View
903
Download
5
Category
Tags:
Preview:
Citation preview
It’s been 3 years since the day Zack and Sally falling in love with each other.
Before that day, Zack, Sally’s boyfriend, has been thinking about this day long times before. He wants to give her a big surprise.
Before that day, Zack, Sally’s boyfriend, has been thinking about this day long times before. He wants to give her a big surprise.
Before that day, Zack, Sally’s boyfriend, has been thinking about this day long times before. He wants to give her a big surprise.
What should I do to make
her feel happy ?????
He’s thinking of ...
He’s thinking of ...He’s thinking of ...
Romantic night at the 5 stars restaurant.
He’s thinking of ...
He’s thinking of ...
Romantic night at the 5 stars restaurant.
Or going shopping!!!
He’s thinking of ...
Romantic night at the 5 stars restaurant.
Or going shopping!!!
Or a romantic movie
He’s thinking of ...
Romantic night at the 5 stars restaurant.
Or going shopping!!!
Or a romantic movieMake their love symbols
He’s thinking of ...
Romantic night at the 5 stars restaurant.
Or going shopping!!!
Or a romantic movieMake their love symbols
Or walking together at night
The answer is….
Hey! How about the Ferris Wheel??? That’s something new and really romantic….
Hey! How about the Ferris Wheel??? That’s something new and really romantic….
Hey! How about the Ferris Wheel??? That’s something new and really romantic….
Hey! How about the Ferris Wheel??? That’s something new and really romantic….
Hey that’s a great idea.
He starts planning everything for that special day.He starts planning everything for that special day.
That day is coming…..
They’re really happy spending time together….
Sally, you should try on that Ferris Wheel…
Sally, you should try on that Ferris Wheel…
Where honey???
Do you see it??..
Whoa..!!..
She gets on the Ferris Wheel, Zack said he has something for her and she has to get on the wheel in other to see that.
• Zack had planned to make a surprise for Sally. He will tell her to get on the Ferris wheel first, then Sally has to answer 2 questions in an definite time to see the special thing that Zack had prepared for only her….
• First he had to calculate the time he will give her to answer his 2 questions.
The Ferris Wheel has the maximum height is 32m and it stand 2m above from the round. It takes 6 minutes to go from the bottom of the wheel to the top of it. From the height of 28m, Sally will have the best view to see Zack’s present.
How long will it take to bring Sally to the best view point?
Solving:
Solving:
First we have to draw the graph so that we can easily solve this problem.
m
min
Solving:
First we have to draw the graph so that we can easily solve this problem.
Maximum height : 32m
32
m
min
Solving:
First we have to draw the graph so that we can easily solve this problem.
Maximum height : 32m
32
Stain 2m above the ground
2
m
min
Solving:
First we have to draw the graph so that we can easily solve this problem.
Maximum height : 32m
32
Stain 2m above the ground
2
m
min
Go from bottom to the top : 6minshalf period = 6mins
6
Solving:
First we have to draw the graph so that we can easily solve this problem.
Maximum height : 32m
32
Stain 2m above the ground
2
m
min
Go from bottom to the top : 6minshalf period = 6mins
6
(32-2)
2= 15
[ the distance from the max and min points to the Sinusoidal Axis.]
17
(An Amplitude)
Solving:
First we have to draw the graph so that we can easily solve this problem.
Maximum height : 32m
32
Stain 2m above the ground
2
m
min
Go from bottom to the top : 6minshalf period = 6mins
6
(32-2)
2= 15
[ the distance from the max and min points to the Sinusoidal Axis.]
17
15
15
(An Amplitude)
Solving:
First we have to draw the graph so that we can easily solve this problem.
Maximum height : 32m
32
Stain 2m above the ground
2
m
min
Go from bottom to the top : 6minshalf period = 6mins
6
(32-2)
2= 15
[ the distance from the max and min points to the Sinusoidal Axis.]
17
From the information above, we can sketch the graph.
(An Amplitude)
Solving:
First we have to draw the graph so that we can easily solve this problem.
Maximum height : 32m
32
Stain 2m above the ground
2
m
min
Go from bottom to the top : 6minshalf period = 6mins
6
(32-2)
2= 15
[ the distance from the max and min points to the Sinusoidal Axis.]
17
From the information above, we can sketch the graph.
Sinusoidal axis
(An Amplitude)
Solving:
First we have to draw the graph so that we can easily solve this problem.
Maximum height : 32m
32
Stain 2m above the ground
2
m
min
Go from bottom to the top : 6minshalf period = 6mins
6
(32-2)
2= 15
[ the distance from the max and min points to the Sinusoidal Axis.]
17
From the information above, we can sketch the graph.
Sinusoidal axis
P = 12mins12
(An Amplitude)
Solving:
First we have to draw the graph so that we can easily solve this problem.
Maximum height : 32m
32
Stain 2m above the ground
2
m
min
Go from bottom to the top : 6minshalf period = 6mins
6
(32-2)
2= 15
[ the distance from the max and min points to the Sinusoidal Axis.]
17
From the information above, we can sketch the graph.
Sinusoidal axis
P = 12mins12
Max point
(An Amplitude)
Solving:
First we have to draw the graph so that we can easily solve this problem.
Maximum height : 32m
32
Stain 2m above the ground
2
m
min
Go from bottom to the top : 6minshalf period = 6mins
6
(32-2)
2= 15
[ the distance from the max and min points to the Sinusoidal Axis.]
17
From the information above, we can sketch the graph.
Sinusoidal axis
P = 12mins12
Max point
Min point
(An Amplitude)
32
2
m
min6
17
12
Sine Function: f(x) = A sin B (x – C) + D
32
2
m
min6
17
12
Sine Function: f(x) = A sin B (x – C) + D
A =
B =
C =
D =
32
2
m
min6
17
12
Sine Function: f(x) = A sin B (x – C) + D
A =
B =
C =
D =
15
32
2
m
min6
17
12
Sine Function: f(x) = A sin B (x – C) + D
15A =
B =
C =
D =
2πP
= 2π12
= π6
32
2
m
min6
17
12
Sine Function: f(x) = A sin B (x – C) + D
A =
B =
C =
D =
15
3 [the graph shifts to the right]
2πP
= 2π12
= π6
32
2
m
min6
17
12
Sine Function: f(x) = A sin B (x – C) + D
A =
B =
C =
D =
15
2πP
= 2π12
= π6
3 [the graph shifts to the right]
+17
32
2
m
min6
17
12
Sine Function: f(x) = A sin B (x – C) + D
A =
B =
C =
D =
152πP =
2π12 =
π6
+17
f(x) = A sin B (x – C) + D
A =
B =
C =
D =
2πP =
2π12 =
π6
15A =
B =
C =
D =
2πP =
2π12 =
π6
3 [the graph shifts to the right]
32
2
m
min6
17
12
Sine Function: f(x) = A sin B (x – C) + D
f(x) = A sin B (x – C) + D
15A =
B =
C =
D =
2πP =
2π12 =
π6
3 [the graph shifts to the right]
+17
π6
15 sin +17(x – 3)
32
2
m
min6
17
12
Sine Function: f(x) = A sin B (x – C) + D
f(x) = A sin B (x – C) + D
Sub the value f(x) = 28m we get:
15A =
B =
C =
D =
2πP =
2π12 =
π6
+17
3 [the graph shifts to the right]
π6
15 sin +17(x – 3)
32
2
m
min6
17
12
Sine Function: f(x) = A sin B (x – C) + D
3 [the graph shifts to the right]
A =
B =
C =
D =
15
2πP
= 2π12
= π6
+17
f(x) = A sin B (x – C) + D
Sub the value f(x) = 28m we get:
28 =
π6
15 sin +17(x – 3)
π6
15 sin +17(x – 3)
We know that:
We know that:
28 = π6
15 sin +17(x – 3)
We know that:
We know that:
sin π666
=
666666
1
2
28 = π6
15 sin +17(x – 3)
We know that:
We know that:
sin π666
=
666666
1
2sin π
666=
666666
1
2sin π
666=
666666
1
2
28 = 15 x (x - 3) +1712
28 = π6
15 sin +17(x – 3)
We know that:
We know that:
sin π666
=
666666
1
2sin π
666=
666666
1
2sin π
666=
666666
1
2
= 11 152
(x - 3)
28 = 15 x (x - 3) +1712
28 = π6
15 sin +17(x – 3)
We know that:
We know that:
sin π666
=
666666
1
2sin π
666=
666666
1
2sin π
666=
666666
1
2
28 = π6
15 sin +17(x – 3)
= 11 152
(x - 3)
28 = 15 x (x - 3) +1712
11 = 15x - 452
We know that:
We know that:
sin π666
=
666666
1
2sin π
666=
666666
1
2sin π
666=
666666
1
2
28 = π6
15 sin +17(x – 3)
= 11 152
(x - 3)
28 = 15 x (x - 3) +1712
11 = 15x - 452
22 = 15x – 45
We know that:
We know that:
sin π666
=
666666
1
2sin π
666=
666666
1
2sin π
666=
666666
1
2
28 = π6
15 sin +17(x – 3)
= 11 152
(x - 3)
28 = 15 x (x - 3) +1712
11 = 15x - 452
22 = 15x – 45
67 = 15x
We know that:
We know that:
sin π666
=
666666
1
2sin π
666=
666666
1
2sin π
666=
666666
1
2
28 = π6
15 sin +17(x – 3)
= 11 152
(x - 3)
28 = 15 x (x - 3) +1712
11 = 15x - 452
22 = 15x – 45
67 = 15xx = 4.47 mins
We know that:
We know that:
sin π666
=
666666
1
2sin π
666=
666666
1
2sin π
666=
666666
1
2
28 = π6
15 sin +17(x – 3)
= 11 152
(x - 3)
28 = 15 x (x - 3) +1712
11 = 15x - 452
22 = 15x – 45
67 = 15xx = 4.47 mins ~ 4.5mins
We could also solve this with cosine function.
Therefore, Sally has about 4.5mins.
Sally has 3 boxes to choose that Zack had prepared before…
She picks the heart box first, and see a question.
If sinx = 712
If sinx = 712
Cosy = 12
If sinx = 712
Cosy = 12
Find cos2x + Sin2y
If sinx = 712
Cosy = 12
Find cos2x + Sin2y
From sinx, we could find cosx
If sinx = 712
Cosy = 12
Find cos2x + Sin2y
From sinx, we could find cosx
Sin x2 + Cos x2 = 1
If sinx = Cosy = 12
Find cos2x + Sin2y
From sinx, we could find cosx
Sin x2 + Cos x2
Cos x2 -
Sin x2
Sin x2
Cos x2
= 1= 1= 1
712
= 1
If sinx = Cosy = 12
Find cos2x + Sin2y
From sinx, we could find cosx
Sin x2 + Cos x2
= 1
Cos x2 -
Sin x2
Sin x2
Cos x2
Cos x2
= 1= 1= 1
-
712
712
( (2
= 1
If sinx = Cosy = 12
Find cos2x + Sin2y
From sinx, we could find cosx
Sin x2 + Cos x2
= 1
Cos x2 -
Sin x2
Sin x2
Cos x2
Cos x2
= 1= 1= 1
-
712
712
( (2
Cos x2 = 1 - 49144
= 1
If sinx = Cosy = 12
Find cos2x + Sin2y
From sinx, we could find cosx
Sin x2 + Cos x2
= 1
Cos x2 -
Sin x2
Sin x2
Cos x2
Cos x2
= 1= 1= 1
-
712
712
( (2
Cos x2 = 1 - 49144
Cos x2 = 95144
= 1
If sinx = Cosy = 12
Find cos2x + Sin2y
From sinx, we could find cosx
Sin x2 + Cos x2
= 1
Cos x2 -
Sin x2
Sin x2
Cos x2
Cos x2
= 1= 1= 1
-
712
712
( (2
Cos x2 = 1 - 49144
Cos x2 = 95144
Cosx = √95144
= 1
If sinx = Cosy = 12
Find cos2x + Sin2y
From sinx, we could find cosx
Sin x2 + Cos x2
= 1
Cos x2 -
Sin x2
Sin x2
Cos x2
Cos x2
= 1= 1= 1
-
712
712
( (2
Cos x2 = 1 - 49144
Cos x2 = 95144
Cosx = √95144
= 1
With the same method, we could find siny
If sinx = Cosy = 12
Find cos2x + Sin2y
From sinx, we could find cosx
Sin x2 + Cos x2
= 1
Cos x2 -
Sin x2
Sin x2
Cos x2
Cos x2
= 1= 1= 1
-
712
712
( (2
Cos x2 = 1 - 49144
Cos x2 = 95144
Cosx = √95144
= 1
With the same method, we could find siny
Sin y2 +2 2Cos y = 1Sin y22 2Cos y
If sinx = Cosy = 12
Find cos2x + Sin2y
From sinx, we could find cosx
Sin x2 + Cos x2
= 1
Cos x2 -
Sin x2
Sin x2
Cos x2
Cos x2
= 1= 1= 1
-
712
712
( (2
Cos x2 = 1 - 49144
Cos x2 = 95144
Cosx = √95144
= 1
With the same method, we could find siny
Sin y2 +2 2Cos y = 1Sin y22
Sin y22 = 1 -
2Cos y
2Cos y
If sinx = Cosy = 12
Find cos2x + Sin2y
From sinx, we could find cosx
Sin x2 + Cos x2
= 1
Cos x2 -
Sin x2
Sin x2
Cos x2
Cos x2
= 1= 1= 1
-
712
712
( (2
Cos x2 = 1 - 49144
Cos x2 = 95144
Cosx = √95144
= 1
With the same method, we could find siny
Sin y2 +2 2Cos y = 1Sin y22
Sin y22 = 1 -
2Cos y
2Cos y
Sin y22 = 1 - 12
( (2
If sinx = Cosy = 12
Find cos2x + Sin2y
From sinx, we could find cosx
Sin x2 + Cos x2
= 1
Cos x2 -
Sin x2
Sin x2
Cos x2
Cos x2
= 1= 1= 1
-
712
712
( (2
Cos x2 = 1 - 49144
Cos x2 = 95144
Cosx = √95144
= 1
With the same method, we could find siny
Sin y2 +2 2Cos y = 1Sin y22
Sin y22 = 1 -
2Cos y
2Cos y
Sin y22 = 1 - 12
( (2
Sin y22 = 1 - 14
If sinx = Cosy = 12
Find cos2x + Sin2y
From sinx, we could find cosx
Sin x2 + Cos x2
= 1
Cos x2 -
Sin x2
Sin x2
Cos x2
Cos x2
= 1= 1= 1
-
712
712
( (2
Cos x2 = 1 - 49144
Cos x2 = 95144
Cosx = √95144
= 1
With the same method, we could find siny
Sin y2 +2 2Cos y = 1Sin y22
Sin y22 = 1 -
2Cos y
2Cos y
Sin y22 = 1 - 12
( (2
Sin y22 = 1 - 14
Sin y22 34=
If sinx = Cosy = 12
Find cos2x + Sin2y
From sinx, we could find cosx
Sin x2 + Cos x2
= 1
Cos x2 -
Sin x2
Sin x2
Cos x2
Cos x2
= 1= 1= 1
-
712
712
( (2
Cos x2 = 1 - 49144
Cos x2 = 95144
Cosx = √95144
= 1
With the same method, we could find siny
Sin y2 +2 2Cos y = 1Sin y22
Sin y22 = 1 -
2Cos y
2Cos y
Sin y22 = 1 - 12
( (2
Sin y22 = 1 - 14
Sin y22 34=
Siny = √32
49144
cos2x + sin2y =
Cos2x = Cos(x + x) Sin2y = sin(y + y)
cos2x + sin2y =
Cos2x = Cos(x + x)
= cosxcosx - sinxsinx
Sin2y = sin(y + y) = sinycosy + cosysiny
cos2x + sin2y =
Cos2x = Cos(x + x)
= cosxcosx - sinxsinx= cos x – sin x2 2
Sin2y = sin(y + y) = sinycosy + cosysiny
= 2sinycosy
cos2x + sin2y =
Cos2x = Cos(x + x)
= cosxcosx - sinxsinx= cos x – sin x2 2
= 95144
49144
-
Sin2y = sin(y + y) = sinycosy + cosysiny
= 2sinycosy
= 2 x 12
√32
cos2x + sin2y =
Cos2x = Cos(x + x)
= cosxcosx - sinxsinx= cos x – sin x2 2
= 95144
49144
-
= 46144
Sin2y = sin(y + y) = sinycosy + cosysiny
= 2sinycosy
= 2 x 12
√32
= √32=
√32
√32
cos2x + sin2y =
Cos2x = Cos(x + x)
= cosxcosx - sinxsinx= cos x – sin x2 2
= 95144
49144
-
= 46144
Sin2y = sin(y + y) = sinycosy + cosysiny
= 2sinycosy
= 2 x 12
√32
= √32
cos2x + sin2y =
= √32
√32
cos2x + sin2y =
Cos2x = Cos(x + x)
= cosxcosx - sinxsinx= cos x – sin x2 2
= 95144
49144
-
= 46144
Sin2y = sin(y + y) = sinycosy + cosysiny
= 2sinycosy
= 2 x 12
√32
= √32
cos2x + sin2y = 46
144 +
= √32
√32
√32
cos2x + sin2y =
Cos2x = Cos(x + x)
= cosxcosx - sinxsinx= cos x – sin x2 2
= 95144
49144
-
= 46144
Sin2y = sin(y + y) = sinycosy + cosysiny
= 2sinycosy
= 2 x 12
√32
= √32
cos2x + sin2y = 46
144 +
= √32
√32
√32
=46
144 +72√3
144
cos2x + sin2y =
Cos2x = Cos(x + x)
= cosxcosx - sinxsinx= cos x – sin x2 2
= 95144
49144
-
= 46144
Sin2y = sin(y + y) = sinycosy + cosysiny
= 2sinycosy
= 2 x 12
√32
= √32
cos2x + sin2y = 46
144 +
= √32
√32
√32
=46
144 +72√3
144
46 + 72√3=144
cos2x + sin2y =
Cos2x = Cos(x + x)
= cosxcosx - sinxsinx= cos x – sin x2 2
= 95144
49144
-
= 46144
Sin2y = sin(y + y) = sinycosy + cosysiny
= 2sinycosy
= 2 x 12
√32
= √32
cos2x + sin2y = 46
144 +
= √32
√32
√32
=46
144 +72√3
144
46 + 72√3=144
2(23 + 36√3)144
=
cos2x + sin2y =
Cos2x = Cos(x + x)
= cosxcosx - sinxsinx= cos x – sin x2 2
= 95144
49144
-
= 46144
Sin2y = sin(y + y) = sinycosy + cosysiny
= 2sinycosy
= 2 x 12
√32
= √32
cos2x + sin2y = 46
144 +
= √32
√32
√32
=46
144 +72√3
144
46 + 72√3=144
2(23 + 36√3)144
=
=23 + 36√3
72
OMG!!! She has done with the first question, and starts to move on with the next one in the Noel box.
The next question is going to be harder than the first one…
The next question is going to be harder than the first one…
cos2x1 + tanx
cotx 1 sin2x2
- 1 = + sin x2 -
How can I solve this one??Uhm… let see…
cos2x1 + tanx
cotx 1 sin2x2
- 1 = + sin x2 -
●
cos2x1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
=
= cos x2 -
sin x2
1 + tanxcos2x
1 + tanxcos2x
1 +sinxcosx
sin x2
cos2x1 + tanx
cotx 1 sin2x2
- 1 = + sin x2 -
●
cos2x1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
=
= cos x2 -
sin x2
1 + tanxcos2x
1 + tanxcos2x
1 +sinxcosx
sin x2
sinxcosx1 +sinxcosx1 +sinxcosx1 +
☺ sinxcosx1 + =
cosx + sinxcosx
cosx + sinxcosx
cosx + sinxcosx
cosx + sinxcosx
cosx + sinx
cos2x1 + tanx
cotx 1 sin2x2
- 1 = + sin x2 -
●
cos2x1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
=
= cos x2 -
sin x2
1 + tanxcos2x
1 + tanxcos2x
1 +sinxcosx
sin x2=
cos x2 sin x2-
cosxcosx + sinx
cos2x1 + tanx
cotx 1 sin2x2
- 1 = + sin x2 -
●
cos2x1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
=
= cos x2 -
sin x2
1 + tanxcos2x
1 + tanxcos2x
1 +sinxcosx
sin x2=
cos x2 sin x2-
cosxcosx + sinx
=
sin x2-cos x2 sin x2-
cos x2 sin x2-
1x
cosxcosx + sinx
cos2x1 + tanx
cotx 1 sin2x2
- 1 = + sin x2 -
●
cos2x1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
=
= cos x2 -
sin x2
1 + tanxcos2x
1 + tanxcos2x
1 +sinxcosx
sin x2=
cos x2 sin x2-
cosxcosx + sinx
=
sin x2-cos x2 sin x2-
cos x2 sin x2-
1x
cosxcosx + sinx
= cosx(cos x2 sin x2- )cosx + sinx
cos2x1 + tanx
cotx 1 sin2x2
- 1 = + sin x2 -
●
cos2x1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
=
= cos x2 -
sin x2
1 + tanxcos2x
1 + tanxcos2x
1 +sinxcosx
sin x2=
cos x2 sin x2-
cosxcosx + sinx
=
sin x2-cos x2 sin x2-
cos x2 sin x2-
1x
cosxcosx + sinx
= cosx(cos x2 sin x2- )cosx + sinx
=cosx (cosx + sinx) (cosx – sinx)
cosx + sinx
cos2x1 + tanx
cotx 1 sin2x2
- 1 = + sin x2 -
●
cos2x1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
=
= cos x2 -
sin x2
1 + tanxcos2x
1 + tanxcos2x
1 +sinxcosx
sin x2=
cos x2 sin x2-
cosxcosx + sinx
=
sin x2-cos x2 sin x2-
cos x2 sin x2-
1x
cosxcosx + sinx
= cosx(cos x2 sin x2- )cosx + sinx
=cosx (cosx + sinx) (cosx – sinx)
cosx + sinx
cos2x1 + tanx
cotx 1 sin2x2
- 1 = + sin x2 -
●
cos2x1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
=
= cos x2 -
sin x2
1 + tanxcos2x
1 + tanxcos2x
1 +sinxcosx
sin x2=
cos x2 sin x2-
cosxcosx + sinx
=
sin x2-cos x2 sin x2-
cos x2 sin x2-
1x
cosxcosx + sinx
= cosx(cos x2 sin x2- )cosx + sinx
=cosx (cosx + sinx) (cosx – sinx)
cosx + sinx
= cosx (cosx – sinx)
● cotx =cosxsinx
cos2x1 + tanx
cotx 1 sin2x2
- 1 = + sin x2 -
●
cos2x1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x
=
= cos x2 -
sin x2
1 + tanxcos2x
1 + tanxcos2x
1 +sinxcosx
sin x2=
cos x2 sin x2-
cosxcosx + sinx
=
sin x2-cos x2 sin x2-
cos x2 sin x2-
1x
cosxcosx + sinx
= cosx(cos x2 sin x2- )cosx + sinx
=cosx (cosx + sinx) (cosx – sinx)
cosx + sinx
= cosx (cosx – sinx)
cos2x1 + tanx
cotx - 1 = cos2x1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x= 1 sin2x
2+ sin x2 -sin x2
cosxsinx
- 11 sin2x2+ sin x2 -sin x2
= cosx (cosx – sinx)
cos2x1 + tanx
cotx - 1 = cos2x1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x= 1 sin2x
2+ sin x2 -sin x2
cosxsinx
- 11 sin2x2+ sin x2 -sin x2
= cosx (cosx – sinx)
cosxsinx
- 1 = cos x2 - sinxcosx sinxcosx + sin x2 - 12
sin x2 12
- sinxcosx
cos2x1 + tanx
cotx - 1 = cos2x1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x= 1 sin2x
2+ sin x2 -sin x2
cosxsinx
- 11 sin2x2+ sin x2 -sin x2
= cosx (cosx – sinx)
cosxsinx
- 1 = cos x2 - sinxcosx + sin x2 -sin x2 sinxcosx 12
12
- sinxcosx
cosxsinx
- 1 = cos x2 sin x2+ - sinxcosx sinxcosx 12
12
- sinxcosx-
cos2x1 + tanx
cotx - 1 = cos2x1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x= 1 sin2x
2+ sin x2 -sin x2
cosxsinx
- 11 sin2x2+ sin x2 -sin x2
= cosx (cosx – sinx)
cosxsinx
- 1 = cos x2 - sinxcosx + sin x2 -sin x2 sinxcosx 12
12
- sinxcosx
cosxsinx
- 1 = cos x2 sin x2+ - sinxcosx sinxcosx 12
12
- sinxcosx-
cosxsinx
- 1 = 1 - 2sinxcosx
cos2x1 + tanx
cotx - 1 = cos2x1 + tanxcos2x
1 + tanxcos2x
1 + tanxcos2x= 1 sin2x
2+ sin x2 -sin x2
cosxsinx
- 11 sin2x2+ sin x2 -sin x2
= cosx (cosx – sinx)
cosxsinx
- 1 = cos x2 - sinxcosx + sin x2 -sin x2 sinxcosx 12
12
- sinxcosx
cosxsinx
- 1 = cos x2 sin x2+ - sinxcosx sinxcosx 12
12
- sinxcosx-
cosxsinx
- 1 = 1 - 2sinxcosxcosxsinx
- 1 = 1 - 2sinxcosxcosxsinx
- 1 = 1 -
cosxsinx
- 1 = 1 - sin2x
cosxsinx
- 1 = 1 - sin2x
cosxsinx
- 1 = 1 -
cosxsinx
- sinx
1 - sin2x
1 - sin2x=
cosxsinx
- 1 =
cosxsinx
- sinx
1 - sin2x
1 - sin2x=
cosx sinx- = sinx (1 - sin2x)
cosxsinx
- 1 =
cosxsinx
- sinx
1 - sin2x
1 - sin2x=
cosx sinx- = sinx (1 - sin2x)
cosx sinx- = sinx (cosx - sinx)2
cosxsinx
- 1 =
cosxsinx
- sinx
1 - sin2x
1 - sin2x=
cosx sinx- = sinx (1 - sin2x)
cosx sinx- = sinx (cosx - sinx)2
cosx sinx- sinx (cosx - sinx)2- = 0
cosxsinx
- 1 =
cosxsinx
- sinx
1 - sin2x
1 - sin2x=
cosx sinx- = sinx (1 - sin2x)
cosx sinx- = sinx (cosx - sinx)2
cosx sinx- sinx (cosx - sinx)2- = 0
(cosx - sinx) [1 – sinx(cosx – sinx)] = 0= 0=[1 – sinx(cosx – sinx)] 0=(cosx - sinx) [1 – sinx(cosx – sinx)] 0=
(cosx - sinx) [1 – sinx(cosx – sinx)] 0=
(cosx - sinx) [1 – sinx(cosx – sinx)] 0=
(cosx - sinx) = =0 0[1 – sinx(cosx – sinx)]
(cosx - sinx) [1 – sinx(cosx – sinx)] 0=
(cosx - sinx) = =0 0[1 – sinx(cosx – sinx)]
cosx = sinx1 – sinxcosx + sin x2 = 0
(cosx - sinx) [1 – sinx(cosx – sinx)] 0=
(cosx - sinx) = =0 0[1 – sinx(cosx – sinx)]
cosx = sinx1 – sinxcosx + sin x2 = 0
tanx = 1
(b/c given tanx = 1)
(cosx - sinx) [1 – sinx(cosx – sinx)] 0=
(cosx - sinx) = =0 0[1 – sinx(cosx – sinx)]
cosx = sinx1 – sinxcosx + sin x2 = 0
tanx = 1
(b/c given tanx = 1)
Divide both sides by cos x2
X = π4
5π4
X =
(cosx - sinx) [1 – sinx(cosx – sinx)] 0=
(cosx - sinx) = =0 0[1 – sinx(cosx – sinx)]
cosx = sinx1 – sinxcosx + sin x2 = 0
tanx = 1
(b/c given tanx = 1)
1 –cos x2
tanx + tan x2
= 0=
0=
X = π4
5π4
X =
(cosx - sinx) [1 – sinx(cosx – sinx)] 0=
(cosx - sinx) = =0 0[1 – sinx(cosx – sinx)]
cosx = sinx1 – sinxcosx + sin x2 = 0
tanx = 1
(b/c given tanx = 1)
1cos x2
= 0=
– tanx + tan x2 0=tan x2
tan x2 + 1 – tanx + tan x2 0=tan x2
X = π4
5π4
X =
(cosx - sinx) [1 – sinx(cosx – sinx)] 0=
(cosx - sinx) = =0 0[1 – sinx(cosx – sinx)]
cosx = sinx1 – sinxcosx + sin x2 = 0
tanx = 1
(b/c given tanx = 1)
1cos x2
= 0=
– tanx + tan x2 0=tan x2
tan x2 + 1 – tanx + tan x2 0=tan x2
2tan x2 – tanx + 1 0=X = π4
5π4
X =
(cosx - sinx) [1 – sinx(cosx – sinx)] 0=
(cosx - sinx) = =0 0[1 – sinx(cosx – sinx)]
cosx = sinx1 – sinxcosx + sin x2 = 0
tanx = 1
(b/c given tanx = 1)
1cos x2
= 0=
– tanx + tan x2 0=tan x2
tan x2 + 1 – tanx + tan x2 0=tan x2
2tan x2 – tanx + 1 0=
= (-1) 2 - 4(2)(1)
X = π4
5π4
X =
(cosx - sinx) [1 – sinx(cosx – sinx)] 0=
(cosx - sinx) = =0 0[1 – sinx(cosx – sinx)]
cosx = sinx1 – sinxcosx + sin x2 = 0
tanx = 1
(b/c given tanx = 1)
1cos x2
= 0=
– tanx + tan x2 0=tan x2
tan x2 + 1 – tanx + tan x2 0=tan x2
2tan x2 – tanx + 1 0=
= (-1) 2 - 4(2)(1)
= 1 – 8 = -7
X = π4
5π4
X =
(cosx - sinx) [1 – sinx(cosx – sinx)] 0=
(cosx - sinx) = =0 0[1 – sinx(cosx – sinx)]
cosx = sinx1 – sinxcosx + sin x2 = 0
tanx = 1
(b/c given tanx = 1)
1cos x2
= 0=
– tanx + tan x2 0=tan x2
tan x2 + 1 – tanx + tan x2 0=tan x2
2tan x2 – tanx + 1 0=
= (-1) 2 - 4(2)(1)
= 1 – 8 = -7
< 0 [ O ]
X = π4
5π4
X =
X = π4
5π4
X =
X = π4
5π4
X =
● ●●
X = 5π4
_+ kπ
(K ͼ I)
● ●●
X = π4
_+ kπ
(K ͼ I)
4 mins 28 secs ….
Will You Marry Me ???
Made by TN – HN
Recommended