2.5 – Rational Functions. Ex. 1 Graph 5 x – 2 Ex. 1 Graph 5 x – 2

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2.5 – Rational Functions

Ex. 1 Graph 5

x – 2

Ex. 1 Graph 5

x – 2

Ex. 1 Graph 5

x – 2

x – 2 = 0

Ex. 1 Graph 5

x – 2

x – 2 = 0

x = 2

Ex. 1 Graph 5

x – 2

x – 2 = 0

x = 2 (vertical asymptote)

Ex. 1 Graph 5

x – 2

x – 2 = 0

x = 2 (asymptote)

Ex. 1 Graph 5

x – 2

x – 2 = 0

x = 2 (asymptote)

Ex. 1 Graph 5

x – 2

x – 2 = 0

x = 2 (asymptote)

*Graph on Calc.

Ex. 1 Graph 5

x – 2

x – 2 = 0

x = 2 (asymptote)

*Graph on Calc.

Type: y = 5/(x – 2)

Ex. 1 Graph 5

x – 2

x – 2 = 0

x = 2 (asymptote)

*Graph on Calc.

Type: y = 5/(x – 2)2nd Table, 3pts on each curve

Ex. 1 Graph 5

x – 2

x – 2 = 0

x = 2 (asymptote)

*Graph on Calc.

Type: y = 5/(x – 2)2nd Table, 3pts on each curve

Ex. 2 Graph x + 1

x2 + 3x + 2

Ex. 2 Graph x + 1

x2 + 3x + 2

x + 1

(x + 2)(x + 1)

Ex. 2 Graph x + 1

x2 + 3x + 2

x + 1

(x + 2)(x + 1)

1

x + 2

Ex. 2 Graph x + 1

x2 + 3x + 2

x + 1

(x + 2)(x + 1)

1

x + 2

Asymp. @ x = -2

Ex. 2 Graph x + 1

x2 + 3x + 2

x + 1

(x + 2)(x + 1)

1

x + 2

Asymp. @ x = -2

Hole @ x = -1

Ex. 2 Graph x + 1

x2 + 3x + 2

x + 1

(x + 2)(x + 1)

1

x + 2

Asymp. @ x = -2

Hole @ x = -1

Graph y = (x+1)/(x2+3x+2)

Ex. 2 Graph x + 1

x2 + 3x + 2

x + 1

(x + 2)(x + 1)

1

x + 2

Asymp. @ x = -2

Hole @ x = -1

*Graph y = (x+1)/(x2+3x+2)

*Then 2nd Table for 3 ordered

pairs per curve.

Ex. 2 Graph x + 1

x2 + 3x + 2

x + 1

(x + 2)(x + 1)

1

x + 2

Asymp. @ x = -2

Hole @ x = -1

*Graph y = (x+1)/(x2+3x+2)

*Then 2nd Table for 3 ordered

pairs per curve.

Ex. 3 Determine any asymptotes and intercepts. Then graph and find the domain.

f(x) = 3x2 – 3

x2 – 9

Ex. 3 Determine any asymptotes and intercepts. Then graph and find the domain.

f(x) = 3x2 – 3 = 3(x + 1)(x – 1)

x2 – 9 (x + 3)(x – 3)

Ex. 3 Determine any asymptotes and intercepts. Then graph and find the domain.

f(x) = 3x2 – 3 = 3(x + 1)(x – 1)

x2 – 9 (x + 3)(x – 3)

Vertical Asymptotes at x = -3 & x = 3

Ex. 3 Determine any asymptotes and intercepts. Then graph and find the domain.

f(x) = 3x2 – 3 = 3(x + 1)(x – 1)

x2 – 9 (x + 3)(x – 3)

Vertical Asymptotes at x = -3 & x = 3

Graph, use Table to find limits for Horizontal.

Ex. 3 Determine any asymptotes and intercepts. Then graph and find the domain.

f(x) = 3x2 – 3 = 3(x + 1)(x – 1)

x2 – 9 (x + 3)(x – 3)

Vertical Asymptotes at x = -3 & x = 3

Graph, use Table to find limits for Horizontal.

Limits show Horizontal Asymptote at y = 3.

Domain: {x | x ≠ -3, x ≠ 3}

• Proportions: 1 fraction = 1 fraction

Ex. 1 Solve each equation.

a. p _ = 2

p – 2 3

• Proportions: 1 fraction = 1 fraction

Ex. 1 Solve each equation.

a. p _ = 2

p – 2 3

• Proportions: 1 fraction = 1 fraction

Ex. 1 Solve each equation.

a. p _ = 2

p – 2 3

2(p – 2)

• Proportions: 1 fraction = 1 fraction

Ex. 1 Solve each equation.

a. p _ = 2

p – 2 3

2(p – 2) =

• Proportions: 1 fraction = 1 fraction

Ex. 1 Solve each equation.

a. p _ = 2

p – 2 3

2(p – 2) = 3p

• Proportions: 1 fraction = 1 fraction

Ex. 1 Solve each equation.

a. p _ = 2

p – 2 3

2(p – 2) = 3p

2p – 4 = 3p

• Proportions: 1 fraction = 1 fraction

Ex. 1 Solve each equation.

a. p _ = 2

p – 2 3

2(p – 2) = 3p

2p – 4 = 3p

-2p -2p

• Proportions: 1 fraction = 1 fraction

Ex. 1 Solve each equation.

a. p _ = 2

p – 2 3

2(p – 2) = 3p

2p – 4 = 3p

-2p -2p

-4

• Proportions: 1 fraction = 1 fraction

Ex. 1 Solve each equation.

a. p _ = 2

p – 2 3

2(p – 2) = 3p

2p – 4 = 3p

-2p -2p

-4 =

• Proportions: 1 fraction = 1 fraction

Ex. 1 Solve each equation.

a. p _ = 2

p – 2 3

2(p – 2) = 3p

2p – 4 = 3p

-2p -2p

-4 = p

b. w + w = 4w – 3

w – 1 w – 1

b. (w-1) w + w (w-1) = 4w – 3 (w-1)

w – 1 w – 1

b. (w-1) w + w (w-1) = 4w – 3 (w-1)

w – 1 w – 1

w + w(w – 1) = 4w – 3

w + w2 – w = 4w - 3

b. (w-1) w + w (w-1) = 4w – 3 (w-1)

w – 1 w – 1

w + w(w – 1) = 4w – 3

w + w2 – w = 4w – 3

w2 = 4w – 3

b. (w-1) w + w (w-1) = 4w – 3 (w-1)

w – 1 w – 1

w + w(w – 1) = 4w – 3

w + w2 – w = 4w – 3

w2 = 4w – 3

w2 – 4w + 3 = 0

b. (w-1) w + w (w-1) = 4w – 3 (w-1)

w – 1 w – 1

w + w(w – 1) = 4w – 3

w + w2 – w = 4w – 3

w2 = 4w – 3

w2 – 4w + 3 = 0

(w – 3)(w – 1) = 0

b. (w-1) w + w (w-1) = 4w – 3 (w-1)

w – 1 w – 1

w + w(w – 1) = 4w – 3

w + w2 – w = 4w – 3

w2 = 4w – 3

w2 – 4w + 3 = 0

(w – 3)(w – 1) = 0

w = 3, w = 1

b. (w-1) w + w (w-1) = 4w – 3 (w-1)

w – 1 w – 1

w + w(w – 1) = 4w – 3

w + w2 – w = 4w – 3

w2 = 4w – 3

w2 – 4w + 3 = 0

(w – 3)(w – 1) = 0

w = 3, w = 1

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