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If the velocity of a car decreases by 10 m/s in every 5 seconds, what is the average acceleration of the car?
Question 1
A. 10 m/s2
B. -10 m/s2
C. 2 m/s2
D. -2 m/s2
Chapter Assessment QuestionsChapter
3
Chapter Assessment Questions
Answer: D
Answer 1
Chapter
3
Reason: Average acceleration is the change of velocity in unit time. Therefore acceleration in this case is:
What will be the change in displacement (d) of a train starting from rest and moving with a constant acceleration (a), if the motion last for t seconds?
Question 2
A.
B.
C.
D.
Chapter Assessment QuestionsChapter
3
Chapter Assessment Questions
Answer: B
Answer 2
Chapter
3
Reason: From the equation of position with constant acceleration, we can write:
A car starting from rest moves with a constant acceleration of a m/s2, what will be the velocity (vf) of the car after traveling d meters?
Question 3
A. vf = 2ad
B. vf = ad
C. vf2 = ad
D. vf2 = 2ad
Chapter Assessment QuestionsChapter
3
Chapter Assessment Questions
Answer: D
Answer 3
Chapter
3
Reason: From the equation of velocity with constant acceleration, we can write vf
2 = vi2 + 2ad (where d is the change in
displacement) But since car is starting from rest vi = 0
Therefore, vf 2 = 2ad.
The acceleration due to gravity on Moon is 6 times less than the gravity on Earth. If a ball on the Moon is dropped from a height of 20 m, What is the velocity of the ball after 1 s?
Question 4
A.
B.
C.
D.
Chapter Assessment QuestionsChapter
3
Chapter Assessment Questions
Answer: A
Answer 4
Reason:
Chapter
3
A ball is thrown vertically upwards, which of the following statements is true when the ball is at the maximum height?
Question 5
A. Acceleration of the ball is zero.
B. Velocity of the ball is maximum.
C. Velocity of the ball is zero.
D. The rate of change of velocity is zero .
Chapter Assessment QuestionsChapter
3
Chapter Assessment Questions
Answer: C
Answer 5
Reason: When the ball reaches the maximum height, it stops and starts falling down. Hence when the ball is at the maximum height the velocity of the ball is zero
Chapter
3
Standardized Test Practice
1. A ball rolls down a hill with a constant acceleration of 2.0 m/s2. The ball starts at rest and travels for 4.0 s before it stops. How far did the ball travel before it stopped?
Multiple Choice
Chapter
3
A. 8.0 m
B. 12 m
C. 16 m
D. 20 m
Standardized Test Practice
2. A ball rolls down a hill with a constant acceleration of 2.0 m/s2. The ball starts at rest and travels for 4.0 s before it stops. What was the ball’s velocity just before it stopped?
Multiple Choice
Chapter
3
A. 2.0 m/s
B. 8.0 m/s
C. 12 m/s
D. 16 m/s
Standardized Test Practice
3. A driver of a car enters a new 110-km/h speed zone on the highway. The driver begins to accelerate immediately and reaches 110 km/h after driving 500 m. If the original speed was 80 km/h, what was his rate of acceleration?
Multiple Choice
Chapter
3
A. 0.44 m/s2
B. 0.60 m/s2
C. 8.4 m/s2
D. 9.80 m/s2
Standardized Test Practice
4. A flowerpot falls off the balcony of a penthouse suite 85 m above the street. How long does it take to hit the ground?
Multiple Choice
Chapter
3
A. 4.2 s
B. 8.3 s
C. 8.7 s
D. 17 s
Standardized Test Practice
5. A rock climber’s shoe loosens a rock, and her climbing buddy at the bottom of the cliff notices that the rock takes 3.20 s to fall to the ground. How high up the cliff is the rock climber?
Multiple Choice
Chapter
3
A. 15.0 m
B. 31.0 m
C. 50.0 m
D. 1.00×102 m
Standardized Test Practice
6. A car traveling at 91.0 km/h approaches the turnoff for a restaurant 30.0 m ahead. If the driver slams on the brakes with an acceleration of –6.40 m/s2, what will be her stopping distance?
Multiple Choice
Chapter
3
A. 14.0 m
B. 29.0 m
C. 50.0 m
D. 100.0 m
Standardized Test Practice
7. What is the correct formula manipulation to find acceleration if using the equation vf
2 = vf2+2ad?
Multiple Choice
Chapter
3
A. (vf2 – vi
2)/d
B. (vf2 + vi
2)/2d
C. (vf – vi) 2/2d
D. (vf2 – vi
2)/2d
8. The graph shows the motion of a farmer’s truck. What is the truck’s total displacement? Assume that north is the positive direction.
Multiple Choice
Chapter
3 Standardized Test Practice
A. 150 m south
B. 125 m north
C. 300 m north
D. 600 m south
Standardized Test Practice
9. How can the instantaneous acceleration of an object with varying acceleration be calculated?
Multiple Choice
Chapter
3
A. by calculating the slope of the tangent on a distance versus time graph
B. by calculating the area under the graph on a distance versus time graph
C. by calculating the area under the graph on a velocity versus time graph
D. by calculating the slope of the tangent on a velocity versus time graph
Standardized Test PracticeChapter
3
10. Graph the following data, and then show calculations for acceleration and displacement after 12.0 s on the graph.
Extended Answer
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