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# 1.) UNIT 2: WORD PROBLEM WORKSHEET The equation C(r) = 4 r + 10 represents t cost C(r) at the county fair based on th number of rides, r. (a.) Jake has $ 18 in his pocket. How man rides can he go on? 4 r + 10 = 18 - 10- 10 4 r = 8 4 4 r = 2

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UNIT 2: WORD PROBLEM WORKSHEET. # 1.). The equation C(r) = 4 r + 10 represents the cost C(r) at the county fair based on the number of rides, r. (a.) Jake has $ 18 in his pocket. How many rides can he go on?. 4 r + 10 = 18. r = 2. - 10. - 10. 4 r = 8. 4. 4. - PowerPoint PPT Presentation

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Page 1: # 1.)

# 1.)

UNIT 2: WORD PROBLEM WORKSHEET

The equation C(r) = 4 r + 10 represents thecost C(r) at the county fair based on the

number of rides, r.

(a.) Jake has $ 18 in his pocket. How manyrides can he go on?

4 r + 10 = 18- 10 - 10

4 r = 8

4 4

r = 2

Page 2: # 1.)

# 1.)

UNIT 2: WORD PROBLEM WORKSHEET

The equation C(r) = 4 r + 10 represents thecost C(r) at the county fair based on the

number of rides, r.

(b.) If Jake wants to ride 10 rides, howmuch money does he have to borrow

from his friends?

4 (10) + 10 = C (r)

40 + 10 = C (r)50 = C (r)

50 – 18 = amt. to borrow

32 = amt. to borrow

Page 3: # 1.)

# 2.)

UNIT 2: WORD PROBLEM WORKSHEET

The cost of a pizza is based on thenumber of toppings plus $ 8. The cost of a

5-topping pizza is $ 14.25. How much would a 3-topping pizza cost?

Let x = cost of one topping

5 x + 8 = 14.25- 8 - 8

5 x = 6.25

5 5

x = 1.25 = cost of one topping

3 (1.25) + 8 = 3.75 + 8 = 11.75= cost of 3-topping pizza

Page 4: # 1.)

# 3.)

UNIT 2: WORD PROBLEM WORKSHEET

A case of 20 soft drinks is $ 12.00. Howmuch does James have to sell each soft

drink for to make a profit of $ 4 per case?

Case would sell for $ 16.00.

Each drink would need to sell for $ 0.80.

20 x = 1620 20

= 45

x = cost of one soft drink

Page 5: # 1.)

# 4.)

UNIT 2: WORD PROBLEM WORKSHEET

Peter is selling cookies. He sells eachcookie for $ 0.75. He had to spend $ 15 onsupplies. How many cookies does he need

to sell to earn $ 10?

x = number of cookies

.75 x = 15 + 10.75 x =

25100 •

• 10075 x =

250075 75

x = 33.33 cookies

He would need to sell at least 34 cookies.

Page 6: # 1.)

# 5.)

UNIT 2: WORD PROBLEM WORKSHEET

Joseph’s dad is three less than twiceJoseph’s age. Together, their ages

are 63. How old is Joseph?

Joseph’s age: x

Dad’s age: 2 x – 3x + 2 x – 3 = 633 x – 3 = 63+ 3 + 3

3 x = 663 3

x = 22

22

Page 7: # 1.)

# 6.)

UNIT 2: WORD PROBLEM WORKSHEET

Jack weighs 158 pounds. This is 2 lessthan ¾ of his father’s weight. How much

does his father weigh?

x = father’s weight

¾ x – 2 = 158+ 2 + 2

¾ x = 1603

4

3

4

x = 640/3 = 213.3 pounds

Page 8: # 1.)

# 7.)

UNIT 2: WORD PROBLEM WORKSHEET

Solve for c:c

pE

2

c

pE

2

• cc •

c • E = p2

E E

c = p2

E

Page 9: # 1.)

# 8.)

UNIT 2: WORD PROBLEM WORKSHEET

Solve for b:

Mt + Tabor = Good School

Page 10: # 1.)

# 9.)

UNIT 2: WORD PROBLEM WORKSHEET

A large bath tub is losing 1.5 gallons

every minute. At 8:00 pm, there

were 32 gallons. At what time were there 17 gallons?

Page 11: # 1.)

# 10.)

UNIT 2: WORD PROBLEM WORKSHEET

3 (x – 2) = 12. What is 2 x – 5?

Page 12: # 1.)

# 11.)

UNIT 2: WORD PROBLEM WORKSHEET

Solve for x.1023

2

x

Page 13: # 1.)

# 12.)

UNIT 2: WORD PROBLEM WORKSHEET

3 (x – 2) = 5 (x + 2) + 1

Solve for x.

Page 14: # 1.)

# 13.)

UNIT 2: WORD PROBLEM WORKSHEET

Find the mistake (if any) in the following problem: Then solve

it correctly.

- 2 ( x – 2) – 3 x = 10 + 5 x- 2 x + 4 – 3 x = 10 + 5 x

0 x + 4 = 10

- 5 x + 4 = 10 + 5 x

0 = 6 No solution