10.1 area of polygons 1

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10.1 Area of Polygons

Page 521

Essential Questions

How do you know when to find circumference or area?

What strategies and formulas can you use?

How is surface area used in the real world? How is the volume of a pyramid related to

the volume of a box? How is the volume of a cone related to the

volume of a cylinder?

Area and Perimeter

Perimeter-The distance around a polygon (the sum of the length of all sides)

Area- The number of square units inside a closed figure

Formulas Triangle: b x h or 1/2bh 2 Rectangle: A = l x w Square: A = l x w or s2

Parallelogram: A = b x h Trapezoid: (b1 +b2) x h or ½ (b1 +b2)x h

2

Area

Steps:1. Write the area formula 2. Substitute the values given3. Answer

Area of a parallelogram

height

base

A = b x h

90º

What is the area of this parallelogram?

base 7 cm.

height 5 cm.A = b x h

A = 5 x 7

A = 35 cm2

PerimeterP= 5 + 7 + 5 + 7 = 24 cm

What is the area of this parallelogram?

6 ft.

5 ft.

8 ft.

A = b x h

A = 5 x 6

A = 30 ft2

PerimeterP= 6 + 8 + 6 + 8 = 28 ft

What is the area of this parallelogram?

5 m.10 m.

12 m. A = b x h

A = 10 x 5

A = 50 m2

PerimeterP= 5 + 12 + 5 +12= 34 m

Area of a trapezoid

• Area =

(b1 +b2) x h

2

base 1

height

base 2

Area of a trapezoid

• Area =

(b1 +b2) x h

2 base 1 base 2

height

What is the area of this trapezoid?

15 inches

8 Inches

7 inches

• Area =

(b1 +b2) x h

2

A= 88 in. sq.

12• Area =

(15 +7) x 8

2 PerimeterP= 7 + 15 + 12 + 12= 46 in

GUIDED PRACTICE for Examples 1 and 2

Substitute values for b1, b2 and h.

Multiply.

A = (b1 + b2)h1

21

2A = (14 + 17)6

= 93 square feet

Write formula for area of a trapezoid.

2. A trapezoid with bases of 14 feet and 17 feet and a height of 6 feet

What is the area of this trapezoid?

A= 412.5 cm sq.

25

15 20 cm

35

• Area =

(b1 +b2) x h

2 • Area =

(20 +35) x 15

2 PerimeterP= 35 + 25 + 20 + 25= 105 cm

How to find the area of a squareor rectangle.

3 cm.

5 cm.

Step 1 – Multiply the length times the width. (A = l x w)

53x

15 cm2

PerimeterP= 3 + 5 + 3 + 5= 16 cm

What is the area?

2 in.

6 in.

26x

12 in.2

A = b x h

PerimeterP= 2 + 6 + 2 + 6 = 16 in

TRIANGLES Area formula for triangles is

A = b x h or ½ b (h) 2

h

b

What is the area of this triangle?

20 in

20 in

Area = b x h

2

A= 200 in. sq.

Area = 20 x 20

2

What is the area of this triangle?

5 in

10 in

Area = b x h

2

A= 25 in. sq.

Area = 5 x 10

2

What is the area of this triangle?

10 in

8 in

Area = b x h

2

A= 40 in. sq.

Area = 10 x 8

2

Find the area and perimeter:

9 cm

18 cm

12 cm8

9 cm

18 cm

12 cm

A= 72 cm sq. P= 9 + 12 + 18 = 39 cm

Area = b x h

2

Area = 18 x 8

2

Find the area and perimeter:

10 in 15 in

7 in

8 in

A= 28 in. sq.P= 10 + 15 + 7 = 32 in.

Area = b x h

2 Area = 8 x 7

2

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