Guided practice

Guided practiceGuided practice

Guided Practice - 1Guided Practice - 1A constant volume of oxygen is heated A constant volume of oxygen is heated

from 100 degrees Celsius to 185 degrees from 100 degrees Celsius to 185 degrees Celsius. The initial pressure is 4.1 atm. Celsius. The initial pressure is 4.1 atm. What is the final pressure?What is the final pressure?

TT11==

TT22==

PP11==

PP22==

Guided Practice - 1Guided Practice - 1A constant volume of oxygen is heated A constant volume of oxygen is heated

from from 100 degrees Celsius100 degrees Celsius to 185 degrees to 185 degrees Celsius. The initial pressure is 4.1 atm. Celsius. The initial pressure is 4.1 atm. What is the final pressure?What is the final pressure?

TT11==

TT22==

PP11==

PP22==

Guided Practice - 1Guided Practice - 1A constant volume of oxygen is heated A constant volume of oxygen is heated

from from 100 degrees Celsius100 degrees Celsius to 185 degrees to 185 degrees Celsius. The initial pressure is 4.1 atm. Celsius. The initial pressure is 4.1 atm. What is the final pressure?What is the final pressure?

TT11= 273 + 100 = 373 K= 273 + 100 = 373 K

TT22==

PP11==

PP22==

Guided Practice - 1Guided Practice - 1A constant volume of oxygen is heated A constant volume of oxygen is heated

from from 100 degrees Celsius100 degrees Celsius to to 185 degrees 185 degrees CelsiusCelsius. The initial pressure is 4.1 atm. . The initial pressure is 4.1 atm. What is the final pressure?What is the final pressure?

TT11= 273 + 100 = 373 K= 273 + 100 = 373 K

TT22==

PP11==

PP22==

Guided Practice - 1Guided Practice - 1A constant volume of oxygen is heated A constant volume of oxygen is heated

from from 100 degrees Celsius100 degrees Celsius to to 185 degrees 185 degrees CelsiusCelsius. The initial pressure is 4.1 atm. . The initial pressure is 4.1 atm. What is the final pressure?What is the final pressure?

TT11= 273 + 100 = 373 K= 273 + 100 = 373 K

TT22= 273 + 185 = 458 K= 273 + 185 = 458 K

PP11==

PP22==

Guided Practice - 1Guided Practice - 1A constant volume of oxygen is heated A constant volume of oxygen is heated

from from 100 degrees Celsius100 degrees Celsius to to 185 degrees 185 degrees CelsiusCelsius. The initial pressure is . The initial pressure is 4.1 atm.4.1 atm. What is the final pressure?What is the final pressure?

TT11= 273 + 100 = 373 K= 273 + 100 = 373 K

TT22= 273 + 185 = 458 K= 273 + 185 = 458 K

PP11==

PP22==

Guided Practice - 1Guided Practice - 1A constant volume of oxygen is heated A constant volume of oxygen is heated

from from 100 degrees Celsius100 degrees Celsius to to 185 degrees 185 degrees CelsiusCelsius. The initial pressure is . The initial pressure is 4.1 atm.4.1 atm. What is the final pressure?What is the final pressure?

TT11= 273 + 100 = 373 K= 273 + 100 = 373 K

TT22= 273 + 185 = 458 K= 273 + 185 = 458 K

PP11= 4.1= 4.1

PP22==

Guided Practice - 1Guided Practice - 1A constant volume of oxygen is heated A constant volume of oxygen is heated

from from 100 degrees Celsius100 degrees Celsius to to 185 degrees 185 degrees CelsiusCelsius. The initial pressure is . The initial pressure is 4.1 atm.4.1 atm. What is the final pressure?What is the final pressure?

TT11= 273 + 100 = 373 K = 273 + 100 = 373 K PP11 = = P P22

TT22= 273 + 185 = 458 K = 273 + 185 = 458 K TT11 T T22

PP11= 4.1 = 4.1

PP22= =

Guided Practice - 1Guided Practice - 1A constant volume of oxygen is heated A constant volume of oxygen is heated

from from 100 degrees Celsius100 degrees Celsius to to 185 degrees 185 degrees CelsiusCelsius. The initial pressure is . The initial pressure is 4.1 atm.4.1 atm. What is the final pressure?What is the final pressure?

TT11= 273 + 100 = 373 K = 273 + 100 = 373 K PP11 = = P P22

TT22= 273 + 185 = 458 K = 273 + 185 = 458 K TT11 T T22

PP11= 4.1 = 4.1

PP22= = 4.1 4.1 = = PP22

373 458373 458

Guided Practice - 1Guided Practice - 1 A constant volume of oxygen is heated from A constant volume of oxygen is heated from 100 100

degrees Celsiusdegrees Celsius to to 185 degrees Celsius185 degrees Celsius. The . The initial pressure is initial pressure is 4.1 atm.4.1 atm. What is the final What is the final pressure?pressure?

TT11= 273 + 100 = 373 K = 273 + 100 = 373 K PP11 = = P P22

TT22= 273 + 185 = 458 K = 273 + 185 = 458 K TT11 T T22

PP11= 4.1 = 4.1

PP22= = 4.1 4.1 = = PP22

373 458373 458

4.1(458) = 373 (P4.1(458) = 373 (P22))

Guided Practice - 1Guided Practice - 1 A constant volume of oxygen is heated from A constant volume of oxygen is heated from 100 100

degrees Celsiusdegrees Celsius to to 185 degrees Celsius185 degrees Celsius. The . The initial pressure is initial pressure is 4.1 atm.4.1 atm. What is the final What is the final pressure?pressure?

TT11= 273 + 100 = 273 K = 273 + 100 = 273 K PP11 = = P P22

TT22= 273 + 185 = 458 K = 273 + 185 = 458 K TT11 T T22

PP11= 4.1 = 4.1 PP22= = 4.1 4.1 = = PP22

373 458373 458 4.1(458) = 373 (P4.1(458) = 373 (P22)) 1877.8 = 373 (P1877.8 = 373 (P22))

Guided Practice - 1Guided Practice - 1 A constant volume of oxygen is heated from A constant volume of oxygen is heated from 100 100

degrees Celsiusdegrees Celsius to to 185 degrees Celsius185 degrees Celsius. The initial . The initial pressure is pressure is 4.1 atm.4.1 atm. What is the final pressure? What is the final pressure?

TT11= 273 + 100 = 373 K = 273 + 100 = 373 K PP11 = = P P22

TT22= 273 + 185 = 458 K = 273 + 185 = 458 K TT11 T T22

PP11= 4.1 = 4.1

PP22= = 4.1 4.1 = = PP22

373 458373 458

4.1(458) = 373 (P4.1(458) = 373 (P22))

1877.8 = 373 (P1877.8 = 373 (P22))

1877.8/373 = P1877.8/373 = P22

Guided Practice - 1Guided Practice - 1 A constant volume of oxygen is heated from A constant volume of oxygen is heated from 100 100

degrees Celsiusdegrees Celsius to to 185 degrees Celsius185 degrees Celsius. The initial . The initial pressure is pressure is 4.1 atm.4.1 atm. What is the final pressure? What is the final pressure?

TT11= 273 + 100 = 373 K = 273 + 100 = 373 K PP11 = = P P22

TT22= 273 + 185 = 458 K = 273 + 185 = 458 K TT11 T T22

PP11= 4.1 = 4.1 PP22= = 4.1 4.1 = = PP22

373 458373 458

4.1(458) = 373 (P2) 1877.8 = 373 (P2) 1877.8/373 = P2

P2 = 5.034

Guided PracticeGuided Practice

A sample of 25 L of NHA sample of 25 L of NH33 gas at 10 degrees gas at 10 degrees

Celsius is heated at constant pressure until Celsius is heated at constant pressure until it fills a volume of 50 L. What is the new it fills a volume of 50 L. What is the new temperature in Celsius. temperature in Celsius.

TT11==

TT22==

VV11==

VV22==

Guided PracticeGuided Practice

A sample of A sample of 25 L25 L of NH of NH33 gas at 1 degrees gas at 1 degrees

Celsius is heated at constant pressure until Celsius is heated at constant pressure until it fills a volume of 50 L. What is the new it fills a volume of 50 L. What is the new temperature in Celsius. temperature in Celsius.

TT11==

TT22==

VV11==

VV22==

Guided PracticeGuided Practice

A sample of A sample of 25 L25 L of NH of NH33 gas at gas at 10 degrees 10 degrees

CelsiusCelsius is heated at constant pressure until is heated at constant pressure until it fills a volume of 50 L. What is the new it fills a volume of 50 L. What is the new temperature in Celsius. temperature in Celsius.

TT11==

TT22==

VV11= 25 L= 25 L

VV22==

Guided PracticeGuided Practice

A sample of A sample of 25 L25 L of NH of NH33 gas at gas at 10 degrees 10 degrees

CelsiusCelsius is heated at constant pressure until is heated at constant pressure until it fills a volume of 50 L. What is the new it fills a volume of 50 L. What is the new temperature in Celsius. temperature in Celsius.

TT11= 273 + 10 = 283= 273 + 10 = 283

TT22==

VV11= 25 L= 25 L

VV22==

Guided PracticeGuided Practice

A sample of A sample of 25 L25 L of NH of NH33 gas at gas at 10 degrees 10 degrees

CelsiusCelsius is heated at constant pressure until is heated at constant pressure until it fills a volume of it fills a volume of 50 L50 L. What is the new . What is the new temperature in Celsius. temperature in Celsius.

TT11= 273 + 10 = 283= 273 + 10 = 283

TT22==

VV11= 25 L= 25 L

VV22==

Guided PracticeGuided Practice

A sample of A sample of 25 L25 L of NH of NH33 gas at gas at 10 degrees 10 degrees

CelsiusCelsius is heated at constant pressure until is heated at constant pressure until it fills a volume of it fills a volume of 50 L50 L. What is the new . What is the new temperature in Celsius. temperature in Celsius.

TT11= 273 + 10 = 283= 273 + 10 = 283

TT22==

VV11= 25 L= 25 L

VV22= 50 L= 50 L

Guided PracticeGuided Practice

A sample of A sample of 25 L25 L of NH of NH33 gas at gas at 10 degrees 10 degrees

CelsiusCelsius is heated at constant pressure until is heated at constant pressure until it fills a volume of it fills a volume of 50 L50 L. What is the new . What is the new temperature in Celsius. temperature in Celsius.

TT11= 273 + 10= 283 = 273 + 10= 283 V1 V1 = = V2V2

TT22= = T1 T2T1 T2

VV11= 25 L= 25 L

VV22= 50 L= 50 L

Guided PracticeGuided Practice

A sample of A sample of 25 L25 L of NH of NH33 gas at gas at 10 degrees 10 degrees CelsiusCelsius is heated at constant pressure until is heated at constant pressure until it fills a volume of it fills a volume of 50 L50 L. What is the new . What is the new temperature in Celsius. temperature in Celsius.

TT11= 273 + 10 = 283 = 273 + 10 = 283 V1 V1 = = V2V2

TT22= = T1 T2T1 T2

VV11= 25 L= 25 L

VV22= 50 L = 50 L 2525 = = 5050

283 T283 T22

Guided PracticeGuided Practice

A sample of A sample of 25 L25 L of NH of NH33 gas at gas at 10 degrees Celsius10 degrees Celsius is heated at constant pressure until it fills a is heated at constant pressure until it fills a volume of volume of 50 L50 L. What is the new temperature in . What is the new temperature in Celsius. Celsius.

TT11= 273 + 10 = 283 = 273 + 10 = 283 V1 V1 = = V2V2TT22= = T1 T2T1 T2VV11= 25 L= 25 LVV22= 50 L = 50 L 2525 = = 5050 283 T283 T22

25 (T2) = 283 (50)25 (T2) = 283 (50)

Guided PracticeGuided Practice

A sample of A sample of 25 L25 L of NH of NH33 gas at gas at 10 degrees Celsius10 degrees Celsius is heated is heated at constant pressure until it fills a volume of at constant pressure until it fills a volume of 50 L50 L. What is . What is the new temperature in Celsius. the new temperature in Celsius.

TT11= 273 + 10= 283 = 273 + 10= 283 V1 V1 = = V2V2TT22= = T1 T2T1 T2VV11= 25 L= 25 LVV22= 50 L = 50 L 2525 = = 5050 283 T283 T22

25 (T25 (T22) = 283 (50)) = 283 (50)

(T2) = (T2) = 283(50)283(50) 2525

Guided PracticeGuided Practice

A sample of A sample of 25 L25 L of NH of NH33 gas at gas at 10 degrees Celsius10 degrees Celsius is heated at constant is heated at constant pressure until it fills a volume of pressure until it fills a volume of 50 L50 L. What is the new temperature in . What is the new temperature in Celsius. Celsius.

TT11= 273 + 10 = 283 = 273 + 10 = 283 V1 V1 = = V2V2TT22= = T1 T2T1 T2VV11= 25 L= 25 LVV22= 50 L = 50 L 2525 = = 5050 283 T283 T22

25 (T25 (T22) = 283 (50)) = 283 (50)

(T2) = (T2) = 283(50)283(50) 2525

T2 = 14150 / 25 = 566 KT2 = 14150 / 25 = 566 K

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Guided Practice - 3Guided Practice - 3

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