Power System Protection - Engineeringlorama/Week2b.pdfPower System Protection Dr. Lionel R. Orama...

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Power System Protection

Dr. Lionel R. Orama Exclusa, PEWeek 2

Jan 25/2006 Copyright L.R. Orama 2006 2

CT Performance

Readings-Mason Chapter 7,pgs 99-115• Steady State (Symmetrical)

– Basics– Accuracy Classification– Effects on Accuracy– Evaluating CT performance

• Transient (Asymmetrical)– Time to Saturation

Copyright L.R. Orama 2006 3

Current Transformers (CT)

• CT produces current proportional to the system conductor current

• Ideal CT has:

• Rated ICT typically 5A (called the CT 2ry

current)

CT

SYSCT N

II =

Copyright L.R. Orama 2006 4

Current Transformers (CT’s)

4002000:5

2001000:5

120600:5

80400:5

40200:5

20100:5

1050:5

TurnsCurrent

Common ratios Polarity dot convention

Copyright L.R. Orama 2006 5

Current Transformers (CT)

36-550KV4000A

12-40KV2500A

5-25KV4000A

600V2000A

Copyright L.R. Orama 2006 6

CT Steady State PerformanceEquivalent circuit of a

bushing CT• CT is a toroid, leakage

flux is minimum– No leakage reactance

in circuit equivalent

• ZB is called the Burden (load)– Impedance in the

internal circuits of the relay

100% ×=CT

E

I

IRatioError

BCTT ZIV =

EP

CT IN

II −=

Jan 27/2006 Copyright L.R. Orama 2006 7

CT Accuracy ClassificationWith 20 times rated 2RY current

(5A X 20 = 100A), CT is classified on a basis of the VMAXit can sustain without exceeding a specified Ratio Error (RE)

• Example using line 2 on the table (10T20):– 10 is the %RE (at 20 times

Rated Current-100A)– 20 is the VMAX it can maintain

without exceeding the 10% RE (VRATING)

• T is for tested device• C for calculated device• RE < 10% for ICT < 100A and

ZB< VT/100A

100% ×=CT

E

I

IRatioError

CalcTest

10C80010T800

10C40010T400

10C20010T200

10C10010T100

10C5010T50

10C2010T20

10C1010T10

Copyright L.R. Orama 2006 8

Copyright L.R. Orama 2006 9

CT Accuracy Classification

• Determination of CT accuracy class– From CT Saturation Curve (120 turns)

• ICT=100A, IE=10A, ES=500V• VT=ES-100RCT (sat curve determines the RCT)

– Ex., if RCT=0.372ohm, then

• VT=500V-100A(0.372ohm)=463V

– CT Accuracy Class would be C400• Since from last table class jumps from 400 to 800

– This is true assuming all I’s, V’s & Z’s are in phase

Jan 30/2006 Copyright L.R. Orama 2006 10

CT Accuracy Classification

• True error at VT = RatingES=VT+ICTRCT

• At VT=800V & ICT=100A• RCT=(.0031ohm/turn)X240turns=0.774ohm• ES=800+100(0.744)=874V (on the curve)• IE=0.4A• %RE= IE /ICT X100=0.4%<10% (OK!)

Copyright L.R. Orama 2006 11

CT Accuracy Classification

( )

100×=

+

−=

−==

−=

+=

CT

E

BCTEP

S

BEP

BCTT

EP

CT

TCTCTS

I

IRE

ZRIN

IE

ZIN

IZIV

IN

II

VRIE

Accu.REIEESN

Accu.REIEESZB

Accu.REIEESRCT

Accu.REIEES

upIP

Accu.REIEES

The higher the turns ratio of the CT, the better the accuracy.

Copyright L.R. Orama 2006 12

CT Accuracy Classification

Is the CT adequate?

%10

100,100

100,100

<

<=

≤=

RE

then

AIA

VZ

orA

VZAI

or

VV

CTRATING

B

RATINGBCT

RATINGT

Copyright L.R. Orama 2006 13

Evaluating CT Performance

( )

( ) ( )

ES

BCTEBCTP

S

BCTEP

S

EP

CTBCTCTCTS

BCTTTCTCTS

IKKE

ZRIZRN

IE

ZRIN

IE

IN

IIZIRIE

ZIVVRIE

21 −=

+−+=

+

−=

−=+=

=+=

L

L

Given IP and a relay IPU, calculate weather or not the relay will operate(ICT>IPU)

Copyright L.R. Orama 2006 14

Evaluating CT Performance

( )

2

1

1

2

1

21

0

0

K

KIE

KEI

ZRK

ZRN

IK

IKKE

ES

SE

BCT

BCTP

ES

=→=

=→=+=

+=

−=

Copyright L.R. Orama 2006 15

Evaluating CT Performance

else

II

if

IN

II

puCT

EP

CT

−=

IE is the operating point of the relay atthe above conditions, then

Try another IPU setting or another N

IPU setting is OK!

Copyright L.R. Orama 2006 16

Transient Performance

Copyright L.R. Orama 2006 17

Transient Performancev t( )

V

10sin ω t⋅ θ+( )⋅:= i t( )

V

Zsin ω t⋅ θ+ φ−( ) sin θ φ−( ) exp

t−τ

⋅−

⋅:=

0 0.01 0.02 0.03 0.04 0.05 0.06

1000

500

500

1000Short Circuit Current (5mi dist. line)

time (s)

curr

ent (

A),

tent

h of

vol

tage

(V

)

i t( )

v t( )

t

3 Feb 2006 Copyright L.R. Orama 2006 18

Transient Performance• Offset fault current

* W.A. Elmore, Protective Relaying Theory & Application,Marcel Dekker, NY, 1982, pg. 80.

Copyright L.R. Orama 2006 19

Transient Performance

* W.A. Elmore, Protective Relaying Theory & Application,Marcel Dekker, NY, 1982, pg. 80. dt

dNe

φ−=

Copyright L.R. Orama 2006 20

Transient Performance

* W.A. Elmore, Protective Relaying Theory & Application,Marcel Dekker, NY, 1982, pg. 80.

Copyright L.R. Orama 2006 21

Transient Performance• Offset fault current

– CT response

* W.A. Elmore, Protective Relaying Theory & Application,Marcel Dekker, NY, 1982, pg. 80.

Copyright L.R. Orama 2006 22

Transient Performance

• CT Flux density for theasymmetrical fault current

−=

−⋅=

=

)cos(2

)sin(1

110

2

1

2

8

teIi

teAN

IRB

AB

DC

DC

t

t

DC

ω

ωω

τ

φ

τ

τ

B-Flux Density (lines/in2)

Total CT Burden (resistive)

Copyright L.R. Orama 2006 23

Transient Performance• Time to Saturation

2

8102

1ln

ANk

kIR

Bt

DC

SDC

⋅=

−−=

ττ BS-Saturation Flux Density

125,000 to 130,000 lines/in2

•States how long the CT will accurately reproduces the fault current•Time constant is that of the power system•R is the resistance of the CT + wiring

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