CHAPTER11 Electindo.com PHYSICS FOR JUNIOR HIGH SCHOOL VII

CHAPTER11

Electindo.comPHYSICS FOR JUNIOR HIGH SCHOOL VII

STRAIGHT MOTION AT CONSTANT ACCELERATION (SMACA)

Electindo.comPHYSICS FOR JUNIOR HIGH SCHOOL VII

STRAIGHT MOTION AT CONSTANT ACCELERATION

DEFINITIONSMACA is a motion that has rectilinear track with constant acceleration and the velocity changes regularly. The example of SMACA can be found at the fruit falling down from its branch, or the motion of object throwing up.

OBJECT MOVES WITH INCONSTANT VELOCITY

ACCELARATED ( a + ) DECELERATED ( a - )

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PHYSICS FOR JUNIOR HIGH SCHOOL VII

GRAPHIC OF SMACAaccelerated ( a + )

space (s) velocity (v) acceleration (a)

Space (s) – Time (t) Velocity (v) – Time (t) Acceleration (a) – Time (t)

X = Vo.t + ½ at2

V = Vo + at

a = (V/Vo) : t

Vo2 = V2+ 2a.s

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PHYSICS FOR JUNIOR HIGH SCHOOL VII

GRAPHIC OF SMACA decelerated ( a — )

Jarak (s) kecepatan (v) Percepatan (a)

Jarak (s) – waktu (t) kecepatan (v) – waktu (t) percepatan (a) – waktu (t)

X = Vo.t - ½ at2

V = Vo - at

a = (V/Vo) : t

V2 = Vo2- 2a.s

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PHYSICS FOR JUNIOR HIGH SCHOOL VII

STRAIGHT MOTION AT CONSTANT ACCELERATION

Ball acceleration when leaving the player = -g.

Velocity in maximum-high V = 0

Answer :

t = (V-Vo)/g= (0 - 12) / (-9,8) = 1.2 s

V = Vo + gt

Time required to reach the maximum-high :

Maximum-high :

1. A BASEBALL PLAYER THROWS A BALL THROUGH Y AXIS WITH STARTING VELOCITY OF 12 M/S. HOW LONG THE TIME SPENT BY THE BALL TO REACH MAXIMUM-HIGH, AND HOW HIGH THE BALL WILL BE ?

( )( ) m3,7=

m/s 9.8-2m/s 12-0

=a2v-v

= y 2

22o

Y=0

Y = 7,3 m

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PHYSICS FOR JUNIOR HIGH SCHOOL VII

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