Lesson 6-7 Pages 298-302 Using Percent Equations Lesson Check 6-6

Lesson 6-7 Pages 298-302

Using Percent Equations

Lesson Check 6-6

What you will learn!1. How to solve percent problems using percent equations.

2. How to solve real-life problems involving discount and interest.

Percent Percent equationequationDiscountDiscountSimple interestSimple interest

What you really need to know!

In a percent equation, the percent is written as a decimal.

What you really need to know!

% of BASE = PART

The word “ of ” means multiply!

What you really need to know!

The number after the word “of” is the base!

The number near the word “is” is the part!

Example 1:

Find 38% of 22.% x BASE = PART38% x 22 = PART0.38 x 22 = PART8.36 = PART

Example 2:

19 is what percent of 25?

% x BASE = PART% x 25 = 19% = 19 ÷ 25% = 0.76 76%

Example 3:

84 is 16% of what number?

% x BASE = PART16% x BASE = 840.16 x BASE = 84BASE = 84 ÷ 0.16BASE = 525

Example 4:

The regular price of a ring is $495. It is on sale at a 20% discount. What is the sale price of the ring?20% x $495 = $99$495 - $99 = $396

Example 5:

Suppose you invest $2,000 at an annual interest rate of 4.5%. How long will it take to earn $495?

I = prt

I = prtI is interest

p is principal

r is annual interest rate

t is time in years

Example 5:

Suppose you invest $2,000 at an annual interest rate of 4.5%. How long will it take to earn $495?

495 = 2,000 • 0.045 • t5.5 years = t

Page 300

Guided Practice

#’s 4-11

Pages 298-300 with someone at home and

study examples!

Read:

Homework: Pages 301-302

#’s 12-40 even

#’s 44-61

Lesson Check 6-7

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Lesson 6-7

Lesson Check 6-7