8. Alternator Stand Alone

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    ELEN 3441 Fundamentals of Power Engineering Spring 2008

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    The Synchronous generatoroperating alone

    Effects of load changes

    increase in the load is anincrease in the real and!orreacti"e power drawn from the

    generator#Since the field resistor is unaffected$ the field current is constant and$ therefore$ theflu%φ is constant too# Since the speed is assumed as constant$ the magnitude ofthe internal generated "oltage is constant also#

    ssuming the same power factor of the load$ change in load will change the

    magnitude of the armature current I A# &owe"er$ the angle will 'e the same (for aconstant PF)# *hus$ the armature reaction "oltage jX SI A will 'e larger for theincreased load# Since the magnitude of the internal generated "oltage is constant

    A S A E V jX I φ = + (+#34#1)

    rmature reaction "oltage "ector will ,mo"e parallel- to its initial position#

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    ELEN 3441 Fundamentals of Power Engineering Spring 2008

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    The Synchronous generatoroperating alone

    .ncrease load effect on generators with

    Lagging PF

    Leading PF

    /nit PF

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    ELEN 3441 Fundamentals of Power Engineering Spring 2008

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    The Synchronous generatoroperating alone

    1# For lagging (inducti"e) loads$ the phase (and terminal) "oltagedecreases significantl #

    2# For unit power factor (purel resisti"e) loads$ the phase (andterminal) "oltage decreases slightl #3# For leading (capaciti"e) loads$ the phase (and terminal) "oltage rises#

    enerall $ when a load on a s nchronous generator is added$ the followingchanges can 'e o'ser"ed

    Effects of adding loads can 'e descri'ed ' the "oltage regulation

    100%nl fl

    fl

    V V VRV

    −= (+#3 #1)

    here V nl is the no5load "oltage of the generator and V fl is its full5load "oltage#

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    ELEN 3441 Fundamentals of Power Engineering Spring 2008

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    The Synchronous generatoroperating alone

    s nchronous generator operating at a lagging power factor has a fairl large positi"e "oltage regulation# s nchronous generator operating at a unit powerfactor has a small positi"e "oltage regulation# s nchronous generator operatingat a leading power factor often has a negati"e "oltage regulation#

    Normall $ a constant terminal "oltage supplied ' a generator is desired# Since thearmature reactance cannot 'e controlled$ an o'"ious approach to ad6ust theterminal "oltage is ' controlling the internal generated "oltage E A = K φω # *hisma 'e done ' changing flu% in the machine while "ar ing the "alue of the fieldresistance R F $ which is summari7ed

    1# ecreasing the field resistance increases the field current in the generator#2# n increase in the field current increases the flu% in the machine#3# n increased flu% leads to the increase in the internal generated "oltage#4# n increase in the internal generated "oltage increases the terminal "oltage of

    the generator#

    *herefore$ the terminal "oltage of the generator can 'e changed ' ad6usting the

    field resistance#

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    ELEN 3441 Fundamentals of Power Engineering Spring 2008

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    The Synchronous generatoroperating alone: Example

    E%ample +#2 480 :$ 0 &7$ ;5connected si%5pole s nchronous generator has aper5phase s nchronous reactance of 1#0 Ω # .ts full5load armature current is 0 at0#8 PF lagging# .ts friction and windage losses are 1#9 < and core losses are 1#0< at 0 &7 at full load# ssume that the armature resistance (and$ therefore$ the I 2 R losses) can 'e ignored# *he field current has 'een ad6usted such that the no5load

    terminal "oltage is 480 :#a# hat is the speed of rotation of this generator='# hat is the terminal "oltage of the generator if

    1# .t is loaded with the rated current at 0#8 PF lagging>2# .t is loaded with the rated current at 1#0 PF>

    3# .t is loaded with the rated current at 0#8 PF leading#c# hat is the efficienc of this generator (ignoring the un

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    ELEN 3441 Fundamentals of Power Engineering Spring 2008

    The Synchronous generatoroperating alone: Example

    Since the generator is ;5connected$ its phase "oltage is

    3 277T V V V φ = =

    t no load$ the armature current I A @ 0 and the internal generated "oltage is E A @

    2++ : and it is constant since the field current was initiall ad6usted that wa #a# *he speed of rotation of a s nchronous generator is

    120 12060 1200

    6m en f rpm

    P = = =

    which is

    1200

    2 125.760m rad sω π = =

    '#1# For the generator at the rated current and the 0#8PF lagging$ the phasor diagram is shown# *he phase"oltage is at 0 0$ the magnitude of E A is 2++ :$

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    The Synchronous generatoroperating alone: Example

    1 60 36.87 60 53.13S A jX I j= × × ∠ − ° = ∠ °and that

    *wo un

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    The Synchronous generatoroperating alone: Example

    '#2# For the generator at the rated current andthe 1#0 PF$ the phasor diagram is shown#*hen

    ( ) 22 cos sin 270.4

    A S A S AV E X I X I V φ θ θ = − − =

    3 468.4T

    V V V φ

    = =and

    '#3# For the generator at the rated current and the0#8 PF leading$ the phasor diagram is shown#*hen

    ( ) 22 cos sin 308.8

    A S A S AV E X I X I V φ θ θ = − − =

    3 535T

    V V V φ

    = =and

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    The Synchronous generatoroperating alone: Example

    c# *he output power of the generator at 0 and 0#8 PF lagging is

    3 cos 3 236.8 60 0.8 34.1out A P V I kW φ θ = = × × × =

    *he mechanical input power is gi"en '

    34.1 0 1.0 1.5 36.6in out elec loss core loss mech loss P P P P P kW = + + + = + + + =

    *he efficienc is34.1

    100 % 100% 93.2%36.6

    out

    in

    P P

    η = × = × =

    d# *he input tor?ue of the generator is

    36.6291.2

    125.7in

    appm

    P N mτ

    ω = = = -

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    The Synchronous generatoroperating alone: Example

    *he induced countertor?ue of the generator is

    e# *he "oltage regulation of the generator is

    34.1271.3

    125.7conv

    appm

    P N mτ

    ω = = = -

    Lagging PF480 410

    100% 17.1%410

    VR−

    = × =

    /nit PF

    Lagging PF

    480 468100% 2.6%

    468VR

    −= × =

    480 535100% 10.3%

    535VR

    −= × = −

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    Terminal characteristics ofsynchronous generators

    ll generators are dri"en ' a prime mo"er $ such as a steam$ gas$ water$ windtur'ines$ diesel engines$ etc# Begardless the power source$ most of prime mo"erstend to slow down with increasing the load# *his decrease in speed is usuallnonlinear 'ut go"ernor mechanisms of some t pe ma 'e included to lineari7e thisdependence#

    *he speed drop (S ) of a prime mo"er is defined as

    100%nl fl

    fl

    n nSD

    n

    −= ×

    Cost prime mo"ers ha"e a speed drop from 2D to 4D# Cost go"ernors ha"e amechanism to ad6ust the tur'ine s no5load speed (set5point ad6ustment)#

    (+#44#1)

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    Terminal characteristics ofsynchronous generators

    t pical speed"s# power plot

    Since the shaft speed is lin

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    Terminal characteristics ofsynchronous generators

    similar relationship can 'e deri"ed for the reacti"e power Q and terminal "oltageV T # hen adding a lagging load to a s nchronous generator$ its terminal "oltagedecreases# hen adding a leading load to a s nchronous generator$ its terminal"oltage increases#

    *he plot of terminal "oltage "s#

    reacti"e power is not necessarillinear#

    Goth the fre?uenc 5power andterminal "oltage "s# reacti"e powercharacteristics are important forparallel operations of generators#

    hen a generator is operating alone suppl ing the load1#*he real and reacti"e powers are the amounts demanded ' the load#2#*he go"ernor of the prime mo"er controls the operating fre?uenc of the s stem#3#*he field current controls the terminal "oltage of the power s stem#

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    Terminal characteristics ofsynchronous generators: Example

    E%ample +#3 generator with no5load fre?uencof 1#0 &7 and a slope s p of 1 C !&7 isconnected to Load 1 consuming 1 C of realpower at 0#8 PF lagging# Load 2 (that is to 'econnected to the generator) consumes a real

    power of 0#8 C at 0#+0+ PF lagging#a# Find the operating fre?uenc of the s stem 'efore the switch is closed#'# Find the operating fre?uenc of the s stem after the switch is closed#c# hat action could an operator ta

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    Terminal characteristics ofsynchronous generators: Example

    a# *he fre?uenc of the s stem with one load is

    161 60

    1 s s nl p

    P f f !"

    s= − = − =

    '# *he fre?uenc of the s stem with two loads is1.8

    61 59.21 s s nl

    p

    P f f !"

    s= − = − =

    c# *o restore the s stem to the proper operating fre?uenc $ the operator shouldincrease the go"ernor no5load set point ' 0#8 &7$ to 1#8 &7# *his will restorethe s stem fre?uenc of 0 &7#