View
29
Download
1
Category
Preview:
DESCRIPTION
Physics 2102 Jonathan Dowling. Physics 2102 Lecture: 04 WED 21 JAN. Electric Fields II. Michael Faraday (1791-1867). Version: 11/14/2014. - PowerPoint PPT Presentation
Citation preview
April 19, 2023
Physics 2102 Physics 2102 Lecture: 04 WED 21 JAN Lecture: 04 WED 21 JAN
Electric Fields IIElectric Fields II
Physics 2102
Jonathan Dowling
Version: 04/19/23
QuickTime™ and a decompressor
are needed to see this picture.
QuickTime™ and a decompressor
are needed to see this picture.
Michael Faraday (1791-1867)
Electric Charges and Electric Charges and FieldsFields
First: Given Electric Charges, We Calculate the Electric Field Using E=kqr/r3.
Example: the Electric Field Produced By a Single Charge, or by a Dipole:
Charge Produces E-Field
E-Field Then Produces Force on Another Charge
Second: Given an Electric Field, We Calculate the Forces on Other Charges Using F=qE
Examples: Forces on a Single Charge When Immersed in the Field of a Dipole, Torque on a Dipole When Immersed in an Uniform Electric Field.
Continuous Charge Continuous Charge DistributionDistribution
• Thus Far, We Have Only Dealt
With Discrete, Point Charges.
• Imagine Instead That a Charge
q Is Smeared Out Over A:
– LINE
– AREA
– VOLUME
• How to Compute the Electric
Field E? Calculus!!!
q
q
q
q
Charge DensityCharge Density
• Useful idea: charge density
• Line of charge:
charge per unit length
=
• Sheet of charge:
charge per unit area =
• Volume of charge:
charge per unit volume =
= q/L
= q/A
= q/V
Computing Electric FieldComputing Electric Field of Continuous Charge of Continuous Charge
DistributionDistribution• Approach: Divide the Continuous Charge Distribution Into Infinitesimally Small Differential Elements
• Treat Each Element As a POINT Charge & Compute Its Electric Field
• Sum (Integrate) Over All Elements
• Always Look for Symmetry to Simplify Calculation!
dq
dq = dLdq = dSdq = dV
Differential Form of Differential Form of Coulomb’s LawCoulomb’s Law
q2
€
rE 12
P1 P2
E-Field at
Point
dq2
€
dr E 12
P1
Differential dE-Field at Point
€
dr E 12 =
k dq2
r122
€
rE 12 =
k q2
r122
Field on Bisector of Charged Field on Bisector of Charged RodRod
• Uniform line of charge +q spread over length L
• What is the direction of the electric field at a point P on the perpendicular bisector?
(a) Field is 0.(b) Along +y(c) Along +x
•Choose symmetrically located elements of length dq = dx
•x components of E cancel
q
L
a
P
o
y
x
dx
€
ds E
dx
€
dr E
€
↑E
Line of Charge: QuantitativeLine of Charge: Quantitative
• Uniform line of charge, length L, total charge q
• Compute explicitly the magnitude of E at point P on perpendicular bisector
• Showed earlier that the net field at P is in the y direction — let’s now compute this!
q
L
a
P
o
y
x
Line Of Charge: Field on bisectorLine Of Charge: Field on bisector
Distance hypotenuse:
€
d = a2 + x 2( )
1/ 2
2
)(
d
dqkdE =
Lq=Charge per unit length:
2/322 )(
)(cos
xa
adxkdEdEy +
== θq
L
a
P
ox
dE
θ
dx
d
2/122 )(cos
xa
a
+=θ
AdjacentOverHypotenuse
Line Of Charge: Field on Line Of Charge: Field on bisectorbisector
∫− +
=2/
2/2/322 )(
L
Ly
xa
dxakE λ
Point Charge Limit: L << a
€
=2kλL
a 4a2 + L2
2/
2/222
L
Laxa
xak
−⎥⎦
⎤⎢⎣
⎡
+=
€
Ey =2kλL
a 4a2 + L2≅
2kλ
a
Line Charge Limit: L >> a
€
Ey =2kλL
a 4a2 + L2≅
kλL
a2=
kq
a2
Integrate: Trig Substitution!
Coulomb’sLaw!
€
Nm2
C
1
m
C
m
⎡
⎣ ⎢
⎤
⎦ ⎥=
N
m
⎡ ⎣ ⎢
⎤ ⎦ ⎥
Units Check!
Binomial Approximation from Taylor Series:
x<<1
Binomial Approximation from Taylor Series:
x<<1
€
2kλL
a 4a2 + L2=
kλL
a21+
L
2a
⎛
⎝ ⎜
⎞
⎠ ⎟2 ⎡
⎣ ⎢
⎤
⎦ ⎥
−1/ 2
≅kλL
a21−
1
2
L
2a
⎛
⎝ ⎜
⎞
⎠ ⎟2 ⎡
⎣ ⎢
⎤
⎦ ⎥≅
kλL
a2 ; (L << a)
2kλL
a 4a2 + L2=
2kλL
aL1+
2a
L
⎛
⎝ ⎜
⎞
⎠ ⎟2 ⎡
⎣ ⎢
⎤
⎦ ⎥
−1/ 2
≅2kλ
a1−
1
2
2a
L
⎛
⎝ ⎜
⎞
⎠ ⎟2 ⎡
⎣ ⎢
⎤
⎦ ⎥≅
2kλ
a ; (L >> a)
€
1± x( )n≅1± nx
€
1± x( )n≅1± nx
Example — Arc of Charge: Example — Arc of Charge: QuantitativeQuantitative
• Figure shows a uniformly charged rod of charge -Q bent into a circular arc of radius R, centered at (0,0).
• Compute the direction & magnitude of E at the origin.
y
x450
x
y
θ
dQ = Rdθdθθθ coscos
2R
kdQdEdEx ==
∫∫ ==2/
0
2/
02
coscos)(
ππ
θθλθθλ
dR
k
R
RdkEx
R
kEx
=
R
kEy
=
R
kE
2= 2Q/(R)
E–Q
Example : Field on Axis of Example : Field on Axis of Charged DiskCharged Disk
• A uniformly charged circular disk (with positive charge)
• What is the direction of E at point P on the axis?
(a) Field is 0(b) Along +z(c) Somewhere in the x-y plane
P
y
x
z
Example : Arc of Example : Arc of ChargeCharge
• Figure shows a uniformly charged rod of charge –Q bent into a circular arc of radius R, centered at (0,0).
• What is the direction of the electric field at the origin?
(a) Field is 0.(b) Along +y(c) Along -y
y
x
• Choose symmetric elements• x components cancel
SummarySummary• The electric field produced by a system of charges at any point in space is the force per unit charge they produce at that point. • We can draw field lines to visualize the electric field produced by electric charges. • Electric field of a point charge: E=kq/r2
• Electric field of a dipole: E~kp/r3
• An electric dipole in an electric field rotates to align itself with the field. • Use CALCULUS to find E-field from a continuous charge distribution.
Recommended