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Chapter 14The Behavior of Gases
Compressibility
The measure of how much the volume of matter decreases
under pressure.
Properties of a Gas
1)They are easy to compress.2)They expand to fill their
containers.3)They occupy far more space
than the liquids or solids from which they form.
Variables that describe a Gas
The four variables and their common units:1. pressure (P) in kilopascals(kPa)
2. volume (V) in Liters(L)3. temperature (T) in Kelvin(K)4. number of moles (n) (mol)
Amount of GasWhen we inflate a balloon, we are adding gas molecules.Increasing the number of gas particles increases the number of collisionsthus, the pressure increasesIf temp. is constant- doubling the number of particles doubles pressure
Pressure and the number of molecules are directly related
More molecules means more collisions.Fewer molecules means fewer collisions.
Common use?
Aerosol (spray) cansgas moves from higher pressure to lower pressure
a propellant forces the product out
whipped cream, hair spray, paint
2. Volume of Gas
In a smaller container, molecules have less room to move.Hit the sides of the container more often.As volume decreases, pressure increases. (think of a syringe)
3. Temperature of GasRaising the temperature of a gas increases the pressure, if the volume is held constant.The molecules hit the walls harder, and more frequently!The only way to increase the temperature at constant pressure is to increase the volume.
Homework
Section: 14.1Practice Problems
ReviewDue: 3/17/06
The Gas LawsThese will describe HOW gases behave.Can be predicted by the theory.Amount of change can be calculated with mathematical equations.
Boyle’s LawAt a constant temperature, gas pressure and volume are inversely related.As one goes up the other goes down
P1 x V1= P2 x V2
A balloon is filled with 25 L of air at 1.0 atm pressure. If the
pressure is changed to 1.5 atm what is the new volume?
P1 = 1 atm
V1 = 25 L
V2 = ? L
P2 = 1.5atm
P1 x V1= P2 x V2
P1 x V1
P2= V2
1atm x 25L1.5atm
= V2
16.7 L = V2
A balloon is filled with 73 L of air at 1.3atm pressure. What
pressure is needed to change the volume to 43L?
P1 = 1.3atm
V1 = 73 L
V2 = 43 L
P2 = ? atm
P1 x V1= P2 x V2
P1 x V1
V2
= P2
1.3atm x 73L43 L
= P2
16.7 L = V2
Charles’s LawThe volume of a gas is directly proportional to the Kelvin temperature, if the pressure is held constant.
V1 V2
T1 T2
=
What is the temperature of a gas expanded from 2.5 L at 25 ºC to
4.1L at constant pressure?
V1 = 2.5L
T1 = 25ºC + 273 = 298K
V2 = 4.1L
T2 = ?ºC
V1 V2
T1 T2=
T2 T1 x V2
V1
=T2 298K x 4.1L 2.5L
=
T2 = 488K = 216°C
What is the final volume of a gas that starts at 8.3 L and
17ºC, and is heated to 96ºC?
V1 = 8.3L
T1 = 17ºC + 273 = 290K
T2 = 96°C + 273 = 369K
V2 = ?ºC
V1 V2
T1 T2=
V1 x T2 V2
T1
= 8.3L x 369K V2
290K=
V2 = 10.6L
Gay-Lussac’s Law
The temperature and the pressure of a gas are directly related, at constant volume.
P1 P2
T1 T2
=
What is the pressure inside a 0.250 L can of deodorant that starts at 25 ºC and 1.2 atm if the temperature is raised to 100 ºC?
P1 = 1.2atm
T1 = 25ºC + 273 = 298K
T2 = 100ºC + 273 = 373K
P2 = ? atm
P1 P2
T1 T2=
P2 T2 P1
T1
= P2 (373K)(1.2atm)
298K=
P2 = 1.5 atm
Combined Gas Law
The Combined Gas Law deals with the situation where only the number of molecules stays constant. Formula: (P1 x V1)/T1= (P2 x V2)/T2
This lets us figure out one thing when two of the others change.
A 15 L cylinder of gas at 4.8 atm pressure and 25 ºC is heated to 75 ºC and compressed to 17 atm. What is the new volume?
P1 = 4.8 atmT1 = 25ºC + 273 = 298K
V1 = 15 L
V2 = ? LP2 = 17 atm
T2 = 75ºC + 273 = 348K
P1 V1 P2 V2
T1 T2=
V2 P1 V1T2
P2 T1=
V1 (4.8 atm)(15L)(348K)
(17 atm)( 298K)=
V1 = 4.9 L
The combined gas law contains all the other gas laws!If the temperature remains constant...
P1 V1
T1
x=
P2 V2
T2
x
Boyle’s Law
The combined gas law contains all the other gas laws!If the pressure remains constant...
P1 V1
T1
x=
P2 V2
T2
x
Charles’s Law
The combined gas law contains all the other gas laws!
If the volume remains constant...
P1 V1
T1
x=
P2 V2
T2
x
Gay-Lussac’s Law
Homework
Section: 14.2Practice Problems
ReviewDue: 3/21/06
Ideal Gases
We are going to assume the gases behave “ideally”- obeys the Gas Laws under all temp. and pres.
Ideal Gases
An ideal gas does not really exist, but it makes the math easier and is a close approximation.Particles have no volume.No attractive forces.
Ideal Gases
There are no gases for which this is true; however,Real gases behave this way at high temperature and low pressure.
The Ideal Gas Law #1Equation: P x V = n x R x TPressure times Volume equals the number of moles times the Ideal Gas Constant (R) times the temperature in Kelvin.This time R does not depend on anything, it is really constant R = 8.31 (L x kPa) / (mol x K)
We now have a new way to count moles (amount of matter), by measuring T, P, and V. We aren’t restricted to STP conditions
P x V R x T
The Ideal Gas Law
n =
Examples
How many moles of air are there in a 2.0 L bottle at 19 ºC and 747 mm Hg?What is the pressure exerted by 1.8 g of H2 gas in a 4.3 L balloon at 27 ºC?Samples 12-5, 12-6 on pages 342 and 343
6. Ideal Gas Law #2P x V = m x R x T
MAllows LOTS of calculations!m = mass, in gramsM = molar mass, in g/mol
Molar mass = m R T P V
DensityDensity is mass divided by volume
m Vso, m M P V R T
D =
D = =
Ideal Gases don’t exist
Molecules do take up spaceThere are attractive forcesOtherwise there would be no liquids formed
Real Gases behave like Ideal Gases.
When the molecules are far apartThe molecules do not take up as big a percentage of the spaceWe can ignore their volume.This is at low pressure
Real Gases behave like Ideal gases when...
When molecules are moving fast= high temperatureCollisions are harder and faster.Molecules are not next to each other very long.Attractive forces can’t play a role.
Avogadro’s HypothesisAvogadro’s Hypothesis: Equal volumes of gases at the same temp. and pressure contain equal numbers of particles. Saying that two rooms of the same size could be filled with the same number of objects, whether they were marbles or baseballs.
Dalton’s Law of Partial Pressures
The total pressure inside a container is equal to the partial pressure due to each gas.The partial pressure is the contribution by that gas.
PTotal = P1 + P2 + P3
We can find out the pressure in the fourth container.By adding up the pressure in the first 3.
2 atm
1 atm
3 atm
=
+ 6 atm
+
ExamplesWhat is the total pressure in a balloon filled with air if the pressure of the oxygen is 170 mm Hg and the pressure of nitrogen is 620 mm Hg?In a second balloon the total pressure is 1.3 atm. What is the pressure of oxygen if the pressure of nitrogen is 720 mm Hg?
Diffusion
Effusion: Gas escaping through a tiny hole in a container.Depends on the speed of the molecule.
Molecules moving from areas of high concentration to low concentration.
Example: perfume molecules spreading across the room.
Graham’s Law
The rate of effusion and diffusion is inversely proportional to the square root of the molar mass of the molecules.Kinetic energy = 1/2 mv2
m is the mass v is the velocity.
RateA MassB
RateB MassA
=
Heavier molecules move slower at the same temp. (by Square root) Heavier molecules effuse and diffuse slowerHelium effuses and diffuses faster than air - escapes from balloon.
Graham’s Law
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