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Algebra 2 Honors – Unit 1 – Review of Algebra 1
Day 1 – Combining Like Terms and Distributive Property
Objectives: SWBAT evaluate and simplify expressions involving real numbers.
SWBAT evaluate exponents SWBAT combine like terms
SWBAT plug values into expressions
SWBAT apply Distributive and Double Distributive Properties
Exponent Vocabulary
Base – The number that will be multiplied
Coefficient – the number in front of an exponent (assume it’s a 1 if there is none).
Exponent – the number of times the base will be multiplied Examples
Simplify the following expressions.
1. 34 2. (–2)4 3. (–5)3
4. –42 5. 2x3 6. (2y)3
Adding and Subtracting Expressions Vocabulary
Terms – Like Terms – A part or piece of an Terms with the exact variable makeup
expression or equation separated by a + or –
Constant – Simplified –
Number with no variable Combining all like terms or solving attached
3 3 3 3 81 ( 2) ( 2) ( 2) ( 2) 16 ( 5)( 5)( 5) 125
1 4 4 16 32x 3(2 )(2 )(2 ) 8y y y y
Distributive Property – Double Distributive Property (FOIL) –
( )b c ca a ab a ac cd dcb b bad
Examples
Simplify the following expressions.
7. (7z2 +2z) + (6z2 +3z) 8. (9v – 8w) – (10w – 5v)
9. 27 4x x 10. 3 22 3 3 2 5x x x x
2
3
(7 4)
7 x 4
x x
x
3 2
4 3 2
2 (3 3 2 5)
6 6 4 10
x x x x
x x x x
11. (2x – 9)(3x + 4) 12. (3x2 + 4)(x2 + 6)
2
2
6 8 27 36
6 19 36
x x x
x x
4 2 2
4 2
3 18 4 24
3 22 24
x x x
x x
2 2
2 2
2
7 2 6 3
7 6 2 3
13 5
z z z z
z z z z
z z
9 8 10 5
9 8 10 5
9 5 8 10
14 18
v w w v
v w w v
v v w w
v w
Imposters of Double Distributive
For the following examples, explain why they are not a double distributive, and then simplify.
13. (3x – 5y) – (4x + 3y) 14. 3 – 2(4m –2)
There is a +/- sign in-between the ( ) There is only one set of ( ) So it is not double distributive, it is so that means this is just Combining like terms distributive property
3 4 5 3
8
x x y y
x y
3 2(4 2)
3 8 4
8 7
m
m
m
15. (2x – 3)(5x2 – x + 3) 16. 3
2m
2
2
2
3 2 2
3 2
2 2 2
2 2 2
2 2 4 2
4 4 2
4 4 2
2 4 8 4 8
6 12 8
m m m
m m m
m m m m
m m m
m m m
m m m m m
m m m
2
3 2 2
3 2
(2 3)(5 3)
10 2 6 15 3 9
10 17 9 9
x x x
x x x x x
x x x
Day 2 – Solve Linear Equations and Inequalities
Objectives: SWBAT solve linear equations and inequalities. SWBAT use a formula.
SWBAT isolate any variable in a formula or literal equation.
GOLDEN RULE OF SOLVING LINEAR EQUATIONS
Six Steps to help solve equations.
1. PEMDAS
2. Combine like terms that are on the same side of the = sign
3. If there are variables on each side of the = sign, find the smallest variable and
move it to the other side.
4. Solve the two step equation by isolating the variable term
5. Multiply/Divide the coefficient of the variable so that there is a single positive
variable = a number
6. Check your work
Examples
Solve the following equations.
1. 8 37
x
2.
313 5
5w 3.
1 5
2 6m
8 37
8 8
57
7 5 77
35
x
x
x
x
313 5
5
5 5
318
5
5 18 3 5
3 1 5 3
30
w
w
w
w
1 5
2 6
3 5
6 6
3 3
6 6
2
6
1
3
11 1
3
1
3
m
m
m
m
m
m
4. 6 2 14n n 5. 14 3 17x x
6. 2 3 1 4 6 6x x 7. 2 6 4 17 2x x
Formulas and Rewriting Equations
Example: The equation 5
329
C F is used to change temperature from Fahrenheit to
Celsius. Find the equivalent Celsius temperature for each of the following Fahrenheit
temperatures.
8. 212 F 9. 70 C
Examples Solve each equation for the indicated variable
10. a2 + b2 = c2 , for a 11. 1 2
1
2A b b h , for 1b
2 2 2
2 2
2 2 2
2 2 2
2 2
a b c
b b
a c b
a c b
a c b
1 2
1 2
1 2
2 2
2 1
12 2
2
2
2
2
A b b h
A b b h
h
Ab b
h
b b
Ab b
h
5212 32
9
5180
9
100
C
C
C
570 32
9
9 5 970 32
5 9 5
126 32
32 32
158
F
F
F
F
2(3 1) 4 6 6
6 2 4 6 6
6 6 6 6
6 6
6 6
All Real Numbers
x x
x x
x x
x x
2( 6) 4 17 2
2 12 4 17 2
2 16 17 2
2 2
16 17
x x
x x
x x
x x
No Solution
6 2 14
6 14
14 14
8
n n
n n
n
n
14 3 17
14 14
0 17 17
17 17
17 17
17 17
17
1
x x
x x
x
x
x
x
Day 3 – Slope Intercept Form and Writing Equations of Lines
Objectives: SWBAT graph lines
SWBAT write the equation of lines from their graphs SWBAT write the equation of lines from a point and a slope
Slope –
Slope intercept form –
Examples State the slope and the y-intercept for each of the following equations.
1. y = x – 1 2. 2
xy 3. y = 5 4. x = –3
Rewrite each equation into slope-intercept form.
5. 3x + 2y = 15 6. 2x – y = 0
1
1
m
b
1
2
0
m
b
0
5
m or no slope
b
'
m undefined
b doesn t have one
3 2 15
3 3
2 3 15
2 2
3 15
2 2
x y
x x
y x
y x
2 0
2 2
2
2
x y
x x
y x
y x
intercept
b
b
m
m sl
y
ope
x
y
"
" "
"
b
begin with b
m
move wi
x
th
y
m
2 1
2 1
y yrisem
run x x
Graph each equation.
7. 2
( ) 13
f x x 8. 3x – 2y = 4
Put a dot on -3 on y axis, Put a dot on -2 on y axis, then move up 2 right 1 then move up 3 right 2 9. 2y 10. 5x
Horizontal Lines: Vertical Lines: y = any number x = any number
" "
32
2
3
2
2
Solve for y first
y x
m
b
22
1
3
m or
b
0
2
m or no slope
b
'
m undefined
b doesn t have one
Write the equation of each line graphed below.
Line a: 3 2y x Line d: 7y
Line b: 1
3y x Line e:
16
2y x
Line c: 9x
Point Slope form of a linear equation–
Traditional Formula (H, K)
Use point slope form to write an equation for each problem. Then change it to slope intercept form.
Pick either formula to use – they both will work
11. It passes through (4, 2) with a slope of –4
a
b
c
d
e
1 1, a pointx y
m s
x
y
o
y
l
x
pe
1 1my xy x
, a point
x x
y y
a slope
h k
y ha x k
2 4 16
2
2 4
2
4 18
4
y
x
x
y x
y
4 16 2
4
4 4
1
2
8
y x
y
y
x
x
12. Contains (4,1) and the slope is undefined
Since the slope is undefined means you will have a vertical line.
x = 1
13. Contains the origin and (–6, –3)
You must find the slope between those two points
2 1
2 1
3 0 3 1
6 0 6 2
y ym
x x
You can now use either point so use (0,0) because it is the easiest
14. Contains an x-intercept of 2 and y-intercept of 3
You must find the slope between those two points (2,0) and (0,3)
2 1
2 1
3 0 3 3
0 2 2 2
y ym
x x
You can now use either point so use (0,3) because it is the easiest
10 0
2
2
0 01
1
2
y
y
x
x
y x
10 0
2
2
2
0
1
01
y x
y
x
x
y
33
2
3
3
2
3
3 0
33
2
y x
x
y x
y
30 3
2
3
3
2
0
3
32
y
y x
x
y x
Day 4 – Solving Systems of Equations by Graphing and Substitution
Objectives: SWBAT solve systems of equations by graphing.
Objectives: SWBAT solve systems of equations by Substitution
What is a system of linear equations?
Two or more equations with the same variable make-up
What is a solution to a system of equations?
A Point
Finding Solutions to Systems of Equations by Graphing
1) Graph Both Lines
2) Find where they intersect
1) y = 2x + 3 and y = –3x – 2
2 3
2
3
y x
m
b
3 2
3
2
y x
m
b
Intersection point Check
1,1
2 3
1 2 1 3
1 2 3
1 1
y x
3 2
1 3 1 2
1 3 2
1 1
y x
Introduction to Substitution
Take the value of one variable and plug it into the second equation.
Find the solution to the system
1. 6
2 3
x
y x
2.
3 6 18
2
x y
y
x is already solved for, so plug it y is already solved for,
into the other equation. so plug it into the other equation.
2 3
2 6 3
12 3
9
y x
y
y
y
3 6 18
3 6 2 18
3 12 18
3 30
10
x y
x
x
x
x
6,9 10,2
Solving Systems of Equations by Substitution
1) Look at the system of equations. Decide which problem will be the easiest to isolate a variable. You have 4 ways to proceed WORKER SMARTER NOT HARDER
2) Decide which variable you want to solve for, and isolate that variable.
3) Plug or “Substitute” the equation into the variable into the other equation,
solve for the single variable.
4) Substitute the value of the first variable, and plug it back into the first equation. Solve for the Second equation. This will produce the part
of your answer.
5) Check it! Put both values into both equations to see if it checks out.
6) ***** If the two equations are the same, the answer is infinite solutions.
7)****** If the two equations are parallel, then there is no solution.
***** If your Math is good, it does not matter where you start substituting! The answer will be the same*******
Examples Solve the following systems of equations using substitution.
3. x = 3y – 4 and 8x – 3y = 136
1) Let’s look at the two equations, which equation would be easier to isolate a particular variable? (EQN 1 since it is already set equal to “x” 2) Take the “3y-4”, and plug into the equation 8x -3y =136. It should now read, “8(3y+4) -
3y =136” 3) Solve for y. Then take that “y” and plug the value of y into “x=3y-4”
4) Solve for x. 5) Check it.
24 32 3
8(
136
21 32 1
3 4) 3 136
36
21 168
8
y y
y
y
y
y y
24 4
2
3(8) 4
0
x
x
x
20 3(8) 4
20 24 4
20 20
8(20) 3(8) 136
160 24 136
136 136
4. 3x – y = 142 and x – 2y = 134
5. 3x + 6y = –39 and 2x – 5y = 55
2 134
2 134
x y
x y
6 402 142
5
3(
402 142
5 260
52
2 134) 142
y y
y
y y
y
y
104 134
2( 52) 134
30
x
x
x
3(30) ( 52) 142
90 52 142
142 142
30 2( 52) 134
30 104 134
134 134
3 6 39
3 6 39
2 13
x y
x y
x y
4 26 5 55
9 26 5
2( 2 13) 5 55
5
9 81
9
y y
y
y y
y
y
3 6( 9) 39
3 54 39
3 15
5
x
x
x
x
3(5) 6( 9) 39
15 54 39
39 39
2(5) 5( 9) 55
10 45 55
55 55
Day 5 – Solving Systems of Equations by Elimination
Objectives: SWBAT solve systems of equations by Elimination
Solving Systems of Equations by Elimination
1) Put both equations into the __Standard_ form. Usually this will be ___Ax + By = C____Form (X AND Y ON THE SAME SIDE).
2) Get __Matching___________________ coefficients in front of either the ‘x’ or ‘y’
variables.
3) Add the two equations together. Make sure this ___cancel out__________ one
of our variables. Solve the remaining __equation______________. You just
found _First part__ of your answer.
4) Substitute ___________ the value for the solved variable back into either equation. Then solve the remaining __Equation________________. This is the other __Part_______ of your answer.
5) Write your answer as a _______X=____________, and ________Y=____________. Or
as an ordered pair.
6) If both variables cancel out, then if it is a true statement then it is all real
numbers, and if it is a false statement then it is no solution.
7) Check your Work.
Examples
Solve the following systems of equations using elimination. 1. 3 2 17 5 2 7x y and x y 2. 7 2 22 7 2 20x y and x y
__ 3 2 1
8 2
7
( ) 7
4
3
5 2
x y
x
x
y
x
15 2
5(3) 2
7
2 8
4
7
y
y
y
y
__ 7 2 22
( ) 2
4
20
2
1
7
2
x
y
x y
y
y
7 1 21
7 2
17 2
1
3
202
x
x
x
x
3. 6y + 37 = 5x and 3x – 9 = 4y + 14 4. 3x – 4y = 18 and 9x – 12y = 54
9 12 54
3 3 4
9 12 5
18
9 12 5
0 0
4
0
4
x y
Infinately Many Solutions
x y
x
x y
x
y
y
5. 8x + 5 = –y and 11 + 2y = –16x
6 37 5
37 37
6 5 37
5 5
6 5 37
y x
y x
x x
y x
3 9 4 14
9 9
3 4 23
4 4
3 4 23
x y
x y
y y
x y
18 15 11
3
1
20 15 1
6 5 37
5 4 3 23
4
5
2
2 2
2
1
y x
y x
y x
y
y x
y
12 37 5
6 2 3
2
7
5
5
5 5
5 5
x
x
x
x
8 5
8 8
5 8
8 5
x y
x x
y x
x y
11 2 16
2 2
11 16 2
16 2 11
y x
y y
x y
x y
2 8 5
16 2 11
16 2 10
16 2 11
0 0 1
x y
x
No So
y
x y
x y
lu ion
y
t
x
Day 6 – Solving Systems of Equations with 3 Variables
Objectives: SWBAT to solve a system involving three equations and three unknowns.
Ordered Triple -
THE ELIMINATION METHOD FOR A THREE-VARIABLE SYSTEM
1) Write two Elimination Equations, (top two and bottom two – but you can pick
any two)
2) Eliminate a variable the first equation (you should be left with an equation
with two variables).
3) Eliminate the same variable in the second set of equations (you should be left with an equation with two variables).
4) Line up the equations with only two variables, and perform Elimination again. Then solve that equation (you will have one part of your ordered triple).
5) Back substitute that solution into one of the equations with two variables to
get the second answer (you will get the second part of your ordered triple).
6) Take those two answers, and back substitute into one of the original
equations for your third answer.
7) Write you answer as an ordered triple and Check your work.
Examples on the next page….
Examples: Solve the System.
1. 2.
Write two Elimination Equations, (top two and bottom two)
Eliminate a variable the first equation (you should be left with an equation with two variables).
Eliminate the same variable in the second set of equations (you should be left with an equation with two variables).
Line up the equations with only two variables, and perform Elimination again. Then solve that equation.
4 2 3 1
2 3 5 14
6 4 1
x y z
x y z
x y z
3 2 10
6 2 2
4 3 7
x y z
x y z
x y z
4 2 3 1
2 3 5 14
x y z
x y z
2 3 5 14
6 4 1
x y z
x y z
3 2 10
6 2 2
x y z
x y z
6 2 2
4 3 7
x y z
x y z
4 2 3 1
2 2 3 5 14
4 2 3 1
4 6 10 28
8 7 29
x y z
x y z
x y z
x y z
y z
3 2 3 5 14
6 4 1
6 9 15 42
6 4 1
8 11 41
x y z
x y z
x y z
x y z
y z
8 7 29
8 11 41
1 8 7 29
8 11 41
8 7 29
8 11 41
4 12
4 12
4
3
y z
y z
y z
y z
y z
y z
z
z
z
2 3 2 10
6 2 2
6 2 4 20
6 2 2
12 3 18
x y z
x y z
x y z
x y z
x z
2 6 2 2
4 3 7
12 4 2 4
4 3 7
13 5 3
x y z
x y z
x y z
x y z
x z
12 3 18
13 5 3
5 12 3 18
3 13 5 3
60 15 90
39 15 9
99 99
99 99
99
1
x z
x z
x z
x z
x z
x z
x
x
x
Back substitute that solution into one of the equations with two variables to get the second answer.
Take those two answers, and back substitute into one of the original equations for your third answer.
Write all three as an Ordered Triple – This is your answer
8 7 29
8 7 3 29
8 21 29
8 8
8 8
8
1
y z
y
y
y
y
y
4 2 3 1
4 2 1 3 3 1
4 2 9 1
4 7 1
4 8
4 8
2
4
x y z
x
x
x
x
x
x
3
1
2
2 1 3, ,
z
y
x
13 5 3
13 1 5 3
13 5 3
5 10
5 10
5
2
x z
z
z
z
y
y
6 2 2
6 1 2 2 2
6 2 2 2
2 4 2
2 6
2 6
2
3
x y z
y
y
y
y
y
y
1
2
3
1 3 2, ,
x
z
y
3.
Write two Elimination Equations, (top two and bottom two)
Eliminate a variable the first equation (you should be left with an equation with two
variables).
Eliminate the same variable in the second set of equations (you should be left with an
equation with two variables).
Line up the equations with only two variables, and perform Elimination again. Then solve that equation.
4 3 5 19
3 8 21
2 3 13
x y z
x y z
x y z
4 3 5 19
3 8 21
x y z
x y z
3 8 21
2 3 13
x y z
x y z
4 3 5 19
3 3 8 21
4 3 5 19
9 3 24 63
5 29 44
x y z
x y z
x y z
x y z
x z
3 8 21
2 3 13
3 8 21
2 3 13
5 8
x y z
x y z
x y z
x y z
x z
5 29 44
5 8
5 29 44
5 5 8
5 29 44
5 25 40
4 4
4 4
4
1
x z
x z
x z
x z
x z
x z
z
z
z
Back substitute that solution into one of the equations with two variables to get the second answer.
Take those two answers, and back substitute into one of the original equations for your third answer.
Write all three as an Ordered Triple – This is your answer
Special Cases
5. 6.
NO SOLUTION INFINATELY MANY SOLUTIONS
5 8
5 1 8
5 8
3
x z
x
x
x
2 3 13
2 3 3 1 13
6 3 13
9 13
4
x y z
y
y
y
y
1
3
4
3 4 1, ,
z
x
y
2 4 10 14
2 5 4
3 4 3 15
x y z
x y z
x y z
2 2 13
9
4 4 21
x y z
x y z
x y z
Day 7 – Domain and Range
Objectives: SWBAT state the domain and range from a set of points. SWBAT state the domain and range from a graph.
Vocabulary ~
Domain~
The set of all inputs or x-coordinates
of a function and/or graph
Range~ The set of all outputs or y-coordinates
of a function and/or graph
Find the domain of the following sets of points
1. (𝟑, −𝟓) , (𝟓, −𝟔) , (−𝟏𝟎, 𝟓) , (𝟐, 𝟎) 2. (−𝟓, 𝟕) , (𝟐, 𝟑) , (𝟑, 𝟑) , (𝟓, −𝟓)
Domain: −𝟏𝟎, 𝟐, 𝟑, 𝟓 Domain: −𝟓, 𝟐, 𝟑, 𝟓
Range: −𝟔, −𝟓, 𝟎, 𝟓 Range: −𝟓, 𝟑, 𝟕
Find the domain and range of each function
Domain: -9, -7, -5, -3, -1 Range: -10, -6, -2, 2, 6 domain: 9 9x Range: 1 9y
Domain
x coordinates
inputs
Domain: 4 5x Range: 5 8y Domain: 8 0x Range: 8 8y
Domain: 7 7x Range: 0 7y Domain: 4 5x Range: 6 6y
Find the domain and range of each function
Domain: 2x Range: 0y Domain: 8x Range: 1y
Domain: ARN Range: 3y Domain:
0x Range: ARN
Domain: ARN Range: ARN Domain: ARN Range: 9y
Day 8 – Notation
Objective: SWBAT write domain and ranges in set, interval, and inequality notation
Words Inequality Notation
Set Notation
Interval Notation
Graph
Open Interval
A set of numbers greater
than a and less than b
𝒂 < 𝒙 < 𝒃 {𝒙|𝒂 < 𝒙 < 𝒃} (𝒂, 𝒃)
Closed
Interval
A set of numbers greater than or
equal to a and less than or
equal to b
𝒂 ≤ 𝒙 ≤ 𝒃 {𝒙|𝒂 ≤ 𝒙 ≤ 𝒃} [𝒂, 𝒃]
Infinite Interval
(Positive)
A set of numbers
where x is greater than a
𝒙 > 𝒂
{𝒙|𝒙 > 𝒂}
{𝒙|𝒙 ≥ 𝒂}
(𝒂, +∞)
[𝒂, +∞)
Infinite Interval
(Negative)
A set of numbers
where x is less than or equal to b
𝒙 < 𝒃
{𝒙|𝒙 < 𝒃}
{𝒙|𝒙 ≤ 𝒃}
(−∞, 𝒃)
(−∞, 𝒃]
Given the following graph, write the domain and range in inequality, set, and interval notation. Also, describe using words.
1.
Words Inequality Set Interval
D
The domain is in-between -9 and 9 inclusive −𝟗 ≤ 𝒙 ≤ 𝟗 {𝒙| − 𝟗 ≤ 𝒙 ≤ 𝟗} [−𝟗, 𝟗]
R The range is in-between 1
and 9 inclusive 𝟏 ≤ 𝒚 ≤ 𝟗 {𝒚|𝟏 ≤ 𝒚 ≤ 𝟗} [𝟏, 𝟗]
2.
Words Inequality Set Interval
D
The domain is greater than
2 𝒙 > 𝟐 {𝒙|𝒙 > 𝟐} (𝟐, ∞)
R The range is less than -3 𝒚 < −𝟑 {𝒚|𝒚 < −𝟑} (−∞, 𝟐)
Words Inequality Set Interval
D
The domain is greater than
or equal to -3 𝒙 ≥ −𝟑 {𝒙|𝒙 ≥ −𝟑} [−𝟑, ∞)
R
The range is greater than or equal to 1 𝒚 ≥ 𝟏 {𝒚|𝒚 > 𝟏} [𝟏, ∞)
Words Inequality Set Interval
D The domain is all real numbers
−∞ < 𝒙 < ∞ {𝒙| − ∞ < 𝒙< ∞}
(−∞, ∞)
R The range is less than or equal to 1
𝒚 ≤ 𝟏 {𝒚|𝒚 ≤ 𝟏} (−∞, 𝟏]
Day 9 – Piecewise Functions – Day 1
Objectives: SWBAT graph functions with restrictive domains
SWBAT evaluate piecewise functions
Piecewise Function Functions or graphs that are formed
by piecing together two or more functions onto one coordinate plane.
Close Dot Indicates if an endpoint is included with
that particular piece of the graph
Open Dot Indicates if an endpoint is not included with that particular piece of the graph
Restricted Domains When the domain is restricted to include a set of specific numbers
Evaluating the piecewise functions given the following domains
2
31 2
2
1 2 1
3 1
x , if x
f ( x ) x , if x
x , if x
1. when x = 0 2. when x = –8 3. for f(–2) 4. for f(10)
2
3x 1, if x 2
2
f (x)
3x
x 1, if 2 x 1
f 0 0 1
f 0 0
, if
1
f
x
0
1
1
2
f (x) x 1, if 2 x 1
3x , if
3x 1, if x 2
2
3f 8 8 1
2
f 8 12 1
8 1
x
1
1
f
2
3x 1, if x 2
2
f (x)
3x , if
x 1, if 2 x 1
f 2 2 1
x 1
f 2 2 1
f 2 1
2
2
3x , i
3x 1, if x 2
2
f (x) x 1, if 2 x
f x 1
f 10 3 10
f 10 3 100
f 10 300
1
Graph the following functions:
You are not graphing the whole line, just the part that the restrictive domain tells you to.
1. = 2 1, 1f x x if x
1
2. = 5, 32
f x x if x
5. = 7, 3 2f x x if x
1
6. = 5 1 63
f x x if x
Day 10 – Piecewise Functions – Day 2
Objectives: SWBAT graph piecewise functions
Graph the following piecewise function.
5 3 if 3 1
2 2 if 2
x x. g( x )
x x
11 3
2 2
2 3
x , if x. f ( x )
x , if x
2 4, 1
3. = , 1
x xf x
x x
1, 4
4. = 2 1 , 3
8, 3 4
x x
f x x x
x
Step functions –
A piecewise functions that involve all horizontal lines.
2, 7 5
5. = 0, 3 3
4, 4 8
x
f x x
x
6. Write a piecewise function for the graph shown below.
1 0 1
2 1 2
3 2 3
if x
f x if x
if x
Given the following graphs, write a piecewise function.
7. 8.
3
2 4
0
1 2
1x if x
x ifx
xf
3 2
1
4
42
x
x if x
f xif x
9. In 2005, the cost C (in dollars) to send U.S. Postal Service Express Mail up to 5 pounds depended on the weight w (in ounces) according to the function below.
13.65, if 0 8
17.85, if 8 32
= 21.05, if 32 48
24.20, if 48 64
27.30, if 64 80
x
x
C w x
x
x
A) Graph the function.
B) What is the cost to send a parcel weighing 2 pounds and 9 ounces?
2 9 2 16 9
41
21.05
lbs ozs
ozs
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