Stoichiometry. Stoichiometry Stoy – key – ohm – e - tree

StoichiometryStoichiometry

Stoy – key – ohm – e - treeStoy – key – ohm – e - tree

9.1 Introduction to Stoichiometry9.1 Introduction to Stoichiometry

1. Define Stoichiometry.1. Define Stoichiometry.

2. Describe the importance of the mole ratio 2. Describe the importance of the mole ratio in stoichiometric calculations.in stoichiometric calculations.

3. Write a mole ratio relating two substances 3. Write a mole ratio relating two substances in a chemical equation.in a chemical equation.

4. Calculate the amount in moles of a 4. Calculate the amount in moles of a reactant or product from the amount in reactant or product from the amount in moles of a different reactant or product.moles of a different reactant or product.

Obj 1: What is Stoichiometry?Obj 1: What is Stoichiometry?

• Stoichiometry means

Stoicheio = element

Metron = measure

• Stoichiometry is the quantitative study of chemical reactions using balanced equations.

Obj 2: Mole RatioObj 2: Mole Ratio

• Mole Ratios come from the coefficients in a balanced equation.

• Mole Ratios are used to convert moles of one substance (X) into moles of another substance (Y).

Obj 3: Mole Ratios Obj 3: Mole Ratios from Balanced Equationsfrom Balanced Equations

1 N1 N22 + 3 H + 3 H22 2 NH 2 NH33

The Possible Mole Ratios are:The Possible Mole Ratios are:

1 N1 N22 + 3 H + 3 H22 2 NH 2 NH33

The Possible Mole Ratios are:The Possible Mole Ratios are:

1 mol N1 mol N22 1 mol N 1 mol N22 3 mol H 3 mol H22

3 mol H3 mol H22 2 mol NH 2 mol NH33 2 mol NH 2 mol NH33

1 N1 N22 + 3 H + 3 H22 2 NH 2 NH33

Other Possible Mole Ratios:Other Possible Mole Ratios:

3 mol H3 mol H22 2 mol NH 2 mol NH33 2 mol NH 2 mol NH33

Obj 4: Using a Mole RatioObj 4: Using a Mole Ratio

1 N1 N22 + 3 H + 3 H22 2 NH 2 NH33

7.5 mol N7.5 mol N22 ? mol H? mol H22 ? mol NH ? mol NH33

1 N1 N22 + 3 H + 3 H22 2 NH 2 NH33

7.5 mol N7.5 mol N2 2 (3 mol H(3 mol H22 ) = ? ) = ?

(1 mol N(1 mol N22 ) )

1 N1 N22 + 3 H + 3 H22 2 NH 2 NH33

7.5 mol N7.5 mol N2 2 (3 mol H(3 mol H22 ) = 22.5 mol H ) = 22.5 mol H22

(1 mol N(1 mol N22 ) )

Using a Mole RatioUsing a Mole Ratio

1 N1 N22 + 3 H + 3 H22 2 NH 2 NH33

7.5 mol N7.5 mol N22 22.5 mol H22.5 mol H22 ? mol NH ? mol NH33

7.5 mol N7.5 mol N2 2 (2 mol NH(2 mol NH33) = ?) = ?

(1 mol N(1 mol N22 ) )

1 N1 N22 + 3 H + 3 H22 2 NH 2 NH33

7.5 mol N7.5 mol N22 22.5 mol H22.5 mol H22 ? mol NH ? mol NH33

7.5 mol N7.5 mol N2 2 (2 mol NH(2 mol NH33) = 15.0 mol NH) = 15.0 mol NH33

(1 mol N(1 mol N22 ) )

Obj 4: Cookie StiochiometryObj 4: Cookie Stiochiometry

One Batch: 1 NOne Batch: 1 N22 + 3 H + 3 H22 2 NH 2 NH33

Double Batch: _ NDouble Batch: _ N22 + _ H + _ H22 _ NH _ NH33

Double Batch: 2 NDouble Batch: 2 N22 + 6 H + 6 H22 4 NH 4 NH33

Triple Batch: _ NTriple Batch: _ N22 + _ H + _ H22 _ NH _ NH33

Triple Batch: 3 NTriple Batch: 3 N22 + 9 H + 9 H22 6 NH 6 NH33

Half Batch: _ NHalf Batch: _ N22 + _ H + _ H22 _ NH _ NH33

Half Batch: 0.5 NHalf Batch: 0.5 N22 + 1.5 H + 1.5 H22 1 NH 1 NH33

Lets Look at Our Problem AgainLets Look at Our Problem AgainWe want 7.5 batch !We want 7.5 batch !

1 N1 N22 + 3 H + 3 H22 2 NH 2 NH33

__ mol N__ mol N2 2 ___ mol H___ mol H22 __ mol NH __ mol NH33

Lets Look at Our Problem AgainLets Look at Our Problem AgainWe want 7.5 batch !We want 7.5 batch !

1 N1 N22 + 3 H + 3 H22 2 NH 2 NH33

7.5 mol N7.5 mol N2 2 22.5 mol H22.5 mol H22 15.0 mol NH 15.0 mol NH33

The EndThe End

The Final CurtainThe Final Curtain

Stoichiometry. Stoichiometry Stoy – key – ohm – e - tree

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