Concept Questions with Answers 8.02 W10D2

Concept Questions with Answers

8.02W10D2

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W10D2DC Circuits

Today’s Reading Assignment W10D2 DC Circuits & Kirchhoff’s Loop Rules Course Notes: Sections 7.1-7.5

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Concept Q: Resistors In ParallelSuppose that . Then the equivalent resistance

1.

2.

3.

4.

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Concept Q: Resistors In ParallelAnswer. When Then the equivalent resistance is the smaller resistance. This is an important circuit design principle.

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Concept Question: Bulbs & Batteries

An ideal battery is hooked to a light bulb with wires. A second identical light bulb is connected in parallel to the first light bulb. After the second light bulb is connected, the current from the battery compared to when only one bulb was connected.

1. Is Higher2. Is Lower3. Is The Same4. Don’t know

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Concept Question Answer: Bulbs & Batteries

There are several ways to see this:(A) The equivalent resistance of the

two light bulbs in parallel is half that of one of the bulbs, and since the resistance is lower the current is higher, for a given voltage.

(B) The battery must keep two resistances at the same potential I doubles.

Answer: 1. More current flows from the battery

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Concept Question: Bulbs & Batteries

An ideal battery is hooked to a light bulb with wires. A second identical light bulb is connected in series with the first light bulb. After the second light bulb is connected, the current from the battery compared to when only one bulb was connected. 1. Is Higher2. Is Lower3. Is The Same

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Concept Question Answer: Bulbs & Batteries

The equivalent resistance of the two light bulbs in series is twice that of one of the bulbs, and since the resistance is higher the current is lower, for the given voltage.

Answer: 2. Less current flows from the battery

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Concept Question: PowerAn ideal battery is hooked to a light bulb with wires. A second identical light bulb is connected in parallel to the first light bulb. After the second light bulb is connected, the power output from the battery (compared to when only one bulb was connected)

1. Is four times higher2. Is twice as high3. Is the same4. Is half as much5. Is ¼ as much

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Concept Question Answer: PowerAnswer: 2. Is twice as high

The current from the battery must double (it must raise two light bulbs to the same voltage difference) and

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Concept Question: PowerAn ideal battery is hooked to a light bulb with wires. A second identical light bulb is connected in series with the first light bulb. After the second light bulb is connected, the light (power) from the first bulb (compared to when only one bulb was connected)

1. Is four times higher2. Is twice as high3. Is the same4. Is half as much5. Is ¼ as much

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Concept Question Answer: PowerAnswer: 5. Is 1/4 as bright

R doubles current is cut in half. So power delivered by the battery is half what it was. But that power is further divided between two bulbs now.

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Concept Question: Measuring Current

If R1 > R2, compare the currents measured by the three ammeters:

1. A1 > A2 > A3

2. A2 > A1 > A3

3. A3 > A1 > A2

4. A3 > A2 > A1

5. A3 > A1 = A2

6. None of the above7. Not enough information is given.

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Concept Question Answer: Measuring Current

Answer: 4. A3 > A2 > A1

The total current must add to the two individual currents, so A3 must be largest. Most current prefers to go through the smaller resistor so A2 > A1 .