Lecture 2: Basic principles of electromagnetic magnetic radiation (EMR)

Preview:

DESCRIPTION

Lecture 2: Basic principles of electromagnetic magnetic radiation (EMR). Prepared by Rick Lathrop 9/99 Updated 9/04. Basic interactions between EMR and the earth surface. Reflection: specular reflection or scattering Absorption Transmission. q 1 q 2. q 1 = q 2. - PowerPoint PPT Presentation

Citation preview

Lecture 2: Basic principles of electromagnetic magnetic

radiation (EMR)

Prepared by Rick Lathrop 9/99

Updated 9/04

Basic interactions between EMR and the earth surface

• Reflection:specular reflection or scattering

• Absorption

• Transmission

1 2

emission

EMR re-emitted as thermal energy

Shorter s refracted more

First law of thermodynamics

• Principle of conservation of energy

• Energy can neither be created or destroyed, it can only be transformed

• Incident E = R + A + T

E R

A T

Adapted from Lillesand & Kiefer Remote Sensing and Image Interpretation

Units of EMR measurement

• Irradiance - radiant flux incident on a receiving surface from all directions, per unit surface area, W m-2

• Radiance - radiant flux emitted or scattered by a unit area of surface as measured through a solid angle, W m-2 sr-1

• Reflectance - fraction of the incident flux that is reflected by a medium

Dual nature of EMR

• EMR as a wave

• EMR as a particle (photon)

Wave nature of EMR

• c = * where• c = 3 x 108 m/sec = frequency,

measured in hertz (cycles/sec) = wavelength• inverse relationship between wavelength

and frequency

EMR wavelength vs. frequencyas gets shorter, v goes higher

= 10 m

= 1013 Hz

= 1.0 m

= 1014 Hz

= 0.1 m

= 1015 Hz

Wave nature of EMR: translating between wavelength and frequency

• c = *

where• c = 3 x 108 m/sec

Example: = 600 Mhz c / orc /x 108 m/sec / 600 x 106 hz =

x 108 m/sec / 6 x 108 hz = m

What EMR region is this wavelength? microwave

The electromagnetic spectrum

The electromagnetic spectrum

Comparative Sizes: from subatomic to human scales

Atom Nucleus

Atom

Molecule

Bacteria

Pinhead

Honeybee

Human & larger

adapted from NY Times graphic 4/8/2003

The visible spectrum

• The visible spectrum is only a tiny window

• We are blind to 99.99% of the energy in the universe

• One of the strengths of remote sensing is that we have created devices that allow us to see beyond the range of human vision

Herschel Discovers Infrared Light• Sir Frederick Herschel (1738-1822)

used a prism to split sunlight to create a spectrum and then measured the temperature of each color. He also included a control just outside the visible colors. He found to his surprise that the control actually had a higher temperature than the visible colors. Based on this observation, he concluded that there must be additional light energy beyond the visible, now known as near infrared.

Incidentally if the peak of sunlight energy is in the shorter visible wavelengths, why did Herschel find the infrared to be hotter. Due to the nonlinear nature of refraction, his prism concentrated the infrared light, while dispersing the shorter wavelength visible colors.

http://coolcosmos.ipac.caltech.edu/cosmic_classroom/classroom_activities/herschel_experiment.html

Gee Whiz:

Why do UV and not NIR rays cause sunburn?

Particle nature of EMR

• E = h * = (h * c)/

where

• E = energy of a photon, measured in joules

• h = Planck’s constant 6.626 x 10-34 J sec

• inverse relationship between wavelength and energy

Why do UV and not NIR rays cause sunburn?

• E = (h * c)/ = (6.626 x 10-34 J sec)(3 x 108 m/sec)/ = 19.878x10-26 J m /

• UV m– E = 19.878x10-26 J m / xm = 66.26 x 10-20 J

• NIR m– E = 19.878x10-26 J m / xm = 22.09 x 10-20 J

UV has approximately 3x the amount of energy per quanta

Gee Whiz:

Which emits more energy – the Sun or Earth?

Relationship between temperature and EMR

• M = * T4

where

• M = total radiant exittance W m-2

= Stefan-Boltzman constant 5.6697 x 10-8 W m-2 K-4

• T = temperature in Kelvin (K)– 0oC = 273.15K

Relationship between temperature and EMR

• M = * T4 where

• What is M for the Sun? T= 6000K– (5.6697 x 10-8 W m-2 K-4)(6000K)4 = – (5.6697 x 10-8 W m-2 K-4)(1.296 x 1015 K4) = = 7.35 x 107 W m-2

• What is M for the Earth? T= 300K (27oC) - (5.6697 x 10-8 W m-2 K-4)(3000K)4 = 4.59 x 102 W m-2

Relationship between temperature and EMRObjects emit energy over a range of wavelengths. As the temperature of the object increases, its radiant flux increases. The wavelength of maximum flux depends on the temperature of the object.

Radiant Flux

Wavelength

Blackbody at temperature T1

Blackbody at temperature T2

T1 > T2

Gee Whiz:

Why is the outside of a candle’s flame red, while the inner flame is blue?

Relationship between wavelength and temperature

m = A / T

where m = wavelength of max radiant exittance

A = 2898 m K T = temperature K Inverse relationship between temperature and m

Relationship between wavelength and temperature

m = A / T

where A = 2898 m K

• What is m for the Sun? T= 6000K

m = 2898 m K/6000K = 0.483um

m for the sun is in the visible

• What is m for the Earth? T= 300K (27oC)

m = 2898 m K/300K = 9.7m

m for the earth is in the thermal IR

Gee Whiz:

Why do humans see in the ‘visible’ and not the NIR?

Human Color Vision

• Human eye contains 2 types of photoreceptors: rods and cones

• Rods are more numerous and more sensitive to the amount of visible light but are not sensitive to color

• 3 types of cones: roughly sensitive to blue (445nm), green (535nm) and red (575nm)

For more info on color vision go to:

http://hyperphysics.phy-astr.gsu.edu/hbase/vision/colviscon.html#c1

Gee Whiz:

Why is the sky blue and clouds white?

Atmospheric windows

Graphic from http://earthobservatory.nasa.gov/Library/RemoteSensingAtmosphere/

•Specific wavelengths where a majority of the EMR is absorbed by the atmosphere•Wavelength regions of little absorption known as atmospheric windows

Atmospheric interference with EMR• Shorter wavelengths strongly scattered,

adding to the received signal

• Longer wavelengths absorbed, subtracting from the received signal

0.4 0.5 0.6 0.7 0.8 1.1 um

Ref

Signal increased by scattering

Signal decreased by absorption

Adapted from Jensen, 1996, Introductory Digital Image Processing

Why is the sky blue and clouds white?

Incoming sunlight

Air molecules scatter short blue light, longer s transmitted

Rayleigh scattering

Clouds scatter all s of visible light, appear white

Mie scattering

Breakdown of EMR components received at the sensor

Fundamental assumptions

• Objects that are related can be detected, identified, and described by analyzing the energy that is reflected or emitted from them

•Measurements over several bands make up a “spectral response pattern” or signature

•This signature is different for different objects

•This difference can be analyzed

Gee Whiz:

Why are plants green?

Chlorophyll pigment is contained in minute structures called plastids that are found in the leave’s parenchyma cells. Chlorophyll differentially absorbs red and blue wavelengths of light, there is less absorption in the green and nearly no absorption in the near IR.

Graphic from: http://iusd.k12.ca.us/uhs/cs2/leaf_cross-section.htm

As light waves move from medium of one density to another (e.g., from water to air), the waves are refracted (i.e., changes direction).

Graphic from: http://www.olympusmicro.com/primer/lightandcolor/refraction.html

How plant leaves reflect lightAs light moves from a hydrated cell to an intercellular space it gets refracted, sometimes multiple times. Eventually, some light may be scattered back out through the upper leaf surface and some transmitted down through the leaf.

Blue & red light strongly absorbed by chlorophyll. Green light is not as strongly absorbed

NIR light (which is not absorbed) is scattered within leaf: some reflected back, some transmitted through

Cross-section of leaf

How plant leaves reflect light

Sunlight B G R NIR

LeafTransmitted light

Incoming light

Reflected light

An example-plant leaves• Chlorophyll absorbs large % of red and

blue for photosynthesis- and strongly reflects in green (.55m)

• Peak reflectance in leaves in near infrared (.7-1.2m) up to 60% of infrared energy per leaf is scattered up or down due to cell wall size, shape, leaf condition (age, stress, disease), etc.

• Reflectance in Mid IR (2-4m) influenced by water content-water absorbs IR energy, so live leaves reduce mid IR return

Spectral reflectance characteristics are both spatially and temporally variable. For example, each leaf (even within the same species) is different and can change. Thus you should think of a spectral signature as more as a spectral “envelope”.

Gee Whiz:

Why do plants turn yellow as they senesce?

As a leaf senesces, the cellular structure starts to break down and may change the NIR as well as the visible reflectance.

A leaf’s chlorophyll (1) begins to break down as the leaf senesces (as in the autumn). Accessory plant pigments (such as carotenoids and anthocyanins) are also found in the leaf cells but are generally masked by chlorophyll. Without chlorophyll, these pigments dominate. Carotenoids absorb blue to blue green wavelengths and thus appear yellow to orange (2). Anthocyanins absorb blue to green wavelengths and thus appear magenta (purple) to red (3) .

Graphic from: http://www.fs.fed.us/conf/fall/leafchng_nf.htm

Extra Puzzler 1

• FM Radio waves have a frequency of approx. 100MHz and this energy passes through your body every second of every day with no harm done! Why?

Extra Puzzler 1

• Radio wave energy passes through your body every second of every day with no harm done! Why?

• E = (h * = (6.626 x 10-34 J sec) (100MHz) = 662.6 x 10-28 J = 6.626 x 10-26 J

• Remember NIR light (which is harmless) has an quanta E of 2.209 x 10-19 J, or approx. 7 orders of magnitude higher.

Extra Puzzler 2

• If a lava flow has a temperature of approximately 1000oC, what would be the best wavelength to sense it?

Extra Puzzler 2• If a lava flow has a temperature of approximately

1000oC, what would be the best wavelength to sense it? m = A / T

m = wavelength of max radiant exittance

A = 2898 m K T = temperature K m = A / T = 2898 m K / 1273 K

m = 2.27 m

Which is in the short-middle infrared

Recommended