The circumference of the circle is 50 feet. The area of the shaded region = ________ example 1 :

The circumference of the circle is 50 feet .

The area of the shaded region = ________

example 1 :

The circumference of the circle is 50 feet .

The area of the shaded region = ________

C = d = 50

therefore the diameter of the circle is 50 feet.

50

50

The circumference of the circle is 50 feet .

The area of the shaded region = ________

C = d = 50

therefore the diameter of the circle is 50 feet

and the radius is 25 feet .

25

50

The circumference of the circle is 50 feet .

The area of the shaded region = ________

C = d = 50

therefore the diameter of the circle is 50 feet

and the radius is 25 feet .

25

The area of the circle = (25)2 = 625 square feet

50

50

the area of the square = 50x50 = 2500 square feet

The circumference of the circle is 50 feet .

The area of the shaded region = ________

C = d = 50

therefore the diameter of the circle is 50 feet

and the radius is 25 feet .

25

The area of the circle = (25)2 = 625 square feet

50

50

2500 square feet - 625 square feet

The circumference of the circle is 50 feet .

The area of the shaded region =(2500 - 625 ) square feet

C = d = 50

therefore the diameter of the circle is 50 feet

and the radius is 25 feet .

25

The area of the circle = (25)2 = 625 square feet

50

50

2500 square feet - 625 square feet

The circumference of the circle is 50 feet .

The area of the shaded region = ________

example 2 :

The circumference of the circle is 50 feet .

The area of the shaded region = ________

C = d = 50

therefore the diameter of the circle is 50 feet.

The circumference of the circle is 50 feet .

The area of the shaded region = ________

C = d = 50

therefore the diameter of the circle is 50 feet.

x

x

Let x = the side of the square

50

The circumference of the circle is 50 feet .

The area of the shaded region = ________

C = d = 50

therefore the diameter of the circle is 50 feet.

x

x

Let x = the side of the square

50

x2 + x2 = 502 = 2500

x2 = 1250 = the area of the square

area of circle = 625

The circumference of the circle is 50 feet .

The area of the shaded region = ________

C = d = 50

therefore the diameter of the circle is 50 feet.

x

x

Let x = the side of the square

50

x2 + x2 = 502 = 2500

x2 = 1250 = the area of the square

area of circle = 625 - area of square = 1250

The circumference of the circle is 50 feet .

The area of the shaded region =(625 - 1250) sq feet

C = d = 50

therefore the diameter of the circle is 50 feet.

x

x

Let x = the side of the square

50

x2 + x2 = 502 = 2500

x2 = 1250 = the area of the square

area of circle = 625 - area of square = 1250

example 3 :

A

B

AB = 30 feet

30

What is the SUM of the areas of the purple squares?_________

example 3 :

A

B

AB = 30 feet

30

What is the SUM of the areas of the purple squares?_________

x

x

y

y

Let x = the length of the side of the large square and let y = the length of the side of the small square

example 3 :

A

B

AB = 30 feet

30

What is the SUM of the areas of the purple squares? x2 + y2

x

x

y

y

Let x = the length of the side of the large square and let y = the length of the side of the small square

Area = x2

Area = y2

example 3 :

A

B

AB = 30 feet

30

What is the SUM of the areas of the purple squares? x2 + y2 = 302 = 900 sq ft

x

x

y

Let x = the length of the side of the large square and let y = the length of the side of the small square

Area = x2

Area = y2

y

example 4 :

7 feet

10 feet

If the area of the triangle is 14 square feet, then the area of the rectangle is ____________

example 4 :

7 feet

10 feet

If the area of the triangle is 14 square feet, then the area of the rectangle is ____________

The area of a triangle = ½ height x base

14 = ½ height x 7

28 = height x 7

4 = height

example 4 :

7 feet

10 feet

If the area of the triangle is 14 square feet, then the area of the rectangle is 10 x 4 = 40 sq ft

The area of a triangle = ½ height x base

14 = ½ height x 7

28 = height x 7

4 = height

4