unit 15 for issuu march 10 2012

M

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14

3

5

10

10

molarity of known x liters of knownMolarity of unknown =

liters of unknown

(NaOH Molarity)(NaOH volume) vinegar Molarity =

vinegar volume

60 grams acetic acid 180 g acetic acid3 moles acetic acid 1 liter solution x x = = 18%

Liter solution 1 mole acetic acid 1000 grams solution 1000 g solution

common name name formula

stomach acid hydrochloric acid HCl

hydrofluoric acid HF

hydrobromic acid HBr

hydrioidic acid HI

nitric acid HNO3

sulfuric acid H2SO4

phosphoric acid H3PO4

vinegar acetic acid CH3CO2H

lye sodium hydroxide NaOH

milk of magnesia magnesium hydroxide Mg(OH)2

calcium hydroxide Ca(OH)2

ammonia NH3

triethylamine (CH3CH2)3N

6.0 x 10-11

[OH-]Acid

Orange juice10.221.66 x 10-43.78

Acid or base?

ExamplepOH[H+]pH

pH + pOH = 14[H+] = 10-pH

pH>7 = basepH<7 = acid

[H+][OH-] = 10-14

Use the change sign (-) button, not the subtract button

Enter 10^-14/1.66E-4

Enter 10^-3.78Enter 14-3.78