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CH
AP
TE
R 1 O
RT
HO
GR
AP
HIC
P
RO
JE
CT
IO
N E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
TA
SK
17
CO
PY
RIG
HT
CHAPTER 2 MECHANICAL DRAWING ENGINEERING GRAPHICS AND DESIGN
TASK 1
TASK 1
1. What system of orthographic projection has
been used? Third-Angle Orthographic
Projection
2. Only one of the sectional front views is correct.
· Number 1 is incorrect because, hatching is
in one direction only in a casting.
· Number 2 is incorrect because, no hidden
detail is shown behind hatching.
· Number 3 is incorrect because, no centre
line are shown in the drawing.
· Number 4 is incorrect because, the front
view is incomplete.
· Number 6 is incorrect because, the
hatching lines are at 30° and must be at
45°.
· Number 7 is incorrect because, the hole in
the centre must not be sectioned.
3. Label the correct sectional front view by
printing the label SECTION ON A-A below it.
5
SECTION ON A-A
COPYRIGHT
AA
B B
SE
CT
IO
N O
N A
-A
SE
CT
IO
N O
N B
-B
TA
SK
2.4
CO
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CH
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R 2 M
EC
HA
NIC
AL D
RA
WIN
G E
NG
IN
EE
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RA
PH
IC
S A
ND
D
ES
IG
N
AA
SE
CT
IO
N O
N A
-A
TA
SK
2.5
CO
PY
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HT
CH
AP
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R 2 M
EC
HA
NIC
AL D
RA
WIN
G E
NG
IN
EE
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G G
RA
PH
IC
S A
ND
D
ES
IG
N
AA
SE
CT
IO
N O
N A
-A
TA
SK
2.6
CO
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CH
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R 2 M
EC
HA
NIC
AL D
RA
WIN
G E
NG
IN
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PH
IC
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D
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IG
N
AA
TA
SK
2.7
CO
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CH
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R 2 M
EC
HA
NIC
AL D
RA
WIN
G E
NG
IN
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PH
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ND
D
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IG
N
SE
CT
IO
N O
N A
-A
SE
CT
IO
N O
N B
-B
B B
B
B
SECTION ON A-A
SECTION ON A-A
AA
TASK 2.9
COPYRIGHT
CHAPTER 2 MECHANICAL DRAWING ENGINEERING GRAPHICS AND DESIGN
SECTION ON A-ASECTION ON B-B
A A
B
B
TASK 2.10
COPYRIGHT
CHAPTER 2 MECHANICAL DRAWING ENGINEERING GRAPHICS AND DESIGN
SE
CT
IO
N O
N B
-B
SE
CT
IO
N O
N A
-A
AA
B B
TA
SK
2.11
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HA
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IN
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IG
N
TASK 3
COPYRIGHT
18
28
22
57
14
55
R8
10
Ø10
Ø8
20
57
22 14
R8
Ø8
18
55
10
10
CHAPTER 2 MECHANICAL DRAWING ENGINEERING GRAPHICS AND DESIGN
SECTION ON A-A
AA
TASK 7
TASK 8
COPYRIGHT
CHAPTER 2 MECHANICAL DRAWING ENGINEERING GRAPHICS AND DESIGN
COPYRIGHT
CHAPTER 2 MECHANICAL DRAWING ENGINEERING GRAPHICS AND DESIGN
TASK 10 Study the views of a Clamp
Arm then answer the questions.
1. Who checked the
drawing?
D DU PLOOY
2. On what date was
the drawing completed?11-05-06
3. How many revisions
have there been? 4
4. What is the drawing
file name?
CLAMP ARM
5. What is the name of
the drawing company?
ADVANCED DESIGNS
6. How many units
must be manufactured?
25
7. What orthographic
system has been used? 3rd ANGLE
8. What drawing
programme was used?
AUTOCAD 2006
9. Determine the sizes
at A, B, C, D, E, F.
A = Ø 18 D = 16
B = 6 E = M10
C = 32 F = M10
10. What is the feature
at T called?
TITLE STRIP
11. Name the line types
at P, Q, R.
P - CENTRE
Q - HATCHING
R - OUTLINE
12. Name features at M,
N.
M - THREAD
N - RIB / WEB
13. How many threaded
holes are there? TWO
14. What is the drawing
scale?
SCALE 1:2
TASK 9 Study the views of a Bracket
Assembly then answer the questions.
1. Who prepared the
drawing?
JASMIN
2. On what date was
the drawing approved?
15-07-13
3. What was Pumla
responsible for?
CHECKING
4. What is the drawing
number?
MS 03/13
5. What would VIEW 1
be called?
LEFT VIEW
6. What would VIEW 2
be called?
SECTIONAL FRONT
7 What would VIEW 3
be called?
TOP
8. What scale is
indicated on the
drawing?
1:1
9. Determine the
dimensions at A, B, C,
D, E.
A 10, B 50, C 67, D 36,
E M20
10. Name the
components S, T and
U.
S-NUT
T-WASHER
U-BOLT
11. What are the angles
of the features at P and
Q.
P-30°
Q-45°
12. Name the feature at
M.
M-WEB
13. How many through
holes are there in the
assembly?
4
14. How many
components make up
the assembly?
TWO
COPYRIGHT
CHAPTER 2 MECHANICAL DRAWING ENGINEERING GRAPHICS AND DESIGN
TASK 11 Study the views of a Clamp
Arm then answer the questions.
1. Who approved the
drawing?
CALYN
2. On what date was
the drawing prepared?
22-10-13
3. What is the drawing
number?
3378
4. What would VIEW 1
be called?
SECTIONAL FRONT
VIEW
5. What would VIEW 2
be called?
RIGHT VIEW
6. What is the drawing
file name?
MS 694-J
7 What was Amie
responsible for?
PREPARING THE
DRAWING
8. What is the total
length of the assembly?
135 mm
9. Determine the
dimensions at A, B, C,
D, E.
A = R31 D = Ø 20
B = 3 E = 84
C = AF16
10. Name the line types
at P, Q, R.
P - CENTRE LINE
Q - HATCHING
R - HIDDEN DETAIL
11. What is the feature
at S called?
P - CENTRE
Q - HATCHING
R - OUTLINE
12. What is the view at
T called?
AUXILIARY VIEW
13. How many
components make up
the assembly?
8
14. Is the drawing
bigger or smaller than
the object?
BIGGER
CHAPTER 2 MECHANICAL DRAWING ENGINEERING GRAPHICS AND DESIGN
TASK 12
A
SECTION ON A-A
A
CLAMP ASSEMBLY
SCALE 1:1
135
98
96
COPYRIGHT
SECTION ON A-A
AA
INSPECTION EYE
SCALE 1:1
Ø52
Ø170
Ø60
TASK 13
COPYRIGHT
CHAPTER 2 MECHANICAL DRAWING ENGINEERING GRAPHICS AND DESIGN
SECTION ON A-A
A A
JOCKEY WHEEL
SCALE 1:1
110
Ø76
20
55
TASK 14
COPYRIGHT
CHAPTER 2 MECHANICAL DRAWING ENGINEERING GRAPHICS AND DESIGN
AA
SE
CT
IO
N O
N A
-A
15
Ø70
40
144
60
TA
SK
16
CO
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RO
LLE
R A
SS
EM
BLY
SC
ALE
1:2
CH
AP
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R 2 M
EC
HA
NIC
AL D
RA
WIN
G
E
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RA
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ND
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IG
N
AA
SECTION ON A-A
OVERHEAD RAIL CARRIER
SCALE 1:2
272
260
Ø120
Ø200
Ø70
TASK 18
COPYRIGHT
CHAPTER 2 MECHANICAL DRAWING ENGINEERING GRAPHICS AND DESIGN
CHAPTER 4 SOLID GEOMETRY ENGINEERING GRAPHICS AND DESIGN
TASK 1 Neatly fill in the missing information in the
table below.
NAME
NUMBER OF
SIDES
EXTERIOR
ANGLE
TRIANGLE 3 120°
SQUARE 4 90°
PENTAGON 5 72°
HEXAGON 6 60°
HEPTAGON 7 51.429°
OCTAGON 8 45°
NONAGON 9 40°
DECAGON 10 36°
HENDECAGON 1132,7°
DODECAGON 12 30°
X
Y
RIG
HT
R
EG
ULA
R S
OLID
S IN
CLIN
ED
13
X'
Y'
CH
AP
TE
R 4 S
OLID
G
EO
ME
TR
Y
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NG
IN
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G G
RA
PH
IC
S A
ND
D
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IG
N
RIG
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R
EG
ULA
R S
OLID
S IN
CLIN
ED
15
X'
X
Y'
Y
CH
AP
TE
R 4 S
OLID
G
EO
ME
TR
Y
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NG
IN
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PH
IC
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ND
D
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IG
N
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R
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ULA
R S
OLID
S IN
CLIN
ED
17
X'
X
Y'
Y
CH
AP
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R 4 S
OLID
G
EO
ME
TR
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IN
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ND
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R S
OLID
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CLIN
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18
X'
X
Y'
Y
CH
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TR
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19
X'
X
Y'
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20
X'
X
Y'
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21
X'
X
Y'
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CH
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TR
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23
X'
X
Y'
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TR
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CLIN
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24
X'
X
Y'
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CH
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TR
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CLIN
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25
X'
X
Y'
Y
CH
AP
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R 4 S
OLID
G
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TR
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IN
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ND
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R
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R S
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S IN
CLIN
ED
26
X'
X
Y'
Y
CH
AP
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R 4 S
OLID
G
EO
ME
TR
Y
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NG
IN
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G G
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PH
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ND
D
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IG
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R
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R S
OLID
S IN
CLIN
ED
27
X'
X
Y'
Y
CH
AP
TE
R 4 S
OLID
G
EO
ME
TR
Y
E
NG
IN
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RIN
G G
RA
PH
IC
S A
ND
D
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IG
N
RIG
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R
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ULA
R S
OLID
S IN
CLIN
ED
28
X'
X
Y'
Y
CH
AP
TE
R 4 S
OLID
G
EO
ME
TR
Y
E
NG
IN
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RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
RIGHT REGULAR SOLIDS CUT 37 & 38
X
X
Y
Y
H
H
T
T
CHAPTER 4 SOLID GEOMETRY ENGINEERING GRAPHICS AND DESIGN
RIGHT REGULAR SOLIDS CUT 39 & 40
X
X
Y
Y
H
HT
T
CHAPTER 4 SOLID GEOMETRY ENGINEERING GRAPHICS AND DESIGN
THE TRUE SHAPE OF A CUT SURFACE 41
TRUE SHAPE
X'
Y'
X Y
V
T
CHAPTER 4 SOLID GEOMETRY ENGINEERING GRAPHICS AND DESIGN
CH
AP
TE
R 4 S
OLID
G
EO
ME
TR
Y
E
NG
IN
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RIN
G G
RA
PH
IC
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ND
D
ES
IG
N
TH
E T
RU
E S
HA
PE
O
F A
C
UT
S
UR
FA
CE
42
TR
UE
S
HA
PE
X'
XY
Y''X''
Y'
V
T
TH
E T
RU
E S
HA
PE
O
F A
C
UT
S
UR
FA
CE
43
X'
Y'
V
T
XY
TR
UE
S
HA
PE
X''Y''
CH
AP
TE
R 4 S
OLID
G
EO
ME
TR
Y
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NG
IN
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G G
RA
PH
IC
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ND
D
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IG
N
TH
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RU
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HA
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F A
C
UT
S
UR
FA
CE
44
X'
XY
X''Y''
Y'
V
T
TR
UE
S
HA
PE
CH
AP
TE
R 4 S
OLID
G
EO
ME
TR
Y
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
THE TRUE SHAPE OF A CUT SURFACE 45
X Y
V
T
X'
Y'
TRUE SHAPE
CHAPTER 4 SOLID GEOMETRY ENGINEERING GRAPHICS AND DESIGN
THE TRUE SHAPE OF A CUT SURFACE 46
X Y
X'
Y'
V
T
TRUE SHAPE
CHAPTER 4 SOLID GEOMETRY ENGINEERING GRAPHICS AND DESIGN
TH
E T
RU
E S
HA
PE
O
F A
C
UT
S
UR
FA
CE
47
X'
XY
X''Y''
Y'
V
T
TR
UE
S
HA
PE
CH
AP
TE
R 4 S
OLID
G
EO
ME
TR
Y
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
TH
E T
RU
E S
HA
PE
O
F A
C
UT
S
UR
FA
CE
48
XY
X''Y''
V
T
TR
UE
S
HA
PE
CH
AP
TE
R 4 S
OLID
G
EO
ME
TR
Y
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
TH
E T
RU
E S
HA
PE
O
F A
C
UT
S
UR
FA
CE
49
X'
XY
X''Y''
Y'
V
T
TR
UE
S
HA
PE
CH
AP
TE
R 4 S
OLID
G
EO
ME
TR
Y
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
TH
E T
RU
E S
HA
PE
O
F A
C
UT
S
UR
FA
CE
50
X'
XY
X''Y''
Y'
V
T
TR
UE
S
HA
PE
CH
AP
TE
R 4 S
OLID
G
EO
ME
TR
Y
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
TH
E T
RU
E S
HA
PE
O
F A
C
UT
S
UR
FA
CE
51
X'
XY
X''Y''
Y'
V
T
TR
UE
S
HA
PE
CH
AP
TE
R 4 S
OLID
G
EO
ME
TR
Y
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
THE TRUE SHAPE OF A CUT SURFACE 52
X Y
X'
Y'
V
T
TRUE SHAPE
CHAPTER 4 SOLID GEOMETRY ENGINEERING GRAPHICS AND DESIGN
THE TRUE SHAPE OF A CUT SURFACE 53
V
T
X Y
X'
Y'
CHAPTER 4 SOLID GEOMETRY ENGINEERING GRAPHICS AND DESIGN
TH
E T
RU
E S
HA
PE
O
F A
C
UT
S
UR
FA
CE
54
Y'
X'
V
T
XY
TR
UE
S
HA
PE
CH
AP
TE
R 4 S
OLID
G
EO
ME
TR
Y
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
THE TRUE SHAPE OF A CUT SURFACE 55
V
T
X Y
X'
Y'
CHAPTER 4 SOLID GEOMETRY ENGINEERING GRAPHICS AND DESIGN
THE TRUE SHAPE OF A CUT SURFACE 56
V
T
X Y
X'
Y'
CHAPTER 4 SOLID GEOMETRY ENGINEERING GRAPHICS AND DESIGN
THE TRUE SHAPE OF A CUT SURFACE 57
V
T
X Y
X'
Y'
TRUE SHAPE
CHAPTER 4 SOLID GEOMETRY ENGINEERING GRAPHICS AND DESIGN
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
POINT 1 TO POINT 4
a''
a'
b
b''
b'
X
Y
c'
c c''
d
d'
d''
X'
X'
X'
Y'
Y'
Y'
Y'
X
X
X
Y
Y
Y
a
X'
COPYRIGHT
1
2
34
a'b'
bB
aA
X Y
c d
d'D
c'C
X Y
e'E
f'F
ef
Y
e''f''
X
X'
Y'
a
X
a'
b'
Y
b
FIGURE 4
8.1) TRUE LENGTH OF AB = 57
8.2) TRUE INCLINATION OF AB TO THE VP = = 45°
FIGURE 5 TO FIGURE 8
FIGURE 3FIGURE 2FIGURE 1
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
5
8
6 7
d'c'
X
c
d
Y
e'
f'
Y
fe
X
FIGURE 5
FIGURE 6
9.1) TRUE LENGTH OF CD = 72
9.2) TRUE INCLINATION OF CD TO THE HP = = 46°
10.1) TRUE LENGTH OF EF = 63
10.2) TRUE INCLINATION OF EF TO THE VP = = 38°
FIGURE 9 and FIGURE 10
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
X
g'
h'
Y
h
g
l
XY
a
b
Aa'
b'
B
FIGURE 7
FIGURE 8
12.1) TRUE LENGTH OF AB = 76
12.2) TRUE INCLINATION OF AB TO THE VP = = 32°
11.1) TRUE LENGTH OF GH = 72
11.2) TRUE INCLINATION OF GH TO THE HP = = 43°
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
FIGURE 11 and FIGURE 12
X
Y
c
d
Dd'
C c'
XY
Ee
f
F
e'
f'
FIGURE 9
FIGURE 10
13.1) TRUE LENGTH OF CD = 79
13.2) TRUE INCLINATION OF CD TO THE VP = = 26°
14.1) TRUE LENGTH OF EF = 84
14.2) TRUE INCLINATION OF EF TO THE HP = = 22°
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
FIGURE 13 and FIGURE 14
XY
Gg
h
H
h'
g'
FIGURE 11
15.1) TRUE LENGTH OF GH = 62
15.2) TRUE INCLINATION OF GH TO THE HP = = 28°
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
FIGURE 15
5.1 A
ll the m
easurem
ents are in m
m.
·T
RU
E LE
NG
TH
O
F A
B
==
6100
·T
RU
E LE
NG
TH
O
F B
C
==
6100
·T
RU
E LE
NG
TH
O
F D
E
==
6100
·T
RU
E LE
NG
TH
O
F E
F
==
6100
5.2
·T
RU
E IN
CLIN
AT
IO
N O
F A
B T
O H
P
== 23°
·T
RU
E IN
CLIN
AT
IO
N O
F D
E T
O H
P =
= 23°
5.3
·T
RU
E LE
NG
TH
O
F B
E=
= 10500
CO
PY
RIG
HT
CH
AP
TE
R 5 D
ES
CR
IP
TIV
E G
EO
ME
TR
Y
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
bB
ac
d
f
c'
b'
a'
f'
e'E
d'
AC
Ee
D
X
Y
TA
SK
5
X
Y
a
Bb
d
a'b' c'
d'
D
Cc
16 TRUE LENGTH OF WIRE AD = AB + BC + CD
= 51 + 32 + 83
= 166
16. WIRE FIGURE 12
FIGURE 12
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
X Y
q
r
s
t
p'
q'Rr'
s' t'
17 TRUE LENGTH OF WIRE PT = PQ + QR + RS + ST
= 76 + 51 + 58 + 25
= 210
TRUE INCLINATION OF PQ TO THE HP = = 43°
TRUE INCLINATION OF RS TO THE VP = = 52°
Pp
Q
S
FIGURE 13
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
17. WIRE FIGURE 13
a'
a
b
de
b'
c'
d'
e'
X
Y
18 TRUE LENGTH OF WIRE AE = AB + BC + CD + DE
= 59 + 60 + 49 + 41
= 209
TRUE INCLINATION OF AB TO THE VP = = 43°
TRUE INCLINATION OF BC TO THE HP = = 44°
B
Cc
FIGURE 14
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
18. WIRE FIGURE 14
q
r
s
t
p'
q's'r'
X
Y
19 TRUE LENGTH OF WIRE PT = PQ + QR + RS + ST
= 80 + 41 + 45 + 80
= 246
TRUE INCLINATION OF PQ TO THE HP = = 41°
TRUE INCLINATION OF ST TO THE VP = = 38°
Pp
Q
S
Tt'
FIGURE 15
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
19. WIRE FIGURE 15
O
X
Y'
Y
X'
a
cC
c'
a'A
b'B
b BAb''
a''
c''
A
C
B
TRUE SHAPE
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
20
O
X
Y'
Y
X'
e
dD
fF
f'F
e'E
d'
d''
f''
e''
EF
D
TRUE SHAPE
D
F
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
21
O
X
Z
Y
mM
nN
lL
N m'
l'L
l''
m''
n''
M
N
L
TRUE SHAPE
Z
M
n'
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
22
R
Q
P
O
X
Y'
Y
X'
q
rR
p
p''
p'
r'
PP
q'Q
q''Q
r''R
TRUE SHAPE
23) TRUE INCLINATION OF PR TO THE HP = = 13°
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
23
O
X Y
X'
t
s
s'
t'
s''
t''
u''
SU
T
S
uU
T
u'U
S
T
TRUE SHAPE
24) TRUE INCLINATION OF SU TO THE HP = = 18°
Y'
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
24
O
X
Y'
Y
X'
b'B
a'
c'C
c b
Aa
c'' b''
a''
C
B
A
B
C
TRUE SHAPE
25) TRUE INCLINATION OF AB TO THE VP = = 50°
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
25
O
X
Y'
Y
X'
fe
d d''
e''f''
e'E
d'
EF
D
D
E
f'F
D
TRUE SHAPE
26) TRUE INCLINATION OF DF TO THE VP = = 29°
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
26
O
X
Y'
Y
l
nN
m''
l''
n''
m'
n'
l'L
M
N
M
L
M
mM
N
TRUE SHAPE
27) TRUE INCLINATION OF MN TO THE HP = = 49°
X'
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
27
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
a'A
b'B
X
Y
ba
eE
fF
f'
e'
X
Y
29.1) T L OF EF = 78
29.2) T I OF EF TO HP = = 42°
28.1) TL OF AB = 68
28.2) T I OF AB TO VP = = 36°
28
29
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
Y
g
h
h'
g'G
X
H
Y
kK
L
l'
k'
X
l
30.1) TL OF GH = 73
30.2) T I OF GH TO VP = = 27°
31.1) T L OF KL = 84
31.2) T I OF KL TO HP = = 33°
30
31
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
e'
a'b'B
d'
c'
b
a
e
c
dD
C
C
32.1) T L OF WIRE A-E (AB+BC+CD+DE) = 62 + 108 + 79 + 111
= 360
32.1) T I OF BC TO VP = = 30°
32.1) T I OF CD TO HP = = 42°
XY
32
CO
PY
RIG
HT
CH
AP
TE
R 5 D
ES
CR
IP
TIV
E G
EO
ME
TR
Y
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
g'
e'
f'F
g
eE
fF
f''
g''
e''
E
E
G
F
X
X'
Y
Y'
G
G
TR
UE
S
HA
PE
T.I. OF EG TO HP = = 10°
33
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
jJ
kK
lL
l' j'
k'K
l''
j''
k''
X
Y
X'
Y'
L
J
L
K
J
TRUE SHAPE
T.I. OF LK TO VP = = 39°
34
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
XY
X'
Y'
t'T
s
u
u'
t'
s'S
s''
u''U
t''T
S
U
U
T
S
TRUE SHAPE
35
CASE STUDY 1
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
a'
b' c'
ad
bc
a''
b''c''
d''d'
A
C
B
TRUE SHAPE
STEEL USED (0,07 m x 50)x2 = 70 m
X
Y
X'
Y'
X
Y'
Y
X'
a
c'
b'
de
B
Aa
e''b''
d'
e'
c''d''
f'
g'
bc
a''f''g''
f
AB x 12 = 57 x 12 = 684
DE x 4 = 52 x 4 = 208
EC x 3 = 56 x 3 = 168
BC x 4 = 25 x 4 = 100
150 x 3 = 450
TOTAL LENGTH OF STEEL TUBING = 1610
f
CASE STUDY 2
COPYRIGHT
CHAPTER 5 DESCRIPTIVE GEOMETRY ENGINEERING GRAPHICS AND DESIGN
CH
AP
TE
R 6 C
IV
IL D
RA
WIN
G
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
TA
SK
1 C
om
plete the table below
.
1
In the block alongside draw
the hatching
style for face brick.
9
In the block alongside draw
the sym
bol used
to indicate a cutting plane.
2
In the block alongside draw
the hatching
style for screed.
10
What is a front view
or a side view
on a civil
draw
ing called?
ELE
VA
TIO
N
3
In the block alongside draw
the hatching
style for concrete.
11
What is a top view
on a civil draw
ing called?
PLA
N
4
In the block alongside draw
the hatching
style for com
pacted hardcore fill.
12
On a ram
p and on a staircase, the arrow
alw
ays indicates.
UP
5
In the block alongside draw
the hatching
style for earth fill.
13
What is the abbreviation for n
atu
ral g
ro
un
d
level.
NG
L
6
In the block alongside draw
the hatching
style for com
mon brick.
14
What is the abbreviation for n
ot to
scale
.N
TS
7
In the block alongside draw
the hatching
style for undisturbed earth.
15
What is the abbreviation for d
am
p p
ro
of
co
urse.
DP
C
8
In the block alongside draw
the sym
bol
used to indicate the finished floor level.
16
What is the abbreviation for fin
ish
ed
flo
or
level.
FF
L
TA
SK
2 P
rint the answ
ers in the table below
.
AR
EA
PE
RIM
ET
ER
1L X
B
=
11 X
8 =
88 m²
A +
B
+
C
+
D
=
8 +
8 +
11 +
11 =
38 m
2
L X
B
=
(13 X
6) +
(4 X
2) =
86 m²
A +
B
+
C
+
D
+
E
+
F
=
6 +
13 +
8 +
4 +
2 +
11 =
42 m
3
L X
B
=
(13 X
6) +
(4 X
2) =
86 m²
A +
B
+
C
+
D
+
E
+
F
+
G
=
6 +
13 +
6 +
3 +
2 +
4 +
2 +
6 =
42 m
4
L X
B
=
(15 X
4) +
(3 X
3) +
(4 X
5) =
119 m²
A +
B
+
C
+
D
+
E
+
F
+
G
+
H
=
15 +
9 +
3 +
3 +
8 +
5 +
4 +
11 =
58 m
5
L X
B
=
(6 X
4) +
(7 X
6) +
(4 X
6) =
90 m²
A +
B
+
C
+
D
+
F
+
G
+
H
+
I +
J +
K
+
L =
6 +
4 +
3 +
7 +
3 +
4 +
6 +
4 +
3 +
7 +
3 +
4 =
54 m
6
L X
B
=
(6 X
3) +
(2 X
3) +
(8 X
10) =
104 m²
A +
B
+
C
+
D
+
F
+
G
+
H
+
I +
J =
6 +
3 +
2 +
10 +
8 +
8 +
3 +
2 +
2 +
3 =
48 m
7
L X
B
=
(8 X
5) +
(6 X
5) +
(5 X
7) +
(1 X
5) =
110 m²
A +
B
+
C
+
D
+
F
+
G
+
H
+
I +
J =
5 +
8 +
6 +
7 +
6 +
5 +
1 +
7 +
6 +
3 =
54 m
A
F.F
.L.
A
CO
PY
RIG
HT
TASK 3
CHAPTER 6 CIVIL DRAWING ENGINEERING GRAPHICS AND DESIGN
TASK 4
COPYRIGHT
THE FOUNDATION, WALL AND SLAB DETAIL OF
A LOAD-BEARING WALL
SCALE 1:10
THE FOUNDATION, WALL AND SLAB DETAIL OF A
NON LOAD-BEARING WALL
SCALE 1:10
NGL
DPC
DPC
CHAPTER 6 CIVIL DRAWING ENGINEERING GRAPHICS AND DESIGN
TASK 5
THE FOUNDATION, WALL AND SLAB
DETAIL OF A LOAD-BEARING WALL
SCALE 1:10
THE FOUNDATION, WALL AND SLAB
DETAIL OF A NON LOAD-BEARING WALL
SCALE 1:10
NGL
DPC
DPC
TASK 6
CHAPTER 6 CIVIL DRAWING ENGINEERING GRAPHICS AND DESIGN
COPYRIGHT
AN INCOMPLETE VIEW OF THE FOUNDATION, WALL AND
SLAB DETAIL OF A NON LOAD-BEARING WALL
SCALE 1:10
NGL
DPCDPC
NGL
TASK 7
TASK 8
CHAPTER 6 CIVIL DRAWING ENGINEERING GRAPHICS AND DESIGN
A A
DPC
NGL
DPC
NGL
PLAN
SCALE 1:40
SECTIONAL ELEVATION A-A
COPYRIGHT
TASK 9
CHAPTER 6 CIVIL DRAWING ENGINEERING GRAPHICS AND DESIGN
A A
DPC
NGL
DPC
NGL
PLAN
SCALE 1:40
SECTIONAL ELEVATION A-A
A A
6000 1876
8000
720 900
720
900
PLAN
SCALE 1:50
ROOM 1 ROOM 2
2000 2000
2000
2000
DPC
NGL
SECTION ON A-A
TOTAL FLOOR AREA = 48m²
PERIMETER = 28m
TASK 10
NGL
DPC
4000
CHAPTER 6 CIVIL DRAWING ENGINEERING GRAPHICS AND DESIGN
COPYRIGHT
PLAN
SCALE 1:50
1521
3000
900
A possible solution.
500 4000 500
500
750
1986
DPC
222
A A
SECTIONAL ELEVATION ON A-A
NGL
DPC
NGL
TOTAL FLOOR AREA = 15m²
PERIMETER = 16m
CHAPTER 6 CIVIL DRAWING ENGINEERING GRAPHICS AND DESIGN
TASK 10.6
COPYRIGHT
SP
GL
PP
HL
VP
CH
AP
TE
R 7 P
ER
SP
EC
TIV
E D
RA
WIN
G
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
TA
SK
1
CO
PY
RIG
HT
PP
HL
GL
SP
VP
TA
SK
2
CO
PY
RIG
HT
CH
AP
TE
R 7 P
ER
SP
EC
TIV
E D
RA
WIN
G
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
SP
PP
HL
GL
VP
TA
SK
3
CO
PY
RIG
HT
CH
AP
TE
R 7 P
ER
SP
EC
TIV
E D
RA
WIN
G
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
HL
GL
SP
PP
DO
OR
WIN
DO
WW
IN
DO
W
VP
TA
SK
4
CO
PY
RIG
HT
CH
AP
TE
R 7 P
ER
SP
EC
TIV
E D
RA
WIN
G
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
SP
PP
GL
HL
VP
TA
SK
5
CO
PY
RIG
HT
CH
AP
TE
R 7 P
ER
SP
EC
TIV
E D
RA
WIN
G
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
PP
SP
HL
VP
GL
TA
SK
6
CO
PY
RIG
HT
CH
AP
TE
R 7 P
ER
SP
EC
TIV
E D
RA
WIN
G
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
TA
SK
7
CO
PY
RIG
HT
SP
PP
GL
HL
CH
AP
TE
R 7 P
ER
SP
EC
TIV
E D
RA
WIN
G
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
SP
GL
PP
HL
VP
LV
PR
TA
SK
8
CO
PY
RIG
HT
CH
AP
TE
R 7 P
ER
SP
EC
TIV
E D
RA
WIN
G
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
SP
PP
HL
GL
VP
LV
PR
TA
SK
9
CO
PY
RIG
HT
CH
AP
TE
R 7 P
ER
SP
EC
TIV
E D
RA
WIN
G
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
SP
PP
HL
GL
VP
LV
PR
TA
SK
10
CO
PY
RIG
HT
CH
AP
TE
R 7 P
ER
SP
EC
TIV
E D
RA
WIN
G
E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
TA
SK
1
CO
MP
ON
EN
TI/P
/O
SY
MB
OL
AP
PE
AR
AN
CE
BA
TT
ER
YI
LA
MP
O
CA
PA
CIT
OR
P
PN
P T
RA
NS
IS
TO
RP
DIO
DE
P
AC
S
UP
PLY
I
VA
RIA
BLE
R
ES
IS
TO
RP
CR
OS
SIN
GG
EA
RT
H
CO
MP
ON
EN
TI/P
/O
SY
MB
OL
AP
PE
AR
AN
CE
IN
DU
CT
OR
P
CO
NN
EC
TIO
NG
DC
S
UP
PLY
I
FU
SE
G
SP
EA
KE
RO
R
ES
IS
TO
RP
LIG
HT
E
MIT
TIN
G
DIO
DE
O
VO
LT
ME
TE
RG
SW
IT
CH
P
V
CH
AP
TE
R 8 E
LE
CT
RIC
AL D
RA
WIN
G E
NG
IN
EE
RIN
G G
RA
PH
IC
S A
ND
D
ES
IG
N
CO
PY
RIG
HT
TASK 4
COPYRIGHT
CHAPTER 8 ELECTRICAL DRAWING ENGINEERING GRAPHICS AND DESIGN
12
3
4
The schematic diagram of a simple electric
circuit is shown. Identify and list the
numbered components.
1. BATTERY
2. SWITCH
3. VARIABLE RESISTOR
4. LAMP LIGHTING
5. CONNECTION
Are the components numbered 4 joined in
parallel or in series? PARALLEL
4
5
V1 5
23
4
6
The schematic diagram of a simple electric
circuit is shown. Identify and list the
numbered components.
1. DC SUPPLY
2. VOLMETER
3. ELECTRILYTIC CAPACITOR
4. SWITCH
5. VARIABLE RESISTOR
6. INDUCTOR
Which component has been placed
incorrectly ? 3
Why? POSITIVE MUST CONNECT TO
POSITIVE
The schematic diagram of a simple electric
circuit is shown. Identify and list the
numbered components.
1. BATTERY
2. SWITCH
3. PNP TRANSISTOR
In the circuit:
How many capacitors are there? 3
How many resistors are there? 3
How many connections are there? 9
1
2
3
1
MV
2 3
4 5
6
The schematic diagram of a simple electric
circuit is shown. Identify and list the
numbered components.
1. AC SUPPLY
2. SWITCH
3. FUSE
4. VOLTMETER
5. MOTOR
6. CONNECTION
1
23
4
IDENTIFYING COMPONENTS IN A
CIRCUIT
The schematic diagram of a simple
electric circuit is shown. Identify and
list the numbered components.
1. CELL
2. SWITCH
3. RESISTOR
4. LIGHT EMITTING DIODE
Recommended