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Thursday, 10/2 Unit 3: Work and Forces
If you are new to the class please come see me. Pick up warm-up from Physics bin Read the ‘I can’ statements on the side board. Review dates below
Upcoming dates Wednesday, 10/8 – quiz Friday, 10/9 – Unit 3 test Friday, 10/24 – last day to turn in 2SW extra credit Friday, 10/31 – end of 2SW
Warm-upA rock of mass 5.0 kg is at rest on the ground. For each situation described, draw a free body diagram (forces must be to scale) and calculate the forces acting on the rock, and describe the motion (direction moving and if it is accelerating). A) The rock is at rest on the ground. Calculate the normal force exerted by the ground on the rock.
b) A rope is tied to the rock and is used to pull the rock upwards. The rock accelerates at 5.0 m/s2. Calculate the force of tension in the rope.
c) As the rock is pulled upwards, the force exerted by the rope is reduced to 40 N. Calculate the acceleration of the rock.
Newton’s 3rd Law, the Law of Interaction
If (object 1) exerts a (type) force in the (direction) direction on (object 2), then (object 2) is exerting a (same type) force directed (opposite direction) on (object 1) simultaneously.
Quiz Put your phone in your bag. If you don’t
have a bag put your phone on my desk When you are done flip your quiz over.
Video http://dsc.discovery.com/videos/assignment-di
scovery-shorts-newtons-explanation-of-gravity.html
Review Equation What does the G in the equation mean?
Will it ever change? Describe the relationship between mass
and distance between the objects. What variable has greatest role in
evaluating the force of gravity between objects? Support your answer
Practice Problem 1Tom has a mass of 70.0-kg and Sally has a mass of 50.0-kg. Tom and Sally are standing 20.0m apart on the dance floor. Sally looks up and sees Tom. She feels an attraction. If the attraction is gravitational, find its size. Assume that both Tom and Sally can be replaced by spherical masses.
Practice Problem 2
What is the gravitational attraction between two spheres (msphere = 1.67 X 10-27 kg) at a distance of 5.0 X 10-15 m?
7.44 x10-36 N
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