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TODAY IN GEOMETRY…
Review: Pythagorean Theorem and Perimeter
Learning Target: 11.1 You will find areas of triangles and parallelograms.
Independent practice
Ch. 7 Retakes
CH.8 TEST – NEXT WEEK!
REVIEW: The lengths of the hypotenuse and one leg of a right triangle are given. Find the perimeter of the triangle.1. Hypotenuse: 15 in. Leg: 12 in.
2. Hypotenuse: 34 ft. Leg: 16 ft.
12 𝑖𝑛 .
15 𝑖𝑛 .𝑥
16 𝑓𝑡 .
34 𝑓𝑡 .𝑥
9 𝑖𝑛 . Perimeter: Perimeter:
12 𝑓𝑡 .
AREA OF A SQUARE:
𝑠
𝑠
𝐴𝑟𝑒𝑎=𝑠 ∙𝑠=𝑠2
AREA OF A RECTANGLE:
𝑏
h
𝐴𝑟𝑒𝑎=𝑏 ∙ h
EXAMPLE: Find the value of x.
Use Area of a Square Substitute known values
Divide
25𝑐𝑚
𝐴𝑟𝑒𝑎=750𝑐𝑚2𝑥
PRACTICE: Find the value of x.
Use Area of a Rectangle Substitute known values
Divide
AREA OF A PARALLELOGRAM:
𝑏
h
𝐴𝑟𝑒𝑎=𝑏 ∙ h
h
EXAMPLE: Find the area of the given figure.
60 °
20 𝑖𝑛 .
12 𝑖𝑛 .60 °
Special Right Triangle:
12 𝑖𝑛 .
𝑥
𝟔√𝟑 𝒊𝒏 .
PRACTICE: Find the area of the given figure.
8𝑚
20𝑚
Use Area of a Parallelogram Substitute known values
Multiply
AREA OF A TRIANGLE:
𝑏
h
𝐴𝑟𝑒𝑎=12𝑏h
EXAMPLE: Find the perimeter and the area of the right triangle.
10 𝑖𝑛 .
6 𝑖𝑛 .
Find missing leg of right triangle using Pythagorean Theorem:
8 𝑖𝑛 .
PRACTICE: Find the perimeter and the area of the right triangle that has a leg of 20 cm and a hypotenuse of 29 cm.
29𝑐𝑚
20𝑐𝑚
Find missing leg of right triangle using Pythagorean Theorem:
21𝑐𝑚
PRACTICE: Find the perimeter and the area of the given polygon.
Perimeter:
Perimeter:
Pythagorean Thrm:
Perimeter:
PRACTICE: Find the area of the shaded region.
Pythagorean Thrm. to find x:
𝒙 𝒙1
2
Find areas separately, then total!
𝒉=𝟖−𝟓=𝟑𝒉
HOMEWORK #6:
Pg. 723: 3-8, 10, 12, 13, 16, 17, 22, 23, 28
If finished, work on other assignments:
HW #1: Pg. 510: 3-16, 19, 24-26HW #2: Pg. 518: 3-11, 13-15, 23-31HW #3: Pg. 526: 8-14, 19-21, 25-27, 43-47HW #4: Pg. 537: 3, 14, 19-25HW #5: Pg. 546: 3-16, 18-23
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