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Quantum Mechanical Cross Sections
In a practical scattering experiment the observables we have on hand are momenta, spins, masses, etc.. We do not directly measure the distances between the projectile and the target nucleus.
pfpi
We start with an initial system of a target in state |A> and the projectile in momentum state |pi>. After the reaction the residual product is in state |B> and the outgoing fragment in momentum state | pf>.
We call the initial state |a>=|Api> and the final state |b>=| Bpf>. We know from experience that interactions cause changes in momenta, and in general, all other changes a system may experience. In classical physics we call the Hamiltonian the generator of time evolution. This is a statement of dynamics. The same concept applies in quantum mechanics. The Hamiltonian, H, governs the time evolution of a quantum system. Equation (1) is the Schroedinger equation in ket notation.
tiH
|
| (1)
1
We define the time evolution operator U(t,t0) such that a system evolves from some initial configuration, |a> to a final configuration |c> according to |c; t> = U(t,t0) |a; t0>. U(t,t0) is a function of the Hamiltonian. The relationship between U(t,t0) and the Hamiltonian is worked out in books on quantum mechanics (ref. 1,2). We will assume that the target and projectile have some internal Hamiltonians HA and Hp and that the target and projectile interact via an interaction V. The total Hamiltonian is
H = HA + Hp + V = H0 + V. Where H0 = HA + Hp , is called the free Hamiltonian. We assume that V becomes negligibly small for large separations between the projectile and target. The total time evolution operator can be written as ( ref.2)
U(t,t0) = U0(t,t0) UI(t,t0) . In this expression U0(t,t0) is the time evolution operator derived from the free Hamiltonian and UI(t,t0) depends on both H0 and V. It is expressed in the integral equation
(4) ,))'(
exp(),'(
(3) ,),'(),'(),'(),'(
(2) ,),'(),'('1),(
0000
00001
00
000
0
ttHittU
ttUttVttUttH
ttUttHdti
ttU
I
I
t
t
II
2
We assume that the free Hamiltonian is time independent. Then U0(t’,t0) in equation (4) is the time evolution operator due to H0. If the states |a> and |b> are eigenstates of H0, then the time evolved states of |a> and |b> are
(5b) ,;|))(exp(;|),(;|
(5a) ,;|))(exp(;|),(;|
00000
00000
tbttEitbttUtb
tattEitattUta
b
a
The time evolved state |c; t> = U(t,t0) |a; t0> is given by ( ref. 2),
bba TbTTUTTS
TaTTUTc
(6) ,2/;|)2/,2/()2/,2/(
2/;|)2/,2/(2/;|
0
Equation (6) tells us that at time t=-T/2 the system is initially in state |a>. At time T/2 the system has evolved into state |c;T/2> which consists of a sum of possible eigenstates |b;-T/2>, each weighted with an amplitude given by Sba , which is time dependent. If we let T/2 and –T/2 go to infinity, then Sba is called the “S – matrix”. The S-matrix must be properly normalized (See ref. 2 chapt. 3). Particle decay rates and cross sections can be calculated once the S-matrix is known.
3
From our discussion in lecture 2 we determined that the scattering rate is
tNN tba
L
L
L
We want to connect this derivation to a quantum calculation. The probability that the initial state a will make the transition to b is | Sba|2 . If N t is the number of targets in the box of sides L, and p the number of projectiles which have traversed the box then the number of transitions from state a to b is :
ptbaba NNTTSN 2|2/,2/(|
normal surface theis S v,ˆv3L
NS p
p
vpj
TTTt )2/(2/
v
|)2/,2/(S|
,for solvecan We
3
2ba
L
N
N
T
TT
p
p
4
(7) ,v
|)2/,2/(|lim
32 L
T
TTSbaT
In an actual calculation the S-matrix will contain terms that cancel the L3 term in (7).
In a non-relativistic calculation v = p/m, whereas for the relativistic case v = p/E. Examples of the differential cross section are:
Elastic scattering of a particle into a solid angle
d
d
Projectile scattering into a solid angle and momentum bite p.
pdpd
d
2
Cross section for 3 body final state, as in 3He(e,e’p)2H, ( 2 bound nuclear states)
epeepe
pdpdd
d
5
5
pepepepe
ppdpdpdd
d
6
Multi-body final state where the electron and proton are detected, in 3He(e,e’p)X ,
Examples of calculating the S-matrix ( ref. 2 chapter 3). We want to calculate
T
TTSTW ba
baT
2|)2/,2/(|)(lim
00000000 ,|),(),(tc,| so, ,),(),(),( tattUttUttUttUttU IIsince
From eqn(6)
000000
000*00
*00
0000
,|t,b'),(,|),(|t,b',|,'
1),(),( since so),,(|t,b'|t,b' and
,|),(),(|,',|,'
tbttStattUtctb
ttUttUttU
tattUttUtbtctb
bbaI
I
6
The states are assumed to be orthonormal so we get
T/2- a,| a| abbreviate wewhere
(8) ,|)2/,2/(|)2/,2/( aTTUbTTS Iba
Substituting eqn (2) into eqn (8) yields
2/
2/(9) ,|)}2/,'()2/,'('1{|)2/,2/(
T
T IIba aTtUTtHdti
bTTS
Equation (9) implicitly includes the time evolution operator, so solutions to (9) are obtained through successive iterations, for example,
)2/,"()2/,"("1)2/,'('
2/TtUTtHdt
iTtU I
t
T II If we substitute this expression into eqn (9) we obtain
2/
2/)}{2/,'('1{|)2/,2/(
T
T Iba TtHdti
bTTS
'
2/|)}2/,"()2/,"("1
t
T II aTtUTtHdti
7
2/
2/
'
2/
2
)1(
|)2/,"()2/,"(")2/,'(')i
(-|b
)2/,2/(|)2/,2/(
T
T
t
T III
baba
aTtUTtHdtTtHdt
TTSabTTS
(10) ,|)2/,'(|')2/,2/( where2/
2/
)1( T
T Iba aTtHbdti
TTS
Eqn (10) is the first approximation, or Born approximation, in the perturbation series expansion of the S-matrix. The expansion can be carried out to higher orders as can be seen. The second order term in the expansion is
2/
2/
'
2/
2)2( |)2/,"()2/,'(|b"')i
(-)2/,2/(T
T II
t
Tba aTtHTtHdtdtTTS
We will focus on the first term, equation (10), as an approximation for the S-matrix.
8
From equation (3) we obtain HI.
))'(exp(|),'(|
and
|))'(exp(|),'(
and
|),'(),'(),'(||),'(|
001
0
000
00001
00
ttEi
bttUb
attEi
attU
attUttVttUbattHb
b
a
I
aTtVbTtEEi
dti
TTS ab
T
Tba |)2/,'(|))2/')((exp(')2/,2/(2/
2/
)1(
Consider the case where the interaction V is time independent. Then the time integral only includes the exponential term. As we let T go to infinity the time integral becomes a delta function in energy. However, we will take the limit of T to infinity a bit later in the calculation.
9
2/
2/
)exp()2/exp()2/,2/(T
T
baba tidtTii
TTI
/)( where ba ab EE
T.by (11) of bottom and top themultiplied wewhere
(11) ,2/
)2/sin()2/exp()2/,2/(
T
TTTi
iTTI
ba
baba
(12) ,a|V|b2/
)2/sin()2/exp()2/,2/()1(
T
TTTi
iTTS
ba
bababa
2
22
22
3
)2/(
)2/(sin
)2
(2
)2
(4lim||
v T
TT
T
VL
ba
ba
Tba
Substituting (12) into (7) we get for the differential cross section,
10
We now take advantage of eqn 5.6.31 in ref. 1,
T/2 where,)()(sin
lim2
2
x
x
x
And we obtain for the cross section
(13) ),(2||v
22
3)1(
babaVL
We see that conservation of energy automatically appears if the time interval T is long enough. We will use (13) to calculate the quantum mechanical cross section in the first approximation (Born approximation) of the S-matrix. Note that the matrix element is,
aVbVba ||11
Cross section for potential scattering
In a practical scattering situation we have a finite acceptance for a detector with a solid angle . There is a range of momenta which are allowed by kinematics which can contribute to the cross section. The cross section for scattering into is then obtained as an integral over all the allowed momenta for that solid angle. In the case of potential scattering we will assume only elastic scattering is allowed. This means that there is a change in momentum between the incoming particle and outgoing particle. We are using periodic boundary conditions, or box normalization, ( see ref. 2) for which the incoming and outgoing states are plane wave states. The incoming wave |a> is
.components z andy for the same theand
(15a) ,,...2,1,0 ,2
k and
(14a) ,)exp(1
|)(
ax
2/3
axax
aa
nL
n
rkiL
arr
12
.components z andy for the same theand
(15b) ,,...2,1,0 ,2
k and
(14b) ,)exp(1
|)(
bx
2/3
bxbx
bb
nL
n
rkiL
brr
The outgoing state |b> is
All possible outgoing states |b> which can be accepted by the solid angle must be included in the summation.
zyx nnn
ba
L)(2|a|V|b|
v2
2
3
We next substitute the matrix element into the above equation. This will be an integral over all relevant degrees of freedom needed to describe the states a and b. For a position dependent interaction and the plane waves above, the integration is over configuration space.
13
arrVrrbrdrdaVb |''|||'|| 33
But we will consider only potentials diagonal ( local) in configuration space.
)kp( , transfer"momentum" theis ,
where),(1
)()exp(1
)(V
so ,)'()()',(
333
ab kkq
qfL
rVrqiL
drq
rrrVrrV
Notice that the matrix element is proportional to the Fourier transform of the potential.
ak
bk
q
(16) ,)(2|)(|L
1
v2
62
3
zyx nnn
baqfL
14
(17) ,)(2|)(|)L
1)(
L
1)(
L
1(
v
1 22
zyx nnn
baqf
In eqn (17) we note the sum over possible n values. The smallest change possible in n is dn = 1. We want to convert the sum in (17) into an integral over wave numbers.
And from eqns (15) we realize that
LLLL
dn
L
dn
L
dndkdkdk zyxzyx 111
222
(18) ,222
)L
1)(
L
1)(
L
1(
zy
nnn kkk
x dkdkdk
zyx zyx
3
2
33
3
)2()2()2( kzyx dkdkdkdkdkdk
15
We substitute (18) into (17) an obtain
(20) ,)))()((1
()( and
(19) ,)(2|)(|)2(v
1
ba
23
2
2
ab
kkk
bak
kEkE
qfdkk
dkzyxk
Note that in the delta function in (20) we have functions ( the energies) of the momenta k, whereas the variable of integration is k. We use the following property of functions of the delta function.
f(x) of zeroes theare x where,||
)())(( i
ii
xx
i
dxdfxx
xf
In the case of potential scattering, or elastic scattering, the zeroes occur for
k = kb = ka . The derivative of the energy with respect to the wave number k is
16
v)(1)( 22
E
p
E
kmk
dk
dkE
dk
d
Integrating over k, the delta function selects the value k = ka which we will simply call k, the magnitude of the initial wave number. Thus,
(21) ,|)(|)2(v
1
|)(|)2(v
2
22
2
22
23
2
22
qfk
d
d
qfk
kk
k
We are now in a position to evaluate the differential elastic cross section using eqn (21) for any potential V. We will need to find the Fourier transform of the potential as a function of q.
17
(1) “Modern Quantum Mechanics – Revised Edition”, J. J. Sakurai, Addison-Wesley, 1994
(2) “Relativistic Quantum Mechanics and Field Theory”, Franz Gross, John Wiley & Sons, 1993
18
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