/188

    E x a m p l e 1 . 1 . 3 . T h e s e t F ] o f a l l f u n c t i o n s x : ] ! R i s a

    v e c t o r s p a c e ( p r o v e ! ) o v e r t h e n u m b e r e l d R i f

    ( x + y ) ( t )

    d e f

    = x ( t ) + y ( t )

    8t

    2 ]

    a n d

    ( x ) ( t )

    d e f

    = x ( t ) 8 t 2 ] :

    1 . 1 . 2 S u b s p a c e s o f t h e V e c t o r S p a c e

    D e n i t i o n 1 . 2 . 1 . T h e s e t W o f v e c t o r s o f t h e v e c t o r s p a c e X ( o v e r t h e

    e l d K ) t h a t i s a v e c t o r s p a c e w i l l r e s p e c t t o v e c t o r a d d i t i o n a n d m u l t i p l i c a -

    t i o n b y a n u m b e r d e n e d i n t h e v e c t o r s p a c e X , i s c a l l e d a s u b s p a c e o f t h e

    v e c t o r s p a c e X a n d d e n o t e d W X :

    P r o p o s i t i o n 1 . 2 . 1 : T h e s e t W o f v e c t o r s o f t h e v e c t o r s p a c e X i s a

    s u b s p a c e o f t h e v e c t o r s p a c e X i f o r e a c h t w o v e c t o r s x y 2 W a n d e a c h

    n u m b e r 2 K v e c t o r s x + y a n d x b e l o n g t o t h e s e t W .

    P r o o f . N e c e s s i t y i s o b v i o u s . T o p r o v e s u c i e n c y , w e h a v e t o s h o w t h a t i n

    o u r c a s e c o n d i t i o n s 1 - 8 f o r a v e c t o r s p a c e a r e s a t i s e d . L e t u s c h e c k c o n d i t i o n

    1 . L e t x y 2 W X : B y a s s u m p t i o n , x + y 2 W X . A s X i s a v e c t o r

    s p a c e , t h e n f o r X a x i o m 1 i s s a t i s e d , a n d t h e n x + y = y + x . T h e r e f o r e ,

    f o r W a x i o m 1 i s s a t i s e d , t o o . L e t u s t e s t t h e v a l i d i t y o f c o n d i t i o n 4 .

    L e t x 2 W X : B y a s s u m p t i o n , ( ; 1 ) x 2 W X : O n t h e o t h e r h a n d , b y

    p r e p o s i t i o n 1 , i n X t h e e q u a l i t y ( ; 1 ) x = ; x : h o l d s . H e n c e t h e i n v e r s e v e c t o r

    ;x b e l o n g s t o s e t W w i t h t h e v e c t o r x , i . e . , c o n d i t i o n 4 i s s a t i s e d . P r o v e

    b y y o u r s e l v e s t h e v a l i d i t y o f c o n d i t i o n s 2 , 3 a n d 5 - 8 . 2

    E x a m p l e 1 . 2 . 1 . T h e v e c t o r s p a c e C ] o v e r R o f a l l f u n c t i o n s c o n t i -

    n o u o s o n ] ( e x a m p l e 1 . 1 . 3 ) i s a s u b s p a c e o f v e c t o r s p a c e F ] : A s t h e

    s u m o f t w o f u n c t i o n s c o n t i n o u o s o n t h e i n t e r v a l , a n d t h e p r o d u c t o f s u c h a

    f u n c t i o n b y a n u m b e r a r e f u n c t i o n s c o n t i n o u o s o n t h i s i n t e r v a l , b y p r o p o s i t i o n

    1 . 2 . 1 , C ] i s a s u b s p a c e o f t h e v e c t o r s p a c e F ] :

    E x a m p l e 1 . 2 . 2 . L e t P

    n

    b e t h e s e t o f a l l p o l y n o m i a l s a

    0

    t

    k

    + a

    1

    t

    k ; 1

    +

    : : : + a

    k ; 1

    t + a

    k

    = x ( k n ) o f a t m o s t d e g r e e n w i t h r e a l c o e c i e n t s . W e

    d e n e a d d i t i o n o f t w o p o l y n o m i a l s a n d m u l t i p l i c a t i o n o f a p o l y n o m i a l b y a

    r e a l n u m b e r i n t h e u s u a l w a y . A s a r e s u l t , w e g e t t h e v e c t o r s p a c e P

    n

    o f

    p o l y n o m i a l s o f a t m o s t d e g r e e n : I f w e d e n o t e b y P

    n

    ] t h e v e c t o r s p a c e o f

    5

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    6/188

    p o l y n o m i a l s o f a t m o s t d e g r e e n d e n e d o n t h e i n t e r v a l ] , t h e n P

    n

    ]

    w i l l b e a s u b s p a c e o f t h e v e c t o r s p a c e C ] :

    E x a m p l e 1 . 2 . 3 .

    L e t u s s h o w t h a t t h e s e t H =

    ( "

    a b

    0 c

    #

    : a b c 2 R

    )

    i s a s u b s p a c e o f t h e m a t r i x v e c t o r s p a c e R

    2 2

    :

    T h e s e t H i s c l o s e d w i t h r e s p e c t t o a d d i t i s m a n d m u l t i p l i c a t i o n b y s c a l a r

    s i n c e

    "

    a b

    0 c

    #

    +

    "

    d e

    0 f

    #

    =

    "

    a + d b + e

    0 c + f

    #

    a n d

    "

    a b

    0 c

    #

    =

    "

    a b

    0 c

    #

    :

    T h u s t h e s e t H i s a s u b s p a c e o f t h e m a t r i x v e c t o r s p a c e R

    2 2

    :

    P r o b l e m 1 . 2 . 1 .

    P r o v e t h a t t h e s e t o f a l l s y m m e t r i c m a t r i c e s f o r m a

    s u b s p a c e o f t h e v e c t o r s p a c e o f a l l s q u a r e m a t r i c e s R

    n n

    :

    P r o p o s i t i o n 1 . 2 . 2 . I f S

    1

    : : : S

    k

    a r e s u b s p a c e s o f t h e v e c t o r s p a c e X ,

    t h e n t h e i n t e r s e c t i o n S = S

    1

    \ S

    2

    \ : : : \ S

    k

    o f t h e s u b s p a c e s i s a s u b s p a c e o f

    t h e v e c t o r s p a c e X :

    P r o v e ! 2

    P r o p o s i t i o n 1 . 2 . 3 . I f S

    1

    S

    k

    a r e s u b s p a c e s o f t h e s p a c e X a n d

    S = f x

    1

    + x

    2

    + : : : + x

    k

    : x

    i

    2 S

    i

    ( i = 1 : k ) g

    i s t h e s u m o f t h e s e s u b s p a c e s , t h e n S i s a s u b s p a c e o f X :

    D e n i t i o n 1 . 2 . 2 . I f e a c h x 2 S c a n b e e x p r e s s e d u n i q u e l y i n t h e f o r m

    x = x

    1

    + x

    2

    + : : : + x

    k

    ( x

    i

    2S

    i

    ) t h e n w e s a y t h a t S i s t h e d i r e c t s u m o f

    s u b s p a c e s S

    i

    a n d i t d e n o t e d S = S

    1

    S

    2

    S

    k

    :

    D e n i t i o n 1 . 2 . 3 . E a c h e l e m e n t o f t h e s p a c e X t h a t c a n b e e x p r e s s e d

    a s

    1

    x

    1

    + : : : +

    n

    x

    n

    w h e r e

    i

    2 K i s c a l l e d a l i n e a r c o m b i n a t i o n o f t h e

    e l e m e n t s x

    1

    : : : x

    n

    o f t h e v e c t o r s p a c e X ( o v e r t h e e l d K ) .

    D e n i t i o n 1 . 2 . 4 . T h e s e t o f a l l p o s s i b l e l i n e a r c o m b i n a t i o n o f t h e s e t Z

    i s c a l l e d t h e s p a n o f t h e s e t Z X :

    E x a m p l e 1 . 2 . 4 . L e t X = R

    3

    a n d Z = f 1 1 0 ]

    T

    1 ; 1 0 ]

    T

    g : T h e n

    s p a n Z = f 0 ]

    T

    : 2 R g : P r o v e !

    6

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    7/188

    P r o p o s i t i o n 1 . 2 . 4 . T h e s e t s p a n Z o f t h e s e t Z X i s t h e l e a s t s u b s p a c e

    t h a t c o n t a i n s t h e s e t Z :

    P r o o f . F i r s t , l e t u s p r o v e t h a t s p a n Z i s a s u b s p a c e o f t h e s p a c e X . I t

    i s s u c i e n t , b y p r o p o s i t i o n 1 . 2 . 1 , t o s h o w t h a t s p a n Z i s c l o s e d w i t h r e s p e c t

    t o v e c t o r a d d i t i o n a n d m u l t i p l i c a t i o n o f t h e v e c t o r b y a n u m b e r :

    x y 2 s p a n Z , x =

    n

    X

    i = 1

    i

    u

    i

    y =

    m

    X

    j = 1

    j

    v

    j

    i

    j

    2 K u

    i

    v

    j

    2 Z )

    x + y =

    n

    X

    i = 1

    i

    u

    i

    +

    m

    X

    j = 1

    j

    v

    j

    i

    j

    2 K u

    i

    v

    j

    2 Z , x + y 2 s p a n Z

    2K

    x

    2s p a n Z

    ,

    2K

    x =

    n

    X

    i = 1

    i

    u

    i

    u

    i

    2Z

    i

    2K

    )

    x =

    n

    X

    i = 1

    i

    u

    i

    =

    n

    X

    i = 1

    (

    i

    i

    ) u

    i

    =

    n

    X

    i = 1

    i

    u

    i

    i

    2 K u

    i

    2 Z , x 2 s p a n Z :

    T h u s , s p a n Z i s a s u b s p a c e o f t h e s p a c e X . L e t u s s h o w t h a t s p a n Z i s

    t h e l e a s t s u b s p a c e o f t h e s p a c e X t h a t c o n t a i n s t h e s e t Z : L e t Y b e s o m e

    s u b s p a c e o f t h e s p a c e X f o r w h i c h Z Y : A s Z Y a n d Y i s a s u b s p a c e ,

    t h e a r b i t r a r y l i n e a r c o m b i n a t i o n o f t h e e l e m e n t s o s t h e s e t Z b e l o n g s t o t h e

    s u b s p a c e Y : T h e r e f o r e , s p a n Z a s t h e s e t o f a l l s u c h l i n e a r c o m b i n a t i o n s

    b e l o n g s t o t h e s p a c e Y : 2

    C o r o l l a r y 1 . 2 . 1 . A s u b s e t W o f t h e v e c t o r s p a c e X i s a s u b s p a c e i i t

    c o i n c i d e s w i t h i t s s p a n , i . e . , W X , W = s p a n W :

    P r o b l e m 1 . 2 . 2 .

    D o e s t h e v e c t o r d =

    h

    8 7 4

    i

    T

    b e l o n g t o t h e s u b -

    s p a c e s p a n f a b c g , w h e n

    a =

    h

    1 ; 1 0

    i

    T

    b =

    h

    2 3 1

    i

    T

    c =

    h

    6 9 3

    i

    T

    ?

    7

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    8/188

    1 . 1 . 3 L i n e a r D e p e n d e n c e o f V e c t o r s . B a s i s o f t h e V e c t o r S p a c e .

    D e n i t i o n 1 . 3 . 1 . A s e t o f v e c t o r s

    f x

    1

    : : : x

    k

    g

    i n t h e v e c t o r s p a c e X ( o v e r t h e e l d K ) i s s a i d t o b e l i n e a r l y d e p e n d e n t i f

    9

    1

    : : :

    k

    2 K : j

    1

    j + : : : + j

    k

    j 6= 0

    1

    x

    1

    + : : : +

    k

    x

    k

    = 0 :

    D e n i t i o n 1 . 3 . 2 . A s e t o f v e c t o r s i n t h e s p a c e X ( o v e r t h e e l d K ) i s

    s a i d t o b e l i n e a r l y i n d e p e n d e n t i f i t i s n o t l i n e a r l y d e p e n d e n t .

    E x a m p l e 1 . 3 . 1 .

    L e t u s c h e c k i f t h e s e t U =

    f1 + x x + x

    2

    1 + x

    2

    gi s

    l i n e a r l y i n d e p e n d e n t i n t h e v e c t o r s p a c e P

    n

    ( n

    2 ) o f a l l p o l y n o m i a l s o f a t

    m o s t d e g r e e n w i t h r e a l c o e c i e n t s .

    L e t u s c o n s i d e r t h e e q u a l i t y

    ( 1 + x ) + ( x + x

    2

    ) + ( 1 + x

    2

    ) = 0 :

    I t i s w e l l - k n o w n i n a l g e b r a t h a t a p o l y n o m i a l i s i d e n t i c a l l y n u l l i a l l i t s

    c o e c i e n t s a r e z e r o s . T h u s w e g e t t h e s y s t e m

    8

    >

    :

    + = 0

    + = 0

    + = 0

    :

    T h i s s y s t e m h a s o n l y a t r i v i a l s o l u t i o n . T h e s e t U i s l i n e a r l y i n d e p e n d e n t .

    P r o b l e m 1 . 3 . 1 .

    P r o v e t h a t e a c h s e t o f v e c t o r s t h a t c o n t a i n s t h e n u l l

    v e c t o r i s l i n e a r l y d e p e n d e n t .

    P r o b l e m 1 . 3 . 2 .

    P r o v e t h a t i f t h e c o l u m n - v e c t o r s o f a d e t e r m i n a n t a r e

    l i n e a r l y d e p e n d e n t , t h e n t h e d e t e r m i n a n t e q u a l s 0 .

    D e n i t i o n 1 . 3 . 3 . A s u b s e t V = f x

    i

    1

    : : : x

    i

    k

    g o f t h e s e t U = f x

    1

    : : : x

    n

    g

    o f v e c t o r s o f t h e v e c t o r s p a c e X i s c a l l e d a m a x i m a l l i n e a r l y i n d e p e n d e n t s u b -

    s e t i f V i s l i n e a r l y i n d e p e n d e n t a n d i t i s n o t a p r o p e r s u b s e t o f a n y l i n e a r l y

    i n d e p e n d e n t s u b s e t o f t h e s e t U .

    P r o p o s i t i o n 1 . 3 . 1 . I f V i s a m a x i m a l l i n e a r l y i n d e p e n d e n t s u b s e t o f t h e

    s e t U t h e n s p a n U = s p a n V :

    8

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    9/188

    P r o o f . A s V U s p a n V s p a n U b y t h e d e n i t i o n o f t h e s p a n . T o p r o v e

    o u r a s s e r t i o n , w e h a v e t o s h o w t h a t s p a n V s p a n U : L e t , b y a n t i t h e s i s , e x i s t

    a v e c t o r x o f t h e s u b s p a c e s p a n U t h a t d o e s n o t b e l o n g t o t h e s u b s p a c e

    s p a n V : T h u s , t h e v e c t o r x c a n n o t b e e x p r e s s e d a s a l i n e a r c o m b i n a t i o n o f

    v e c t o r s o f V b u t c a n b e e x p r e s s e d a s a l i n e a r c o m b i n a t i o n o f v e c t o r s o f U

    w h e n a t l e a s t o n e v e c t o r x

    j

    2 U i s u s e d , a t w h i c h x

    j

    =2 V a n d x

    j

    i s n o t

    e x p r e s s a b l e a s a l i n e a r c o m b i n a t i o n o f v e c t o r s o f V : S e t V f x

    j

    g U i s

    l i n e a r l y i n d e p e n d e n t a n d c o n t a i n s t h e s e t V a s a p r o p e r s u b s e t . H e n c e V i s

    n o t t h e m a x i m a l l i n e a r l y i n d e p e n d e n t s u b s e t . W e h a v e g o t a c o n t r a d i c t i o n

    t o t h e a s s u m p t i o n . T h u s s p a n V s p a n U Q . E . D . 2

    D e n i t i o n 1 . 3 . 4 . A s e t B = f x

    i

    g

    i 2 I

    o f v e c t o r s o f t h e v e c t o r s p a c e X

    i s c a l l e d a b a s i s o f t h e v e c t o r s p a c e X i f B i s l i n e a r l y i n d e p e n d e n t a n d e a c h

    v e c t o r x o f t h e s p a c e X c a n b e e x p r e s s e d a s a l i n e a r c o m b i n a t i o n o f v e c t o r s

    o f t h e s e t B x =

    P

    i 2 I

    i

    x

    i

    , w h e r e c o e t i e n t s

    i

    ( i = 1 : n ) a r e c a l l e d

    c o o r d i n a t e s o f t h e v e c t o r x r e l a t i v e t o t h e b a s i s B :

    D e n i t i o n 1 . 3 . 5 . I f t h e n u m b e r o f v e c t o r s i n t h e b a s i s B o f t h e v e c t o r

    s p a c e X i . e . , t h e n u m b e r o f e l e m e n t s o f t h e s e t I i s n i t e , t h e n t h i s n u m b e r

    i s c a l l e d t h e d i m e n s i o n o f t h e v e c t o r s p a c e X a n d d e n o t e d d i m X a n d t h e

    s p a c e X i s c a l l e d a n i t e - d i m e n s i o n a l o r a n i t e - d i m e n s i o n a l v e c t o r s p a c e . I f

    t h e n u m b e r o f v e c t o r s i n t h e b a s i s B o f t h e v e c t o r s p a c e X i s i n n i t e , t h e n

    t h e v e c t o r s p a c e X i s c a l l e d i n n i t e - d i m e n s i o n a l o r a n i n n i t e - d i m e n s i o n a l

    v e c t o r s p a c e .

    P r o p o s i t i o n 1 . 3 . 2 . A s u b s e t B o f t h e v e c t o r s o f t h e v e c t o r s p a c e X i s

    a b a s i s o f t h e s p a c e i i t i s t h e m a x i m a l l i n e a r l y i n d e p e n d e n t s u b s e t .

    E x a m p l e 1 . 3 . 2 . V e c t o r s

    e

    k

    = 0 0 : : : 0

    k ; 1 z e r o s

    1 0 : : : 0

    n ; k z e r o s

    ]

    T

    ( k = 1 : n )

    f o r m a b a s i s i n s p a c e R

    n

    : L e t u s c h e c k t h e v a l i d i t y o f t h e c o n d i t i o n s i n

    d e n i t i o n 1 . 3 . 4 . A s

    n

    X

    k = 1

    k

    e

    k

    = 0 ,

    1

    : : :

    n

    ]

    T

    = 0 : : : 0 ]

    T

    ,

    n

    X

    k = 1

    j

    k

    j = 0

    t h e v e c t o r s y s t e m f e

    k

    g

    k = 1 : n

    i s l i n e a r l y i n d e p e n d e n t , a n d , d u e t o

    1

    : : :

    n

    ]

    T

    =

    n

    X

    k = 1

    k

    e

    k

    9

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    10/188

    a n a r b i t r a r y v e c t o r o f t h e s p a c e R

    n

    c a n b e e x p r e s s e d a s a l i n e a r c o m b i n a t i o n

    o f v e c t o r s e

    k

    :

    P r o b l e m 1 . 3 . 3 . V e c t o r s y s t e m

    ( "

    1 0

    0 0

    #

    "

    0 1

    0 0

    #

    "

    0 0

    1 0

    #

    "

    0 0

    0 1

    # )

    f o r m s a b a s i s i n s p a c e R

    2 2

    :

    E x a m p l e 1 . 3 . 3 . V e c t o r s y s t e m f 1 t t

    2

    : : : t

    n

    g f o r m s a b a s i s i n v e c t o r

    s p a c e P

    n

    o f p o l y n o m i a l s o f a t m o s t d e g r e e n : T r u e l y , t h e s e t f 1 t t

    2

    : : : t

    n

    g

    i s l i n e a r l y i n d e p e n d e n t s i n c e

    x = a

    0

    t

    n

    + a

    1

    t

    n ; 1

    + : : : + a

    n ; 1

    t + a

    n

    = 0 ) a

    k

    = 0 ( k = 1 : n )

    a n d e a c h v e c t o r o f t h e s p a c e P

    n

    ( i . e . , a r b i t r a r y p o l y n o m i a l o f a t m o s t d e g r e e

    n ) c a n b e e x p r e s s e d i n t h e f o r m

    x = a

    0

    t

    n

    + a

    1

    t

    n ; 1

    + : : : + a

    n ; 1

    t + a

    n

    :

    D e n i t i o n 1 . 3 . 6 . T w o v e c t o r s p a c e s X a n d X

    0

    a r e c a l l e d i s o m o r p h i c ,

    i f t h e r e e x i s t a o n e - t o - o n e c o r r e s p o n d e n c e b e t w e e n t h e s p a c e s ' : X ! X

    0

    s u c h t h a t

    1 ) 8 x y 2 X ' ( x + y ) = ' ( x ) + ' ( y )

    2 ) 8 x 2 X 8 2 K ' ( x ) = ' ( x ) :

    P r o p o s i t i o n 1 . 3 . 3 . A l l v e c t o r s p a c e s ( o v e r t h e s a m e n u m b e r e l d K ) o f

    t h e s a m e d i m e n s i o n a r e i s o m o r p h i c .

    1 . 1 . 4 S c a l a r P r o d u c t

    D e n i t i o n 1 . 4 . 1 . A v e c t o r s p a c e X o v e r t h e e l d K i s c a l l e d a s p a c e

    w i t h s c a l a r p r o d u c t i f t o e a c h p a i r o f e l e m e n t s x y 2 X t h e r e c o r r e s p o n d s a

    c e r t a i n n u m b e r h x y i 2 K c a l l e d t h e s c a l a r p r o d u c t o f t h e v e c t o r s x a n d y

    s u c h t h a t f o l l o w i n g c o n d i t i o n ( t h e a x i o m s o f s c a l a r p r o d u c t ) a r e s a t i s e d :

    1 . h x x i 0 h x x i = 0 ) x = 0

    1 0

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    11/188

    2 . h x y i = h y x i w h e n h y x i i s t h e c o n j u g a t e c o m p l e x n u m b e r o f

    h x y i

    3 . h x + y z i = h x z i + h y + z i ( a d d i t i v i t y w i t h r e s p e c t t o t h e r s t f a c -

    t o r )

    4 . h x y i = h x y i ( h o m o g e n e i t y w i t h r e s p e c t t o t h e r s t f a c t o r ) .

    I f X i s a v e c t o r s p a c e o v e r R , t h e n , b y t h e d e n i t i o n , h x y i 2 R a n d

    c o n d i t i o n 1 a c q u i r e s t h e f o r m

    hx y

    i=

    hy x

    i, i . e . , i n t h i s c a s e s c a l a r p r o d u c t

    i s c o m m u t a t i v e .

    E x a m p l e 1 . 4 . 1 . L e t u s d e n e i n C

    n

    t h e s c a l a r p r o d u c t o f v e c t o r s

    x =

    h

    1

    n

    i

    T

    y =

    h

    1

    n

    i

    T

    b y t h e f o r m u l a

    h x y i =

    n

    X

    k = 1

    k

    k

    .

    L e t u s c h e c k t h e v a l i d i t y o f c o n d i t i o n s 1 - 4 : h x x i =

    P

    n

    k = 1

    k

    k

    =

    P

    n

    k = 1

    j

    k

    j

    2

    0

    h x x i =

    P

    n

    k = 1

    j

    k

    j

    2

    = 0 )

    k

    = 0 ( k = 1 : n ) , x = 0

    h x y i =

    P

    n

    k = 1

    k

    k

    =

    P

    n

    k = 1

    k

    k

    =

    P

    n

    k = 1

    k

    k

    = h y x i

    h x + y z i =

    P

    n

    k = 1

    (

    k

    +

    k

    ) &

    k

    =

    P

    n

    k = 1

    k

    &

    k

    +

    P

    n

    k = 1

    k

    &

    k

    = h x z i + h y z i

    h x y i =

    P

    n

    k = 1

    k

    k

    =

    P

    n

    k = 1

    k

    k

    = h x y i :

    E x a m p l e 1 . 4 . 2 . L e t u s c o n s i d e r t h e v e c t o r s p a c e L

    2

    ] o f a l l f u n c t i o n s

    i n t e g r a b l e ( i n L e b e s q u e ' s s e n s e ) o n t h e i n t e r v a l ] : W e d e n e t h e s c a l a r

    p r o d u c t f o r s u c h f u n c t i o n s b y t h e f o r m u l a

    h x y i =

    Z

    x ( t ) y ( t ) d t :

    V e r i f y t h a t a l l t h e a x i o m s 1 - 4 o f s c a l a r p r o d u c t a r e s a t i s e d .

    P r o p o s i t i o n 1 . 4 . 1 . S c a l a r p r o d u c t

    hx y

    ih a s t h e f o l l o w i n g p r o p e r t i e s :

    1 . h x y + z i = h x y i + h x z i ( a d d i t i v i t y w i t h r e s p e c t t o t h e s e c o n d

    f a c t o r )

    2 .

    hx y

    i=

    hx y

    i( c o n j u g a t e h o m o g e n e i t y w i t h r e s p e c t t o t h e s e c o n d

    f a c t o r )

    3 .

    hx 0

    i=

    h0 y

    i= 0

    8x y

    2X

    1 1

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    12/188

    4 . h x y i = j j

    2

    h x y i :

    L e t u s p r o v e t h e s e a s s e r t i o n s :

    h x y + z i = h y + z x i = h y x i + h z x i = h y x i + h z x i = h x y i + h x z i

    h x y i = h y x i = h y x i = h y x i = h x y i h x 0 i = h x 0 x i = 0 h x x i = 0

    h x y i = h x y i = j j

    2

    h x y i : 2

    P r o p o s i t i o n 1 . 4 . 2 ( C a u c h y - S c h w a r t z i n e q u a l i t y ) . F o r a r b i t r a r y v e c t o r s

    x a n d y o f t h e v e c t o r s p a c e w i t h s c a l a r p r o d u c t X i t h o l d s t h e i n e q u a l i t y

    j hx y

    i j

    q

    hx x

    i

    q

    hy y

    i:

    P r o o f . I f h x y i = 0 , t h e n , b y t h e d e n i t i o n o f t h e s c a l a r p r o d u c t ( c o n d i t i o n

    1 ) t h e i n e q u a l i t y h o l d s . N o w l e t u s c o n s i d e r t h e c a s e h x y i 6= 0 : W e d e n e a n

    a u x i l i a r y f u n c t i o n

    ' ( ) = h x + h x y i y x + h x y i y i :

    A s f o r 2 R

    ' ( ) = h x x i + h x y i h x y i + h x y i h y x i +

    2

    j h x y i j

    2

    h y y i =

    =

    2

    j h x y i j

    2

    h y y i + 2 j h x y i j

    2

    + h x x i 0 8 2 R ,

    , j h x y i j

    4

    ; j h x y i j

    2

    h x x i h y y i 0 :

    T h e l a s t i n e q u a l i t y i s e q u i v a l e n t t o t h e i n e q u a l i t y j h x y i j

    2

    h x x i h y y i a n d

    t h i s | t o t h e C a u c h y - S c h w a r t z i n e q u a l i t y . T h e C a u c h y - S c h w a r t z i n e q u a l -

    i t y m a k e s i t p o s s i b l e t o d e n e t h e a n g l e b e t w e e n t w o v e c t o r s b y t h e s c a l a r

    p r o d u c t .

    D e n i t i o n 1 . 4 . 2 . T h e a n g l e b e t w e e n a r b i t r a r y v e c t o r s x a n d y o f t h e

    v e c t o r s p a c e w i t h s c a l a r p r o d u c t X i s d e n e d b y t h e f o r m u l a

    c o s (

    d

    x y ) = h x y i = (

    q

    h x x i

    q

    h y y i ) :

    P r o b l e m 1 . 4 . 1 .

    S h o w t h a t f o r e a c h t w o c o m p l e x v e c t o r s x a n d y t h e

    e q u a l i t y

    h x y i = h x y i :

    h o l d s .

    P r o b l e m 1 . 4 . 2 .

    T h e s c a l a r p r o d u c t i n t h e v e c t o r s p a c e P

    n

    ] o f p o l y -

    n o m i a l s o f a t m o s t d e g r e e n w i t h r e a l c o e c i e n t s o n ] i s d e n e d b y t h e

    f o r m u l a

    hx y

    i=

    Z

    x ( t ) y ( t ) d t :

    1 2

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    13/188

    F i n d t h e a n g l e b e t w e e n t h e p o l y n o m i a l s x = t ; 1 a n d y = t

    2

    + 1 :

    1 . 1 . 5 N o r m o f a V e c t o r

    D e n i t i o n 1 . 5 . 1 . A v e c t o r s p a c e X ( o v e r t h e n u m b e r e l d K ) i s c a l l e d

    a n o r m e d s p a c e , i f t o e a c h v e c t o r x 2 X t h e r e c o r r e s p o n d s a c e r t a i n n o n -

    n e g a t i v e r e a l n u m b e r k x k c a l l e d t h e n o r m o f t h e v e c t o r , s u c h t h a t t h e f o l -

    l o w i n g c o n d i t i o n s a r e s a t i s e d :

    1 . k x k = 0 , x = 0 ( i d e n t i t y a x i o m )

    2 . k x k = j j k x k ( h o m o g e n e i t y a x i o m )

    3 . k x + y k k x k + k y k ( t r i a n g l e i n e q u a l i t y ) .

    D e n i t i o n 1 . 5 . 2 . T h e d i s t a n c e ( x y ) b e t w e e n t w o v e c t o r s i n t h e n o r m e d

    s p a c e X i s d e n e d b y t h e f o r m u l a ( x y ) = k x ; y k :

    P r o p o s i t i o n 1 . 5 . 1 ( H o l d e r i n e q u a l i t y ) . I f 1 < p

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    14/188

    k x k

    1

    = m a x

    1 k n

    j

    k

    j :

    L e t u s v e r i f y t h a t t h e p - n o r m ( 1 p

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    15/188

    L e t u s p r o v e t h e l a s t t h r e e a s s e r t i o n s :

    k x k

    2

    = ( j

    1

    j

    2

    + : : : + j

    n

    j

    2

    )

    1 = 2

    0

    @

    n

    X

    i = 1

    n

    X

    j = 1

    j

    i

    j j

    j

    j

    1

    A

    1 = 2

    =

    = ( (

    n

    X

    k = 1

    j

    i

    j )

    2

    )

    1 = 2

    = k x k

    1

    U s i n g t h e H o l d e r i n e q u a l i t y , w e g e t i n c a s e p = q = 2 t h a t

    k x k

    1

    = j

    1

    j + : : : + j

    n

    j = 1 j

    1

    j + : : : + 1 j

    n

    j = j 1

    1

    j + : : : + j 1

    n

    j

    ( 1

    2

    + : : : + 1

    2

    )

    1 = 2

    (

    2

    1

    + : : : +

    2

    n

    )

    1 = 2

    =

    p

    n k x k

    2

    kx

    k

    1

    = m a x

    1 k n

    j

    k

    j= ( ( m a x

    1 k n

    j

    k

    j)

    2

    )

    1 = 2

    (

    2

    1

    + : : : +

    2

    n

    )

    1 = 2

    =

    kx

    k

    2

    k x k

    2

    = (

    2

    1

    + : : : +

    2

    n

    )

    1 = 2

    ( ( m a x

    1 k n

    j

    k

    j )

    2

    + : : : + ( m a x

    1 k n

    j

    k

    j )

    2

    )

    1 = 2

    =

    = ( n ( m a x

    1 k n

    j

    k

    j )

    2

    )

    1 = 2

    =

    p

    n k x k

    1

    k x k

    1

    = m a x

    1 k n

    j

    k

    j j

    1

    j + : : : + j

    n

    j n m a x

    1 k n

    j

    k

    j = n k x k

    1

    : 2

    P r o p o s i t i o n 1 . 5 . 4 . A s p a c e w i t h s c a l a r p r o d u c t X i s a n o r m e d s p a c e

    w i t h t h e n o r m

    k x k =

    q

    h x x i :

    P r o o f . L e t u s v e r i f y t h e v a l i d i t y o f c o n d i t i o n s 1 - 3 :

    k x k = 0 ,

    q

    h x x i = 0 , h x x i = 0 , x = 0

    k x k =

    q

    h x x i =

    q

    j j

    2

    h x x i = j j

    q

    h x x i = j j k x k

    k x + y k =

    q

    h x + y x + y i =

    q

    h x x i + h x y i + h y x i + h y y i =

    =

    q

    k x k

    2

    + h x y i + h x y i + k y k

    2

    =

    q

    k x k

    2

    + 2 < h x y i + k y k

    2

    q

    k x k

    2

    + 2 j ( x y ) j + + k y k

    2

    q

    k x k

    2

    + 2 k x k k y k + k y k

    2

    q

    ( k x k + k y k )

    2

    = k x k + k y k :

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    16/188

    P r o p o s i t i o n 1 . 5 . 5 . I n t h e n o r m e d s p a c e w i t h s c a l a r p r o d u c t t h e p a r a l -

    l e l o g r a m r u l e :

    kx + y

    k

    2

    +

    kx

    ;y

    k

    2

    = 2 (

    kx

    k

    2

    +

    ky

    k

    2

    ) :

    h o l d s .

    P r o o f . B y t h e i m m e d i a t e c h e c k , w e g e t

    k x + y k

    2

    + k x ; y k

    2

    = h x + y x + y i + h x ; y x ; y i =

    = h x x i + h x y i + h y x i + h y y i + h x x i ; h x y i ; h y x i + h y y i =

    = 2 ( k x k

    2

    + k y k

    2

    ) :

    D e n i t i o n 1 . 5 . 3 . I t i s s a i d t h a t t h e s e q u e n c e f x

    ( k )

    g o f t h e e l e m e n t s o f

    t h e s p a c e C

    n

    c o n v e r g e s w i t h r e s p e c t t o t h e p - n o r m t o t h e e l e m e n t x 2 C

    n

    i f

    l i m

    k ! 1

    x

    ( k )

    ; x

    p

    = 0 :

    I n t h i s c a s e w e s h a l l w r i t e x

    ( k )

    ! x :

    R e m a r k 1 . 5 . 1 . S i n c e a l l t h e p - n o r m s o f t h e s p a c e C

    n

    a r e e q u i v a l e n t ,

    t h i s i m p l i e s t h a t t h e c o n v e r g e n c e o f t h e s e q u e n c e f x

    ( k )

    g w i t h r e s p e c t t o t h e

    - n o r m w i l l y i e l d i t s c o n v e r g e n c e w i t h r e s p e c t t o t h e - n o r m .

    P r o b l e m 1 . 5 . 2 . S h o w t h a t i f x

    2C

    n

    , t h e n l i m

    p ! 1

    kx

    k

    p

    =

    kx

    k

    1

    :

    P r o b l e m 1 . 5 . 3 . S h o w t h a t i f x 2 C

    n

    , t h e n

    k x k

    p

    c ( k

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    17/188

    i s c a l l e d t h e r e l a t i v e e r r o r o f t h e a p p r o x i m a t i o n ( x 6= 0 ) .

    I n c a s e o f t h e 1 ; n o r m t h e r e l a t i v e e r r o r c a n b e c o n s i d e r e d a s a n i n d e x

    o f t h e c o r r e c t s i g n i c a n t d i g i t s . N a m e l y , i f k

    b

    x ; x k

    1

    = k x k

    1

    1 0

    ; k

    t h e n

    t h e g r e a t e s t c o m p o n e n t o f t h e v e c t o r

    b

    x h a s k c o r r e c t s i g n i c a n t d i g i t s .

    E x a m p l e 1 . 5 . 2 . L e t x = 2 : 5 4 3 0 : 0 6 3 5 6 ]

    T

    a n d

    b

    x = 2 : 5 4 1 0 : 0 6 9 3 7 ]

    T

    :

    F i n d "

    a b s

    a n d "

    r e l

    , a n d t h e n t h e n u m b e r o f t h e c o r r e c t s i g n i c a n t d i g i t s

    o f t h e g r e a t e s t c o m p o n e n t o f t h e a p p r o x i m a t i o n

    b

    x b y "

    r e l

    . W e g e t

    b

    x ;

    x = ; 0 : 0 0 2 0 : 0 0 5 8 1 ]

    T

    "

    a b s

    = k

    b

    x ; x k

    1

    = 0 : 0 0 5 8 1 a n d k x k

    1

    = 2 : 5 4 3 a n d

    "

    r e l

    0 : 0 0 2 3 1 0

    ; 3

    ) k = 3 : T h u s t h e g r e a t e s t c o m p o n e n t

    b

    1

    o f

    b

    x h a s

    t h r e e c o r r e c t s i g n i c a n t d i g i t s . A t t h e s a m e t i m e , t h e c o m p o n e n t

    b

    2

    h a s o n l y

    o n e c o r r e c t s i g n i c a n t d i g i t .

    1 . 1 . 6 O r t h o g o n a l V e c t o r s

    D e n i t i o n 1 . 6 . 1 . T h e v e c t o r s x a n d y o f t h e v e c t o r s p a c e w i t h s c a l a r

    p r o d u c t X a r e c a l l e d o r t h o g o n a l i f h x y i = 0 : W e w r i t e x ? y t o i n d i c a t e t h e

    o r t h o g o n a l i t y o f v e c t o r s x a n d y : A v e c t o r x o f t h e v e c t o r s p a c e X i s c a l l e d

    o r t h o g o n a l t o t h e s e t Y X i f x ? y 8 y 2 Y :

    P r o b l e m 1 . 6 . 1 .

    F i n d a l l v e c t o r s t h a t a r e o r t h o g o n a l b o t h t o t h e v e c t o r

    a =

    h

    4 0 6 ; 2 0

    i

    T

    a n d b =

    h

    2 1 ; 1 1 1

    i

    T

    :

    D e n i t i o n 1 . 6 . 2 . T h e s e t s Y a n d Z o f t h e v e c t o r s p a c e X a r e c a l l e d

    o r t h o g o n a l i f y ? z 8 y 2 Y a n d 8 z 2 Z :

    D e n i t i o n 1 . 6 . 3 . A s e q u e n c e f x

    ( k )

    g o f v e c t o r s o f t h e v e c t o r s p a c e w i t h

    s c a l a r p r o d u c t X i s c a l l e d a C a u c h y s e q u e n c e i f f o r a n y > 0 t h e r e i s a

    n a t u r a l n u m b e r n

    0

    s u c h t h a t f o r a l l m 2 N a n d n > n

    0

    j j x

    ( n )

    ; x

    ( n + m )

    j j =

    q

    h x

    ( n )

    ; x

    ( n + m )

    x

    ( n )

    ; x

    ( n + m )

    i < " :

    D e n i t i o n 1 . 6 . 4 . A v e c t o r s p a c e w i t h s c a l a r p r o d u c t X i s c a l l e d c o m -

    p l e t e i f e v e r y C a u c h y s e q u e n c e i s c o n v e r g e n t t o a p o i n t o f t h e s p a c e X .

    D e n i t i o n 1 . 6 . 5 . A v e c t o r s p a c e w i t h c o m p l e x s c a l a r p r o d u c t i s c a l l e d a

    H i l b e r t s p a c e H i f i t t u r n s o u t t o b e c o m p l e t e w i t h r e s p e c t t o t h e c o n v e r g e n c e

    b y t h e n o r m

    kx

    k=

    q

    hx x

    i.

    1 7

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    18/188

    P r o p o s i t i o n 1 . 6 . 1 . T h e s p a c e C

    n

    w i t h t h e s c a l a r p r o d u c t h x y i =

    P

    n

    k = 1

    k

    k

    i s a H i l b e r t s p a c e .

    P r o p o s i t i o n 1 . 6 . 2 . T h e s p a c e L

    2

    ] o f a l l s q u a r e - i n t e g r a b l e f u n c t i o n s

    o n t h e i n t e r v a l ] w i t h t h e s c a l a r p r o d u c t h x y i =

    R

    x ( t ) y ( t ) d t i s a H i l b e r t

    s p a c e .

    P r o p o s i t i o n 1 . 6 . 3 . O r t h o g o n a l i t y o f v e c t o r s i n t h e v e c t o r s p a c e w i t h

    s c a l a r p r o d u c t X h a s t h e f o l l o w i n g p r o p e r t i e s ( 1 - 4 ) :

    1 . x ? x , x = 0

    2 . x ? y , y ? x

    3 . x

    ? fy

    1

    : : : y

    k

    g )x

    ?( y

    1

    + : : : + y

    k

    )

    4 . x ? y ) x ? y 8 2 K

    o r t h o g o n a l i t y o f v e c t o r s i n a H i l b e r t s p a c e h a s a n a d d i t i o n a l p r o p e r t y :

    5 . x ? y

    n

    ( n = 1 2 3 : : : ) y

    n

    ! y ) x ? y :

    L e t u s p r o v e t h e s e a s s e r t i o n s :

    x ? x , h x x i = 0 , x = 0

    x ? y , h x y i = 0 , h y x i = 0 , h y x i = 0 , y ? x

    x

    ? fy

    1

    : : : y

    k

    g ,x

    ?y

    1

    : : :

    x

    ?y

    k

    , hx y

    1

    i= 0

    : : :

    ^ hx y

    k

    i= 0

    )

    ) h x y

    1

    i + : : : + h x y

    k

    i = 0 , h x y

    1

    + : : : + y

    k

    i = 0 , x ? ( y

    1

    + : : : + y

    k

    )

    x ? y , h x y i = 0 , h x y i = 0 8 2 K ,

    , h x y i = 0 8 2 K , x ? y

    x ? y

    n

    8 n 2 N y

    n

    ! y , h x y

    n

    i = 0 ^ k y

    n

    ; y k ! 0 )

    ) h x y

    n

    i = 0 ^ j h x y

    n

    i ; h x y i j = j h x y

    n

    ; y i j k x k k y

    n

    ; y k ! 0 )

    ) h x y i = 0 , x ? y :

    D e n i t i o n 1 . 6 . 6 . T h e o r t h o g o n a l c o m p l e m e n t o f t h e s e t Y

    X i s t h e

    s e t Y

    ?

    o f a l l v e c t o r s o f t h e s p a c e X t h a t a r e o r t h o g o n a l t o t h e s e t Y , i . e . ,

    Y

    ?

    = f x : ( x 2 X ) ( x ? y 8 y 2 Y ) g :

    P r o b l e m 1 . 6 . 2 .

    L e t U = s p a n

    h

    1 0 1

    i

    T

    h

    0 2 1

    i

    T

    R

    3

    :

    F i n d t h e o r t h o g o n a l c o m p l e m e n t o f t h e s e t U :

    1 8

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    19/188

    P r o p o s i t i o n 1 . 6 . 4 . I f X i s a v e c t o r s p a c e w i t h s c a l a r p r o d u c t , x 2 X

    Y X a n d x ? Y t h e n x ? s p a n Y : I f , i n a d d i t i o n , X i s c o m p l e t e , i . e . , i s a

    H i l b e r t s p a c e , t h e n x

    ?s p a n Y :

    P r o o f . B y a s s e r t i o n s 3 a n d 4 o f p r o p o s i t i o n 1 . 6 . 3 , x ? s p a n Y . I f y 2 s p a n Y

    i . e . , 9 y

    n

    2 s p a n Y s u c h t h a t y

    n

    ! y t h e n , d u e t o t h e o r t h o g o n a l i t y x ? y

    n

    a n d a s s e r t i o n 5 o f p r o p o s i t i o n 1 . 6 . 3 , w e g e t x ? y , i . e . , x ? s p a n Y :

    P r o p o s i t i o n 1 . 6 . 5 . T h e o r t h o g o n a l c o m p l e m e n t Y

    ?

    o f t h e s e t Y X i s

    a s u b s p a c e o f t h e s p a c e X : T h e o r t h o g o n a l c o m p l e m e n t Y

    ?

    o f t h e s e t Y H

    i s a c l o s e d s u b s p a c e o f t h e H i l b e r t s p a c e H i . e . , Y

    ?

    i s a s u b s p a c e o f t h e

    s p a c e H t h a t c o n t a i n s a l l i t s b o u n d a r y p o i n t s .

    P r o o f . D u e t o t h e p r o p o s i t i o n 1 . 2 . 1 , i t i s s u c i e n t f o r t h e p r o o f o f t h e

    r s t a s s e r t i o n o f p r o p o s i t i o n 1 . 6 . 5 t o s h o w t h a t Y

    ?

    i s c l o s e d w i t h r e s p e c t t o

    v e c t o r a d d i t i o n a n d s c a l a r m u l t i p l i c a t i o n . I t w i l l f o l l o w f r o m a s s e r t i o n 5 o f

    t h e s a m e p r o p o s i t i o n , i t h o l d s t h e s e c o n d a s s e r t i o n o f p r o p o s i t i o n 1 . 6 . 5 t o o .

    P r o p o s i t i o n 1 . 6 . 6 . I f Y i s a c l o s e d s u b s p a c e o f t h e H i l b e r t s p a c e

    H t h e n e a c h x 2 H c a n b e e x p r e s s e d u n i q u e l y a s t h e s u m x = y + z ,

    y 2 Y z 2 Y

    ?

    :

    C o r o l l a r y 1 . 6 . 1 . I f Y i s a c l o s e d s u b s p a c e o f t h e H i l b e r t s p a c e , t h e n

    t h e s p a c e H c a n b e p r e s e n t e d a s t h e d i r e c t s u m H = L L

    ?

    o f t h e c l o s e d

    s u b s p a c e s L a n d L

    ?

    , a n d ( L

    ?

    )

    ?

    = L :

    D e n i t i o n 1 . 6 . 7 . T h e d i s t a n c e o f t h e v e c t o r x o f t h e H i l b e r t s p a c e H

    f r o m t h e s u b s p a c e Y H i s d e n e d b y t h e f o r m u l a

    ( x Y ) = i n f

    y 2 Y

    k x ; y k :

    P r o p o s i t i o n 1 . 6 . 7 . I f Y i s a c l o s e d s u b s p a c e o f t h e H i l b e r t s p a c e H

    a n d x 2 H , t h e n t h e r e e x i s t s a u n i q u e l y d e n e d y 2 Y s u c h t h a t k x ; y k =

    ( x Y ) :

    D e n i t i o n 1 . 6 . 8 . T h e v e c t o r y i n p r o p o s i t i o n 1 . 6 . 7 i s c a l l e d t h e o r t h o g -

    o n a l p r o j e c t i o n o f x o n t o t h e s u b s p a c e Y .

    D e n i t i o n 1 . 6 . 9 . A v e c t o r s y s t e m S = f x

    1

    : : : x

    k

    g i s c a l l e d o r t h o g o n a l

    i f ( x

    i

    x

    j

    ) = k x

    i

    k

    2

    i j

    w h e r e

    i j

    i s t h e K r o n e c k e r d e l t a . T h e v e c t o r s y s t e m

    S = f x

    1

    : : : x

    k

    g i s c a l l e d o r t h o n o r m a l i f ( x

    i

    x

    j

    ) =

    i j

    .

    E x a m p l e 1 . 6 . 1 . T h e v e c t o r s y s t e m f e

    k

    g ( k = 1 : n ) , w h e r e e

    k

    =

    0 0 : : : 0

    k ; 1 z e r o s

    1 0 : : : 0

    n ; k z e r o s

    ]

    T

    i s o r t h o n o r m a l i n C

    n

    .

    1 9

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    20/188

    E x a m p l e 1 . 6 . 2 . T h e v e c t o r s y s t e m

    f 1 =

    p

    2 ( c o s t ) =

    p

    ( s i n t ) =

    p

    ( c o s 2 t ) =

    p

    ( s i n 2 t ) =

    p

    : : : g

    i s o r t h o n o r m a l i n L

    2

    ; ] :

    E x a m p l e 1 . 6 . 3 . T h e v e c t o r s y s t e m f e x p ( i 2 k t ) g

    k 2 Z

    i s o r t h o n o r m a l i n

    L

    2

    0 1 ] : T r u e l y ,

    ( x

    k

    x

    j

    ) =

    Z

    1

    0

    e x p ( i 2 k t ) e x p ( i 2 j t ) d t =

    Z

    1

    0

    e x p ( i 2 ( k

    ;j ) t ) d t =

    =

    (

    ( e x p ( i 2 ( k ; j ) ) ; 1 ) = ( i 2 ( k ; j ) ) = 0 , k u i k 6= j

    1 a s k = j :

    P r o p o s i t i o n 1 . 6 . 8 . ( G r a m - S c h m i d t o r t h o g o n a l i z a t i o n t h e o r e m ) . I f

    f x

    1

    : : : x

    k

    g i s a l i n e a r l y i n d e p e n d e n t v e c t o r s y s t e m i n t h e v e c t o r s p a c e w i t h

    s c a l a r p r o d u c t H , t h e n t h e r e e x i s t s a n o r t h o n o r m a l s y s t e m f "

    1

    : : : "

    k

    g s u c h

    t h a t s p a n f x

    1

    : : : x

    k

    g = s p a n f "

    1

    : : : "

    k

    g :

    L e t u s p r o v e t h i s a s s e r t i o n b y c o m p l e t e i n d u c t i o n . I n t h e c a s e k = 1 ,

    w e d e n e "

    1

    = x

    1

    = k x

    1

    k a n d , o b v i o u s l y , s p a n f x

    1

    g = s p a n f "

    1

    g : S o w e h a v e

    s h o w n t h e e x i s t e n c e o f t h e i n d u c t i o n b a s e . W e h a v e t o s h o w t h e a d m i s s -

    a b i l y o f t h e i n d u c t i o n s t e p . L e t u s a s s u m e t h a t t h e p r o p o s i t i o n h o l d s f o r

    k = i ; 1 , i . e . , t h e r e e x i s t s a n o r t h o n o r m a l s y s t e m f "

    1

    : : : "

    i ; 1

    g s u c h t h a t

    s p a n f x

    1

    : : : x

    i ; 1

    g = s p a n f "

    1

    : : : "

    i ; 1

    g : N o w w e c o n s i d e r t h e v e c t o r

    y

    i

    =

    1

    "

    1

    + : : : +

    i ; 1

    "

    i ; 1

    + x

    i

    j

    2 K :

    L e t u s c h o o s e t h e c o e c i e n t s

    ( = 1 : i - 1 ) s o t h a t y

    i

    ? "

    ( = 1 : i - 1 ) i . e ,

    ( y

    i

    "

    ) = 0 : W e g e t i

    ;1 c o n d i t i o n s :

    ( "

    "

    ) + ( x

    i

    "

    ) = 0 e h k

    = ; ( x

    i

    "

    ) ( = 1 : i - 1 ) :

    T h u s ,

    y

    i

    = x

    i

    ; ( x

    i

    "

    1

    ) "

    1

    ; : : : ; ( x

    i

    "

    i ; 1

    ) "

    i ; 1

    :

    N o w w e c h o s e "

    i

    = y

    i

    = k y

    i

    k : S i n c e

    "

    2 s p a n f x

    1

    : : : x

    i ; 1

    g ( = 1 : i - 1 )

    w e g e t , b y t h e c o n s t r u c t i o n o f v e c t o r s y

    i

    a n d "

    i

    , "

    i

    2 s p a n f x

    1

    : : : x

    i

    g :

    H e n c e

    s p a n

    f"

    1

    : : : "

    i

    g s p a n

    fx

    1

    : : : x

    i

    g:

    2 0

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    21/188

    F r o m t h e r e p r e s e n t a t i o n o f t h e v e c t o r y

    i

    w e s e e t h a t x

    i

    i s a l i n e a r c o m b i n a t i o n

    o f v e c t o r s "

    1

    : : : "

    i

    :

    T h u s ,

    s p a n f x

    1

    : : : x

    i

    g s p a n f "

    1

    : : : "

    i

    g :

    F i n a l l y ,

    s p a n f x

    1

    : : : x

    i

    g = s p a n f "

    1

    : : : "

    i

    g :

    E x a m p l e 1 . 6 . 4 . G i v e n a v e c t o r s y s t e m f x

    1

    x

    2

    x

    3

    g i n R

    4

    , w h e r e

    x

    1

    = 1 0 1 0 ]

    T

    x

    2

    = 1 1 1 0 ]

    T

    x

    3

    = 0 1 0 1 ]

    T

    :

    F i n d s u c h a n o r t h o g o n a l s y s t e m f "

    1

    "

    2

    "

    3

    g , f o r w h i c h

    s p a n f x

    1

    x

    2

    x

    3

    g = s p a n f "

    1

    "

    2

    "

    3

    g :

    T o a p p l y t h e o r t h o g o n a l i z a t i o n p r o c e s s o f p r o p o s i t i o n 1 . 6 . 8 , w e c h e c k r s t t h e

    s y s t e m f x

    1

    x

    2

    x

    3

    g f o r t h e l i n e a r l y i n d e p e n d e n c e ( o n e c a n o m i t t h i s p r o c e s s ,

    t o o , b e c a u s e t h e s i t u a t i o n w i l l b e c l e a r i n t h e c o u r s e o f t h e o r t h o g o n a l i z a t i o n :

    2

    6

    4

    1 0 1 0

    1 1 1 0

    0 1 0 1

    3

    7

    5

    I I - I

    2

    6

    4

    1 0 1 0

    0 1 0 0

    0 1 0 1

    3

    7

    5

    I I I - I I

    2

    6

    4

    1 0 1 0

    0 1 0 0

    0 0 0 1

    3

    7

    5

    )

    t h e s y s t e m f x

    1

    x

    2

    x

    3

    g i s l i n e a r l y i n d e p e n d e n t . N o w w e n d

    "

    1

    = x

    1

    = k x

    1

    k = 1 =

    p

    2 0 1 =

    p

    2 0 ]

    T

    :

    F o r y

    2

    w e g e t :

    y

    2

    = x

    2

    ; ( x

    2

    "

    1

    ) "

    1

    = 1 1 1 0 ]

    T

    ;

    p

    2 1 =

    p

    2 0 1 =

    p

    2 0 ]

    T

    = 0 1 0 0 ]

    T

    :

    A s k y

    2

    k = 1 "

    2

    = y

    2

    = k y

    2

    k = 0 1 0 0 ]

    T

    : T h e v e c t o r y

    3

    c a n b e e x p r e s s e d i n

    t h e f o r m :

    y

    3

    = x

    3

    ; ( x

    3

    "

    1

    ) "

    1

    ; ( x

    3

    "

    2

    ) "

    2

    =

    = 0 1 0 1 ]

    T

    ;0

    1 =

    p

    2 0 1 =

    p

    2 0 ]

    T

    ;1

    0 1 0 0 ]

    T

    = 0 0 0 1 ]

    T

    :

    T h u s ,

    "

    3

    = y

    3

    = k y

    3

    k = 0 0 0 1 ]

    T

    :

    2 1

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    22/188

    E x a m p l e 1 . 6 . 5 . G i v e n a l i n e a r l y i n d e p e n d e n t v e c t o r s y s t e m f x

    1

    x

    2

    x

    3

    g

    i n L

    2

    ; 1 1 ] , w h e r e x

    1

    = 1 x

    2

    = t a n d x

    3

    = t

    2

    : F i n d a n o r t h o g o n a l s y s t e m

    f"

    1

    "

    2

    "

    3

    g, s u c h t h a t

    s p a n f x

    1

    x

    2

    x

    3

    g = s p a n f "

    1

    "

    2

    "

    3

    g :

    C h e c k t h a t t h e s y s t e m f x

    1

    x

    2

    x

    3

    g i s l i n e a r l y i n d e p e n d e n t . T h e r s t v e c t o r

    i s

    "

    1

    = x

    1

    = k x

    1

    k = 1 =

    p

    2 :

    T h e v e c t o r y

    2

    c a n b e e x p r e s s e d i n t h e f o r m :

    y

    2

    = x

    2

    ; ( x

    2

    "

    1

    ) "

    1

    = t ; (

    Z

    1

    ; 1

    t (

    1

    p

    2

    ) d t ) t = t ; 0 t = t :

    T h u s ,

    "

    2

    = y

    2

    = k y

    2

    k = t =

    s

    Z

    1

    ; 1

    t t d t = t =

    s

    2

    3

    =

    s

    3

    2

    t :

    T h e v e c t o r y

    3

    c a n b e e x p r e s s e d i n t h e f o r m :

    y

    3

    = x

    3

    ; ( x

    3

    "

    1

    ) "

    1

    ; ( x

    3

    "

    2

    ) "

    2

    =

    = t

    2

    ; (

    Z

    1

    ; 1

    t

    2

    (

    1

    p

    2

    ) d t )

    1

    p

    2

    ; (

    Z

    1

    ; 1

    t

    2

    (

    s

    3

    2

    t ) d t )

    s

    3

    2

    t =

    = t

    2

    ;

    1

    2

    2

    3

    ; 0 = t

    2

    ;

    1

    3

    :

    T h e r e f o r e ,

    "

    3

    = y

    3

    = k y

    3

    k = ( t

    2

    ;

    1

    3

    ) =

    s

    Z

    1

    ; 1

    ( t

    2

    ;

    1

    3

    ) ( t

    2

    ;

    1

    3

    ) d t =

    = ( t

    2

    ;

    1

    3

    ) =

    s

    2

    5

    ;

    4

    9

    +

    2

    9

    =

    s

    4 5

    8

    ( t

    2

    ;

    1

    3

    ) =

    3

    2

    s

    5

    2

    ( t

    2

    ;

    1

    3

    ) :

    T h e f u n c t i o n s "

    1

    "

    2

    a n d "

    3

    a r e t h e n o r m e d L e g e n d r e p o l y n o m i a l s o n ; 1 1 ] :

    P r o b l e m 1 . 6 . 3 . S h o w t h a t a v e c t o r s y s t e m f x

    1

    : : : x

    n

    g w i t h p a i r w i s e

    o r t h o g o n a l e l e m e n t s i s l i n e a r l y i n d e p e n d e n t .

    2 2

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    23/188

    1 . 2 M a t r i c e s

    1 . 2 . 1 N o t a t i o n f o r a M a t r i x a n d O p e r a t i o n s w i t h M a t r i c e s

    T h e v e c t o r s p a c e o f a l l m n ; m a t r i c e s w i t h r e a l e l e m e n t s w i l l b e d e n o t e d

    b y R

    m n

    a n d

    A

    2R

    m n

    ,A = ( a

    i k

    ) =

    2

    6

    6

    4

    a

    1 1

    a

    1 n

    .

    .

    .

    .

    .

    .

    a

    m 1

    a

    m n

    3

    7

    7

    5

    a

    i k

    2R :

    T h e e l e m e n t o f t h e m a t r i x A t h a t s t a n d s i n t h e i ; t h r o w a n d k ; t h c o l u m n

    w i l l b e d e n o t e d b y a

    i k

    o r A ( i k ) o r A ]

    i k

    : T h e m a i n o p e r a t i o n s w i t h m a t r i c e s

    a r e f o l l o w i n g :

    t r a n s p o s i t i o n o f m a t r i c e s ( R

    m n

    !R

    n m

    )

    B = A

    T

    , b

    i k

    = a

    a d d i t i o n o f m a t r i c e s ( R

    m n

    R

    m n

    ! R

    m n

    )

    C = A + B , c

    i k

    = a

    i k

    + b

    i k

    m u l t i p l i c a t i o n o f m a t r i c e s b y a n u m b e r ( R R

    m n

    ! R

    m n

    )

    B = A , b

    i k

    = a

    i k

    m u l t i p l i c a t i o n o f m a t r i c e s ( R

    m p

    R

    p n

    ! R

    m n

    )

    C = A B , c

    i k

    =

    p

    X

    j = 1

    a

    i j

    b

    j k

    :

    P r o b l e m 2 . 1 . 1 .

    L e t

    A =

    "

    a c e

    b d f

    #

    B =

    2

    6

    4

    k n

    l p

    m r

    3

    7

    5

    :

    F i n d t h e m a t r i x A B :

    2 3

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    24/188

    P r o b l e m 2 . 1 . 2 .

    L e t

    A =

    2

    6

    6

    6

    6

    6

    6

    6

    6

    6

    6

    6

    6

    4

    1 0 0 0 0

    1 1 0

    .

    .

    .

    0 0

    0 1 1

    .

    .

    .

    0 0

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    0 0

    .

    .

    .

    .

    .

    .

    1 0

    0 0 0 1 1

    3

    7

    7

    7

    7

    7

    7

    7

    7

    7

    7

    7

    7

    5

    2 R

    n n

    :

    F i n d t h e m a t r i x A

    n ; 1

    :

    P r o b l e m 2 . 1 . 3 .

    L e t

    A =

    "

    1 1

    1 1

    #

    :

    P r o v e t h a t

    A

    n

    = 2

    n ; 1

    A ( n 2 N ) :

    E x a m p l e 2 . 1 . 1 .

    L e t u s s h o w t h a t m u l t i p l i c a t i o n o f m a t r i c e s i s n o t

    c o m m u t a t i v e . L e t

    A =

    "

    1 4

    3 2

    #

    B =

    "

    ; 2 5

    1 2

    #

    :

    W e n d t h e p r o d u c t s :

    A B =

    "

    1 4

    3 2

    # "

    ; 2 5

    1 2

    #

    =

    "

    2 1 3

    ; 4 1 9

    #

    B A =

    "

    ; 2 5

    1 2

    # "

    1 4

    3 2

    #

    =

    "

    1 3 2

    7 8

    #

    :

    A s A B 6= B A d o e s n o t h o l d f o r t h e e x a m p l e , m u l t i p l i c a t i o n o f m a t r i c e s i s

    n o t c o m m u t a t i v e i n g e n e r a l .

    P r o p o s i t i o n 2 . 1 . 1 . I f A 2 R

    m p

    a n d B 2 R

    p n

    t h e n

    ( A B )

    T

    = B

    T

    A

    T

    :

    P r o o f . I f C = ( A B )

    T

    t h e n

    c

    i k

    = ( A B )

    T

    ]

    i k

    = A B ]

    k i

    =

    p

    X

    j = 1

    a

    k j

    b

    j i

    :

    2 4

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    25/188

    I f D = B

    T

    A

    T

    w e a l s o h a v e

    d

    i k

    = B

    T

    A

    T

    ]

    i k

    =

    p

    X

    j = 1

    B

    T

    ]

    i j

    A

    T

    ]

    j k

    =

    p

    X

    j = 1

    B ]

    j i

    A ]

    k j

    =

    =

    p

    X

    j = 1

    a

    k j

    b

    j i

    = c

    i k

    : 2

    D e n i t i o n 2 . 1 . 1 . A m a t r i x A 2 R

    n n

    i s c a l l e d s y m m e t r i c i f A

    T

    = A

    a n d s k e w - s y m m e t r i c i f A

    T

    = ; A :

    P r o b l e m 2 . 1 . 4 .

    I s m a t r i x A s y m m e t r i c o r s k e w - s y m m e t r i c i f

    a ) A =

    2

    6

    4

    ; 1 3 2

    3 1 3

    2 3 ; 1

    3

    7

    5

    b ) A =

    2

    6

    4

    0 2 ; 4

    ; 2 1 ; 7

    4 7 2

    3

    7

    5

    c ) A =

    2

    6

    4

    2 ; 3 5

    3 1 2

    ; 5 1 4

    3

    7

    5

    :

    P r o p o s i t i o n 2 . 1 . 2 . E a c h m a t r i x A 2 R

    n n

    c a n b e e x p r e s s e d a s a s u m

    o f a s y m m e t r i c m a t r i x a n d a s k e w - s y m m e t r i c m a t r i x .

    P r o o f . E a c h m a t r i x A 2 R

    n n

    c a n b e e x p r e s s e d a s A = B + C w h e r e

    B = ( A + A

    T

    ) = 2 a n d C = ( A

    ;A

    T

    ) = 2 : A s

    B

    T

    = ( ( A + A

    T

    ) = 2 )

    T

    = ( A

    T

    + A ) = 2 = B

    a n d

    C

    T

    = ( ( A ; A

    T

    ) = 2 )

    T

    = C = ( A

    T

    ; A ) = 2 = ; C

    t h e p r o p o s i t i o n h o l d s . 2

    P r o b l e m 2 . 1 . 5 .

    R e p r e s e n t t h e m a t r i x

    A =

    2

    6

    6

    6

    4

    2 ; 3 5 1

    ; 3 ; 2 3 0

    3 ; 7 0 6

    4 5 2 4

    3

    7

    7

    7

    5

    a s a s u m o f a s y m m e t r i c a n d a s k e w - s y m m e t r i c m a t r i x .

    D e n i t i o n 2 . 1 . 2 . I f A i s a m n ; m a t r i x w i t h c o m p l e x e l e m e n t s , i . e . ,

    A 2 C

    m n

    t h e n t h e t r a n s p o s e d s k e w - s y m m e t r i c m a t r i x A

    H

    w i l l b e d e n e d

    b y t h e e q u a l i t y

    B = A

    H

    ,b

    i k

    = a

    k i

    :

    2 5

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    26/188

    D e n i t i o n 2 . 1 . 3 . A m a t r i x A 2 C

    n n

    i s c a l l e d a n H e r m i t i a n m a t r i x i f

    A

    H

    = A :

    P r o b l e m 2 . 1 . 6 .

    I s m a t r i x A a n H e r m i t i a n m a t r i x i f

    a ) A =

    2

    6

    4

    i ; 2 + i ; 5 + 3 i

    2 + i 5 i ; 2 + i

    5 + 3 i 2 + i ; 8 i

    3

    7

    5

    b ) A =

    2

    6

    4

    5 2 + 3 i 1 + i

    2 ; 3 i ; 3 ; 2 i

    1 ; i 2 i 0

    3

    7

    5

    :

    P r o b l e m 2 . 1 . 7 .

    L e t A 2 C

    m n

    : S h o w t h a t m a t r i c e s A A

    H

    a n d A

    H

    A

    a r e H e r m i t i a n m a t r i c e s .

    T h e m a t r i x A 2 C

    m n

    c a n b e e x p r e s s e d b o t h b y t h e c o l u m n - v e c t o r s

    c

    k

    ( k = 1 : n ) o f t h e m a t r i x A a n d b y t h e r o w - v e c t o r s r

    T

    i

    ( i = 1 : m ) o f

    t h e t r a n s p o s e o f m a t r i x A ( \ p a s t i n g " t h e m a t r i c e s o f t h e c o l u m n - v e c t o r s o r

    o f t h e t r a n s p o s e d r o w - v e c t o r s )

    A =

    h

    c

    1

    c

    n

    i

    h

    c

    1

    c

    n

    i

    =

    2

    6

    6

    4

    r

    T

    1

    .

    .

    .

    r

    T

    m

    3

    7

    7

    5

    w h e r e c

    k

    2 C

    m

    a n d r

    i

    2 C

    n

    a n d

    r

    i

    =

    2

    6

    6

    4

    a

    i 1

    .

    .

    .

    a

    i n

    3

    7

    7

    5

    c

    k

    =

    2

    6

    6

    4

    a

    1 k

    .

    .

    .

    a

    m k

    3

    7

    7

    5

    :

    E x a m p l e 2 . 1 . 2 . L e t u s d e m o n s t r a t e t h e s e n o t i o n s o n a m a t r i x A

    2R

    3 2

    :

    A =

    2

    6

    4

    2 3

    4 1

    3 2

    3

    7

    5

    ) c

    1

    =

    2

    6

    4

    2

    4

    3

    3

    7

    5

    c

    2

    =

    2

    6

    4

    3

    1

    2

    3

    7

    5

    r

    1

    =

    "

    2

    3

    #

    r

    2

    =

    "

    4

    1

    #

    r

    3

    =

    "

    3

    2

    #

    r

    T

    1

    =

    h

    2 3

    i

    r

    T

    2

    =

    h

    4 1

    i

    r

    3

    =

    h

    3 2

    i

    A =

    h

    c

    1

    c

    2

    i

    =

    h

    c

    1

    c

    2

    i

    =

    2

    6

    4

    r

    T

    1

    r

    T

    2

    r

    T

    3

    3

    7

    5

    :

    2 6

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    27/188

    I f A 2 R

    m n

    t h e n A ( i : ) d e n o t e s t h e i ; t h r o w o f t h e m a t r i x A , i . e . ,

    A ( i : ) =

    h

    a

    i 1

    a

    i n

    i

    a n d A ( : k ) d e n o t e s t h e k - t h c o l u m n o f t h e m a t r i x A , i . e . ,

    A ( : k ) =

    2

    6

    6

    4

    a

    1 k

    .

    .

    .

    a

    m k

    3

    7

    7

    5

    :

    I f 1 p q < n 1 r m t h e n

    A ( r p : q ) =

    h

    a

    r p

    a

    r q

    i

    2 R

    1 ( q ; p + 1 )

    a n d i f 1 p n 1 r s m t h e n

    A ( r : s p ) =

    2

    6

    6

    4

    a

    r p

    .

    .

    .

    a

    s p

    3

    7

    7

    5

    2 R

    s ; r + 1

    :

    I f A 2 R

    m n

    a n d i = ( i

    1

    : : : i

    p

    ) a n d k = ( k

    1

    : : : k

    q

    ) w h e r e

    i

    1

    : : : i

    p

    2 f 1 2 : : : m g k

    1

    : : : k

    q

    2 f 1 2 : : : n g

    t h e n t h e c o r r e s p o n d i n g s u b m a t r i x i s

    A ( i k ) =

    2

    6

    6

    4

    A ( i

    1

    k

    1

    ) A ( i

    1

    k

    q

    )

    .

    .

    .

    .

    .

    .

    A ( i

    p

    k

    1

    ) A ( i

    p

    k

    q

    )

    3

    7

    7

    5

    :

    E x a m p l e 2 . 1 . 3 . I f

    A =

    2

    6

    6

    6

    4

    1 4 ; 1 2 ; 4 8

    2 ; 2 4 1 3 5

    5 6 ; 7 2 ; 1 9

    4 5 6 ; 4 9 1

    3

    7

    7

    7

    5

    a n d i = ( 2 4 ) a n d k = ( 1 3 5 ) t h e n

    A ( i k ) =

    "

    2 4 3

    4 6 9

    #

    :

    2 7

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    28/188

    1 . 2 . 2 B a n d M a t r i c e s a n d B l o c k M a t r i c e s

    D e n i t i o n 2 . 2 . 1 . A m a t r i x w h o s e e l e m e n t s d i e r e n t f r o m z e r o a r e o n l y

    o n t h e m a i n a n d s o m e a d j a c e n t d i a g o n a l s i s c a l l e d a b a n d m a t r i x .

    D e n i t i o n 2 . 2 . 2 . I t i s s a i d t h a t t h e m a t r i x A 2 R

    m n

    i s a b a n d m a t r i x

    w i t h t h e l o w e r b a n d w i d t h p i f

    ( i > k + p ) ) a

    i k

    = 0

    a n d w i t h t h e u p p e r b a n d w i d t h q i f

    ( k > i + q ) ) a

    i k

    = 0

    a n d w i t h t h e b a n d w i d t h p + q + 1 :

    E x a m p l e 2 . 2 . 1 . T h e m a t r i x

    A =

    2

    6

    6

    6

    6

    6

    6

    6

    6

    4

    0 0 0 0 0

    0 0 0 0

    0 0 0

    0 0 0

    0 0 0

    0 0 0

    3

    7

    7

    7

    7

    7

    7

    7

    7

    5

    i s a b a n d m a t r i x b e c a u s e a l l t h e e l e m e n t s d i e r e n t f r o m z e r o a r e o n t h e m a i n

    a n d t w o l o w e r a n d o n e u p p e r d i a g o n a l s . T h e l o w e r b a n d w i d t h o f t h e m a t r i x

    A i s 2 b e c a u s e a

    i k

    = 0 a s i > k + 2 a n d t h e u p p e r b a n d w i d t h i s 1 b e c a u s e

    a

    i k

    = 0 a s k > i + 1 : T h e b a n d w i d t h o f t h e m a t r i x i s 2 + 1 + 1 = 4 : T h e

    e l e m e n t s o f t h e m a t r i x t h a t a r e n e c e s s a r i l y n o t z e r o s a r e d e n o t e d b y c r o s s e s .

    S o m e o f t h e m o s t i m p o r t a n t t y p e s o f b a n d m a t r i c e s a r e p r e s e n t e d i n

    t a b l e 2 . 2 . 1 . I f D 2 R

    m n

    i s a d i a g o n a l m a t r i x , q = m i n f m n g a n d d

    i

    = d

    i i

    t h e n t h e n o t a t i o n D = d i a g ( d

    1

    : : : d

    q

    ) : w i l l b e u s e d .

    2 8

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    29/188

    T a b l e 2 . 2 . 1 .

    T h e m a t r i c e ' s t y p e L o w e r b a n d w i d t h U p p e r b a n d w i d t h

    d i a g o n a l m a t r i x 0 0

    u p p e r t r i a n g u l a r m a t r i x 0 n - 1

    l o w e r t r i a n g u l a r m a t r i x m - 1 0

    t r i d i a g o n a l m a t r i x 1 1

    u p p e r t r i d i a g o n a l m a t r i x 0 1

    l o w e r t r i d i a g o n a l m a t r i x 1 0

    u p p e r H e s s e n b e r g m a t r i x 1 n - 1

    l o w e r H e s s e n b e r g m a t r i x m - 1 1

    P r o b l e m 2 . 2 . 1 .

    F i n d t h e t y p e , l o w e r b a n d w i d t h , u p p e r b a n d w i d t h a n d

    b a n d w i d t h o f t h e m a t r i x A i f

    A =

    2

    6

    6

    6

    6

    6

    6

    4

    1 3 0 0 0

    4 2 1 1 0

    0 2 3 4 1

    0 0 5 4 6

    0 0 0 6 5

    3

    7

    7

    7

    7

    7

    7

    5

    A =

    2

    6

    6

    6

    6

    6

    6

    6

    6

    6

    6

    6

    6

    6

    6

    6

    4

    1 1 0 0 0 1

    2 2 1 0

    .

    .

    .

    0 0

    1 2 3 1

    .

    .

    .

    0 0

    0 1 2 4

    .

    .

    .

    .

    .

    .

    0

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    .

    0 0 0

    .

    .

    .

    n ; 1 1

    0 0 0 0 2 n

    3

    7

    7

    7

    7

    7

    7

    7

    7

    7

    7

    7

    7

    7

    7

    7

    5

    :

    D e n i t i o n 2 . 2 . 3 . A m a t r i x A = ( A

    ) 2 R

    m n

    i s c a l l e d a q r ; b l o c k

    m a t r i x i f

    A =

    2

    6

    6

    4

    A

    1 1

    : : : A

    1 r

    .

    .

    .

    .

    .

    .

    A

    q 1

    : : : A

    q r

    3

    7

    7

    5

    m

    1

    m

    q

    n

    1

    n

    r

    w h e r e m

    1

    + : : : + m

    q

    = m a n d n

    1

    + : : : + n

    r

    = n a n d A

    i s a m

    n

    ; m a t r i x .

    E x a m p l e 2 . 2 . 2 . T h e m a t r i x

    A =

    2

    6

    6

    6

    4

    a a a b b

    a a a b b

    a a a b b

    c c c d d

    3

    7

    7

    7

    5

    2 9

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    30/188

    i s a 2 2 ; b l o c k m a t r i x , w h e r e m

    1

    = 3 m

    2

    = 1 n

    1

    = 3 a n d n

    2

    = 2 a n d

    A

    1 1

    =

    2

    6

    4

    a a a

    a a a

    a a a

    3

    7

    5

    A

    1 2

    =

    2

    6

    4

    b b

    b b

    b b

    3

    7

    5

    A

    2 1

    =

    h

    c c c

    i

    A

    2 2

    =

    h

    d d

    i

    :

    L e t

    B =

    2

    6

    6

    4

    B

    1 1

    : : : B

    1 r

    .

    .

    .

    .

    .

    .

    B

    q 1

    : : : B

    q r

    3

    7

    7

    5

    m

    1

    m

    q

    n

    1

    n

    r

    a n d C = A + B : T h e n

    C =

    2

    6

    6

    4

    C

    1 1

    : : : C

    1 r

    .

    .

    .

    .

    .

    .

    C

    q 1

    : : : C

    q r

    3

    7

    7

    5

    =

    2

    6

    6

    4

    A

    1 1

    + B

    1 1

    : : : A

    1 r

    + B

    1 r

    .

    .

    .

    .

    .

    .

    A

    q 1

    + B

    q 1

    : : : B

    q r

    + B

    q r

    3

    7

    7

    5

    :

    P r o p o s i t i o n 2 . 2 . 1 . I f A 2 R

    m p

    B 2 R

    p n

    a n d C = A B a r e b l o c k

    m a t r i c e s :

    A =

    2

    6

    6

    6

    6

    6

    6

    6

    4

    A

    1 1

    : : : A

    1 r

    .

    .

    .

    .

    .

    .

    A

    1

    : : : A

    r

    .

    .

    .

    .

    .

    .

    A

    q 1

    : : : A

    q r

    3

    7

    7

    7

    7

    7

    7

    7

    5

    m

    1

    m

    m

    q

    p

    1

    p

    r

    B =

    2

    6

    6

    4

    B

    1 1

    : : : B

    1

    : : : B

    1 s

    .

    .

    .

    .

    .

    .

    .

    .

    .

    B

    r 1

    : : : B

    r

    : : : B

    r s

    3

    7

    7

    5

    p

    1

    p

    r

    n

    1

    n

    n

    s

    C =

    2

    6

    6

    6

    6

    6

    6

    6

    4

    C

    1 1

    : : : C

    1

    : : : C

    1 s

    .

    .

    .

    .

    .

    .

    .

    .

    .

    C

    1

    : : : C

    : : : C

    s

    .

    .

    .

    .

    .

    .

    .

    .

    .

    C

    q 1

    : : : C

    q

    : : : C

    q s

    3

    7

    7

    7

    7

    7

    7

    7

    5

    m

    1

    m

    m

    q

    n

    1

    n

    n

    s

    3 0

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    31/188

    w h e r e 1 q 1 s m

    1

    + : : : + m

    q

    = m p

    1

    + : : : + p

    s

    = p

    n

    1

    + : : : + n

    r

    = n , t h e n

    C

    =

    r

    X

    = 1

    A

    B

    ( = 1 : q

    = 1 : s ) .

    P r o o f . L e t

    = m

    1

    + : : : + m

    ; 1

    = n

    1

    + : : : + n

    ; 1

    1 r

    = p

    1

    + : : : + p

    ; 1

    m

    0

    = n

    0

    = p

    0

    = 0 :

    A s C

    ]

    i k

    i s a n e l e m e n t o f t h e b l o c k C

    o f t h e m a t r i x C s t a n d i n g i n t h e

    i ; t h r o w a n d k ; t h c o l u m n o f t h i s b l o c k , a n d A

    ]

    i j

    i s a n e l e m e n t o f t h e

    b l o c k A

    o f t h e m a t r i x A s t a n d i n g i n t h e i

    ;t h r o w a n d j

    ;t h c o l u m n o f t h i s

    b l o c k , a n d B

    ] i s a n e l e m e n t o f t h e b l o c k B

    o f t h e m a t r i x B s t a n d i n g

    i n t h e j ; t h r o w a n d k ; t h c o l u m n , t h e n

    C

    ]

    i k

    = c

    + i + k

    A

    ]

    i j

    = a

    + i + j

    B

    ]

    j k

    = b

    + j + k

    :

    T h e r e f o r e ,

    C

    ]

    i k

    = c

    + i + k

    =

    p

    X

    j = 1

    a

    + i j

    b

    j + k

    =

    =

    p

    1

    X

    j = 1

    a

    + i j

    b

    j + k

    +

    p

    1

    + p

    2

    X

    j = p

    1

    + 1

    a

    + i j

    b

    j + k

    + : : : +

    p

    X

    j = p

    1

    + p

    2

    + + p

    r ; 1

    + 1

    a

    + i j

    b

    j + k

    =

    =

    p

    1

    X

    j = 1

    A

    1

    ]

    i j

    B

    1

    ]

    j k

    +

    p

    2

    X

    j = 1

    A

    2

    ]

    i j

    B

    2

    ]

    j k

    + : : : +

    p

    r

    X

    j = 1

    A

    r

    ]

    i j

    B

    r

    ]

    j k

    =

    = A

    1

    B

    1

    ]

    i k

    + A

    2

    B

    2

    ]

    i k

    + : : : + A

    r

    B

    r

    ]

    i k

    =

    r

    X

    j = 1

    A

    j

    B

    j

    ]

    i k

    :

    T h e r e f o r e , a l l t h e c o r r e s p o n d i n g e l e m e n t s o f t h e m a t r i c e s C

    a n d

    P

    s

    = 1

    A

    B

    a r e e q u a l , a n d o u r p r o p o s i t i o n h o l d s . 2

    C o r o l l a r y 2 . 2 . 1 . I f A

    2R

    m p

    B

    2R

    p n

    A =

    2

    6

    6

    4

    A

    1

    .

    .

    .

    A

    q

    3

    7

    7

    5

    m

    1

    m

    q

    B =

    h

    B

    1

    : : : B

    r

    i

    3 1

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    32/188

    n

    1

    n

    r

    a n d m

    1

    + : : : + m

    q

    = m a n d n

    1

    + : : : + n

    r

    = n t h e n

    A B = C =

    2

    6

    6

    4

    C

    1 1

    : : : C

    1 r

    .

    .

    .

    .

    .

    .

    C

    q 1

    : : : C

    q r

    3

    7

    7

    5

    m

    1

    m

    q

    n

    1

    n

    r

    w h e r e C

    = A

    B

    ( = 1 : q

    = 1 : r ) .

    C o r o l l a r y 2 . 2 . 2 . I f A 2 R

    m p

    B 2 R

    p n

    A =

    h

    A

    1

    : : : A

    s

    i

    p

    1

    p

    s

    B =

    2

    6

    6

    4

    B

    1

    .

    .

    .

    B

    s

    3

    7

    7

    5

    p

    1

    p

    s

    a n d p

    1

    + : : : + p

    s

    = p t h e n A B = C =

    P

    p

    k = 1

    A

    k

    B

    k

    :

    E x a m p l e 2 . 2 . 3 . I t h o l d s

    "

    A

    1 1

    A

    1 2

    A

    2 1

    A

    2 2

    # "

    x

    1

    x

    2

    #

    =

    "

    A

    1 1

    x

    1

    + A

    1 2

    x

    2

    A

    2 1

    x

    1

    + A

    2 2

    x

    2

    #

    :

    E x a m p l e 2 . 2 . 4 . I t h o l d s

    2

    6

    6

    6

    6

    6

    6

    4

    a a a b

    a a a b

    a a a b

    c c c d

    c c c d

    3

    7

    7

    7

    7

    7

    7

    5

    2

    6

    6

    6

    4

    e f f

    e f f

    e f f

    g h h

    3

    7

    7

    7

    5

    =

    "

    A B

    C D

    # "

    E F

    G H

    #

    =

    "

    A E + B G A F + B H

    C E + D G C F + D H

    #

    w h e r e A = ( a ) i s a 3 3 ; m a t r i x , B = ( b ) i s a 3 1 ; m a t r i x , C = ( c ) i s a

    2 3 ; m a t r i x , D = ( d ) i s a 2 1 ; m a t r i x , E = ( e ) i s a 3 1 ; m a t r i x , F = ( f )

    i s a 3 2 ; m a t r i x , G = ( g ) i s a 1 1 ; m a t r i x a n d H = ( h ) i s a 1 2 ; m a t r i x .

    3 2

  • 8/8/2019 ( eBook - PDF - EnG ) Applications of Linear Algebra ( Ma Thematic )

    33/188

    E x a m p l e 2 . 2 . 5 .

    L e t u s n d t h e p r o d u c t A B o f b l o c k m a t r i c e s A a n d

    B , w h e n A a n d B a r e 3 3 ; m a t r i c e s

    A =

    2

    6

    6

    6

    6

    6

    6

    6

    4

    1 2

    .

    .

    . 2

    3 4

    .

    .

    . 0

    .

    .

    .

    0 0

    .

    .

    .

    ;1

    3

    7

    7

    7

    7

    7

    7

    7

    5

    B =

    2

    6

    6

    6

    6

    6

    6

    6

    4

    ; 3 1 0

    .

    .

    . 1

    2 3 ; 1

    .

    .

    . 1

    .

    .

    .

    0 0 0

    .

    .

    . 1

    3

    7

    7

    7

    7

    7

    7

    7

    5

    :

    W e d e n o t e

    A =

    "

    C D

    E F

    #

    B =

    "

    G H

    K L

    #

    w h e r e

    C =

    "

    1 2

    3 4

    #

    D =

    "

    2

    0

    #

    E =

    h

    0 0

    i

    F =

    h

    ; 1

    i

    a n d

    G =

    "

    ; 3 1 0

    2 3 ; 1

    #

    H =

    "

    1

    1

    #

    K =

    h

    0 0 0

    i

    L =

    h

    1

    i

    :

    W e n o t e t h a t t h e d i m e n s i o n s o f t h e m a t r i c e s a r e i